I have a variable that was entered as 31.01.2002 for all entries, and is a character. I would like to put it in numerical form with date9. .
I have tried the below:
date=input(oldway, 10.);
date=input(oldway, date9.);
put date=ddmmyy10.;
date=input(compress(oldway,'.'),10.);
date = INPUT(compress(oldway),date9.);
format date date9.;
run;
I have also tried combinations of the above and to no avail.
Any ideas for forward motion?
Kind Regards!!
You can't input your date using the date9. informat as your string variable isn't in that format. You can use ddmmyy10., though, and that also takes care of the . characters.
data have;
input old $10.;
cards;
31.01.2014
28.02.2014
01.01.2015
;
run;
data want;
set have;
new = input(old, ddmmyy10.);
format new date9.;
run;
try this:
data _null_;
date ="31.01.2014";
date=compress(date,".");
new_date=input(date,ddmmyy8.);
format new_date date9.;
put new_date;
run;
Related
Want to convert date = 01-SEP-2021 to date = 01SEP2021. I used this code to convert:
New date = input(compress(date,'-'),date9.);
But that didn't work. I also used substring to remove the parts of day month and year but seems this method is a bit lengthy.
If the type is numeric and SAS already displays it as a date then it's a formatting issue.
proc datasets lib=work nolist;
modify have;
format date date9.;
quit;
Otherwise, it must be a character and you have to convert it to a date and display it in date9. format.
data want;
date = '01-SEP-2021';
new_date = input(date, anydtdte.); *anydtdte. automatically reads a variety of date formats;
format new_date date9.;
run;
I have a SAS field where the datatype is number and format is date9.
It has a value like 30SEP2018.
How do I convert it to a SAS date so I can do date operations?
SAS dates are stored as number starting from 1/1/1960 and it starts form number = 0 and increases by 1 for every day. Your date is stored as number and then you get from proc contents and format is to display in the way you want.
data have;
input date:date9.;
format date date9.;
datalines;
30SEP2018
;
proc contents data=have;
run;
you can calculations on above date and gives you appropriate results as shown below
data want;
set have;
new_date= date+1;
new_date1= date-1;
format new_date new_date1 date9.;
run;
proc print; run;
In Base SAS, how do i convert a character Year (2018) to 01/01/2018 in date format?
data date;
length charyear $8.;
charyear='2018';
run;
In general, when constructing a date from date parts, you should use SAS MDY function. MDY(month,day,year) returns a numeric date, but you need to convert all arguments to numbers, before using the function.
data date;
length charyear $8.;
charyear='2018';
format numDate date9.;
numDate = mdy(1,1, input(charyear, best.));
run;
In your particular case it can be done even easier by using function INPUT with a corresponding date informat:
data date;
length charyear $8.;
charyear='2018';
format numDate date9.;
numDate = input("01JAN" || charyear, date9.);
run;
I have a table in SAS where in one column, the date is stored (e.g. "2005/10").
How do I have to convert this to a SAS data format?
Among many other tries, I tried this code:
data test;
format date YYMMS.;
date = input(ObservationMonth, YYMMS.);
put date=date9.;
run;
You could just use the anydtdte. informat.
data want;
format date yymms.;
text="2005/10";
date=input(text,anydtdte.);
put date;
run;
This informat detects most date formattings and converts the character-stored value to a SAS date.
One way is to use substr() and mdy() to extract the date components:
data _null_;
ObservationMonth ="2005/10";
date =mdy(substr(ObservationMonth,6,2),1,substr(ObservationMonth,1,4));
put date = date9.;
run;
Another option is to use the anydtdte informat (note that results may differ depending on your locale):
data _null_;
ObservationMonth ="2005/10";
date =input(ObservationMonth,anydtdte.);
put date = date9.;
run;
Yet another option is to modify the input to enable use of the YYMMDDw. informat:
data _null_;
ObservationMonth ="2005/10";
date =input(ObservationMonth!!'/01', YYMMDD10.);
put date = date9.;
run;
you're fantastic, guys! Thank you so much, with a "set" statement it works fine!
My datalines has 2 variables, date 1 and date 2 with corresponding format ddmmyy10. and mmddyy10.
data date;
input date1 ddmmyy10. date2 mmddyy10.;
datalines;
09/01/2015 01/09/2015
10/01/2015 01/10/2015
11/01/2015 01/11/2015
12/01/2015 01/12/2015
13/01/2015 01/13/2015
;
run;
I tried to add the code but still not work
infile datalines delimiter=' ';
The : (colon) format modifier enables you to use list input but also to specify an informat after a variable name, whether character or numeric. SAS reads until it encounters a blank column, the defined length of the variable (character only), or the end of the data line, whichever comes first.
Format Modifier
data date;
input date1: ddmmyy10. date2: mmddyy10.;
datalines;
09/01/2015 01/09/2015
10/01/2015 01/10/2015
11/01/2015 01/11/2015
12/01/2015 01/12/2015
13/01/2015 01/13/2015
;
run;
The reason why the code is not working is because you are using List input to read non-standard data without colon input modifier or informat statement.
For non-standard data(commas, dollar, date etc. -> Reading Raw data -> Kinds of Data ) or standard data of length greater than 8 byte using List input technique you would need to use either INFORMAT statement or colon modifier with INPUT statement.
1) Assign informat for the input variables using INFORMAT statement or ATTRIB statement
data date;
informat date1 ddmmyy10. date2 mmddyy10.;
input date1 date2;
format date1-date2 yymmdd10.;
datalines;
09/01/2015 01/09/2015
10/01/2015 01/10/2015
;
run;
2) Use Colon (:) input modifier
data date;
input date1: ddmmyy10. date2: mmddyy10.;
format date1-date2 yymmdd10.;
datalines;
09/01/2015 01/09/2015
10/01/2015 01/10/2015
;
run;