I am trying to format the information from a column that I am querying and compare that to information in a cell. I have tried to hack together various ways to do this, but I am not a proficient SQL/spreadsheet user.
In COLUMN I there is nothing.
In COLUMN K there is a match on A2.
In COLUMN N there is Information formatted like 31'-40' and 41'+.
I would prefer to use = instead of contains.
The REPLACE Function seems to work when I substitute N for a String and run it on the W3 School Website.
The REGEXREPLACE seems to work on D2. I would expect them to match, but they do not.
COUNT( QUERY( '2019'!A2:P, "select D where I='' and upper(K) contains '" & UPPER(A2) & "' and REPLACE(REPLACE(REPLACE(N, '-', ''), '''', ''), '+','') contains '"& Regexreplace(D2,"[[:punct:]]","") &"' ")
I get 0 matches.
you almost had it, but try like this:
=COUNTA(FILTER(2019!D2:D, I2:I="",
REGEXMATCH(UPPER(K2:K), UPPER(A2)),
REGEXMATCH(UPPER(N2:N), UPPER(D2))))
Related
in my Google sheet table I have the first list with summary of invoices which are then separated to 4 lists according to parameters (manually). I need to know about all invoices from the first list, on which category/list they are.
So for example - lists: Alphabet, abc, def, mno, xyz. In Alphabet is column "list".
How to write function which found invoice on another list according to ID (column B) from Alphabet and write name of the correct list to column "list". I tried to write this function using IF, match, etc. But I still don't have solution. Can you help me please? Sorry for my English :-)
So here is an example which you could adapt. In columns E:H on the first sheet (and I could hide these columns later, starting in row2 and dragging down as needed, I put the following formulas:
=IF(LEN(iferror(query(abc!$A$2:$A,"select A where A='" & $A2 &"'"),""))>0,"abc","")
=IF(LEN(iferror(query(def!$A$2:$A,"select A where A='" & $A2 &"'"),""))>0,"def","")
=IF(LEN(iferror(query(mno!$A$2:$A,"select A where A='" & $A2 &"'"),""))>0,"mno","")
=IF(LEN(iferror(query(xyz!$A$2:$A,"select A where A='" & $A2 &"'"),""))>0,"xyz","")
Probably I could have simplified a little by putting the sheet names in E1:H1, but you get the idea.
Each of these looks for the ID. If the query succeeds, it returns the name of the sheet. If it fails, it returns the empty string.
Now in column B where I actually want the results, I put this formula in B2 and drag to copy as needed.
=if(E2&F2&G2&H2="","nowhere",E2&F2&G2&H2)
It says put those strings together, and if there is nothing there say nowhere, otherwise say the list. If it appears on more than one, and that can really happen, you could use JOIN instead.
I have a column tags containing ids in a comma separated list.
I want to search all rows where a given value is in that column.
Say I have two rows where the column tags looks like this:
Row1: 1,2,3,4
Row2: 2,5,3,12
and I want to search for a row where the column contains a 1. I try to do it this way:
$qb = $this->createQueryBuilder('p')
->where(':value IN (p.tags))
->setParameter('value', 1);
I expect it to do something like
SELECT p.* FROM mytable AS p WHERE 1 IN (p.tags)
Executing this in MySQL directly works perfectly. In Doctrine it does not work:
Error: Expected Literal, got 'p'
It works the other way around, though, but this is not what I need:
->where("p.tags IN :value")
I've tried a lot to make this work, but it just won't... Any ideas?
I think you should use the LIKE function for each scenario, as example:
$q = "1";
$qb = $this->createQueryBuilder('p')
->andWhere(
$this->expr()->orX(
$this->expr()->like('p.tags', $this->expr()->literal($q.',%')), // Start with...
$this->expr()->like('p.tags', $this->expr()->literal('%,'.$q.',%')), // In the middle...
$this->expr()->like('p.tags', $this->expr()->literal('%,'.$q)), // End with...
),
);
See the SQL statement result in this fiddle
Hope this help
While it is easy to do replace of the the search text in the code after getting the dataset from an sql with a where clause:
x = x.Replace("SearchText","<span style='color:RED'>SearchText</span>");
I was wondering if there was a way to this IN the SQL.
Select x.Replace("SearchText","<span class='highlight'>SearchText</span>") as x from t where x like '%SearchText%'
or something like that.
The reason I am asking is because I do a:
COALESCE(LastName + ', ' + FirstName, LastName, FirstName) as Name
and I don't want a returned Name field of "Bobbly, Bob" to get two highlighted areas when searching for a LastName that includes "Bob" or a FirstName that includes "Bob" (Noting that first and last names have different search phrases"
Yeah, I could just return the two field separately and join them in code, but I just want to see if it can be done in SQL.
T-SQL includes a Replace Function
REPLACE ( string_expression , string_pattern , string_replacement )
That should do what you need
COALESCE(REPLACE(FirstName,'SearchText1','<span class=''highlight''>' + 'SearchText1' + '</span>')+','
+REPLACE(LastName,'SearchText2','<span class=''highlight''>'+'SearchText2'+'</span>')
,REPLACE(FirstName,'SearchText1','<span class=''highlight''>' + 'SearchText1' + '</span>')
,REPLACE(LastName,'SearchText2','<span class=''highlight''>'+'SearchText2'+'</span>')
,'')
For example we have a large database contains lots of oracle packages, and now we want to see where a specific table resists in the source code. The source code is stored in user_source table and our desired table is called 'company'.
Normally, I would like to use:
select * from user_source
where upper(text) like '%COMPANY%'
This will return all words containing 'company', like
121 company cmy
14 company_id, idx_name %% end of coding
453 ;companyname
1253 from db.company.company_id where
989 using company, idx, db_name,
So how to make this result more intelligent using regular expression to parse all the source lines matching a meaningful table name (means a table to the compiler)?
So normally we allow the matched word contains chars like . ; , '' "" but not _
Can anyone make this work?
To find company as a "whole word" with a regular expression:
SELECT * FROM user_source
WHERE REGEXP_LIKE(text, '(^|\s)company(\s|$)', 'i');
The third argument of i makes the REGEXP_LIKE search case-insensitive.
As far as ignoring the characters . ; , '' "", you can use REGEXP_REPLACE to suck them out of the string before doing the comparison:
SELECT * FROM user_source
WHERE REGEXP_LIKE(REGEXP_REPLACE(text, '[.;,''"]'), '(^|\s)company(\s|$)', 'i');
Addendum: The following query will also help locate table references. It won't give the source line, but it's a start:
SELECT *
FROM user_dependencies
WHERE referenced_name = 'COMPANY'
AND referenced_type = 'TABLE';
If you want to identify the objects that refer to your table, you can get that information from the data dictionary:
select *
from all_dependencies
where referenced_owner = 'DB'
and referenced_name = 'COMPANY'
and referenced_type = 'TABLE';
You can't get the individual line numbers from that, but you can then either look at user_source or use a regexp on the specific source code, which woudl at least reduce false positives.
SELECT * FROM user_source
WHERE REGEXP_LIKE(text,'([^_a-z0-9])company([^_a-z0-9])','i')
Thanks #Ed Gibbs, with a little trick this modified answer could be more intelligent.
I have a database filled with some codes like
EE789323
990
78000
These numbers are ALWAYS endings of a larger code. Now I have a function that needs to check if the larger code contains the subcode.
So if I have codes 90 and 990 and my full code is EX888990, it should match both of them.
However I need to do it in the following way:
SELECT * FROM tableWithRecordsWithSubcode
WHERE subcode MATCHES [reg exp with full code];
Is a regular expression like this this even possible?
EDIT:
To clarify the issue I'm having, I'm not using SQL here. I just used that to give an example of the type of query I'm using.
In fact I'm using iOS with CoreData, and I need a predicate to fetch me only the records that match.
In the way that is mentioned below.
Given the observations from a comment:
Do you have two tables, one called tableWithRecordsWithSubcode and another that might be tableWithFullCodeColumn? So the matching condition is in part a join - you need to know which subcodes match any of the full codes in the second table? But you're only interested in the information in the tableWithRecordsWithSubcode table, not in which rows it matches in the other table?
and the laconic "you're correct" response, then we have to rewrite the query somewhat.
SELECT DISTINCT S.*
FROM tableWithRecordsWithSubcode AS S
JOIN tableWithFullCodeColumn AS F
ON F.Fullcode ...ends-with... S.Subcode
or maybe using an EXISTS sub-query:
SELECT S.*
FROM tableWithRecordsWithSubcode AS S
WHERE EXISTS(SELECT * FROM tableWithFullCodeColumn AS F
WHERE F.Fullcode ...ends-with... S.Subcode)
This uses a correlated sub-query but avoids the DISTINCT operation; it may mean the optimizer can work more efficiently.
That just leaves the magical 'X ...ends-with... T' operator to be defined. One possible way to do that is with LENGTH and SUBSTR. However, SUBSTR does not behave the same way in all DBMS, so you may have to tinker with this (possibly adding a third argument, LENGTH(s.subcode)):
LENGTH(f.fullcode) >= LENGTH(s.subcode) AND
SUBSTR(f.fullcode, LENGTH(f.fullcode) - LENGTH(s.subcode)) = s.subcode
This leads to two possible formulations:
SELECT DISTINCT S.*
FROM tableWithRecordsWithSubcode AS S
JOIN tableWithFullCodeColumn AS F
ON LENGTH(F.Fullcode) >= LENGTH(S.Subcode)
AND SUBSTR(F.Fullcode, LENGTH(F.Fullcode) - LENGTH(S.Subcode)) = S.Subcode;
and
SELECT S.*
FROM tableWithRecordsWithSubcode AS S
WHERE EXISTS(
SELECT * FROM tableWithFullCodeColumn AS F
WHERE LENGTH(F.Fullcode) >= LENGTH(S.Subcode)
AND SUBSTR(F.Fullcode, LENGTH(F.Fullcode) - LENGTH(S.Subcode)) = S.Subcode);
This is not going to be a fast operation; joins on computed results such as required by this query seldom are.
I'm not sure why you think that you need a regular expression... Just use the charindex function:
select something
from table
where charindex(code, subcode) <> 0
Edit:
To find strings at the end, you can create a pattern with the % wildcard from the subcode:
select something
from table
where '%' + subcode like code