I know that this is simple problem. I'm still learning and getting familiarize with the XSLT coding. I have a problem in my XSLT and I don't know if I did it correctly. I need to get the value from the input file and store it in the new element tag name and that I don't need to populate the namespaces and attributes what's on the parent root element. I did a research about this and I saw many references but I can't apply it. The XSLT(v02) that I made is working fine (just copy from the references) if the root element doesn't have any namespaces and attributes. But, when I put a namespaces and attribute, no output populated.
Input file
<Root xmlns="http://abcd.com" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" releaseID="9.2" versionID="2.12.3" xsi:schemaLocation="abcd.com abcd.xsd">
<Element>
<Field>AAAAA</Field>
</Element>
<Element>
<Field>BBBBB</Field>
</Element>
<Element>
<Field>CCCCC</Field>
</Element>
xslt file
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/">
<NewRecord>
<xsl:for-each select="Root/Element">
<NewTransaction>
<Position>
<xsl:value-of select="position()"/>
</Position>
<TransactionID>
<xsl:value-of select="Field"/>
</TransactionID>
</NewTransaction>
</xsl:for-each>
</NewRecord>
</xsl:template>
output generated
<NewRecord/>
My expected output should look like this:
<NewRecord>
<NewTransaction>
<Position>1</Position>
<TransactionID>AAAAA</TransactionID>
</NewTransaction>
<NewTransaction>
<Position>2</Position>
<TransactionID>BBBBB</TransactionID>
</NewTransaction>
<NewTransaction>
<Position>3</Position>
<TransactionID>CCCCC</TransactionID>
</NewTransaction>
I think the problem is in the <xsl:template match="/">, I'm still confused on the nodes that I need to put. Thank you for your help.
If you are really using XSLT 2.0, you only need to add:
xpath-default-namespace="http://abcd.com"
to the stylesheet tag, and leave everything else as is.
If you're using xslt 1.0, you'll have to declare the same namespace in the stylesheet, and use the prefix you map to the namespace to qualify the names of the elements:
The prefix can be whatever you want. I picked abcd to match your example, but it could be any legal identifier.
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:abcd="http://abcd.com">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/">
<NewRecord>
<xsl:for-each select="abcd:Root/abcd:Element">
<NewTransaction>
<Position>
<xsl:value-of select="position()"/>
</Position>
<TransactionID>
<xsl:value-of select="abcd:Field"/>
</TransactionID>
</NewTransaction>
</xsl:for-each>
</NewRecord>
</xsl:template>
</xsl:stylesheet>
Related
I'm trying to understand the usage of keys and can't get my example to work.
Starting with this XML:
<items>
<item>Blue</item>
<item>Green</item>
<item>Orange</item>
</items>
I want to get this output XML:
<items>
<item>PURPLE</item>
<item>BLACK</item>
<item>PINK</item>
</items>
I defined the mapping directly in a variable in the XSLT transformation:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
version="2.0">
<xsl:output method="xml" indent="yes"/>
<xsl:variable name="mappings">
<mapping orig="Blue" repla="PURPLE"/>
<mapping orig="Green" repla="BLACK"/>
<mapping orig="Orange" repla="PINK"/>
</xsl:variable>
<xsl:key name="mappingsKey" match="$mappings/mapping" use="#orig"/>
<xsl:template match="items">
<xsl:copy>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
<xsl:template match="item">
<xsl:copy>
<xsl:value-of select="key('mappingsKey',.)"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
I know I'm missing the instruction to tell which is the replacement value, but don't know how to define it.
Example available here: https://xsltfiddle.liberty-development.net/ejivdHp/1
Thanks.
The $mappings variable is in a different document than the processed XML. You need to point the key() function to there. And you also need to select the repla attribute:
<xsl:value-of select="key('mappingsKey', ., $mappings)/#repla"/>
Referencing the variable in the match pattern of the xsl:key element is meaningless.
https://xsltfiddle.liberty-development.net/ejivdHp/2
While answering this question, it occurred to me that I know how to use the XSLT 3.0 (XPath 3.0) serialize() function, but that I do not know how to avoid serialization of namespaces that are in scope. Here is a minimal example:
XML Input
<?xml version="1.0" encoding="UTF-8" ?>
<ci:cichlids xmlns:ci="http://www.cichlids.com">
<cichlid id="1">
<name>Zeus</name>
<color>gold</color>
<teeth>molariform</teeth>
<breeding-type>lekking</breeding-type>
</cichlid>
</ci:cichlids>
XSLT 3.0 Stylesheet
<xsl:stylesheet version="3.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:output="http://www.w3.org/2010/xslt-xquery-serialization"
xmlns:ci="http://www.cichlids.com">
<xsl:output method="xml" encoding="UTF-8" indent="yes" />
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="/ci:cichlids/cichlid">
<xsl:variable name="serial-params">
<output:serialization-parameters>
<output:omit-xml-declaration value="yes"/>
</output:serialization-parameters>
</xsl:variable>
<xsl:value-of select="serialize(., $serial-params/*)"/>
</xsl:template>
</xsl:stylesheet>
Actual Output
<?xml version="1.0" encoding="UTF-8"?>
<ci:cichlids xmlns:ci="http://www.cichlids.com">
<cichlid xmlns:ci="http://www.cichlids.com" id="1">
<name>Zeus</name>
<color>gold</color>
<teeth>molariform</teeth>
<breeding-type>lekking</breeding-type>
</cichlid>
</ci:cichlids>
The serialization process included the namespace declaration that is in scope for the cichlid element, although it is not used on this element. I would like to remove this declaration and make the output look like
Expected Output
<?xml version="1.0" encoding="UTF-8"?>
<ci:cichlids xmlns:ci="http://www.cichlids.com">
<cichlid id="1">
<name>Zeus</name>
<color>gold</color>
<teeth>molariform</teeth>
<breeding-type>lekking</breeding-type>
</cichlid>
</ci:cichlids>
I know how to modify the cichlid element, removing the namespaces in scope, and serialize this modified element instead. But this seems a rather cumbersome solution. My question is:
What is a canonical way to serialize an XML element using the serialize() function without also serializing unused namespace declarations that are in scope?
Testing with Saxon-EE 9.6.0.7 from within Oxygen.
Serialization will always give you a faithful representation of the data model that you are serializing. If you want to modify the data model, that's called transformation. Run a transformation to remove the unwanted namespaces, then serialize the result.
Michael Kay already gave the correct answer and I have accepted it. This is just to flesh out his comments. By
Run a transformation to remove the unwanted namespaces, then serialize the result.
he means applying a transformation like the following before calling serialize():
XSLT Stylesheet
<xsl:stylesheet version="3.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:output="http://www.w3.org/2010/xslt-xquery-serialization"
xmlns:ci="http://www.cichlids.com">
<xsl:output method="xml" encoding="UTF-8" indent="yes" />
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:variable name="cichlid-without-namespace">
<xsl:copy-of copy-namespaces="no" select="/ci:cichlids/cichlid"/>
</xsl:variable>
<xsl:template match="/ci:cichlids/cichlid">
<xsl:variable name="serial-params">
<output:serialization-parameters>
<output:omit-xml-declaration value="yes"/>
</output:serialization-parameters>
</xsl:variable>
<xsl:value-of select="serialize($cichlid-without-namespace, $serial-params/*)"/>
</xsl:template>
</xsl:stylesheet>
XML Output
<?xml version="1.0" encoding="UTF-8"?>
<ci:cichlids xmlns:ci="http://www.cichlids.com">
<cichlid id="1">
<name>Zeus</name>
<color>gold</color>
<teeth>molariform</teeth>
<breeding-type>lekking</breeding-type>
</cichlid>
</ci:cichlids>
I'm trying to create a standard-use XSLT that will perform a given task based upon a user-provided XPATH expression as an XSLT parameter.
That is, I need something like this:
<xsl:template match="$paramContainingXPATH">
<!-- perform the task on the node(s) in the given xpath -->
</xsl:template>
For example, suppose I have some XML:
<xml>
<nodeA>whatever</nodeA>
<nodeB>whatever</nodeB>
<nodeC>whatever</nodeC>
<nodeD>whatever</nodeD>
<nodeE>whatever</nodeE>
</xml>
The XSLT needs to transform just a node or nodes matching a provided XPATH expression. So, if the xslt parameter is "/xml/nodeC", it processes nodeC. If the xslt parameter is "*[local-name() = 'nodeC' or local-name() = 'nodeE']", it processes nodeC and nodeE.
This should work for absolutely any XML message. That is, the XSLT cannot have any direct knowledge of the content of the XML. So, it could be a raw XML, or a SOAP Envelope.
I was guessing I might need to grab all the nodes matching the xpath, and then looping over them calling a named template, and using the standard identity template for all other nodes.
All advice is appreciated.
If you really need that feature with XSLT 1.0 or 2.0 then I think you should consider writing one stylesheet that takes that string parameter with the XPath expression and then simply generates the code of a second stylesheet where the XPath expression is used as a match pattern and the other needed templates like the identity template are included statically. Dynamic XPath evaluation is only available in XSLT 3.0 or in earlier versions as a proprietary extension mechanism.
You cannot match a template using a parameter - but you can traverse the tree and compare the path of each node with the given path. Here's a simple example:
XSLT 1.0
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:param name="path" select="'/world/America/USA/California'"/>
<xsl:template match="/">
<root>
<xsl:apply-templates select="*"/>
</root>
</xsl:template>
<xsl:template match="*">
<xsl:variable name="path-to-me">
<xsl:for-each select="ancestor-or-self::node()">
<xsl:value-of select="name()" />
<xsl:if test="position()!=last()">
<xsl:text>/</xsl:text>
</xsl:if>
</xsl:for-each>
</xsl:variable>
<xsl:if test="$path=$path-to-me">
<xsl:call-template name="action"/>
</xsl:if>
<xsl:apply-templates select="*"/>
</xsl:template>
<xsl:template name="action">
<return>
<xsl:value-of select="." />
</return>
</xsl:template>
</xsl:stylesheet>
Applied to a slightly more ambitious test input of:
<world>
<Europe>
<Germany>1</Germany>
<France>2</France>
<Italy>3</Italy>
</Europe>
<America>
<USA>
<NewYork>4</NewYork>
<California>5</California>
</USA>
<Canada>6</Canada>
</America>
</world>
the result will be:
<?xml version="1.0" encoding="UTF-8"?>
<root>
<return>5</return>
</root>
This could be made more efficient by passing the accumulated path as a parameter of the recursive template, so that each node needs only to add its own name to the chain.
Note:
The given path must be absolute;
Predicates (including positional predicates) and attributes are not implemented in this. They probably could be, with a bit more effort;
Namespaces are ignored (I don't see how you could pass an XPath as a parameter and include namespaces anyway).
If your processor supports an evaluate() extension function, you could forgo the calculated text path and test for intersection instead.
Edit:
Here's an example using EXSLT dyn:evaluate() and set:intersection():
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:dyn="http://exslt.org/dynamic"
xmlns:set="http://exslt.org/sets"
extension-element-prefixes="dyn set">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:param name="path" select="'/world/America/USA/California'"/>
<xsl:variable name="path-set" select="dyn:evaluate($path)" />
<xsl:template match="/">
<root>
<xsl:apply-templates select="*"/>
</root>
</xsl:template>
<xsl:template match="*">
<xsl:if test="set:intersection(. , $path-set)">
<xsl:call-template name="action"/>
</xsl:if>
<xsl:apply-templates select="*"/>
</xsl:template>
<xsl:template name="action">
<return>
<xsl:value-of select="." />
</return>
</xsl:template>
</xsl:stylesheet>
Note that this will also work with with paths like:
/world/America/USA/*[2]
//California
and many others that the text comparison method could not accommodate.
I'm sending the element name as a param to the XSLT
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" version="2.0">
<xsl:output method="xml"/>
<xsl:param name="user"/>
<xsl:template match="/">
<xsl:call-template name="generic" />
</xsl:template>
<xsl:template name="generic">
<count><xsl:value-of select="count(.//*[local-name()=$user])"/></count>
</xsl:template>
</xsl:stylesheet>
I hope this could help!
How can i copy an entire xml as is in an Variable?
Below is the sample xml:
<?xml version="1.0" encoding="UTF-8"?>
<products author="Jesper">
<product id="p1">
<name>Delta</name>
<price>800</price>
<stock>4</stock>
</product>
</products>
I have tried below xslt but it is not working.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format" version="1.0">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="#*|node()">
<xsl:variable name="reqMsg">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:variable>
<xsl:copy-of select="$reqMsg"/>
</xsl:template>
</xsl:stylesheet>
Regards,
Rahul
Your transformation fails because at a certain point, it tries to create a variable (result tree fragment) containing an attribute node. This is not allowed.
It's not really clear what you mean by "copying an entire XML to a variable". But you probably want to simply use the select attribute on the root node:
<xsl:variable name="reqMsg" select="/"/>
This will actually create variable with a node-set containing the root node of the document. Using this variable with xsl:copy-of will output the whole document.
<xsl:copy-of select="document('path/to/file.xml')" />
Or if you need it more than once, to avoid repeating the doc name:
<xsl:variable name="filepath" select="'path/to/file.xml'" />
…
<xsl:copy-of select="document($filepath)" />
The result of document() should be cached IIRC, so don't worry about calling it repeatedly.
Consider the following XSLT script:
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text" encoding="iso-8859-1"/>
<xsl:variable name="stringmap">
<map>
<entry><key>red</key><value>rot</value></entry>
<entry><key>green</key><value>gruen</value></entry>
<entry><key>blue</key><value>blau</value></entry>
</map>
</xsl:variable>
<xsl:template match="/">
<!-- IMPLEMENT ME -->
</xsl:template>
</xsl:stylesheet>
I'd like this script to print redgreenblue.
Is there any way to treat the XML markup which is stored in the stringmap variable as a document of its own which I can run XPath queries on? I'm basically looking for something like
<xsl:for-each select="document($stringmap)/map/entry">
<xsl:value-of select="key"/>
</xsl:for-each>
(except that the document() function expects an URI).
Motivation: I have various long <xsl:choose> elements which map a given string to another string. I'd like to replace all those with a single template which takes a 'map' argument (which is a simple XML document). My hope is that I can then replace the <xsl:choose> with a simple statement like <xsl:value-of select="$stringmap/map/entry/value[../key='$givenkey']"/>
I'm using XSLT 1.0 using xsltproc.
You're almost right, using document('') will allow you to process node sets inside the current stylesheet:
<xsl:for-each select="document('')/xsl:stylesheet/xsl:variable[#name='stringmap']/map/entry">
<xsl:value-of select="key"/>
</xsl:for-each>
It's not necessary to define the map node set as a variable in this case:
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet xmlns:data="some.uri" version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<data:map>
<entry><key>red</key><value>rot</value></entry>
<entry><key>green</key><value>gruen</value></entry>
<entry><key>blue</key><value>blau</value></entry>
</data:map>
<xsl:template match="/">
<xsl:for-each select="document('')/xsl:stylesheet/data:map/entry">
<xsl:value-of select="key"/>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
If you do not use xsl:variable as a wrapper, you must remember that a top level elements must have a non null namespace URI.
In XSLT 2.0 it would've been possible to just iterate over the content in a variable:
<xsl:variable name="map">
<entry><key>red</key><value>rot</value></entry>
<entry><key>green</key><value>gruen</value></entry>
<entry><key>blue</key><value>blau</value></entry>
</xsl:variable>
<xsl:template match="/">
<xsl:for-each select="$map/entry">
<xsl:value-of select="key"/>
</xsl:for-each>
</xsl:template>
A posting by M. David Peterson just taught me how to make this work:
It's not necessary to have an <xsl:variable> for this case. Instead, I can embed the data document directly into the XSL stylesheet (putting it into a namespace for sanity) and then select elements from that. Here's the result:
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:map="uri:map">
<xsl:output method="text" encoding="iso-8859-1"/>
<map:colors>
<entry><key>red</key><value>rot</value></entry>
<entry><key>green</key><value>gruen</value></entry>
<entry><key>blue</key><value>blau</value></entry>
</map:colors>
<xsl:template match="/">
<xsl:for-each select="document('')/*/map:colors/entry">
<xsl:value-of select="key"/>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
This generates the expected output redgreenblue.
The trick is to use document('') to get a handle to the XSLT document itself, then * to get into the toplevel xsl:stylesheet element and from there I can access the color map.