Convert XML to XML using XSL (XSLT) & API - xslt

I have the input xml as below
<node>
<id>1234</id>
<value1>DoNoChange</value1>
<value2></value2>
<value3></value3>
</node>
Now, i would use the XSL to convert the above XML to below one
<node>
<id>1234</id>
<value1>DoNoChange</value1>
<value2>NewValue2</value2>
<value2>NewValue3</value2>
</node>
Which NewValue2 and NewValue3 is the response content from an API calls such as http://example.com/api/getDataByID/1234 which will return response as
<data>
<value2>NewValue2</value2>
<value3>NewValue3</value3>
<data>
Could you please advice my how can build the XSL for it?
What I have tried so far is
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:param name="code" select="1234"/>
<xsl:variable name="endpoint" as="xs:string" select="'http://example.com/api/getDataByID/1'"/>
<!-- the http request element -->
<xsl:variable name="request">
<http-request method="get" mime-type="application/xml" content-type="application/xml">
</http-request>
</xsl:variable>
<xsl:template match="node/id">
<xsl:variable name="rest_response" select="ex:httpSend($request, $endpoint)"/>
<id><xsl:value-of select="$rest_response/data"/></id>
</xsl:template>
</xsl:stylesheet>
The logic I'm trying to do are
When I see the match of node/id
I will call API using "id" as a param to a Rest API (Get Method)
(Note: currently I don't know how to use id as param, I hardcoded so
far)
Capture the response of the API into a variable Populate variable
data to fields such as "value2", value3" (Note: This one I have no
clue how to make it)
Thanks,

If your call to the API returns an XML response, then you should be able to do something like:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/node">
<xsl:copy>
<xsl:copy-of select="id | value1"/>
<xsl:variable name="response" select="document(concat('http://example.com/api/getDataByID/', id))" />
<value2>
<xsl:value-of select="$response/data/value2"/>
</value2>
<value3>
<xsl:value-of select="$response/data/value3"/>
</value3>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Untested, because no testing environment has been provided.

Related

Is there a way to replace the for-each with apply-templates in an XSLT Transform?

Environment: XSLT 1.0
The transform will take each element in partOne section and lookup #field attribute in partTwo section using #find attribute and then output #value attribute.
I'm using a for-each loop and was wondering if apply-templates could work?
xml
<?xml version="1.0" encoding="utf-8"?>
<?xml-stylesheet type="text/xsl" href="file.xslt"?>
<xml>
<partOne>
<target field="hello"/>
<target field="world"/>
</partOne>
<partTwo>
<number input="2" find="hello" value="valone" />
<number input="2" find="world" value="valtwo" />
<number input="2" find="hello" value="valthree" />
<number input="2" find="world" value="valfour" />
</partTwo>
</xml>
xsl
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:output method="text"/>
<xsl:template match="/">
<xsl:apply-templates />
</xsl:template>
<xsl:template match="/xml/partOne/target">
,<xsl:value-of select="#field"/>
<xsl:for-each select="/xml/partTwo/number[#find=current()/#field]">
,<xsl:value-of select="#value"/>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
Output:
,hello
,valone
,valthree
,world
,valtwo
,valfour
Well, it seems straight-forward to change
<xsl:for-each select="/xml/partTwo/number[#find=current()/#field]">
,<xsl:value-of select="#value"/>
</xsl:for-each>
to
<xsl:apply-templates select="/xml/partTwo/number[#find=current()/#field]"/>
with a template
<xsl:template match="partTwo/number">
,<xsl:value-of select="#value"/>
</xsl:template>
As your root template so far processes all elements you need to change it to
<xsl:template match="/">
<xsl:apply-templates select="xml/partOne"/>
</xsl:template>
to avoid processing the partTwo element(s) twice.
For the cross-reference you might want to use a key in both versions:
<xsl:key name="ref" match="partTwo/number" use="#find"/>
and then select="key('ref', #field)" instead of select="/xml/partTwo/number[#find=current()/#field]" for the apply-templates or for-each.

Multiple Namespaces on an element with XSLT 1.0

I am using Microsoft's XSLT processor (1.0 only)
XML opening lines:
<?xml version="1.0" encoding="utf-8"?>
<Header xmlns="http:\\OldNameSpace.com">
<Detail>
Have the following XSLT template to pick up the <Header> element of my document and change its namespace.
<xsl:template match="*">
<xsl:element name="{name()}" xmlns="http:\\NewNameSpace.com">
<xsl:copy-of select="#*"/>
<xsl:apply-templates />
</xsl:element>
</xsl:template>
Which turns <Header xmlns="http:\\OldNameSpace.com"> Into <Header xmlns="http:\\NewNameSpace.com">
However I now need to add a second namespace to this so that I get the following output:
<Header xmlns="NewNameSpace.com" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
I have tried using:
<xsl:template match="*">
<xsl:element name="{name()}" xmlns="NewNameSpace.com" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<xsl:copy-of select="#*"/>
<xsl:apply-templates />
</xsl:element>
</xsl:template>
However I still only get the same output as the original XSLT template.
Can anyone enlighten to me as to why this is?
This transformation:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:old="http:\\OldNameSpace.com"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
exclude-result-prefixes="old xsi">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:param name="pNewNamespace" select="'http:\\NewNameSpace.com'"/>
<xsl:variable name="vXsi" select="document('')/*/namespace::*[name()='xsi']"/>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="old:*">
<xsl:element name="{local-name()}" namespace="{$pNewNamespace}">
<xsl:copy-of select="$vXsi"/>
<xsl:copy-of select="#*"/>
<xsl:apply-templates />
</xsl:element>
</xsl:template>
</xsl:stylesheet>
when applied on the following XML document:
<Header xmlns="http:\\OldNameSpace.com">
<Detail/>
</Header>
produces (what I guess is) the wanted, correct result:
<Header xmlns="http:\\NewNameSpace.com"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<Detail/>
</Header>
xsl:element (unlike literal result elements) does not copy all in scope namespaces to the result, just the namespace required for the element name 9either implicitly from its name or as specified with the namespace argument).
xslt2 adds an xsl:namespace instruction for this case but in xslt1 the easiest thing to do is
where
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
somewhere on an ancestor (eg on xsl:stylesheet.)
that will add a spurious xsi:tmp="" to the output but also then a namespace declaration,
If you actually need an attribute in this namespace eg xsi:type use that instead of tmp in the above and you are done. If you don't mind the extra, possibly invalid attribute in the xsi namespace you are done. Otherwise do the above in a variable, then use msxsl:node-set to query in to the variable and remove the spurious extra attribute.
If you know statically what namespace you want to generate, then the easiest way to do it in XSLT 1.0 is using xsl:copy-of. Create a source document <dummy xmlns:xsi="http://whatever"/>,
and then do <xsl:copy-of select="document('dummy.xml')/*/namespace::xsi"/> inside your call of xsl:element.

Storing into a variable and displaying the unique entries using XSL

In that, I want to display only the unique fruit entries in it. Here is the XML tag what I'm using for parsing
<main>
<local id="1" type="Primary">
-<summary Date="23-02-12">
-<fruit>apple</fruit>
-<fruit>Orange</fruit>
</summary>
</local>
<local id="2" type="Primary">
-<summary Date="23-02-12">
-<fruit>apple</fruit>
-<fruit>mango</fruit>
</summary>
</local>
</main>
The expected result should be in the below format
<fruit>apple</fruit>
<fruit>Orange</fruit>
<fruit>Mango</fruit>
Here are the code snippet what I'm trying to use
<xsl:for-each select="main/local">
<xsl:for-each select="symbol/fruit">
<xsl:copy-of select="."/>
<xsl:copy-of select="fruit[not(.=$fruit)]"/>
</xsl:for-each>
</xsl:for-each>
But I'm not getting any output display for this, Can you please help me how can I remove this duplicate redundancy from here.? Thank You in advance
To do this in XSLT1.0 you can make use of a technique called 'Meunchian' grouping. First you define a key to 'look-up' the fruit elements based on the value
<xsl:key name="fruit" match="fruit" use="." />
Then, to get the unique fruit names, you match fruit elements that happen to be the first fruit element in the key (and to check two nodes are the same the generate-id() method is used)
<xsl:apply-templates
select="//fruit[generate-id() = generate-id(key('fruit', .)[1])]" />
Here is the full XSLT
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:key name="fruit" match="fruit" use="." />
<xsl:template match="/">
<xsl:apply-templates
select="//fruit[generate-id() = generate-id(key('fruit', .)[1])]" />
</xsl:template>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
When applied to your sample XML, the following is output:
<fruit>apple</fruit>
<fruit>Orange</fruit>
<fruit>mango</fruit>

XSLT: Add namespace to root element

I need to change namespaces in the root element as follows:
input document:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<foo xsi:schemaLocation="urn:isbn:1-931666-22-9 http://www.loc.gov/ead/ead.xsd"
xmlns:ns2="http://www.w3.org/1999/xlink" xmlns="urn:isbn:1-931666-22-9"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
desired output:
<foo audience="external" xsi:schemaLocation="urn:isbn:1-931666-22-9
http://www.loc.gov/ead/ead.xsd" xmlns:xsi="http://www.w3.org/2001/XMLSchema-
instance" xmlns:xlink="http://www.w3.org/1999/xlink" xmlns="urn:isbn:1-931666-22-9">
I was trying to do it as I copy over the whole document and before I give any other transformation instructions, but the following doesn't work:
<xsl:template match="* | processing-instruction() | comment()">
<xsl:copy copy-namespaces="no">
<xsl:for-each select=".">
<xsl:attribute name="audience" select="'external'"/>
<xsl:namespace name="xlink" select="'http://www.w3.org/1999/xlink'"/>
</xsl:for-each>
<xsl:copy-of select="#*"/>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
Thanks for any advice!
XSLT 2.0 isn't necessary to solve this problem.
Here is an XSLT 1.0 solution, which works equally well as XSLT 2.0 (just change the version attribute to 2.0):
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xlink="http://www.w3.org/1999/xlink"
exclude-result-prefixes="xlink"
>
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="/*">
<xsl:element name="{name()}" namespace="{namespace-uri()}">
<xsl:copy-of select=
"namespace::*
[not(name()='ns2')
and
not(name()='')
]"/>
<xsl:copy-of select=
"document('')/*/namespace::*[name()='xlink']"/>
<xsl:copy-of select="#*"/>
<xsl:attribute name="audience">external</xsl:attribute>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
When the above transformation is applied on this XML document:
<foo
xsi:schemaLocation="urn:isbn:1-931666-22-9 http://www.loc.gov/ead/ead.xsd"
xmlns:ns2="http://www.w3.org/1999/xlink"
xmlns="urn:isbn:1-931666-22-9"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"/>
the wanted result is produced:
<foo xmlns="urn:isbn:1-931666-22-9"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xlink="http://www.w3.org/1999/xlink"
xsi:schemaLocation="urn:isbn:1-931666-22-9 http://www.loc.gov/ead/ead.xsd"
audience="external"/>
You should really be using the "identity template" for this, and you should always have it on hand. Create an XSLT with that template, call it "identity.xslt", then into the current XSLT. Assume the prefix "bad" for the namespace you want to replace, and "good" for the one you want to replace it with, then all you need is a template like this (I'm at work, so forgive the formatting; I'll get back to this when I'm at home): ... If that doesn't work in XSLT 1.0, use a match expression like "*[namespace-uri() = 'urn:bad-namespace'", and follow Dimitre's instructions for creating a new element programmatically. Within , you really need to just apply-template recursively...but really, read up on the identity template.

How to use group by in xslt

I have a xml that has so many elements and most of that contain attributes.. for some of the attributes values are same so I need to group them and generate diff xml.
I/p Ex:
<TestNode>
<ABC1 value="10.7" format="$" />
<ABC2 value="10.5" format="$" />
<ABC3 value="20" format="Rs" />
<ABC4 value="50" format="Rs" />
<ABC5 value="10.5" format="$" />
</TestNode>
I need to group the rows by format. Note: Format is not fixed... it may grow ...
O/P Ex:
is it possible to get ? Thanks in advance...
In XSLT 1.0 you would use Muenchian grouping.
Define a key "format", from which we can easily select all elements given a format name. Than apply Muenchian grouping to find the unique formats in the input.
Then it gets simple. The "*" template will be applied once per format, and uses the key() to fetch all entries for that format.
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes" />
<xsl:key name="format" match="TestNode/*" use="#format" />
<xsl:template match="TestNode">
<body>
<xsl:apply-templates select="*[generate-id(.)=generate-id(key('format',#format)[1])]"/>
</body>
</xsl:template>
<xsl:template match="*">
<format format="{#format}">
<xsl:copy-of select="key('format', #format)" />
</format>
</xsl:template>
</xsl:stylesheet>
In XSLT 2.0 you should be able to do it with <xsl:for-each-group>, current-grouping-key() and current-group()
Example:
<xsl:for-each-group
select="TestNode/*"
group-by="#format"
>
<group format="{current-grouping-key()}">
<xsl:for-each select="current-group()">
<xsl:copy-of select="."/>
</xsl:for-each>
</group>
</xsl:for-each-group>
See: http://www.w3.org/TR/xslt20/#grouping