Replace values using Key defined with inline variable - xslt

I'm trying to understand the usage of keys and can't get my example to work.
Starting with this XML:
<items>
<item>Blue</item>
<item>Green</item>
<item>Orange</item>
</items>
I want to get this output XML:
<items>
<item>PURPLE</item>
<item>BLACK</item>
<item>PINK</item>
</items>
I defined the mapping directly in a variable in the XSLT transformation:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
version="2.0">
<xsl:output method="xml" indent="yes"/>
<xsl:variable name="mappings">
<mapping orig="Blue" repla="PURPLE"/>
<mapping orig="Green" repla="BLACK"/>
<mapping orig="Orange" repla="PINK"/>
</xsl:variable>
<xsl:key name="mappingsKey" match="$mappings/mapping" use="#orig"/>
<xsl:template match="items">
<xsl:copy>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
<xsl:template match="item">
<xsl:copy>
<xsl:value-of select="key('mappingsKey',.)"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
I know I'm missing the instruction to tell which is the replacement value, but don't know how to define it.
Example available here: https://xsltfiddle.liberty-development.net/ejivdHp/1
Thanks.

The $mappings variable is in a different document than the processed XML. You need to point the key() function to there. And you also need to select the repla attribute:
<xsl:value-of select="key('mappingsKey', ., $mappings)/#repla"/>
Referencing the variable in the match pattern of the xsl:key element is meaningless.
https://xsltfiddle.liberty-development.net/ejivdHp/2

Related

Why variable goes wrong as "document-node()" in sub xsl:template?

Looking directly at the example:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="xs"
version="3.0">
<xsl:template match="/">
<xsl:variable name="v1" select="." as="document-node()"/>
<xsl:apply-templates select=".//name"/>
</xsl:template>
<xsl:template match="name">
<xsl:variable name="v2" select="." as="document-node()"/>
<xsl:apply-templates/>
</xsl:template>
</xsl:stylesheet>
source xml:
<?xml version="1.0" encoding="UTF-8"?>
<root>
<item>
<name>John</name>
<age>21</age>
</item>
</root>
The question is that: variable v1 can be declarated well, but v2 has an error "Required item type of value of variable $v2 is document-node(); supplied expression (.) has item type element(Q{}name)".
I looked up the definition of document-node() in w3c xpath document, it says "document-node() matches any document node." 2.5.5.2 Matching an ItemType and an Item. I still can't understand why v2 is wrong with type document-node().
I have make a online test demo
Because it's not a document-node(), it's an element(). Use element() instead. <xsl:template match="/"> matches a document-node(), and <xsl:template match="name"> matches an element() node.

XPath 3.0 Serialize without Namespaces in Scope

While answering this question, it occurred to me that I know how to use the XSLT 3.0 (XPath 3.0) serialize() function, but that I do not know how to avoid serialization of namespaces that are in scope. Here is a minimal example:
XML Input
<?xml version="1.0" encoding="UTF-8" ?>
<ci:cichlids xmlns:ci="http://www.cichlids.com">
<cichlid id="1">
<name>Zeus</name>
<color>gold</color>
<teeth>molariform</teeth>
<breeding-type>lekking</breeding-type>
</cichlid>
</ci:cichlids>
XSLT 3.0 Stylesheet
<xsl:stylesheet version="3.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:output="http://www.w3.org/2010/xslt-xquery-serialization"
xmlns:ci="http://www.cichlids.com">
<xsl:output method="xml" encoding="UTF-8" indent="yes" />
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="/ci:cichlids/cichlid">
<xsl:variable name="serial-params">
<output:serialization-parameters>
<output:omit-xml-declaration value="yes"/>
</output:serialization-parameters>
</xsl:variable>
<xsl:value-of select="serialize(., $serial-params/*)"/>
</xsl:template>
</xsl:stylesheet>
Actual Output
<?xml version="1.0" encoding="UTF-8"?>
<ci:cichlids xmlns:ci="http://www.cichlids.com">
<cichlid xmlns:ci="http://www.cichlids.com" id="1">
<name>Zeus</name>
<color>gold</color>
<teeth>molariform</teeth>
<breeding-type>lekking</breeding-type>
</cichlid>
</ci:cichlids>
The serialization process included the namespace declaration that is in scope for the cichlid element, although it is not used on this element. I would like to remove this declaration and make the output look like
Expected Output
<?xml version="1.0" encoding="UTF-8"?>
<ci:cichlids xmlns:ci="http://www.cichlids.com">
<cichlid id="1">
<name>Zeus</name>
<color>gold</color>
<teeth>molariform</teeth>
<breeding-type>lekking</breeding-type>
</cichlid>
</ci:cichlids>
I know how to modify the cichlid element, removing the namespaces in scope, and serialize this modified element instead. But this seems a rather cumbersome solution. My question is:
What is a canonical way to serialize an XML element using the serialize() function without also serializing unused namespace declarations that are in scope?
Testing with Saxon-EE 9.6.0.7 from within Oxygen.
Serialization will always give you a faithful representation of the data model that you are serializing. If you want to modify the data model, that's called transformation. Run a transformation to remove the unwanted namespaces, then serialize the result.
Michael Kay already gave the correct answer and I have accepted it. This is just to flesh out his comments. By
Run a transformation to remove the unwanted namespaces, then serialize the result.
he means applying a transformation like the following before calling serialize():
XSLT Stylesheet
<xsl:stylesheet version="3.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:output="http://www.w3.org/2010/xslt-xquery-serialization"
xmlns:ci="http://www.cichlids.com">
<xsl:output method="xml" encoding="UTF-8" indent="yes" />
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:variable name="cichlid-without-namespace">
<xsl:copy-of copy-namespaces="no" select="/ci:cichlids/cichlid"/>
</xsl:variable>
<xsl:template match="/ci:cichlids/cichlid">
<xsl:variable name="serial-params">
<output:serialization-parameters>
<output:omit-xml-declaration value="yes"/>
</output:serialization-parameters>
</xsl:variable>
<xsl:value-of select="serialize($cichlid-without-namespace, $serial-params/*)"/>
</xsl:template>
</xsl:stylesheet>
XML Output
<?xml version="1.0" encoding="UTF-8"?>
<ci:cichlids xmlns:ci="http://www.cichlids.com">
<cichlid id="1">
<name>Zeus</name>
<color>gold</color>
<teeth>molariform</teeth>
<breeding-type>lekking</breeding-type>
</cichlid>
</ci:cichlids>

Coying an entire xml in a Variable using xslt

How can i copy an entire xml as is in an Variable?
Below is the sample xml:
<?xml version="1.0" encoding="UTF-8"?>
<products author="Jesper">
<product id="p1">
<name>Delta</name>
<price>800</price>
<stock>4</stock>
</product>
</products>
I have tried below xslt but it is not working.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format" version="1.0">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="#*|node()">
<xsl:variable name="reqMsg">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:variable>
<xsl:copy-of select="$reqMsg"/>
</xsl:template>
</xsl:stylesheet>
Regards,
Rahul
Your transformation fails because at a certain point, it tries to create a variable (result tree fragment) containing an attribute node. This is not allowed.
It's not really clear what you mean by "copying an entire XML to a variable". But you probably want to simply use the select attribute on the root node:
<xsl:variable name="reqMsg" select="/"/>
This will actually create variable with a node-set containing the root node of the document. Using this variable with xsl:copy-of will output the whole document.
<xsl:copy-of select="document('path/to/file.xml')" />
Or if you need it more than once, to avoid repeating the doc name:
<xsl:variable name="filepath" select="'path/to/file.xml'" />
…
<xsl:copy-of select="document($filepath)" />
The result of document() should be cached IIRC, so don't worry about calling it repeatedly.

How do I make the value of one element a new attribute to the root?

I want to transform a markup like <root><a><c>CA</c></a></root> to <root juris="CA"><a><c>CA</c></a></root>
If you could specify more about the schema that is allowed, something more specific can be written. With what was given, something like this should work though:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:template match="/root">
<xsl:copy>
<xsl:attribute name="juris"><xsl:value-of select="./a/c"/></xsl:attribute>
<xsl:copy-of select="*"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
As it stands, I would not be surprised if this led to issues with more complex inputs.

Generate XSLT to map source value structures to destination field depending on source content

I have a source list of xml in this format:
<metadata>
<metadatum>
<description>OnEnter</description>
<value>Hello World</id>
</metadatum>
<metadatum>
<description>OnLeave</description>
<value>Goodbye World</id>
</metadatum>
</metadata>
and a target structure like this:
<friendlyText>
<onEnter>[Content Here]</onEnter>
<onLeave>[Content Here]</onLeave>
</friendlyText>
Is it possible to create an XSLT that will map the 'value' field in the metadata hierarchy to the proper target node depending on the source 'description'?
I'm trying to get this done with Altova MapForce; it feels like there should be an interface to allow this, I'm just not finding it.
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >
<xsl:output method="xml" indent="yes"/>
<xsl:template match="metadata">
<friendlyText>
<xsl:apply-templates select="metadatum"/>
</friendlyText>
</xsl:template>
<xsl:template match="metadatum">
<xsl:element name="{description}">
<xsl:value-of select="value"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
Output:
<?xml version="1.0" encoding="utf-8"?>
<friendlyText>
<OnEnter>Hello World</OnEnter>
<OnLeave>Goodbye World</OnLeave>
</friendlyText>
This transformation is a general solution that can work with any "target structure" that is in a separate XML document:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:my="my:my" exclude-result-prefixes="my">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:variable name="vUpper" select=
"'ABCDEFGHIJKLMNOPQRSTUVWXYZ'"/>
<xsl:variable name="vLower" select=
"'abcdefghijklmnopqrstuvwxyz'"/>
<my:target>
<friendlyText>
<onEnter>[Content Here]</onEnter>
<onLeave>[Content Here]</onLeave>
</friendlyText>
</my:target>
<xsl:variable name="vTarget" select="document('')/*/my:target/*"/>
<xsl:variable name="vMeta" select="/*/metadatum"/>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="/">
<xsl:apply-templates select="$vTarget"/>
</xsl:template>
<xsl:template match="friendlyText/*/text()">
<xsl:value-of select=
"$vMeta[translate(description, $vLower, $vUpper)
=
translate(name(current()/..), $vLower, $vUpper)
]/value"/>
</xsl:template>
</xsl:stylesheet>
when applied on the provided XML document (corrected to be made well-formed):
<metadata>
<metadatum>
<description>OnEnter</description>
<value>Hello World</value>
</metadatum>
<metadatum>
<description>OnLeave</description>
<value>Goodbye World</value>
</metadatum>
</metadata>
produces the wanted, correct result:
<friendlyText xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:my="my:my">
<onEnter>Hello World</onEnter>
<onLeave>Goodbye World</onLeave>
</friendlyText>
Do note: Only for convenience, the "target structure" is inline here. In a real world case it would be better to keep the "target structure" in a separate file and to load it using the document() function. Only the line:
<xsl:variable name="vTarget" select="document('')/*/my:target/*"/>
will need to be changed to:
<xsl:variable name="vTarget" select="document('someFileUrl')/*"/>