XPath 3.0 Serialize without Namespaces in Scope - xslt

Question

While answering this question, it occurred to me that I know how to use the XSLT 3.0 (XPath 3.0) serialize() function, but that I do not know how to avoid serialization of namespaces that are in scope. Here is a minimal example:
XML Input
<?xml version="1.0" encoding="UTF-8" ?>
<ci:cichlids xmlns:ci="http://www.cichlids.com">
<cichlid id="1">
<name>Zeus</name>
<color>gold</color>
<teeth>molariform</teeth>
<breeding-type>lekking</breeding-type>
</cichlid>
</ci:cichlids>
XSLT 3.0 Stylesheet
<xsl:stylesheet version="3.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:output="http://www.w3.org/2010/xslt-xquery-serialization"
xmlns:ci="http://www.cichlids.com">
<xsl:output method="xml" encoding="UTF-8" indent="yes" />
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="/ci:cichlids/cichlid">
<xsl:variable name="serial-params">
<output:serialization-parameters>
<output:omit-xml-declaration value="yes"/>
</output:serialization-parameters>
</xsl:variable>
<xsl:value-of select="serialize(., $serial-params/*)"/>
</xsl:template>
</xsl:stylesheet>
Actual Output
<?xml version="1.0" encoding="UTF-8"?>
<ci:cichlids xmlns:ci="http://www.cichlids.com">
<cichlid xmlns:ci="http://www.cichlids.com" id="1">
<name>Zeus</name>
<color>gold</color>
<teeth>molariform</teeth>
<breeding-type>lekking</breeding-type>
</cichlid>
</ci:cichlids>
The serialization process included the namespace declaration that is in scope for the cichlid element, although it is not used on this element. I would like to remove this declaration and make the output look like
Expected Output
<?xml version="1.0" encoding="UTF-8"?>
<ci:cichlids xmlns:ci="http://www.cichlids.com">
<cichlid id="1">
<name>Zeus</name>
<color>gold</color>
<teeth>molariform</teeth>
<breeding-type>lekking</breeding-type>
</cichlid>
</ci:cichlids>
I know how to modify the cichlid element, removing the namespaces in scope, and serialize this modified element instead. But this seems a rather cumbersome solution. My question is:
What is a canonical way to serialize an XML element using the serialize() function without also serializing unused namespace declarations that are in scope?
Testing with Saxon-EE 9.6.0.7 from within Oxygen.

Answer 1

Serialization will always give you a faithful representation of the data model that you are serializing. If you want to modify the data model, that's called transformation. Run a transformation to remove the unwanted namespaces, then serialize the result.

Answer 2

Michael Kay already gave the correct answer and I have accepted it. This is just to flesh out his comments. By
Run a transformation to remove the unwanted namespaces, then serialize the result.
he means applying a transformation like the following before calling serialize():
XSLT Stylesheet
<xsl:stylesheet version="3.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:output="http://www.w3.org/2010/xslt-xquery-serialization"
xmlns:ci="http://www.cichlids.com">
<xsl:output method="xml" encoding="UTF-8" indent="yes" />
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:variable name="cichlid-without-namespace">
<xsl:copy-of copy-namespaces="no" select="/ci:cichlids/cichlid"/>
</xsl:variable>
<xsl:template match="/ci:cichlids/cichlid">
<xsl:variable name="serial-params">
<output:serialization-parameters>
<output:omit-xml-declaration value="yes"/>
</output:serialization-parameters>
</xsl:variable>
<xsl:value-of select="serialize($cichlid-without-namespace, $serial-params/*)"/>
</xsl:template>
</xsl:stylesheet>
XML Output
<?xml version="1.0" encoding="UTF-8"?>
<ci:cichlids xmlns:ci="http://www.cichlids.com">
<cichlid id="1">
<name>Zeus</name>
<color>gold</color>
<teeth>molariform</teeth>
<breeding-type>lekking</breeding-type>
</cichlid>
</ci:cichlids>