I'm actually creating a discord bot and I'm trying to match some command options and I have a problem getting the value between the square brackets. (if there is)
I've already tried to add a ? to match one or more of these but it's not working, searching about how I could match between two characters but found nothing that helped me.
Here is the pattern I've got so far : https://regexr.com/4icgi
and here it is in text : /[+|-](.+)(\[(.+)\])?/g
What I expect it to do is from an option like that : +user[someRandomPeople]
to extract the parameter user and the value someRandomPeople and if there is no square brackets, it will only extract the parameter.
You may use
^[+-](.*?)(?:\[(.*?)\])?$
Or, if there should be no square brackets inside the optional [...] substring at the end:
^[+-](.*?)(?:\[([^\][]*)\])?$
Or, if the matches are searched for on different lines:
^[+-](.*?)(?:\[([^\][\r\n]*)\])?$
See the regex demo and the regex graph:
Details
^ - start of string
[+-] - + or - (note that | inside square brackets matches a literal | char)
(.*?) - Group 1: any 0 or more chars other than line break chars as few as possible
(?:\[(.*?)\])? - an optional sequence of
\[ - a [ char
(.*?) - Group 2: any 0 or more chars other than line break chars as few as possible ([^\][]* matches 0 or more chars other than [ and ])
\] - a ] char
$ - end of string.
Related
I have the following examples that must match with my regex
1,[]
1,[0,0,0,[]]
1,[0,0,0,0,0,[]]
1,1
1
I came up with a simple way of matching the middle ones with .?,\[.*\[\]\] but it doesnt match the first and the last one.
Maybe this is too much to handle with regex but I want to check the following things:
If there is a ',' it should have a following character or characters(numbers or letters)
If a bracket is opened: it should close '[]'
The bracket insides can be whatever but it must respect rule 1 and 2.
I am trying to find a solution so I'm grateful if you can help me. Thank you.
You can use
^\d+(?:,(?:(\[(?:[^][]++|\g<1>)*])|\d+))?$
See the regex demo. Details:
^ - start of string
\d+ - one or more digits
(?:,(?:(\[(?:[^][]++|\g<1>)*])|\d+))? - an optional sequence of
, - a comma
(?:(\[(?:[^][]++|\g<1>)*])|\d+) - one of the alternatives:
(\[(?:[^][]++|\g<1>)*]) - Group 1: [, then zero or more occurrences of one or more chars other than [ and ] or Group 1 pattern recursed
| - or
\d+ - one or more digits
$ - end of string.
I have tags (only ASCII chars inside brackets) of the following structure: [Root.GetSomething], instead, some contributors ended up submitting contributions with Cyrillic chars that look similar to Latin ones, e.g. [Rооt.GеtSоmеthіng].
I need to locate, and then replace those inconsistencies with the matching ASCII characters inside the brackets.
I tried \[([АаІіВСсЕеРТтОоКкХхМ]+)\]; (\[)([^\x00-\x7F]+)(\]), and some variations of the range but those searches don't see any matches. I seem to be missing something important in the regex execution logic.
You can use a regex matching any "interesting" Cyrillic char in between [ + letters or . + ] and a conditional replacement pattern:
Find What: (?:\G(?!\A)|\[)[a-zA-Z.]*\K(?:(А)|(а)|(І)|(і)|(В)|(С)|(с)|(Е)|(е)|(Р)|(Т)|(т)|(О)|(о)|(К)|(к)|(Х)|(х)|(М))(?=[[:alpha:].]*])
Replace With: (?1A:?2a:?3I:?4i:?5B:?6C:?7c:?8E:?9e:?{10}P:?{11}T:?{12}t:?{13}O:?{14}o:?{15}K:?{16}k:?{17}X:?{18}x:?{19}M)
Make sure Match Case option is ON. See a regex demo with a string:
Details:
(?:\G(?!\A)|\[) - end of the previous successful match or a [ char
[a-zA-Z.]* - zero or more . or ASCII letters
\K - match reset operator that discards the currently matched text from the overall match memory buffer
(?:(А)|(а)|(І)|(і)|(В)|(С)|(с)|(Е)|(е)|(Р)|(Т)|(т)|(О)|(о)|(К)|(к)|(Х)|(х)|(М)) - a non-capturing group containing 19 alternatives each of which is put into a separate capturing group
(?=[[:alpha:].]*]) - a positive lookahead that requires zero or more letters or . and then a ] char immediately to the right of the current location.
The (?1A:?2a:?3I:?4i:?5B:?6C:?7c:?8E:?9e:?{10}P:?{11}T:?{12}t:?{13}O:?{14}o:?{15}K:?{16}k:?{17}X:?{18}x:?{19}M) replacement pattern replaces А with A (\u0410) if Group 1 matched, а (\u0430) with a if Group 2 matched, etc.
Here is a text example that I will usually get:
CERTIFICATION/repos_1/test_examples_1_01_C.py::test_case[6]
CERTIFICATION/repos_1/test_examples_2_01_C.py::test_case[7]
INTEGRATION/test_example_scan_1.py::test_case
INTEGRATION/test_example_scan_2.py::test_case
Here is the regex I'm using to capture 3 different groups:
^.*\/(.*)\.py.*:{2}(.*(\[.*\])?)
If we take an example with the first line of my examples I should get:
test_examples_1_BV_01_C - test_case[6] - [6]
And for the last line:
test_example_scan_2 - test_case - None
But if you try this regex you will find out that the first example does not work. I can't get
the [6]. If you remove the "?" you will have no match with line that does not have "[.*]" at the end
So, how can I get all those information ? And what do I do wrong ?
Regards
You can use
^.*\/(.*)\.py.*::(.*?(\[.*?\])?)$
See the regex demo
Details:
^ - start of string
.* - any zero or more chars other than line break chars, as many as possible
\/ - a / char
(.*) - Group 1: any zero or more chars other than line break chars, as many as possible
\.py - .py substring
.* - any zero or more chars other than line break chars, as many as possible
:: - a :: string
(.*?(\[.*?\])?) - Group 2: any zero or more chars other than line break chars, as few as possible, and then an optional Group 3 matching [, any zero or more chars other than line break chars, as few as possible, and a ]
$ - end of string.
With the help of negated character class you can get all matches and make this regex lot more efficient:
^.*/([^.]+)\.py::([^[]+(\[[^]]*]|))$
RegEx Demo
I am trying to use replace in Sublime using regular expressions but I'm stuck. I tried various combinations but don't seem to be getting there.
This is the input and my desired output:
Input: N_BBP_c_46137_n
Output : BBP
I tried combinations of:
[^BBP]+\b
\*BBP*+\g
But none of the above (and many others) don't seem to work.
To turn N_BBP_c_46137_n into BBP and according to the comment just want that entire long name such as N_BBP_ to be replaced by only BBP* you might also use a capture group to keep BBP.
\bN_(BBP)_\S*
\bN_ Match N preceded by a word boundary
(BBP) Capture group 1, match BBP (or use [A-Z]+ to match 1+ uppercase chars)
_\S* Match _ followed by 0+ times a non whitespace char
In the replacement use the first capturing group $1
Regex demo
You may use
(N_)[^_]*(_c_\d+_n)
Replace with ${1}some new value$2.
Details
(N_) - Group 1 ($1 or ${1} if the next char is a digit): N_
[^_]* - any 0 or more chars other than _
-(_c_\d+_n) - Group 2 ($2): _c_, 1 or more digits and then _n.
See the regex demo.
I'm trying to analyse some SQLCMD scripts for code quality tests. I have a regex not working as expected:
^(\s*)USE (\[?)(?<![master|\$])(.)+(\]?)
I'm trying to match:
Strings that start with USE (ignore whitespace)
Followed by optional square bracket
Followed by 1 or more non-whitespace characters.
EXCEPT where that text is "master" (case insensitive)
OR EXCEPT where that that text is a $ symbol
Expected results:
USE [master] - don't match
USE [$(CompiledDatabaseName)] - don't match
USE [anything_else.01234] - match
Also, the same patterns above without the [ and ] characters.
I'm using Sublime Text 2 as my RegEx search tool and referencing this cheatsheet
Your pattern - ^(\s*)USE (\[?)(?<![master|\$])(.)+(\]?) - uses a lookbehind that is variable-width (its length is not known beforehand) if you fix the character class issue inside it (i.e. replace [...] with (...) as you mean an alternative list of $ or a character sequence master) and thus is invalid in a Boost regex. Your (.)+ capturing is wrong since this group will only contain one last character captured (you could use (.+)), but this also matches spaces (while you need 1 or more non-whitespace characters). ? is the one or zero times quantifier, but you say you might have 2 opening and closing brackets (so, you need a limiting quantifier {0,2}).
You can use
^\h*USE(?!\h*\[{0,2}[^]\s]*(?:\$|(?i:master)))\h*\[{0,2}[^]\s]*]{0,2}
See regex demo
Explanation:
^ - start of a line in Sublime Text
\h* - optional horizontal whitespace (if you need to match newlines, use \s*)
USE - a literal case-sensitive character sequence USE
(?!\h*\[{0,2}[^]\s]*(?:\$|(?i:master))) - a negative lookahead that makes sure the USE is NOT followed with:
\h* - zero or more horizontal whitespace
\[{0,2} - zero, one or two [ brackets
[^]\s]* - zero or more characters other than ] and whitespace
(?:\$|(?i:master)) - either a $ or a case-insensitive master (we turn off case sensitivity with (?i:...) construct)
\h* - go on matching zero or more horizontal whitespace
\[{0,2} - zero, one or two [ brackets
[^]\s]* - zero or more characters other than ] and whitespace (when ] is the first character in a character class, it does not have to be escaped in Boost/PCRE regexps)
]{0,2} - zero, one or two ] brackets (outside of character class, the closing square bracket does not need escaping)