In Base SAS, how do i convert a character Year (2018) to 01/01/2018 in date format?
data date;
length charyear $8.;
charyear='2018';
run;
In general, when constructing a date from date parts, you should use SAS MDY function. MDY(month,day,year) returns a numeric date, but you need to convert all arguments to numbers, before using the function.
data date;
length charyear $8.;
charyear='2018';
format numDate date9.;
numDate = mdy(1,1, input(charyear, best.));
run;
In your particular case it can be done even easier by using function INPUT with a corresponding date informat:
data date;
length charyear $8.;
charyear='2018';
format numDate date9.;
numDate = input("01JAN" || charyear, date9.);
run;
Related
Want to convert date = 01-SEP-2021 to date = 01SEP2021. I used this code to convert:
New date = input(compress(date,'-'),date9.);
But that didn't work. I also used substring to remove the parts of day month and year but seems this method is a bit lengthy.
If the type is numeric and SAS already displays it as a date then it's a formatting issue.
proc datasets lib=work nolist;
modify have;
format date date9.;
quit;
Otherwise, it must be a character and you have to convert it to a date and display it in date9. format.
data want;
date = '01-SEP-2021';
new_date = input(date, anydtdte.); *anydtdte. automatically reads a variety of date formats;
format new_date date9.;
run;
I have a SAS field where the datatype is number and format is date9.
It has a value like 30SEP2018.
How do I convert it to a SAS date so I can do date operations?
SAS dates are stored as number starting from 1/1/1960 and it starts form number = 0 and increases by 1 for every day. Your date is stored as number and then you get from proc contents and format is to display in the way you want.
data have;
input date:date9.;
format date date9.;
datalines;
30SEP2018
;
proc contents data=have;
run;
you can calculations on above date and gives you appropriate results as shown below
data want;
set have;
new_date= date+1;
new_date1= date-1;
format new_date new_date1 date9.;
run;
proc print; run;
I would like to get only date and time separately from 01JAN13:08:29:00
Format & Infomat available in Dataset is:
Date Num 8 DATETIME.(format) ANYDTDTM40(informat)
And If I run datepart() on 01JAN13:08:29:00 I get output as 19359 (I don't want it.)
The DATEPART function extracts the date value from a datetime value. The date value as you have seen is simply a number. A date format must be applied to a variable holding a date value. Base SAS variables have only two value types, character and numeric.
data want;
now_dtm = datetime();
now_dt = datepart(now_dtm);
now_dt_unformatted = now_dt;
format now_dtm datetime.;
format now_dt date9.; * <----- this is what you need, format stored in data set header information;
run;
proc print data=want;
run;
* you can change the format temporarily during a proc step;
proc print data=want;
format now_dt yymmdd10.; * <---- changes format for duration of proc step;
format now_dt_unformatted mmddyy10.;
run;
Actually 19,359 is exactly the value you want. You started with the number of seconds since 1960 and converted it to the number of days since 1960.
data x ;
dt = '01JAN13:08:29:00'dt ;
date = datepart(dt);
time = timepart(dt);
put (dt date time) (=);
run;
Results
dt=1672648140 date=19359 time=30540
You just need to attach a format to your new variable so that SAS will display the value in a format that humans will recognize. You could use a format like DATE9. to have it show 19,359 as 01JAN2013. Similarly you need to attach a format to the time part to make it print in format that human's will interpret as a time.
format date date9. time time8. ;
I have a table in SAS where in one column, the date is stored (e.g. "2005/10").
How do I have to convert this to a SAS data format?
Among many other tries, I tried this code:
data test;
format date YYMMS.;
date = input(ObservationMonth, YYMMS.);
put date=date9.;
run;
You could just use the anydtdte. informat.
data want;
format date yymms.;
text="2005/10";
date=input(text,anydtdte.);
put date;
run;
This informat detects most date formattings and converts the character-stored value to a SAS date.
One way is to use substr() and mdy() to extract the date components:
data _null_;
ObservationMonth ="2005/10";
date =mdy(substr(ObservationMonth,6,2),1,substr(ObservationMonth,1,4));
put date = date9.;
run;
Another option is to use the anydtdte informat (note that results may differ depending on your locale):
data _null_;
ObservationMonth ="2005/10";
date =input(ObservationMonth,anydtdte.);
put date = date9.;
run;
Yet another option is to modify the input to enable use of the YYMMDDw. informat:
data _null_;
ObservationMonth ="2005/10";
date =input(ObservationMonth!!'/01', YYMMDD10.);
put date = date9.;
run;
you're fantastic, guys! Thank you so much, with a "set" statement it works fine!
I have a variable that was entered as 31.01.2002 for all entries, and is a character. I would like to put it in numerical form with date9. .
I have tried the below:
date=input(oldway, 10.);
date=input(oldway, date9.);
put date=ddmmyy10.;
date=input(compress(oldway,'.'),10.);
date = INPUT(compress(oldway),date9.);
format date date9.;
run;
I have also tried combinations of the above and to no avail.
Any ideas for forward motion?
Kind Regards!!
You can't input your date using the date9. informat as your string variable isn't in that format. You can use ddmmyy10., though, and that also takes care of the . characters.
data have;
input old $10.;
cards;
31.01.2014
28.02.2014
01.01.2015
;
run;
data want;
set have;
new = input(old, ddmmyy10.);
format new date9.;
run;
try this:
data _null_;
date ="31.01.2014";
date=compress(date,".");
new_date=input(date,ddmmyy8.);
format new_date date9.;
put new_date;
run;