I am trying to copy elements of array sequentially to excel .
Here is the code :
array = ['A','B','C','D','E']
print len(array)
for i in range(1,len(array)):
sheet2.cell(i,1).value = array[i]
#print cell
#sheet2.cell(i,1).value = cell
wb2.save(path2)
Expected :
Should sequentially write A,B,C,D,E to the rows in excel
Actual:
Starts writing from B,C,D,E
What am i missing. Something very simple
if you use-> for i in range(1,len(array)):
you'll miss the first element of array because it starts with 1. index
python arrays start with 0 index
use it like -> for i in range(len(array)): or for i in range(0,len(array)):
Python indices start with 0, excel indices apparently with 1. So simply do:
array = ['A','B','C','D','E']
print len(array)
for i in range(0,len(array)):
sheet2.cell(i+1,1).value = array[i]
print cell
sheet2.cell(i+1,1).value = cell
wb2.save(path2)
In python array starts with zero. This is the correct code:
array = ['A','B','C','D','E']
print len(array)
for i in range(0,len(array)):
sheet2.cell(i+1,1).value = array[i]
#print cell
#sheet2.cell(i+1,1).value = cell
wb2.save(path2)
Notice that the for loop starts from 0.
Related
i have to write a function that takes as an input a list and if to Consecutive numbers have the same sighn then they both go to a same list in lists if not a new list in list is opened for example:
[2,5,-3,-1,-1,3,-2,-2]->[[2,5]],[-3,-1,-1],[3],[-2,-2]]
this is my code :
def num_8(lst):
my_lst=[[lst[0]]]
j=0
for i in range(1,len(lst)):
if (lst[i]> 0 and lst[i-1]>0) or (lst[i]<0 and lst[i-1]<0):
my_lst[j].append(lst[i])
print(my_lst)
else:
j=j+1
my_lst[j].append([lst[i]])
return my_lst
print(num_8([2,5,-3,-1,-1,3,-2,-2]))
but i keep on getting
my_lst[j].append([lst[i]])
IndexError: list index out of range
and i dont know were i get out of range :( thanks
The error is with the else part.
my_lst[j] does not exisit at that point(The len of my_lst is j -1)
So you'll have to append the first number to my_lst and not my_lst[j] (Similar to what you have done in the first line of the function)
my_lst.append([lst[i]])
I have data in the form of list of lists where I am trying to match the demand and supply such that each demand matches uniquely to one supply item.
dmndId_w_freq = [['a',4,[1,2,3,4]],['b',6,[5,6,7,8,3,4]],['c',7,[6,5,7,9,8,3,4]],['d',8,[1,6,3,4,5,6,7,10]]]
num_sims = 1
for sim_count in range(num_sims):
dmndID_used_flag = {}
splID_used_flag = {}
dmndID_splId_one_match = {}
for i in dmndId_w_freq:
if i[0] not in dmndID_used_flag.keys():
for j in i[2]:
#print j
#print "CLICK TO CONTINUE..."
#raw_input()
if j in splID_used_flag.keys():
i[2].remove(j)
dmndID_splId_one_match[i[0]] = i[2][0]
splID_used_flag[i[2][0]] = 1
dmndID_used_flag[i[0]] = 1
print
print dmndID_splId_one_match
#print splID_used_flag
#print dmndID_used_flag
#raw_input()
I would expect the output dmndID_splId_one_match to be something like {'a':1,'b':5,'c':6,'d':3}.
But I end up getting {'a':1,'b':5,'c':6,'d':6}
So I am NOT getting a unique match as the supply item 6 is getting mapped to demands 'c' as well as demand 'd'.
I tried to debug the code by looping through it and it seems that the problem is in the for-loop
for j in i[2]:
The code is not going through all the elements of i[2]. It does not happen with the 'a' and 'b' part. but starts happening with the 'c' part. It goes over 6 and 5 but skips 7 (the third element of the list [6,5,7,9,8,3,4]). Similarly, in the 'd' part it skips the 2nd element 6 in the list [1,6,3,4,5,6,7,10]. And that is why the mapping is happening twice, since I am not able to remove it.
What am I doing wrong that it is not executing the for-loop as expected?
Is there a better way to write this code?
I figured out the problem in the for loop. I am looping through i[2] and then trying to modify it within the loop. this makes it unstable.
So presently code is as so:
table = []
for line in open("harrytest.csv") as f:
data = line.split(",")
table.append(data)
transposed = [[table[j][i] for j in range(len(table))] for i in range(len(table[0]))]
openings = transposed[1][1: - 1]
openings = [float(i) for i in openings]
mean = sum(openings)/len(openings)
print mean
minimum = min(openings)
print minimum
maximum = max(openings)
print maximum
range1 = maximum - minimum
print range1
This only prints one column of 7 for me, it also leaves out the bottom line. We are not allowed to import with csv module, use numpy, pandas. The only module allowed is os, sys, math & datetime.
How do I write the code so as to get median, first, last values for any column.
Change this line:
openings = transposed[1][1: - 1]
to this
openings = transposed[1][1:]
and the last row should appear. You calculations for mean, min, max and range seem correct.
For median you have to sort the row and select the one middle element or average of the two middle elements. First and last element is just row[0] and row[-1].
I used the split() function to convert string to a list time = time.split() and this is how my output looks like :
[u'1472120400.107']
[u'1472120399.999']
[u'1472120399.334']
[u'1472120397.633']
[u'1472120397.261']
[u'1472120394.328']
[u'1472120393.762']
[u'1472120393.737']
Then I tried accessing the contents of the list using print time[1] which gives the index out of range error (cause only a single value is stored in one list). I checked questions posted by other people and used print len(time). This is the output for that:
1
[u'1472120400.107']
1
[u'1472120399.999']
1
[u'1472120399.334']
1
[u'1472120397.633']
1
[u'1472120397.261']
1
[u'1472120394.328']
1
[u'1472120393.762']
1
[u'1472120393.737']
I do this entire thing inside a for loop because I get logs dynamically and have to extract out just the time.
This is part of my code:
line_collect = lines.collect() #spark function
for line in line_collect :
a = re.search(rx1,line)
time = a.group()
time = time.split()
#print time[1] #index out of range error which is why I wrote another for below
for k in time :
time1 = time[k]#trying to put those individual list values into one variable but get type error
print len(time1)
I get the following error :
time1 = time[k]
TypeError: list indices must be integers, not unicode
Can someone tell me how to read each of those single list values into just one list so I can access each of them using a single index[value]. I'm new to python.
My required output:
time =['1472120400.107','1472120399.999','1472120399.334','1472120397.633','1472120397.261','1472120394.328','1472120393.762','1472120393.737']
so that i can use time[1] to give 1472120399.999 as result.
Update: I misunderstood what you wanted. You have the correct output already and it's a string. The reason you have a u before the string is because it's a unicode string that has 16 bits. u is a python flag to distinguish it from a normal string. Printing it to the screen will give you the correct string. Use it normally as you would any other string.
time = [u'1472120400.107'] # One element just to show
for k in time:
print(k)
Looping over a list using a for loop will give you one value at a time, not the index itself. Consider using enumerate:
for k, value in enumerate(time):
time1 = value # Or time1 = time[k]
print(time1)
Or just getting the value itself:
for k in time:
time1 = k
print(time1)
--
Also, Python is zero based language, so to get the first element out of a list you probably want to use time[0].
Thanks for your help. I finally got the code right:
newlst = []
for line in line_collect :
a = re.search(rx1,line)
time = a.group()
newlst.append(float(time))
print newlst
This will put the whole list values into one list.
Output:
[1472120400.107, 1472120399.999, 1472120399.334, 1472120397.633,
1472120397.261, 1472120394.328, 1472120393.762, 1472120393.737]
I am trying to script a dynamic way way to only take the first two elements in a list and I am having some trouble. Below is a breakdown of what I have in my List
Declaration:
Set List = CreateObject("Scripting.Dictionary")
List Contents:
List(0) = 0-0-0-0
List(1) = 0-1-0-0
List(2) = 0-2-0-0
Code so far:
for count = 0 To UBound(List) -1 step 1
//not sure how to return
next
What I currently have does not work.
Desired Return List:
0-0-0-0
0-1-0-0
You need to use the Items method of the Dictionary. For more info see here
For example:
Dim a, i
a = List.Items
For i = 0 To List.Count - 1
MsgBox(a(i))
Next i
or if you just want the first 2:
For i = 0 To 1
MsgBox(a(i))
Next i
UBound() is for arrays, not dictionaries. You need to use the Count property of the Dictionary object.
' Show all dictionary items...
For i = 0 To List.Count - 1
MsgBox List(i)
Next
' Show the first two dictionary items...
For i = 0 To 1
MsgBox List(i)
Next