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How do read two first letters and delete line?
This code remove all line where is GG
.*gg.*.*.*
ggang - delete
gangg -undelete
Tested in notepad++:
find: ^(gg.*)$
replace: (leave blank)
in:
ggang
gangg
out:
gangg
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I want to receive in example regex match only 17 and 20 (skip 3 match only two match)
Depending on what you want to do, this one can be a good solution
[0-9]{2}(?!$)
It matches the groups of 2 digits not at the end of a line !
You can also try : ([0-9]{2})\s[A-z]+\s([0-9]{2}) if you want only 2 groups
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I have the data as follows in txt:
136.40.226.97|ubnt|ubnt|
138.197.81.94|listd|54e172662|
138.68.254.243|wordpress|wordpress|
139.162.55.12|public|public|
139.60.58.136|system|OkwKcECs8qJP2Z|
I want to convert it to this:
|ubnt|ubnt|136.40.226.97
|listd|54e172662|138.197.81.94
|wordpress|wordpress|138.68.254.243
|public|public|139.162.55.12
|system|OkwKcECs8qJP2Z|139.60.58.136
In Find and Replace window Ctrl+H change Search Mode to Regular expression and set:
Find what: (\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3})(.*)
Replace with: (\2)(\1)
This will find too groups: IP(1), rest of line(2), then Replace writes them in inverted order.
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I need help with a really simple regex find/replace command for Eclipse. It'd be great if you could provide me with something to try.
I need to replace all occurrences of the text typeSingleton(*) ), with typeSet({ * } ).
Assume that inside brackets you may have letters, brackets, spaces, then:
Find: typeSingleton\(([a-z ]+(\([a-z ]+\))? ?)\)
Replace: typeSet({$1})
EDIT
Demo: https://regex101.com/r/dD0wK0/1
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I have File and I want to replace fix character * : ~ with # using regex but, it should not replace(ignore) B~~ word because, it need to remain as it is. Anybody have idea for that?
Input :
ABCHKLJNKL*dskjnsdfkdsmflkmdls
MLKMLKMLKMLKMLKMMML
zlmlkmm:skjnjnskfjnkjsdnkfjnkdjs
B~~KJNNKJNJNKKJNKJNFKKJNJNK
Output Should be :
ABCHKLJNKL#dskjnsdfkdsmflkmdls
MLKMLKMLKMLKMLKMMML
zlmlkmm#skjnjnskfjnkjsdnkfjnkdjs
B~~KJNNKJNJNKKJNKJNFKKJNJNK
Please provide regex because i want to done with one step.
Thanks
[*:]|(?<!B[~])[~](?![~])
Try this.This should do it.See demo.Replace by #.
https://regex101.com/r/tX2bH4/66
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How do you find the first word after a string literal via regex?
I.e.
I want to extract "DAQJ7PS" from the line:
ERROR service.PostService - Failed to save post DAQJ7PS
/ERROR service\.PostService - Failed to save post (.+)/
will give you the result in the first capturing group. This can be tuned if you have more specific requirements.