I am using Microsoft's XSLT processor (1.0 only)
XML opening lines:
<?xml version="1.0" encoding="utf-8"?>
<Header xmlns="http:\\OldNameSpace.com">
<Detail>
Have the following XSLT template to pick up the <Header> element of my document and change its namespace.
<xsl:template match="*">
<xsl:element name="{name()}" xmlns="http:\\NewNameSpace.com">
<xsl:copy-of select="#*"/>
<xsl:apply-templates />
</xsl:element>
</xsl:template>
Which turns <Header xmlns="http:\\OldNameSpace.com"> Into <Header xmlns="http:\\NewNameSpace.com">
However I now need to add a second namespace to this so that I get the following output:
<Header xmlns="NewNameSpace.com" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
I have tried using:
<xsl:template match="*">
<xsl:element name="{name()}" xmlns="NewNameSpace.com" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<xsl:copy-of select="#*"/>
<xsl:apply-templates />
</xsl:element>
</xsl:template>
However I still only get the same output as the original XSLT template.
Can anyone enlighten to me as to why this is?
This transformation:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:old="http:\\OldNameSpace.com"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
exclude-result-prefixes="old xsi">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:param name="pNewNamespace" select="'http:\\NewNameSpace.com'"/>
<xsl:variable name="vXsi" select="document('')/*/namespace::*[name()='xsi']"/>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="old:*">
<xsl:element name="{local-name()}" namespace="{$pNewNamespace}">
<xsl:copy-of select="$vXsi"/>
<xsl:copy-of select="#*"/>
<xsl:apply-templates />
</xsl:element>
</xsl:template>
</xsl:stylesheet>
when applied on the following XML document:
<Header xmlns="http:\\OldNameSpace.com">
<Detail/>
</Header>
produces (what I guess is) the wanted, correct result:
<Header xmlns="http:\\NewNameSpace.com"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<Detail/>
</Header>
xsl:element (unlike literal result elements) does not copy all in scope namespaces to the result, just the namespace required for the element name 9either implicitly from its name or as specified with the namespace argument).
xslt2 adds an xsl:namespace instruction for this case but in xslt1 the easiest thing to do is
where
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
somewhere on an ancestor (eg on xsl:stylesheet.)
that will add a spurious xsi:tmp="" to the output but also then a namespace declaration,
If you actually need an attribute in this namespace eg xsi:type use that instead of tmp in the above and you are done. If you don't mind the extra, possibly invalid attribute in the xsi namespace you are done. Otherwise do the above in a variable, then use msxsl:node-set to query in to the variable and remove the spurious extra attribute.
If you know statically what namespace you want to generate, then the easiest way to do it in XSLT 1.0 is using xsl:copy-of. Create a source document <dummy xmlns:xsi="http://whatever"/>,
and then do <xsl:copy-of select="document('dummy.xml')/*/namespace::xsi"/> inside your call of xsl:element.
Related
I'm still pretty new to XSLT and I have the following XML which I need to remove the namespace. I also found the following XSLT which almost gets the job done with the exception that it will not retain the xmlns declaration.
XML:
<?xml version="1.0" encoding="UTF-8"?>
<etd_ms:thesis xmlns:etd_ms="http://www.ndltd.org/standards/metadata/etdms/1.0/"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.ndltd.org/standards/metadata/etdms/1.0/ http://www.ndltd.org/standards/metadata/etdms/1.0/etdms.xsd">
<etd_ms:title>Aspects of negritude in the works of two Harlem renaissance authors : Claude McKay and Langston Hughes</etd_ms:title>
<etd_ms:creator>Charles, Asselin</etd_ms:creator>
<etd_ms:subject/>
<etd_ms:publisher>Concordia University</etd_ms:publisher>
<etd_ms:contributor role="advisor">Butovsky, M</etd_ms:contributor>
<etd_ms:date>1980</etd_ms:date>
<etd_ms:type>Electronic Thesis or Dissertation</etd_ms:type>
<etd_ms:identifier>TC-QMG-1</etd_ms:identifier>
<etd_ms:format>text</etd_ms:format>
<etd_ms:identifier>https://spectrum.library.concordia.ca/1/1/MK49585.pdf</etd_ms:identifier>
<etd_ms:language>en</etd_ms:language>
<etd_ms:degree>
<etd_ms:name>M.A.</etd_ms:name>
<etd_ms:level>masters</etd_ms:level>
<etd_ms:discipline>Dept. of English</etd_ms:discipline>
<etd_ms:grantor>Concordia University</etd_ms:grantor>
</etd_ms:degree>
</etd_ms:thesis>
and here's the XSLT:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes" method="xml" encoding="utf-8" omit-xml-declaration="no"/>
<!-- Stylesheet to remove all namespaces from a document -->
<!-- NOTE: this will lead to attribute name clash, if an element contains
two attributes with same local name but different namespace prefix -->
<!-- Nodes that cannot have a namespace are copied as such -->
<!-- template to copy elements -->
<xsl:template match="*">
<xsl:element name="{local-name()}">
<xsl:apply-templates select="#* | node()"/>
</xsl:element>
</xsl:template>
<!-- template to copy attributes -->
<xsl:template match="#*">
<xsl:attribute name="{local-name()}">
<xsl:value-of select="."/>
</xsl:attribute>
</xsl:template>
<!-- template to copy the rest of the nodes -->
<xsl:template match="comment() | text() | processing-instruction()">
<xsl:copy/>
</xsl:template>
</xsl:stylesheet>
The results is the following:
<?xml version="1.0" encoding="UTF-8"?>
<thesis xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.ndltd.org/standards/metadata/etdms/1.0/ http://www.ndltd.org/standards/metadata/etdms/1.0/etdms.xsd">
<title>Aspects of negritude in the works of two Harlem renaissance authors : Claude McKay and Langston Hughes</title>
<creator>Charles, Asselin</creator>
<subject/>
<publisher>Concordia University</publisher>
<contributor role="advisor">Butovsky, M</contributor>
<date>1980</date>
<type>Electronic Thesis or Dissertation</type>
<identifier>TC-QMG-1</identifier>
<format>text</format>
<identifier>https://spectrum.library.concordia.ca/1/1/MK49585.pdf</identifier>
<language>en</language>
<degree>
<name>M.A.</name>
<level>masters</level>
<discipline>Dept. of English</discipline>
<grantor>Concordia University</grantor>
</degree>
</thesis>
It's almost there, with the exception that I need to keep the xmlns declaration, so ultimatly the root element should be something like:
<thesis xmlns="http://www.ndltd.org/standards/metadata/etdms/1.0/"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.ndltd.org/standards/metadata/etdms/1.0/ http://www.ndltd.org/standards/metadata/etdms/1.0/etdms.xsd">
Can someone help me resolving this issue? Thanks.
Change
<xsl:element name="{local-name()}">
to
<xsl:element name="{local-name()}" namespace="http://www.ndltd.org/standards/metadata/etdms/1.0/">
My requirement is to convert the following array
<array>
<value>755</value>
<value>5861</value>
<value>4328</value>
</array>
to this array.
<array>
<int>755</int>
<int>5861</int>
<int>4328</int>
</array>
Following is my XSLT code to do the transformation & it works. Is it the correct way because in one post I saw the use of "identity template". but I haven't used it.
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="/array">
<xsl:element name="array">
<xsl:for-each select="value">
<xsl:element name="int">
<xsl:value-of select="." />
</xsl:element>
</xsl:for-each>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
Your current method works. It is more of a "pull" style stylesheet. The "push" style uses apply-templates.
You could shorten it a bit by using element literals, which makes it a little easier to read:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="/array">
<array>
<xsl:for-each select="value">
<int>
<xsl:value-of select="." />
</int>
</xsl:for-each>
</array>
</xsl:template>
</xsl:stylesheet>
A solution using the identity template and a custom template for the value element:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" indent="yes"/>
<!--identity template, which copies every attribute and
node(element, text, comment, and processing instruction)
that it matches and then applies templates to all of it's
attributes and child nodes (if there are any) -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<!--Specialized template that matches the value element.
Because it is more specific than the identity template above it has
a higher priority and will match when the value element is encountered.
It creates an int element and then applies templates to any attributes
and child nodes of the value element -->
<xsl:template match="value">
<int>
<xsl:apply-templates select="#*|node()"/>
</int>
</xsl:template>
</xsl:stylesheet>
You can do:
<xsl:template match="/array">
<array>
<xsl:for-each select="value">
<int>
<xsl:value-of select="." />
</int>
</xsl:for-each>
</array>
</xsl:template>
Here is a quote from the accepted answer of your link:
XSL cannot replace anything. The best you can do is to copy the parts you want to keep, then output the parts you want to change instead of the parts you don't want to keep.
That is where the identity template comes into play: it copies everything not targetted by another matching template. The upshot is, that if your base XML contains other content than just the array, then you should also include the identity template in your xslt. But if you are sure that your xml will contain no other content, then you don't need it.
The requirement is to find the duplicate element(BaseName) in XML and marked the parent element(Account) with isDuplicate attribute. The XSL is working correctly when the input XML RootElement has no namespaces. When the root element has namespace then I get empty object. I am not sure why the namespace is causing XSL to generate empty output. Any help to get the right output would be greatly appreciated.`
Input XML WITH NAMESPACE
<?xml version="1.0"?>
<objects xmlns="urn:s.sexmaple.com" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<Account>
<Id>001A00F</Id>
<RecordTypeId>012A00</RecordTypeId>
<BaseName>EFGH</BaseName>
</Account>
<Account>
<Id>001A0</Id>
<RecordTypeId>012A0</RecordTypeId>
<BaseName>ABCD</BaseName>
</Account>
<Account>
<Id>001A</Id>
<RecordTypeId>012A</RecordTypeId>
<BaseName>ABCD</BaseName>
</Account>
</objects>
XSL
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
<xsl:output method="xml"
version="1.0"
encoding="UTF-8"
indent="yes"/>
<xsl:strip-space elements="*" />
<xsl:template match="node()|#*">
<xsl:copy copy-namespaces="no">
<xsl:apply-templates select="node()|#*" />
</xsl:copy>
</xsl:template>
<xsl:template match="/">
<xsl:variable name="Accounts">
<objects>
<xsl:for-each select="//Account">
<xsl:sort select="BaseName" />
<xsl:apply-templates select="." />
</xsl:for-each>
</objects>
</xsl:variable>
<xsl:variable name="unqentity">
<objects>
<xsl:for-each select="$Accounts/objects/Account">
<xsl:choose>
<xsl:when test="not(following-sibling::Account/BaseName=./BaseName) and not(preceding-sibling::Account/BaseName=./BaseName) ">
<xsl:copy-of select="." />
</xsl:when>
<xsl:otherwise>
<Account>
<xsl:attribute name="isDuplicate">yes</xsl:attribute>
<xsl:for-each select="child::*">
<xsl:element name="{name()}">
<xsl:copy-of select="#*|node()" />
</xsl:element>
</xsl:for-each>
</Account>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
</objects>
</xsl:variable>
<xsl:copy-of select="$unqentity" />
</xsl:template>
</xsl:stylesheet>
Output XML WHEN INPUT XML HAS NAMESPACE
<?xml version="1.0" encoding="UTF-8"?>
<objects/>
Output XML when Input has no Namespaces
<?xml version="1.0" encoding="UTF-8"?>
<objects>
<Account>
<Id>001A00F</Id>
<RecordTypeId>012A00</RecordTypeId>
<BaseName>EFGH</BaseName>
</Account>
<Account isDuplicate="yes">
<Id>001A0</Id>
<RecordTypeId>012A0</RecordTypeId>
<BaseName>ABCD</BaseName>
</Account>
<Account isDuplicate="yes">
<Id>001A</Id>
<RecordTypeId>012A</RecordTypeId>
<BaseName>ABCD</BaseName>
</Account>
</objects>
When you have a namespace, it means the element within the namespace is not the same as an element without a namespace (or indeed an element in a different name space).
This means when you do this in your XSLT...
<xsl:for-each select="//Account">
You are looking for an Account element with no namespace, and so it will not match the Account element in your source XML, which is in the amusingly titled "urn:s.sexmaple.com" (which I suspect is a misspelling)
As you are using XSLT2.0 though, there is a simple way to get around this, by specifying a default namespace for any xpath expressions, using the xpath-default-namespace. Normally, this may be enough, but you have slightly complicated matters by creating new elements within a variable, which you then later try to select.
<xsl:for-each select="$Accounts/objects/Account">
This means when you create the objects and Account elements in the $Accounts variable, they will need to be part of the namespace too.
To cut to the chase, this is what your xsl:stylesheet element needs to look like
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"
xmlns="urn:s.sexmaple.com"
xpath-default-namespace="urn:s.sexmaple.com">
So, the xpath-default-namespace="urn:s.sexmaple.com" is used to match elements in your source XML, whilst the xmlns="urn:s.sexmaple.com" is used to ensure the elements you create in the variable have this namespace and can be matched later on.
Having said all that, you have rather over-complicated your whole XSLT. Are you simply trying to add an IsDuplicate attribute to Account elements with the same BaseName? Well, create a key to look up duplicates, like so
<xsl:key name="account" match="Account" use="BaseName" />
Then you can look up duplicates like so:
<xsl:if test="key('account', BaseName)[2]">
<xsl:attribute name="isDuplicate">Yes</xsl:attribute>
</xsl:if>
Try this XSLT, which should give the same results
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xpath-default-namespace="urn:s.sexmaple.com">
<xsl:output method="xml" indent="yes"/>
<xsl:key name="account" match="Account" use="BaseName" />
<xsl:template match="Account">
<xsl:copy>
<xsl:if test="key('account', BaseName)[2]">
<xsl:attribute name="isDuplicate">Yes</xsl:attribute>
</xsl:if>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Note how this only needs to use xpath-default-namespace as it is not creating whole new elements, just copying existing ones (which get their namespace copied across too).
The reason your input XML without a namespace works were the one with a namespace doesn't, isn't because of the input XML, but because of the XSLT stylesheet.
When your XML file has a default namespace, that namespace will need to be declared in the stylesheet itself.
For example, with the following XML:
<test xmlns="test.xml.schema">
<element>Content</element>
</test>
When I apply the following XSLT:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
<xsl:template match="/">
<out>
<namespace>None</namespace>
<xsl:apply-templates />
</out>
</xsl:template>
<xsl:template match="test">
<test out="True">hello</test>
</xsl:template>
<xsl:template match="*"/>
</xsl:stylesheet>
The output is just:
<out><namespace>None</namespace></out>
The <xsl:template match="test"> can't match on the test element in the input xml, as it is actually test.xml.schema:test while the match in the stylesheet, with no namespace is actually :test. Thus no match is possible.
However, when we just add a namespace for the input document adn modify the template, like so:
<xsl:stylesheet xmlns:t="test.xml.schema" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
<xsl:template match="/">
<out>
<namespace>test.xml.schema</namespace>
<xsl:apply-templates />
</out>
</xsl:template>
<xsl:template match="t:test">
<test out="True">hello</test>
</xsl:template>
<xsl:template match="*"/>
</xsl:stylesheet>
The output becomes:
<out xmlns:t="test.xml.schema">
<namespace>test.xml.schema</namespace>
<test out="True">hello</test>
</out>
Its important to note that the namespace abbreviation in the input document and XSL don't need to be the same (eg. blank vs. "t"), but the namespaces themselfs do: (e.g both blank and "t" must be bound to test.xml.schema).
Also note, that using a default namespace in XSLT can be fraught with issues. So its best to use declared namespaces in XSLT.
I have a xml which I want to get in the expected format as shown below. I am trying to use apply templates concept to this. But some how, I am not able to see the expected result.
<?xml version="1.0" encoding="UTF-8"?>
<SOAP:ENV>
<SOAP:HEADER/>
<SOAP:BODY>
<OutputResponse>
<RespStructure ID="1">
<RespStatus>Success</RespStatus>
<RespMessage>
<Country>Australia</Country>
<Capital>Canberra</Capital>
</RespMessage>
<RespMessage>
<Country>England</Country>
<Capital>London</Capital>
</RespMessage>
<RespMessage>
<Country>China</Country>
<Capital>Beijing</Capital>
</RespMessage>
</RespStructure>
</OutputResponse>
</SOAP:BODY>
</SOAP:ENV>
Now in this message, I am having RespMessage and RespStatus both as part of RespStructure. But Respstatus is a single nodeset where RespMessage is a multiple values nodeset(Country, Capital). When I am using apply templates, either only first RespMessage is getting selected (2nd repetition not appearing) or Respstatus not giving it's value. I try to get below output.
<?xml version="1.0" encoding="UTF-8"?>
<SOAP:ENV>
<SOAP:HEADER/>
<SOAP:BODY>
<OutputResponse>
<RespStructure ID="1">
<TransactionStatus>Success</TransactionStatus>
<ListOfCountries>
<SelectedCountry>Australia</SelectedCountry>
<FIrstSelectedCapital>Canberra</FIrstSelectedCapital>
</ListOfCountries>
<ListOfCountries>
<SelectedCountry>England</SelectedCountry>
<FIrstSelectedCapital>London</FIrstSelectedCapital>
</ListOfCountries>
<ListOfCountries>
<SelectedCountry>China</SelectedCountry>
<FIrstSelectedCapital>Beijing</FIrstSelectedCapital>
</ListOfCountries>
</RespStructure>
</OutputResponse>
</SOAP:BODY>
</SOAP:ENV>
I am changing all the names of fields, but I should get all multiple nodes without any missing.
I used below code snippet from forum, but I failed to apply. How can I populate RespStatus using below snippet. When I gave different template, both are not called and only one got printed. I tried to change apply templates to more specific nodeset also.
<xsl:template match="#*|node()">
<xsl:apply-templates select="#*|node()" />
</xsl:template>
<xsl:template match="Body">
<SOAPENV>
<Header/>
<OutputResponse>
<xsl:apply-templates select="#*|node()" />
</OutputResponse>
</SOAPENV>
</xsl:template>
<xsl:template match="RespMessage">
<ListOfCountries>
<SelectedCountry><xsl:value-of select="Country" /></SelectedCountry>
<FIrstSelectedCapital><xsl:value-of select="Capital" /></FIrstSelectedCapital>
</ListOfCountries>
</xsl:template>
Thanks for response. Apologies for any spell mistakes.
Looking at your XSL snippet, it should match, and transform all RespMessage elements, unless there is some other part of the XSLT, which you have not shown, that is affecting things.
One issue you do have, and this might be just how you have editted your question, is that your original XML uses the namespace prefix "SOAP", but you have not declared a namespace for this prefix. I would expect the first line to be something like this
<SOAP:ENV xmlns:SOAP="http://schemas.xmlsoap.org/soap/envelope/">
Without this, you will not be able to apply your XSLT on it all.
The use of namespaces also means the second template, matching body, won't match anything
<xsl:template match="Body">
(Actually, it won't match anything because it is case sensitive, and in the original XML it is SOAP:BODY)
Looking at the rest of the XSLT, if you want to copy across existing elements without changing, you should be using the identity template. The first template in your XSLT should look like this
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()" />
</xsl:copy>
</xsl:template>
With this in place, all you need is to add a template to match, and transform RespStatus.
<xsl:template match="RespStatus">
<xsl:element name="TransactionStatus">
<xsl:value-of select="." />
</xsl:element>
</xsl:template>
Try this XSLT
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:SOAP="http://schemas.xmlsoap.org/soap/envelope/">
<xsl:output omit-xml-declaration="yes" indent="yes" />
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()" />
</xsl:copy>
</xsl:template>
<xsl:template match="RespStatus">
<xsl:element name="TransactionStatus">
<xsl:value-of select="." />
</xsl:element>
</xsl:template>
<xsl:template match="RespMessage">
<xsl:element name="ListOfCountries">
<SelectedCountry><xsl:value-of select="Country" /></SelectedCountry>
<FIrstSelectedCapital><xsl:value-of select="Capital" /></FIrstSelectedCapital>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
I need to change namespaces in the root element as follows:
input document:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<foo xsi:schemaLocation="urn:isbn:1-931666-22-9 http://www.loc.gov/ead/ead.xsd"
xmlns:ns2="http://www.w3.org/1999/xlink" xmlns="urn:isbn:1-931666-22-9"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
desired output:
<foo audience="external" xsi:schemaLocation="urn:isbn:1-931666-22-9
http://www.loc.gov/ead/ead.xsd" xmlns:xsi="http://www.w3.org/2001/XMLSchema-
instance" xmlns:xlink="http://www.w3.org/1999/xlink" xmlns="urn:isbn:1-931666-22-9">
I was trying to do it as I copy over the whole document and before I give any other transformation instructions, but the following doesn't work:
<xsl:template match="* | processing-instruction() | comment()">
<xsl:copy copy-namespaces="no">
<xsl:for-each select=".">
<xsl:attribute name="audience" select="'external'"/>
<xsl:namespace name="xlink" select="'http://www.w3.org/1999/xlink'"/>
</xsl:for-each>
<xsl:copy-of select="#*"/>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
Thanks for any advice!
XSLT 2.0 isn't necessary to solve this problem.
Here is an XSLT 1.0 solution, which works equally well as XSLT 2.0 (just change the version attribute to 2.0):
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xlink="http://www.w3.org/1999/xlink"
exclude-result-prefixes="xlink"
>
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="/*">
<xsl:element name="{name()}" namespace="{namespace-uri()}">
<xsl:copy-of select=
"namespace::*
[not(name()='ns2')
and
not(name()='')
]"/>
<xsl:copy-of select=
"document('')/*/namespace::*[name()='xlink']"/>
<xsl:copy-of select="#*"/>
<xsl:attribute name="audience">external</xsl:attribute>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
When the above transformation is applied on this XML document:
<foo
xsi:schemaLocation="urn:isbn:1-931666-22-9 http://www.loc.gov/ead/ead.xsd"
xmlns:ns2="http://www.w3.org/1999/xlink"
xmlns="urn:isbn:1-931666-22-9"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"/>
the wanted result is produced:
<foo xmlns="urn:isbn:1-931666-22-9"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xlink="http://www.w3.org/1999/xlink"
xsi:schemaLocation="urn:isbn:1-931666-22-9 http://www.loc.gov/ead/ead.xsd"
audience="external"/>
You should really be using the "identity template" for this, and you should always have it on hand. Create an XSLT with that template, call it "identity.xslt", then into the current XSLT. Assume the prefix "bad" for the namespace you want to replace, and "good" for the one you want to replace it with, then all you need is a template like this (I'm at work, so forgive the formatting; I'll get back to this when I'm at home): ... If that doesn't work in XSLT 1.0, use a match expression like "*[namespace-uri() = 'urn:bad-namespace'", and follow Dimitre's instructions for creating a new element programmatically. Within , you really need to just apply-template recursively...but really, read up on the identity template.