How to extract node names without doubles - xslt

Question

I'm wondering if there is an xsl code that could loop through an xml file and extract only the nodenames. Also making sure it doesn't write it twice.
This is for my project at my client's side. I need to convert xml to text and I'm doing this with groovy and xslt. As the xml files are large, it takes a lot of time to get through the xml file to find the different 'value-off''s.
I've already this, but it gives me ALL the nodes and it's values, so each node more then once
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text" encoding="UTF-8"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/">
<xsl:apply-templates select="/currencies/record"></xsl:apply-templates>
</xsl:template>
<xsl:key name="names" match="*|#*" use="name()"/>
<xsl:template match="/currencies/record">
<xsl:for-each select="//*">
<xsl:value-of select="local-name()"/>=<xsl:apply-templates select="current()/text()"/>
<xsl:text>
</xsl:text>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
The xml looks like this:
<record deprecated="false"
id="CUR00001"
date.creation="2010-03-22"
adm.status="current">
<authority-code>AED</authority-code>
<code-4217>AED</code-4217>
<label>
<lg.version lg="bul" script="Cyrillic">Дирхам на ОАЕ</lg.version>
<lg.version lg="ces">UAE dirham n. emirátský dirham</lg.version>
<lg.version lg="dan">Emiratarabisk dirham</lg.version>
<lg.version lg="deu" gender.grammar="M">VAE-Dirham</lg.version>
<lg.version lg="deu" number.grammar="P">VAE-Dirhams</lg.version>
<lg.version lg="fin">Arabiemiirikuntien dirhami</lg.version>
<lg.version lg="fra" gender.grammar="M">Dirham des Émirats arabes unis</lg.version>
...
</label>
<currency.subunit>
<lg.version lg="bul" script="Cyrillic">филс</lg.version>
<lg.version lg="ces">fils</lg.version>
<lg.version lg="dan">fils</lg.version>
<lg.version lg="deu" gender.grammar="M">Fils</lg.version>
<lg.version lg="ell" script="Greek">φιλς</lg.version>
<lg.version lg="eng" gender.grammar="N">fils</lg.version>
...
<start.use>1990-01-01</start.use>
<linkCOUid>COU0450</linkCOUid>
<use.context>TED_SCHEMA</use.context>
</record>
In my example "lg.version" is present a lot of times, I'm expecting it to be there just 1 time.
Thanks for any help.

Answer 1

Always say which version of XSLT you are using.
In XSLT 2.0 it is simply distinct-values(//*/node-name()) (assuming that by "nodes" you really mean "elements").
If you're on 1.0 and can't move forward for some reason, use Muenchian grouping - which makes it much more complicated.