I have a regular experession like this PRCE using php:
^/someurl/*
There are a lot of urls like
/someurl/test
/someurl/something/{version}/{name}/{etc}
and i need to exclude urls like this one:
^/someurl/test/{version}/commands/*
{version} is a float number like 2.1.1 2.4
I've tried this
^((?!/someurl/test/[0-9].+/commands/*))
It works
But I need to add this to single line like
^/someurl/* Excluding ^((?!/someurl/test/[0-9].+/commands/*))
How to join them? Thanks.
You may use
^/someurl/(?!test/[0-9.]+/commands/).*
Or a bit more precise
^/someurl/(?!test/[0-9]+(?:\.[0-9]+)+/commands/).*
See the regex demo
Details
^/someurl/ - /someurl/ at the start of the string
(?!test/[0-9.]+/commands/) - immediately to the right of the current position, there can't be test/, then 1+ digits or dots, then /commands/ substring (if [0-9]+(?:\.[0-9]+)+ is used it will match 1 or more digits, and then 1 or more repetitions of a dot followed with 1+ digits)
.* - any 0+ chars as many as possible.
Related
A colleague has written some C# code that outputs GUIDs to a CSV file. The code has been running for a while but it has been discovered that the GUIDs contain underscore characters, instead of hyphens :-(
There are several files which have been produced already and rather than regenerate these, I'm thinking that we could use the Search and Replace facility in Notepad++ to search across the files for "GUIDs" in this format:
{89695C16_C0FF_4E7C_9BB2_8B50FAC9D371}
and replace it with a properly formatted GUID like this:
{89695C16-C0FF-4E7C-9BB2-8B50FAC9D371}.
I have a RegEx to find the offending GUIDs (probably not very efficient):
(([A-Z]|[0-9]){8}_)(([A-Z]|[0-9]){4})_(([A-Z]|[0-9]){4})_(([A-Z]|[0-9]){4}_(([A-Z]|[0-9]){12}))
but I don't know what RegEx to use to replace the underscores with. Does anybody know how to do this?
You can use the following solution:
Find What: (?:\G(?!\A)|{(?=[a-f\d]{8}(?:_[a-f\d]{4}){4}[a-f\d]{8}\}))[a-f\d]*\K_
Replace with: -
Match case: OFF
See the settings and demo:
See the regex demo online. Details:
(?:\G(?!\A)|{(?=[a-f\d]{8}(?:_[a-f\d]{4}){4}[a-f\d]{8}\})) - either the end of the previous match or a { char immediately followed with eight alphanumeric chars, four repetitions of an underscore and then four alphanumeric chars and then eight alphanumeric chars and a } char
[a-f\d]* - zero or more alphanumeric chars
\K - match reset operator that discards the text matched so far from the overall match memory buffer
_ - an underscore.
You can match the pattern with 5 capture groups where you would match the underscores in between.
Then you can use the capture groups in the replacement with $1-$2-$3-$4-$5
{\K([A-Z0-9]{8})_([A-Z0-9]{4})_([A-Z0-9]{4})_([A-Z0-9]{4})_([A-Z0-9]{12})(?=})
{ Match {
\K Clear the match buffer (forget what is matched so far)
([A-Z0-9]{8})_ Capture group 1, match 8 times a char A-Z0-9
([A-Z0-9]{4})_ Capture 4 times a char A-Z0-9 in group 2
([A-Z0-9]{4})_ Same for group 3
([A-Z0-9]{4})_ Same for group 4
([A-Z0-9]{12}) Capture 12 times a char A-Z0-9 in group 5
(?=}) Positive lookahead, assert } to the right
Regex demo
If the pattern should also match without matching the curly's { and } you can append word boundaries
\b([A-Z0-9]{8})_([A-Z0-9]{4})_([A-Z0-9]{4})_([A-Z0-9]{4})_([A-Z0-9]{12})\b
Regex demo
I am attempting to pick apart data from the following string utlizing a regex expression:
Ethane, C2 11.7310 3.1530 13.9982 HV, Dry # Base P,T 1432.00
The ultimate goal is to be able to pull out the middle three data points as individual values 11.7310, 3.153, 13.9982
The code expression I am working with at the moment is as follows:
(?<=C2 )(\d*\.?\d+)
This yields a full match of 11.7310 and a Group 1 match of 11.7310, but I can't figure out how to match the other two data points.
I am using PCRE (PHP) to create my expression.
You may use
(?:\G(?!^)|\bC2)\s+\K\d*\.?\d+
See the regex demo.
Details
(?:\G(?!^)|\bC2) - either the end of the previous successful match or C2 whole word
\s+ - 1+ whitespaces
\K - match reset operator discarding all the text matched so far in the match memory buffer
\d* - 0+ digits
\.? - an optional dot
\d+ - 1+ digits.
Given any URL, like:
https://stackoverflow.com/v1/summary/1243PQ/details/P1/9981
How do I extract the numeric or alphanumeric part of the URL? I.e. the following strings from the url given above:
1. v1
2. 1243PQ
3. P1
4. 9981
To rephrase, a regex to extract strings from a string (URL) which have at least 1 digit and 0 or more alphabet characters, separated by '/'.
I tried to capture a repeating group (^[a-zA-Z0-9]+)+ and ([a-zA-Z]{0,100}[0-9]{1,100})+ but it didn't work. In hindsight intuition does say this shouldn't work. I am unsure how do I match patterns over a group and not just a single character.
If I understand what you really want:
Extracting parts with only numbers or with numbers following alphabets
then; I can suggest this regex:
\b[a-zA-Z]*[0-9]+[a-zA-z]*\b
Regex Demo
I use \b to assert position of a word boundary or a part.
As numbers are required and alphabets can comes before or after that I use above regex.
If following alphabets are not required then I can suggest this regex:
\b[a-zA-z0-9]*[0-9]+[a-zA-Z0-9]*\b
Regex Demo
I believe this should work for you:
(\d*\w+\d+\w*)
EDIT: actually, this should be sufficient
(\w+\d+\w*)
or
(\w*\d+\w*)
Well, you could do this:
(\w*\d+\w*) with the g (global) regex option
On the example URL, it would look like this:
const regex = /(\w*\d+\w*)/g;
const url = 'https://stackoverflow.com/v1/summary/1243PQ/details/P1/9981';
console.log(url.match(regex))
Try \/[a-zA-Z]*\d+[a-zA-Z0-9]*
Explanation:
\/ - match / literally
[a-zA-Z]* - 0+ letters
\d+ - 1+ digits - thanks to this, we require at least one digits
[a-zA-Z0-9]* - 0+ letters or digits
Demo
It will captrure together with / at the beginning, so you need to trim it.
I have implemented the following Regex pattern
^[\d,|+\d,]+$
It validates the following pattern
14,+96,4,++67
I need to invalidate ++67 from my pattern and I need to keep values with only a single leading + sign.
How should I change my Regex pattern?
You may use
^\+?\d+(?:,\+?\d+)*$
See the regex demo.
Details
^ - start of string
\+? - an optional + char
\d+ - 1+ digits
(?:,\+?\d+)* - zero or more repetitions of a sequence of patterns:
, - a comma
\+? - an optional plus
\d+ - 1+ digits
$ - end of string
Perhaps you meant to do this?
^(\d,|\+\d,)+$
Square brackets use every character or character class within, which does not appear to be what you really want. For disjunction you need round brackets.
You can try this one
^(\d+\,?|\+\d+,?)+$
I am trying to create a regex to validate a field where the user can enter a 5 digit number with the option of adding a / followed by 3 letters. I have tried quite a few variations of the following code:
^(\d{5})+?([/]+[A-Z]{1,3})?
But I just can't seem to get what I want.
For instance l would like the user to either enter a 5 digit number such as 12345 with the option of adding a forward slash followed by any 3 letters such as 12345/WFE.
You probably want:
^\d{5}(?:/[A-Z]{3})?$
You might have to escape that forward slash depending on your regex flavor.
Explanation:
^ - start of string anchor
\d{5} - 5 digits
(?:/[A-Z]{3}) - non-capturing group consisting of a literal / followed by 3 uppercase letters (depending on your needs you could consider making this a capturing group by removing the ?:).
? - 0 or 1 of what precedes (in this case that's the non-capturing group directly above).
$ - end of string anchor
All in all, the regex looks like this:
You can use this regex
/^\d{5}(?:\/[a-zA-Z]{3})?$/
^\d{5}(?:/[A-Z]{3})?$
Here it is in practice (this is a great site to test your regexes):
http://regexr.com?36h9m
^(\d{5})(\/[A-Z]{3})?
Tested in rubular