This question already has answers here:
c++ initial value of dynamic array
(6 answers)
How can I make `new[]` default-initialize the array of primitive types?
(4 answers)
Initialization of array on heap
(7 answers)
C++: new call that behaves like calloc?
(11 answers)
Operator new initializes memory to zero
(4 answers)
Closed 3 years ago.
What it the initial values of an array declared in the heap. it's a zero or random values in memory?
int* ptrAr;
ptrAr = new int[5];
Related
This question already has answers here:
Does C++ zero-initialise unspecified values during aggregate initialization?
(2 answers)
Why would my array would be filled out to zero, when I initialised it to -1
(5 answers)
how does array[100] = {0} set the entire array to 0?
(4 answers)
Closed 6 months ago.
I have a constructor that looks like
A (const int(&inArr)[4])
{
...
}
And I can construct an instance with list-initialization as such,
A a({3,4,5,6});
However, I can also construct an instance with a shorter list, e.g. {3,2}, or an empty list {}. From my testing in MSVC and Clang, the array received by the constructor is always zeroed after the values in the list. i.e. {3,2} will be read as [3,2,0,0], and {} as [0,0,0,0].
I am wondering if this is standard behaviour that can be relied upon, or if this may vary across platforms/compilers?
This question already has answers here:
what will happen when std::move with c style array or not movable object
(2 answers)
Can std::move move a built-in types or c pointer or array
(1 answer)
What is std::move(), and when should it be used?
(9 answers)
Closed 8 months ago.
I want to do something like this:
int data[4] = {1,2,3,4};
int otherData[4];
otherData = std::move(data);
compiler says invalid array assignment, so how can I transfer values from data to otherData
This question already has answers here:
difference between two array declaration methods c++
(4 answers)
What is the difference between Static and Dynamic arrays in C++?
(13 answers)
Closed 10 months ago.
int numList1[10];
int *numList2 = new int[10];
I have seen too many solutions from others used the second way to assign array, do they work as the same?
This question already has answers here:
What happens to uninitialized variables? C++ [duplicate]
(3 answers)
Uninitialized variable behaviour in C++
(4 answers)
Default variable value
(10 answers)
Closed 2 years ago.
For example, if I have:
int num;
double num2;
int* ptr;
Are these variables just randomly allocated some memory?
This question already has answers here:
What and where are the stack and heap?
(31 answers)
Array as array[n] and as pointer array*
(2 answers)
Closed 5 years ago.
I have just been starting with C++ and I have come across multiple types of array declaration in C++
int data[3];
and other type is,
int *data= new data[3];
What is the difference between the two?
Since, I have not allocated memory in the first case will I overwrite memory which may already be in use and potentially cause segmentation error?