Can't manage to display form from my view - django

Question

I'm trying to create a page where admins can upload some files using some FileField. The problem is that I can't manage to display any field from my form, I must be missing something important but I can't find out what, hope anyone can help me.
Here is the code related to this form:
urls.py
urlpatterns = patterns(
'',
url(r'^admin_fichiers_phyto/$', phyto_views.AdminFichiersPhyto.as_view(), name='phyto-admin-fichiers-phyto'),
)
phyto_admin_fichiers.html
{% block forms %}
{% if user.is_staff%}
<fieldset>
<div>
<span>{{ form.other }}</span>
</div>
</fieldset>
<p>
<input id="submit" class="btn btn-primary" type="submit" value="Synchronisation Autre" name="autre"/>
<input id="submit" class="btn btn-primary" type="submit" value="Synchronisation Traitements généraux" name="trtm_gen"/>
</p>
{% endif %}
{% endblock %}
views.py
class AdminFichiersPhyto(TemplateView):
template_name = 'phyto/phyto_admin_fichiers.html'
form_class = forms.PhytoFileForm
current_url = 'phyto-files'
context_object_name = 'phyto_files'
def post(self, request, *args, **kwargs):
if request.POST.get('autre'):
return HttpResponse('<h1>autre</h1>')
if request.POST.get('trtm_gen'):
return HttpResponse('<h1>Traitement Generaux</h1>')
forms.py
class PhytoFileForm(forms.Form):
class Meta:
model = models.PhytoFile
fields = ['general_treatment', 'other']
def __init__(self, *args, **kwargs):
super(PhytoFileForm, self).__init__(*args, **kwargs)
models.py
class PhytoFile(models.Model):
general_treatment = models.FileField(upload_to='fichiers_phyto/', blank=True, null=True)
other = models.FileField(upload_to='fichiers_phyto/', blank=True, null=True)
Here is what my webpage is showing :
https://imgur.com/a/yH0be0K
I can't understand why the Field isn't displayed, I really hope somebody have the knowledge to help me with my problem ! ^_^
Have a nice day ! :D

Answer 1

You have several major issues here.
TemplateView doesn't know anything about form_class (or context_object_name, for that matter). And by defining post like that you've avoided actually doing anything with the uploaded data. You need to use a view that deals with forms; in your case, a CreateView would be ideal. Inside that view, that response code needs to go in form_valid.
Secondly, PhytoFileForm needs to inherit from forms.ModelForm; a standard Form class doesn't know anything about models and doesn't use a Meta class. However, since you're not customizing the form beyond the field selection, you can just rely on the automatic form created by CreateView.
Next, your template is broken; it doesn't have an HTML form element. Also, since your form class has two fields but you only display one on the template, the form will never be valid.
So, putting it together:
class AdminFichiersPhyto(CreateView):
template_name = 'phyto/phyto_admin_fichiers.html'
model = models.PhytoFile
def form_valid(self, form):
form.save()
if request.POST.get('autre'):
return HttpResponse('<h1>autre</h1>')
if request.POST.get('trtm_gen'):
return HttpResponse('<h1>Traitement Generaux</h1>')
{% block forms %}
{% if user.is_staff%}
<form method="post" action="" enctype="multipart/form-data">
<fieldset>
<div>
<span>{{ form.other }}</span>
</div>
<div>
<span>{{ form. general_treatment }}</span>
</div>
</fieldset>
<p>
<input id="submit" class="btn btn-primary" type="submit" value="Synchronisation Autre" name="autre"/>
<input id="submit" class="btn btn-primary" type="submit" value="Synchronisation Traitements généraux" name="trtm_gen"/>
</p>
</form>
{% endif %}
{% endblock %}