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What happens to uninitialized variables? C++ [duplicate]
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Uninitialized variable behaviour in C++
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Default variable value
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Closed 2 years ago.
For example, if I have:
int num;
double num2;
int* ptr;
Are these variables just randomly allocated some memory?
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int* getAddress(int var) {
return &var;
}
How does this function work? The return type is int pointer but the line return &var; returns a memory address not a pointer.
Also, if I understand correctly, a memory address and pointer I different. A memory address is an address to a specific part in memory while a pointer stores a memory address.
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difference between two array declaration methods c++
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What is the difference between Static and Dynamic arrays in C++?
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Closed 10 months ago.
int numList1[10];
int *numList2 = new int[10];
I have seen too many solutions from others used the second way to assign array, do they work as the same?
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What it the initial values of an array declared in the heap. it's a zero or random values in memory?
int* ptrAr;
ptrAr = new int[5];
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I have just been starting with C++ and I have come across multiple types of array declaration in C++
int data[3];
and other type is,
int *data= new data[3];
What is the difference between the two?
Since, I have not allocated memory in the first case will I overwrite memory which may already be in use and potentially cause segmentation error?
This question already has answers here:
How does a C++ reference look, memory-wise?
(9 answers)
Closed 5 years ago.
Declaring pointer:
int a;
int *x=&a;
x occupies 8 bytes of memory
Likewise if we declare a reference to a variable:
int a;
int &x =a;
How much memory does the the reference to a occupy?
That's undefined. Not as in Undefined Behavior, but the question simply doesn't have an answer.