Calculate the sum in the rows of the array - c++

Question

I have a two-dimensional array A. I need
the elements of the array are written to the elements of the dynamic array elements record the calculated sum of the row of the array A. The dynamic array elements are displayed using pointers.
const unsigned row = 3;
const unsigned col = 4;
int A[row][col];
std::cout << "Input A:\n";
for (int index = 0; index < row; ++index)
{
for (int j = 0; j < col; ++j)
{
std::cout << "A[" << index << "][" << j << "]=";
std::cin >> A[index][j];
}
}
unsigned* array = new unsigned[row];
for (int index = 0; index < row; ++index)
{
for (int j = 0; j < col; ++j)
{
array[index] += A[index][j];
}
}
for (unsigned* index = array; *index; ++index)
{
std::cout << *index << "\n";
}
But alas, it does not work properly. Help me figure it out.
UPD:
unsigned* end = array + row + 1;
std::cout << "Array:\n";
for (unsigned *ptr = array, index = 1; ptr <= end; ++ptr, ++index)
{
std::cout << *ptr << "\t";
}

Answer 1

You never initialized the array so this line has undefined behavior:
array[index] += A[index][j];
You can simply fix if with:
for (int index = 0; index < row; ++index) {
array[index] = 0;
}
Or:
for (int index = 0; index < row; ++index) {
unsigned sum = 0;
for (int j = 0; j < col; ++j) {
sum += A[index][j];
}
array[index] = sum;
}
And the last output can be changed too. Your version reads out of bounds so yet another undefined behavior.
for (int index = 0; index < row; ++index) {
std::cout << array[index] << "\n";
}