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How do you find the first word after a string literal via regex?
I.e.
I want to extract "DAQJ7PS" from the line:
ERROR service.PostService - Failed to save post DAQJ7PS
/ERROR service\.PostService - Failed to save post (.+)/
will give you the result in the first capturing group. This can be tuned if you have more specific requirements.
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I want to receive in example regex match only 17 and 20 (skip 3 match only two match)
Depending on what you want to do, this one can be a good solution
[0-9]{2}(?!$)
It matches the groups of 2 digits not at the end of a line !
You can also try : ([0-9]{2})\s[A-z]+\s([0-9]{2}) if you want only 2 groups
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does anyone know how to write the regex for this list of urls for workbox
/
/tracker/patientlist
/tracker/visitlist
/tracker/triage
i am new to regex
Assuming you want to match the root url /, or /tracker/*, try this:
/(tracker/\w+)?
Here is one way.(Not sure what other URI variations you may have, but this should do it). If the first part is always /tracker, then use Bohemian's answer.
(\/[a-zA-Z]+)
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How do read two first letters and delete line?
This code remove all line where is GG
.*gg.*.*.*
ggang - delete
gangg -undelete
Tested in notepad++:
find: ^(gg.*)$
replace: (leave blank)
in:
ggang
gangg
out:
gangg
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I have File and I want to replace fix character * : ~ with # using regex but, it should not replace(ignore) B~~ word because, it need to remain as it is. Anybody have idea for that?
Input :
ABCHKLJNKL*dskjnsdfkdsmflkmdls
MLKMLKMLKMLKMLKMMML
zlmlkmm:skjnjnskfjnkjsdnkfjnkdjs
B~~KJNNKJNJNKKJNKJNFKKJNJNK
Output Should be :
ABCHKLJNKL#dskjnsdfkdsmflkmdls
MLKMLKMLKMLKMLKMMML
zlmlkmm#skjnjnskfjnkjsdnkfjnkdjs
B~~KJNNKJNJNKKJNKJNFKKJNJNK
Please provide regex because i want to done with one step.
Thanks
[*:]|(?<!B[~])[~](?![~])
Try this.This should do it.See demo.Replace by #.
https://regex101.com/r/tX2bH4/66
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i want to parse the values between -. but for some data like 1st url contains -- so in that case i need to get the gap only and the next one i am able to get **camry** successfully by using *(site_data,'[^-]+',1,2)*. but i want to handle the gap as well.
U=Google--undefined|http://www.google.com/urlsa=t&rct=j&q=&esrc=s&frm=1&source=web&cd=2&ved=0CFMQFjAB&url=http://www.toyota.com/tundra/features.html&ei=-zwQUvOyGIXu2QWC7oGgBg&usg=AFQjCNFQKGcr2dbDeC-0zagtYdKFEfXXzQ&bvm=bv.50768961,d.aWc
U=Bing-camry-undefined|http://www.bing.com/searchq=camry&pc=MOZI&form=MOZSBR
Please help on this.
You can extract the string along with the hyphens, and then trim the hyphens.
trim('-' from regexp_substr(site_data,'-[^-]*-'))
Alternatively, you can also use regexp_replace function.
regexp_replace(site_data,'(-([^-]*)-)|(.)','\2')