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I am using Notepad++ and want to replace a comma coming in between numbers with a dot.
Like in below text file:
00:00:00,166 --> 00:00:03,999
In this section we will look at
should be like below:
00:00:00.166 --> 00:00:03.999
In this section we will look at
Thanks
Try this:
Find:
(?<=\d),(?=\d)
Replace with:
.
Here is a screenshot. Make sure you select Regular Expression radio button (pointed to by arrow).
Regex:
(?<=\d) - Positive look behind for a digit char
(?=\d) - Positive look ahead for a digit char
Demo:
https://regex101.com/r/iw1XsV/1
Related
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The program contains text of this type:
A B Ccccc
A Ccccc
ACcccc
ABCcccc
I need only such text to remain:
Ccccc
I wrote a replacement function, but I just can’t pick up a pattern
How to make such a pattern?
No need for regex, nor VBA. It seems you simply are looking for the position of the last upper-case letter and then to extract from there:
Formula in B1 (with Excel O365):
=MID(A1,MAX(SEQUENCE(LEN(A1))*(EXACT(UPPER(MID(A1,SEQUENCE(LEN(A1)),1)),MID(A1,SEQUENCE(LEN(A1)),1)))),LEN(A1))
If you don't have Excel O365:
=MID(A1,MAX(ROW(A1:INDEX(A:A,LEN(A1)))*(EXACT(UPPER(MID(A1,ROW(A1:INDEX(A:A,LEN(A1))),1)),MID(A1,ROW(A1:INDEX(A:A,LEN(A1))),1)))),LEN(A1))
You probably need to enter as array through: CtrlShiftEnter
If you must go through VBA and regex then a pattern like:
[A-Z][^A-Z]*$
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Is there a RegEx to remove everything but digits and spaces in Notepad++?
I know there is one that removes only digits but i dont need that.
PS: I do not want the lines to be removed
Example:
11234123 alex-james
1412412 mmafsmasdas
After regex:
11234123
1412412
As the pattern use [^\d ]+. Almost what Poul Bak proposed, but change * into +, i.e. the sequence of chars to match should be non-empty.
There is no point in searching for an empty string and replace it with another empty string.
correction:
try this:
([^0-9| ]+)
this will surely work!!!
open the file in notepad++ press CTRL+H check the box with search mode regular expression and put in the above regex and click replace all
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Please help in below matter:
I would like to find character (in my case: --) and replace with other (in my case: zz, or **) but only inside html comments (<!-- -->).
Thank you in advance.
If the regex flavor supports the \G anchor, it is done like this
Global find with (<!--(?=[\S\s]*?-->)|(?!^)\G)((?:(?!--)[\S\s])*?)(--)(?!>)
replace with $1$2zz or $1$2**
If the \G anchor is not supported it can be done with a
callback.
Match the comment <!--([\S\s]*?)--> in a replace call,
then in callback replace any -- in group 1 with zz or **, return the new comment (possibly unchanged) to the original replacement.
Construct it like return "<!--" + newcontent + "-->";
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I am interested in finding combinations of 2 words that appear in the same sentence.
For example:
Looking for "hello" & "There" that are in the same sentence.
My name is Danny. Hello. I am there. whats up ? <-- NO MATCH
My name is Danny. Hello there. whats up ? <-- MATCH
The rule is simple - I dont want a dot character (.) top appear between the 2 words.
You might want to try this:
\b(H|h)ello\b[^.]+\b(T|t)here\b
It matches Hello There, Hello there, or hello there, depending on the case.
Demo is here.
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I would like to search for everything before the string http://thepaperwall.com/wallpapers/ but not including that string.
I would also like to search for everything after .jpg but not including .jpg.
So my final string should look like this:
http://thepaperwall.com/wallpapers/cityscape/small/small_642331afcd78d0840485bb352d99b289b50e8467.jpg
How can I do this?
You can use look-behind and look-ahead to get a string position between 2 other strings:
(?<=http://thepaperwall.com/wallpapers/).*(?=\.jpg)
You need a non-capturing group:
(.*)(?:http:\/\/thepaperwall\.com\/wallpapers\/.*\.jpg)(.*)
Live demo