Regex from Python to Kotlin - regex

Question

I have a question about Regular Expression (Regex) and I really newbie in this. I found a tutorial a Regex written in Python to delete the data and replace it with an empty string.
This is the code from Python:
import re
def extract_identity(data, context):
"""Background Cloud Function to be triggered by Pub/Sub.
Args:
data (dict): The dictionary with data specific to this type of event.
context (google.cloud.functions.Context): The Cloud Functions event
metadata.
"""
import base64
import json
import urllib.parse
import urllib.request
if 'data' in data:
strjson = base64.b64decode(data['data']).decode('utf-8')
text = json.loads(strjson)
text = text['data']['results'][0]['description']
lines = text.split("\n")
res = []
for line in lines:
line = re.sub('gol. darah|nik|kewarganegaraan|nama|status perkawinan|berlaku hingga|alamat|agama|tempat/tgl lahir|jenis kelamin|gol darah|rt/rw|kel|desa|kecamatan', '', line, flags=re.IGNORECASE)
line = line.replace(":","").strip()
if line != "":
res.append(line)
p = {
"province": res[0],
"city": res[1],
"id": res[2],
"name": res[3],
"birthdate": res[4],
}
print('Information extracted:{}'.format(p))
In the above function, information extraction is done by removing all e-KTP labels with regular expressions.
This is the sample of e-KTP:
And this is the result after scanning that e-KTP using the python code:
Information extracted:{'province': 'PROVINSI JAWA TIMUR', 'city': 'KABUPATEN BANYUWANGI', 'id': '351024300b730004', 'name': 'TUHAN', 'birthdate': 'BANYUWANGI, 30-06-1973'}
This is the full tutorial from the above code.
And then my question is, can we use Regex in Kotlin to remove the label from the result of e-KTP like in python code? Because I try some logic that I understand it does not remove the label of e-KTP. My code in Kotlin like this:
....
val lines = result.text.split("\n")
val res = mutableListOf<String>()
Log.e("TAG LIST STRING", lines.toString())
for (line in lines) {
Log.e("TAG STRING", line)
line.matches(Regex("gol. darah|nik|kewarganegaraan|nama|status perkawinan|berlaku hingga|alamat|agama|tempat/tgl lahir|jenis kelamin|gol darah|rt/rw|kel|desa|kecamatan"))
line.replace(":","")
if (line != "") {
res.add(line)
}
Log.e("TAG RES", res.toString())
}
Log.e("TAG INSERT", res.toString())
tvProvinsi.text = res[0]
tvKota.text = res[1]
tvNIK.text = res[2]
tvNama.text = res[3]
tvTgl.text = res[4]
....
And this is the result of my code:
TAG LIST STRING: [PROVINSI JAWA BARAP, KABUPATEN TASIKMALAYA, NIK 320625XXXXXXXXXX, BRiEAFAUZEROMARA, Nama, TempatTgiLahir, Jenis keiamir, etc]
TAG INSERT: [PROVINSI JAWA BARAP, KABUPATEN TASIKMALAYA, NIK 320625XXXXXXXXXX, BRiEAFAUZEROMARA, Nama, TempatTgiLahir, Jenis keiamir, etc]
The label still exists, It's possible to remove a label using Regex or something in Kotlin like in Python?

Answer 1

The point is to use kotlin.text.replace with a Regex as the search argument. For example:
text = text.replace(Regex("""<REGEX_PATTERN_HERE>"""), "<REPLACEMENT_STRING_HERE>")
You may use
line = line.replace(Regex("""(?i)gol\. darah|nik|kewarganegaraan|nama|status perkawinan|berlaku hingga|alamat|agama|tempat/tgl lahir|jenis kelamin|gol darah|rt/rw|kel|desa|kecamatan"""), "")
Note that (?i) at the start of the pattern is a quick way to make the whole pattern case insensitive.
Also, when you need to match a . with a regex you need to escape it. Since a backslash can be coded in several ways and people often fail to do it correctly, it is always recommended to define regex patterns within raw string literals, in Kotlin, you may use the triple-double-quoted string literals, i.e. """...""" where each \ is treated as a literal backslash that is used to form regex escapes.