Apologies for this quite abstract title.
More clearly:
I have two classes Controler and Interface (hardware sense, unrelated to design pattern)
Both are abstract with some pure virtual methods and hence intended to be subclassed
I need each Controler created to be associated with an Interface object
Each Controler subclass only work with a subset of Interface subclasses (ControlerA + InterfaceA or ControlerB + InterfaceB but not ControlerA + InterfaceB)
Each Interface subclass has its own methods not inherited (this is why only one kind of Controler can use it)
The Controler base class need to call some method of the base class Interface
I try to pass an Interface objet to the Controler constructor, hence in my class definition the Interface attribute represents the abstract base class. But if my Controler subclass A need to call a specific method of the Interface A, an compilation error is raised as the Interface base class doesn't own this method.
The only workaround I found was to call dynamic_cast, but it obviously seems wrong.
Here are my Interface classes:
class Interface {
public:
Interface() {};
virtual void method() = 0;
};
class InterfaceA : public Interface {
public:
InterfaceA() : Interface() {};
void method() override { cout << "A overriding" << endl; }
void onlyA() { cout << "A only" << endl; }
};
class InterfaceB : public Interface {
public:
InterfaceB() : Interface() {};
void method() override { cout << "B overriding" << endl; }
void onlyB() { cout << "B only" << endl; }
};
Here are my Controler classes:
class Controler {
public:
Controler(Interface* i) : m_interface(i) {};
virtual void uniqueMethod() = 0;
void commonMethod() { m_interface->method(); }
Interface* m_interface;
};
class ControlerA : public Controler {
public:
ControlerA(InterfaceA* i) : Controler(i) {};
void uniqueMethod() override {dynamic_cast<InterfaceA *>(m_interface)->onlyA();}
};
class ControlerB : public Controler {
public:
ControlerB(InterfaceB* i) : Controler(i) {};
void uniqueMethod() override {dynamic_cast<InterfaceB *>(m_interface)->onlyB();}
};
And here is how I plan to use them:
auto ia = new InterfaceA();
auto ca = ControlerA(ia);
ca.commonMethod(); // Method defined in the base class
ca.uniqueMethod(); // Method defined in InterfaceA only
You can try it on Repl.it.
Is there any design pattern to solve this issue?
There is a problem indeed. There exists an invariant between the dynamic type of m_interface and the dynamic type of the object that implement Controler. But this invariant cannot be maintained by the Controler class. So the m_interface member is not a the right place.
The consequence is that you need to check at runtime that this member has the right type by using the dynamic_cast each time you call uniqueMethod. If the invariant is broken, the code will have UB because it would dereference a null pointer.
So this is not really a design pattern issue, but more fundamentally an object oriented programming recommendation: classes must ensure invariants.
class Controler {
public:
virtual void uniqueMethod() = 0;
virtual void commonMethod() = 0;
};
class ControlerA : public Controler {
public:
ControlerA(InterfaceA* i):m_interface{i} {
assert(dynamic_cast<InterfaceA*>(i)!=nullptr);
};
void uniqueMethod() override { m_interface->onlyA();}
void commonMethod() override { m_interface->method(); }
private: InterfaceA* m_interface;
};
class ControlerB : public Controler {
public:
ControlerB(InterfaceB* i):m_interface{i} {
assert(dynamic_cast<InterfaceB*>(i)!=nullptr);
};
void uniqueMethod() override { m_interface->onlyB();}
void commonMethod() override { m_interface->method(); }
private: InterfaceB* m_interface;
};
So now, it looks that we have a regular pattern, so this is where we can think about a more generic design:
template<class Inter,void(Inter::* OnlyFunc)()>
class ControlerImpl : public Controler {
public:
ControlerImpl(Inter* i):m_interface{i} {
assert(dynamic_cast<Inter*>(i)!=nullptr);
};
void uniqueMethod() override { (m_interface->*OnlyFunc)();}
void commonMethod() override { m_interface->method(); }
private: Inter* m_interface;
};
using ControlerA = ControlerImpl<InterfaceA,&InterfaceA::onlyA>;
using ControlerB = ControlerImpl<InterfaceB,&InterfaceB::onlyB>;
Related
I'm currently trying to wrap my head around the basics of C++ inheritance. Consider the following piece of code:
// Interfaces
class InterfaceBase
{
public:
virtual void SomeMethod() = 0;
};
class InterfaceInherited : public InterfaceBase
{
};
// Classes
class ClassBase : public InterfaceBase
{
public:
virtual void SomeMethod()
{
}
};
class ClassInherited : public ClassBase, public InterfaceInherited
{
};
int main()
{
ClassBase myBase; // OK
ClassInherited myInherited; // Error on this line
return 0;
}
Here I have two interfaces with an inheritance relationship. The same goes for the two classes which implement the interfaces.
This gives me the following compiler error:
C2259 'ClassInherited': cannot instantiate abstract class
It seems that the class ClassInherited does not inherit the implementation of SomeMethod from ClassBase. Thus it is abstract and cannot be instantiated.
How would I need to modify this simple example in order to let ClassInherited inherit all the implemented methods from ClassBase?
You are encountering a diamond problem.
The solution is to use virtual inheritance (Live), to ensure that only one copy of base class members are inherited by grand-childs:
// Interfaces
class InterfaceBase
{
public:
virtual void SomeMethod() = 0;
};
class InterfaceInherited : virtual public InterfaceBase
{
};
// Classes
class ClassBase : virtual public InterfaceBase
{
public:
virtual void SomeMethod()
{
}
};
class ClassInherited : public ClassBase, public InterfaceInherited
{
};
int main()
{
ClassBase myBase; // OK
ClassInherited myInherited; // OK
return 0;
}
I have class hierarchy as shown below. It's a simplified version of actual code.
class Base
{
public :
// user_define_type is a output parameter
virtual void Fill(user_define_type);
}
class A : public Base
{
public :
void Fill(user_define_type) override;
}
class B : public Base
{
public :
void Fill(user_define_type) override;
}
I am overriding Fill() method as I need different formatting in both derived classes. Now I have to write one more class deriving from "Base" as it has common functionality. Now my problem is that new class will have to implement Fill() that will operate on different user defined type. As I am returning base class pointer from factory so new Fill() has to be virtual in base but that means I have to add it's definition in older classes "A" and "B" and throw not supported exception from them. This is not a good design. Any better design you guys can suggest ? Thanks in advance.
I believe you need to create a common base class for your user_defined_types in order to achieve this. I also think this could be a good place to use the strategy pattern.
Basically, you create
class user_defined_type_base
{
...
}
class user_defined_type_derived : public user_defined_type_base
{
...
}
class DoSomething
{
private:
DoSomethingStrategy *strategy;
public:
DoSomething(DoSomethingStrategy *strategy) { this->strategy = strategy; }
void Fill(user_defined_type_base *type) { this->strategy->Fill(type); }
}
class DoSomethingStrategy
{
public:
virtual void Fill(user_defined_type_base *obj) = 0;
}
class DoSomethingStrategyA : public DoSomethingStrategy
{
public:
void Fill(user_defined_type_base *obj)
{
...
}
}
class DoSomethingStrategyB : public DoSomethingStrategy
{
public:
void Fill(user_defined_type_base *obj)
{
...
}
}
class DoSomethingStrategyC : public DoSomethingStrategy
{
public:
void Fill(user_defined_type_base *obj)
{
...
}
}
void main()
{
DoSomethingStrategy *strategy = new DoSomethingStragegyA();
DoSomething *dosomething = new DoSomething(strategy);
user_defined_type_base *type = new user_defined_type_base();
dosomething->Fill(type);
DoSomethingStrategy *strategyC = new DoSomethingStragegyC();
DoSomething *dosomethingC = new DoSomething(strategyC);
user_defined_type_base *typeC = new user_defined_type_derived();
dosomethingC->Fill(typeC);
}
Hi I am trying to implement an interface in C++. I want to be able to call a function from a class that could be implemented by various different classes. The approach I have tried fails since I cannot call the function with a pointer to the interface (abstract class). Here is the basic gist of the code I have tried:
Interface class:
class InterfaceClass{
virtual void handle() = 0;
};
Calling class:
CallingClass::CallingClass(InterfaceClass * owner){
this->owner = owner;
}
void CallingClass::doStuff(){
owner->handle();
}
Implementing classes:
class Class1 : public InterfaceClass {
public:
Class1();
void handle();
}
class Class2 : public InterfaceClass {
public:
Class2();
void handle();
}
each of the handle() functions in the implementing classes just prints out the class name. Each implementing class contains an object of the CallingClass which calls doStuff in a separate timer thread. I am trying to keep it so that the CallingClass doesnt need to know anything about the classes that implement the handle() function.
It fails since I cannot call the function of an abstract class. I expected this but cant figure a way around it. Any advise would be much appreciated! Let me know if any more information is needed.
Thanks
you were missing the public: keyword in the Interface class.
you need to remember that C++ class are by default private, so you should add public where it is needed.
this is a working example for you:
class InterfaceClass {
public:
virtual void handle() = 0;
};
class Calling{
public:
Calling(InterfaceClass * owner) {
this->owner = owner;
}
void doStuff() {
owner->handle();
}
~Calling() { delete owner; }
private :
InterfaceClass* owner;
};
class Class1 : public InterfaceClass {
public:
void handle() override
{
std::cout << "Class1"<<std::endl;
}
};
class Class2 : public InterfaceClass {
public:
void handle()
{
std::cout << "Class2" << std::endl;;
}
};
int main(int argc, char** argv)
{
Calling c1(new Class1());
c1.doStuff();
Calling c2(new Class2());
c2.doStuff();
}
Let a class hierarchy :
class Base { virtual ~Base() throw(); };
class DerivedA : public Base { };
class DerivedB : public Base { };
I would like to have some code specific to each of these derived classes. However that code also being specific to the application that makes use of this class hierarchy, I do not want to embbed this derived-class-specific code into these derived classes. To avoid doing so, I thought about writing free functions :
void DerivedASpecificWork( DerivedA da );
void DerivedBSpecificWork( DerivedB db );
However, when given an instance of a derived class through a reference/pointer to a Base, I do not have access to the actual type of the instance, and thus cannot call the proper Derived*SpecificWork() function.
I would like to know if there is nome kind of design pattern that would allow me to call a derived-class-specific function without knowing the actual type of the instance, i.e having the same mechanism as virtual functions provide, but without having these virtual functions that would require me to embbed application-specific code into that class hierarchy.
Actually, why I want to do that is to provide informations about an exception that occured within a natively implemented function called by a Lua script. Each exception carrying its own set of information, the way I want to represent the error within the script depends on the type of the exception. I could create a pure virtual method in the base class that would be implemented by derived classes, but this would require me to embbed Lua-related code into my exception hierarchy, which I do not want to do since the Lua is specific to one of the application using that exception hierarchy.
Also I cannot use C++11.
Thank you.
May be Brigde pattern can help you.
This pattern can be used when you want to avoid a permanent binding between an abstraction and it's implementation.
(I don't see your comment about your restriction in using c++11, but you can remove std::unique_ptr, std::move and override keyword)
class AppSpecificImp
{
public:
virtual void DoWork() = 0;
};
class Base
{
public:
virtual ~Base() throw();
virtual DoWork() = 0;
};
class DerivedA : public Base
{
public:
DerivedA(std::unique_ptr<AppSpecificImp> appImp)
: imp(std::move(appImp))
{
}
void DoWork() override
{
// DerivedA specific code
imp->DoWork();
}
private:
std::unique_ptr<AppSpecificImp> imp;
};
class DerivedB : public Base
{
public:
DerivedB(std::unique_ptr<AppSpecificImp> appImp)
: imp(std::move(appImp))
{
}
void DoWork() override
{
// DerivedB specific code
imp->DoWork();
}
private:
std::unique_ptr<AppSpecificImp> imp;
};
Edit to show Visitor pattern usage:
With visitor pattern you can do what you want but with more Effort.
class Visitor
{
public:
virtual void VisitDerivedA(DerivedA* object) = 0;
virtual void VisitDerivedB(DerivedB* object) = 0;
};
class Base
{
public:
virtual void Visit(Visitor* visitor) = 0;
};
class DerivedA : public Base
{
public:
virtual void Visit(Visitor* visitor)
{
visitor->VisitDerivedA(this);
}
};
class DerivedB : public Base
{
public:
virtual void Visit(Visitor* visitor)
{
visitor->VisitDerivedB(this);
}
};
class AppSpecificVisitor : public Visitor
{
public:
void VisitDerivedA(DerivedA* object)
{
// Do any work related to DerivedA class
}
void VisitDerivedB(DerivedB* object)
{
// Do any work related to DerivedB class
}
}
int main()
{
AppSpecificVisitor myVisitor;
Base* myBase = // any class in your hierarchy
myBase->Visit(&myVisitor);
}
As I said in comments with Visitor pattern you can add new functionally without changing the main hierarchy(Base->Derived types). You just define a new visitor implementation and write your logic for every class in main hierarchy. In your example you can pack app specific logic in an object and reference that in your derived objects that is an easier approach.
Why not using a new set of hierarchy for application specific implementation ?
class AppBase
{
public:
virtual ~AppBase() throw();
virtual void work_with_app() = 0;
};
class Base
{
public:
Base(AppBase& app) : m_app(app) {}
virtual ~Base() throw();
protected:
AppBase& m_app;
};
class DerivedA : public Base { DerivedA(AppBase& app) : Base(app) {} };
class DerivedB : public Base { DerivedA(AppBase& app) : Base(app) {} };
// Application specific implementation :
class AppLuaSpecific : public AppBase
{
public:
void work_with_app() { /* Lua app specific */ }
};
This way, your 1st hierarchy : Base, DerivedA, DerivedB can live without knowing anything about the app specific code implemented in AppLuaSpecific.
You can implement your own app-specific dispatch as follows (check it live on Coliru):
#include <iostream>
#include <typeinfo>
struct Base { virtual ~Base() {} };
struct DerivedA : public Base { };
struct DerivedB : public Base { };
namespace AppSpecific
{
template<class F>
void dispatch(const Base& b)
{
const std::type_info& t = typeid(b);
if ( t == typeid(DerivedA) )
F::doit(static_cast<const DerivedA&>(b));
else if ( t == typeid(DerivedB) )
F::doit(static_cast<const DerivedB&>(b));
}
struct Foo
{
static void doit(const DerivedA& da) { std::cout << "Foo(DerivedA)\n"; }
static void doit(const DerivedB& db) { std::cout << "Foo(DerivedB)\n"; }
};
struct Bar
{
static void doit(const DerivedA& da) { std::cout << "Bar(DerivedA)\n"; }
static void doit(const DerivedB& db) { std::cout << "Bar(DerivedB)\n"; }
};
} // namespace AppSpecific
int main()
{
DerivedA da;
DerivedB db;
Base& b1 = da;
Base& b2 = db;
AppSpecific::dispatch<AppSpecific::Foo>(b1);
AppSpecific::dispatch<AppSpecific::Foo>(b2);
AppSpecific::dispatch<AppSpecific::Bar>(b1);
AppSpecific::dispatch<AppSpecific::Bar>(b2);
}
I need help for an implementation that uses multiple inheritance of Interfaces...
There is an existing code whith an interface which has a lot of functions. The instances are created using a factory.
class IBig
{
// Lot of pure virtual functions
};
And his inplementation:
class CBig: public IBig
{
// Implementation
}
I Want to split the interface in multiple smaller interfaces, but it should stay compatible to the existing code for some time.
Here is a sample of what I tried to do:
class IBaseA
{
public:
virtual void DoA() = 0;
};
class IBaseB
{
public:
virtual void DoB() = 0;
};
// The same interface, now based on multiple smaller interfaces
class IBig : public IBaseA, public IBaseB
{
};
class CBaseA: public IBaseA
{
public:
virtual void DoA()
{
printf("DoA\n");
}
};
class CBaseB: public IBaseB
{
public:
virtual void DoB()
{
printf("DoB\n");
}
};
// Inherit from base classes where the implementation is, and from IBig as
// the instance of CBig is returned as IBig.
class CBig: public CBaseA, public CBaseB, public IBig
{
};
The problem here is that the class CBig cannot be instanciated. The compiler says the functions DoA and DoB are pure virtual, even if they are inplemented in CBaseA and CBaseB. What should I do if i don't want to implement again the functions, just to call the function of the base class ?
NB: I know the design is ugly, but this is only temporary until the big interface can be replaced, and.... I want to understand ! ;-)
Thanks in advance !
Here we should use virtual inheritance. This feature assures that there is only one instance of your virtually-inherited base class when you instantiate a subclass. For your example, this would look like:
#include <cstdio>
class IBaseA
{
public:
virtual void DoA() = 0;
};
class IBaseB
{
public:
virtual void DoB() = 0;
};
// The same interface, now based on multiple smaller interfaces
class IBig : virtual public IBaseA, virtual public IBaseB
// ^ ^
{
};
class CBaseA: virtual public IBaseA
// ^
{
public:
virtual void DoA()
{
printf("DoA\n");
}
};
class CBaseB: virtual public IBaseB
// ^
{
public:
virtual void DoB()
{
printf("DoB\n");
}
};
// Inherit from base classes where the implementation is, and from IBig as
// the instance of CBig is returned as IBig.
class CBig: public CBaseA, public CBaseB, public IBig
{
};
int main()
{
CBig cb;
}
The above changes ensure that there are not extra declarations of DoA and DoB created when you inherit from IBaseA and IBaseB multiple times.