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Please help in below matter:
I would like to find character (in my case: --) and replace with other (in my case: zz, or **) but only inside html comments (<!-- -->).
Thank you in advance.
If the regex flavor supports the \G anchor, it is done like this
Global find with (<!--(?=[\S\s]*?-->)|(?!^)\G)((?:(?!--)[\S\s])*?)(--)(?!>)
replace with $1$2zz or $1$2**
If the \G anchor is not supported it can be done with a
callback.
Match the comment <!--([\S\s]*?)--> in a replace call,
then in callback replace any -- in group 1 with zz or **, return the new comment (possibly unchanged) to the original replacement.
Construct it like return "<!--" + newcontent + "-->";
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I am having the following String
{'Sample': '#it{tq}', 'Yield': 0.011063753491221462, 'Error': 0}
and I would like to extract the value from 'Sample', that means '#it{tq}'. I tried that using a regular expression: 'Sample':(\s*.+?\s)
but its giving me: '#it{tq}', including that comma at the end. Does anyone know how to erase the comma at the end?
this regular expression should do the job.
regex: 'Sample':\s*('[^']*')
https://regex101.com/r/DL5Ltq/2
how about using this:
'Sample': '(.*?)',
beware that the regex in the accepted answer cannot process the case having single quote escape text inside the capture group like this: {'Sample': '#it'{tq}'}.
If you use (.*?), it greedily process any single character inside two single quote.
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The program contains text of this type:
A B Ccccc
A Ccccc
ACcccc
ABCcccc
I need only such text to remain:
Ccccc
I wrote a replacement function, but I just can’t pick up a pattern
How to make such a pattern?
No need for regex, nor VBA. It seems you simply are looking for the position of the last upper-case letter and then to extract from there:
Formula in B1 (with Excel O365):
=MID(A1,MAX(SEQUENCE(LEN(A1))*(EXACT(UPPER(MID(A1,SEQUENCE(LEN(A1)),1)),MID(A1,SEQUENCE(LEN(A1)),1)))),LEN(A1))
If you don't have Excel O365:
=MID(A1,MAX(ROW(A1:INDEX(A:A,LEN(A1)))*(EXACT(UPPER(MID(A1,ROW(A1:INDEX(A:A,LEN(A1))),1)),MID(A1,ROW(A1:INDEX(A:A,LEN(A1))),1)))),LEN(A1))
You probably need to enter as array through: CtrlShiftEnter
If you must go through VBA and regex then a pattern like:
[A-Z][^A-Z]*$
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Is there a RegEx to remove everything but digits and spaces in Notepad++?
I know there is one that removes only digits but i dont need that.
PS: I do not want the lines to be removed
Example:
11234123 alex-james
1412412 mmafsmasdas
After regex:
11234123
1412412
As the pattern use [^\d ]+. Almost what Poul Bak proposed, but change * into +, i.e. the sequence of chars to match should be non-empty.
There is no point in searching for an empty string and replace it with another empty string.
correction:
try this:
([^0-9| ]+)
this will surely work!!!
open the file in notepad++ press CTRL+H check the box with search mode regular expression and put in the above regex and click replace all
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I am using Notepad++ and want to replace a comma coming in between numbers with a dot.
Like in below text file:
00:00:00,166 --> 00:00:03,999
In this section we will look at
should be like below:
00:00:00.166 --> 00:00:03.999
In this section we will look at
Thanks
Try this:
Find:
(?<=\d),(?=\d)
Replace with:
.
Here is a screenshot. Make sure you select Regular Expression radio button (pointed to by arrow).
Regex:
(?<=\d) - Positive look behind for a digit char
(?=\d) - Positive look ahead for a digit char
Demo:
https://regex101.com/r/iw1XsV/1
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I need help with a really simple regex find/replace command for Eclipse. It'd be great if you could provide me with something to try.
I need to replace all occurrences of the text typeSingleton(*) ), with typeSet({ * } ).
Assume that inside brackets you may have letters, brackets, spaces, then:
Find: typeSingleton\(([a-z ]+(\([a-z ]+\))? ?)\)
Replace: typeSet({$1})
EDIT
Demo: https://regex101.com/r/dD0wK0/1