I'm still pretty new to XSLT and I have the following XML which I need to remove the namespace. I also found the following XSLT which almost gets the job done with the exception that it will not retain the xmlns declaration.
XML:
<?xml version="1.0" encoding="UTF-8"?>
<etd_ms:thesis xmlns:etd_ms="http://www.ndltd.org/standards/metadata/etdms/1.0/"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.ndltd.org/standards/metadata/etdms/1.0/ http://www.ndltd.org/standards/metadata/etdms/1.0/etdms.xsd">
<etd_ms:title>Aspects of negritude in the works of two Harlem renaissance authors : Claude McKay and Langston Hughes</etd_ms:title>
<etd_ms:creator>Charles, Asselin</etd_ms:creator>
<etd_ms:subject/>
<etd_ms:publisher>Concordia University</etd_ms:publisher>
<etd_ms:contributor role="advisor">Butovsky, M</etd_ms:contributor>
<etd_ms:date>1980</etd_ms:date>
<etd_ms:type>Electronic Thesis or Dissertation</etd_ms:type>
<etd_ms:identifier>TC-QMG-1</etd_ms:identifier>
<etd_ms:format>text</etd_ms:format>
<etd_ms:identifier>https://spectrum.library.concordia.ca/1/1/MK49585.pdf</etd_ms:identifier>
<etd_ms:language>en</etd_ms:language>
<etd_ms:degree>
<etd_ms:name>M.A.</etd_ms:name>
<etd_ms:level>masters</etd_ms:level>
<etd_ms:discipline>Dept. of English</etd_ms:discipline>
<etd_ms:grantor>Concordia University</etd_ms:grantor>
</etd_ms:degree>
</etd_ms:thesis>
and here's the XSLT:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes" method="xml" encoding="utf-8" omit-xml-declaration="no"/>
<!-- Stylesheet to remove all namespaces from a document -->
<!-- NOTE: this will lead to attribute name clash, if an element contains
two attributes with same local name but different namespace prefix -->
<!-- Nodes that cannot have a namespace are copied as such -->
<!-- template to copy elements -->
<xsl:template match="*">
<xsl:element name="{local-name()}">
<xsl:apply-templates select="#* | node()"/>
</xsl:element>
</xsl:template>
<!-- template to copy attributes -->
<xsl:template match="#*">
<xsl:attribute name="{local-name()}">
<xsl:value-of select="."/>
</xsl:attribute>
</xsl:template>
<!-- template to copy the rest of the nodes -->
<xsl:template match="comment() | text() | processing-instruction()">
<xsl:copy/>
</xsl:template>
</xsl:stylesheet>
The results is the following:
<?xml version="1.0" encoding="UTF-8"?>
<thesis xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.ndltd.org/standards/metadata/etdms/1.0/ http://www.ndltd.org/standards/metadata/etdms/1.0/etdms.xsd">
<title>Aspects of negritude in the works of two Harlem renaissance authors : Claude McKay and Langston Hughes</title>
<creator>Charles, Asselin</creator>
<subject/>
<publisher>Concordia University</publisher>
<contributor role="advisor">Butovsky, M</contributor>
<date>1980</date>
<type>Electronic Thesis or Dissertation</type>
<identifier>TC-QMG-1</identifier>
<format>text</format>
<identifier>https://spectrum.library.concordia.ca/1/1/MK49585.pdf</identifier>
<language>en</language>
<degree>
<name>M.A.</name>
<level>masters</level>
<discipline>Dept. of English</discipline>
<grantor>Concordia University</grantor>
</degree>
</thesis>
It's almost there, with the exception that I need to keep the xmlns declaration, so ultimatly the root element should be something like:
<thesis xmlns="http://www.ndltd.org/standards/metadata/etdms/1.0/"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.ndltd.org/standards/metadata/etdms/1.0/ http://www.ndltd.org/standards/metadata/etdms/1.0/etdms.xsd">
Can someone help me resolving this issue? Thanks.
Change
<xsl:element name="{local-name()}">
to
<xsl:element name="{local-name()}" namespace="http://www.ndltd.org/standards/metadata/etdms/1.0/">
Related
we have a requirement to remove the prefix <dsr:LineItemItems>6</dsr:LineItemItems> in XML content, when we used the below code it was successfully removing the prefix "dsr" from xml elements but we need the xmlns namespaces in the output xml payload which is present in the POSLog tag.
Need all the namespaces/content present in the input first tag <POSLog> in the output xml too.
Input xml:
<?xml version="1.0" encoding="utf-8"?>
<POSLog xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:dsr="http://www.dsr.com/rsd/tlog/markup/poslog" xsi:schemaLocation="http://www.nrf-arts.org/IXRetail/namespace/ POSLog.xsd http://www.dsr.com/rsd/tlog/markup/poslog DSRPOSLog.xsd" xmlns="http://www.nrf-arts.org/IXRetail/namespace/">
<dsr:LineItemItems>6</dsr:LineItemItems>
XSL code:
<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:dsr="http://www.dsr.com/rsd/tlog/markup/poslog" xsi:schemaLocation="http://www.nrf-arts.org/IXRetail/namespace/ POSLog.xsd
http://www.dsr.com/rsd/tlog/markup/poslog DSRPOSLog.xsd" xmlns="http://www.nrf-arts.org/IXRetail/namespace/" >
<xsl:output method="xml" version="1.0" encoding="UTF-8" />
<xsl:template match="*">
<xsl:element name="{local-name()}" >
<xsl:apply-templates select="#*|node()"/>
</xsl:element>
</xsl:template>
<xsl:template match="#*">
<xsl:attribute name="{local-name()}">
<xsl:value-of select="."/>
</xsl:attribute>
</xsl:template>
</xsl:stylesheet>
Output xml by the xsl code:
<?xml version="1.0" encoding="UTF-8"?>
<POSLog schemaLocation="http://www.nrf-arts.org/IXRetail/namespace/ POSLog.xsd http://www.dsr.com/rsd/tlog/markup/poslog DSRPOSLog.xsd">
<LineItemItems>6</LineItemItems>
Need the output as below with all the namespaces without change in the First Tag
<?xml version="1.0" encoding="UTF-8"?>
<POSLog xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:dsr="http://www.dsr.com/rsd/tlog/markup/poslog" xsi:schemaLocation="http://www.nrf-arts.org/IXRetail/namespace/ POSLog.xsd http://www.dsr.com/rsd/tlog/markup/poslog DSRPOSLog.xsd" xmlns="http://www.nrf-arts.org/IXRetail/namespace/">
<LineItemItems>6</LineItemItems>
Thanks,
Ravi
Add an extra template to match the document element and copy it, rather than reconstructing a new element without namespaces. And in the existing template matching elements, add an attribute to indicate the namespace in the xsl:element constructor.
The following stylesheet ensures that all elements are bound to the namespace http://www.nrf-arts.org/IXRetail/namespace/ and that the namespace prefix dsr is retained:
<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:dsr="http://www.dsr.com/rsd/tlog/markup/poslog" xsi:schemaLocation="http://www.nrf-arts.org/IXRetail/namespace/ POSLog.xsd
http://www.dsr.com/rsd/tlog/markup/poslog DSRPOSLog.xsd" >
<xsl:output method="xml" version="1.0" encoding="UTF-8" />
<!-- copy the document element, preserving it's namespaces -->
<xsl:template match="/*">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<!--create elements using the local-name, but bound to the desired namespace -->
<xsl:template match="*">
<xsl:element name="{local-name()}" namespace="http://www.nrf-arts.org/IXRetail/namespace/" >
<xsl:apply-templates select="#*|node()"/>
</xsl:element>
</xsl:template>
<xsl:template match="#*">
<xsl:attribute name="{local-name()}">
<xsl:value-of select="."/>
</xsl:attribute>
</xsl:template>
</xsl:stylesheet>
There are three ways of creating an element in the result tree, and they differ in how they handle namespaces:
xsl:element creates an element with no namespaces other than those used in the element name and in the names of its attributes
xsl:copy copies all the namespaces present on the source element you are copying whether or not they are actually used
a literal result element (e.g. <POSLog>) copies all the namespaces that are in scope for the element in the stylesheet, other than namespaces excluded using exclude-result-prefixes
So you want to create the outermost element of your result document using either xsl:copy or a literal result element, not using xsl:element.
The other problem you have is that you have renamed xsi:schemaLocation as schemaLocation. That happened because you used <xsl:attribute name="{local-name()}"/>. It would be better here to simply use xsl:copy-of to copy the attribute.
This question already has answers here:
XSLT with XML source that has a default namespace set to xmlns
(3 answers)
Closed 4 years ago.
I am new to XSLT transformation. I have namepace mapping issue in my output xml.
The input XML is
<m:class xmlns:m="http://www.NotRequirednamespace.com">
<queryDetails>hello</queryDetails>
</m:class>
My XSLT is look like
<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xpath-default-namespace="http://www.neededNamespace.com" xmlns:t="http://www.NotRequirednamespace.com" exclude-result-prefixes="t">
<xsl:output indent="yes" method="xml" encoding="utf-8" omit-xml-declaration="yes"/>
<!-- Stylesheet to remove all namespaces from a document -->
<!-- NOTE: this will lead to attribute name clash, if an element contains
two attributes with same local name but different namespace prefix -->
<!-- Nodes that cannot have a namespace are copied as such -->
<xsl:template match="/">
<school xmlns="http://www.neededNamespace.com">
<xsl:apply-templates/>
</school>
</xsl:template>
<!-- template to copy elements -->
<xsl:template match="*">
<xsl:element name="{local-name()}">
<xsl:apply-templates select="#* | node()"/>
</xsl:element>
</xsl:template>
<!-- template to copy attributes -->
<xsl:template match="#*">
<xsl:attribute name="{local-name()}">
<xsl:value-of select="."/>
</xsl:attribute>
</xsl:template>
<!-- template to copy the rest of the nodes -->
<xsl:template match="comment() | text() | processing-instruction()">
<xsl:copy/>
</xsl:template>
</xsl:stylesheet>
The output XML is
<school xmlns="http://www.neededNamespace.com">
<class xmlns="">
<queryDetails>hello</queryDetails>
</class>
</school>
But I dont want the name default namespace (xmlns="") in the element class. I like to specify the default namespace for the class element as "http://www.neededNamespace.com". So that I need the output xml as follows.
<school xmlns="http://www.neededNamespace.com">
<class>
<queryDetails>hello</queryDetails>
</class>
</school>
I have tried all the options i know. Can you help in this. Thanks in advance.
Do you really need all that code? Or are you just using this as an incantation, in the hope it will somehow appease the evil spirits? Like what does xpath-default-namespace do in an XSLT 1.0 stylesheet? (Answer: either nothing, or produce a fatal error - depending on how tolerant your processor is).
Now, if your XML example is representative, then all you need to do is:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns="http://www.neededNamespace.com">
<xsl:output method="xml" version="1.0" encoding="utf-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/">
<school>
<xsl:apply-templates/>
</school>
</xsl:template>
<xsl:template match="*">
<xsl:element name="{local-name()}">
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
What this does is:
Create a new root element named <school>;
Create a new element for each existing element, and name it with the local name of the existing element.
Since the stylesheet contains a declaration of a default namespace, ALL newly created elements (in both #1 and #2 above) will be placed in that namespace.
Since your input does not include any attributes, that should be all the code that's required.
In case you worry they may add some attributes in the future that you wish to pass to the output, just change the second template to:
<xsl:template match="*">
<xsl:element name="{local-name()}">
<xsl:copy-of select="#*"/>
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
This assumes the attributes will be in no namespace - and that's a very reasonable assumption. Attributes do not inherit their parent's namespace, and very rarely do you see authors place attributes in namespaces explicitly. Only if you really need to anticipate such possibility do you need additional code to handle the attributes.
So you don't want to remove the namespace of the "class" element, you want to change it. Use the "namespace" attribute of the xsl:element node.
Instead of
<xsl:element name="{local-name()}">
you want
<xsl:element name="{local-name()}" namespace="http://www.neededNamespace.com">
I need to make certain modifications to my XML input, depending on certain conditions. I am using XSLT 1.0.
the value of the message_type element (child element of m_cotrol) should be changed
A new element message_status should be added (as a child of the m_control element).
These changes are reflected in the expected output XML. With my current XSLT code, I am only able to achieve the second requirement.
Input XML:
<?xml version="1.0"?>
<message xmlns="http://www.origoservices.com" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<m_control>
<control_timestamp>2013-04-12T09:24:38.902</control_timestamp>
<message_id>a50ec030-72ab</message_id>
<retry_number>0</retry_number>
<message_type>Request</message_type>
<message_version>test.XSD</message_version>
<expected_response_type>synchronous</expected_response_type>
<initiator_id>FST</initiator_id>
<initiator_orchestration_id>1637280</initiator_orchestration_id>
<responder_id>mycomp</responder_id>
</m_control>
<m_content>
<b_control>
<service_provider_reference_number>650971</service_provider_reference_number>
<intermediary_case_reference_number>Sample1</intermediary_case_reference_number>
<quote_type>Comparison</quote_type>
<quote_or_print>Print</quote_or_print>
<message_version_number>3.7</message_version_number>
<submission_date>0001-04-12</submission_date>
</b_control>
</m_content>
</message>
Expected Output:
<message xmlns="http://www.origoservices.com" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<m_control>
<control_timestamp>2013-04-12T09:24:38.902</control_timestamp>
<message_id>a50ec030-72ab</message_id>
<retry_number>0</retry_number>
<message_type>Response</message_type>
<message_version>test.XSD</message_version>
<expected_response_type>synchronous</expected_response_type>
<initiator_id>FST</initiator_id>
<initiator_orchestration_id>1637280</initiator_orchestration_id>
<responder_id>mycomp</responder_id>
<message_status>User not allowed access</message_status>
</m_control>
<m_content>
<b_control>
<service_provider_reference_number>650971</service_provider_reference_number>
<intermediary_case_reference_number>Sample1</intermediary_case_reference_number>
<quote_type>Comparison</quote_type>
<quote_or_print>Print</quote_or_print>
<message_version_number>3.7</message_version_number>
<submission_date>0001-04-12</submission_date>
<quote_response_status>Error</quote_response_status>
<quote_error_note>
<reason>[Error] Check if the User has access to the requested service</reason>
</quote_error_note>
</b_control>
</m_content>
</message>
XSLT code: Based on the value of DataPower variable (var://service/error-message), I need the expected output.
<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:dp="http://www.datapower.com/extensions" version="1.0" extension-element-prefixes="dp" exclude-result-prefixes="dp">
<xsl:output method="xml" encoding="UTF-8"/>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="//*[contains(name(),'m_control')]">
<xsl:choose>
<xsl:when test="dp:variable('var://service/error-message') = 'not present'">
<m_control xmlns="http://www.origoservices.com">
<xsl:apply-templates select="#* | *"/>
<message_status>User not recognized</message_status>
</m_control>
</xsl:when>
</xsl:choose>
</xsl:template>
<xsl:template match="//*[contains(name(),'b_control')]">
<xsl:choose>
<xsl:when test="dp:variable('var://service/error-subcode')='0x01d30002'">
<b_control xmlns="http://www.origoservices.com">
<xsl:apply-templates select="#* | *"/>
<quote_response_status>Error</quote_response_status>
<quote_error_note>
<reason>[Error] Check if the User has access to the requested service</reason>
</quote_error_note>
</b_control>
</xsl:when>
</xsl:choose>
</xsl:template>
</xsl:stylesheet>
The following stylesheet meets both of your requirements. It does a common identity transform (which your XSLT does, too) with exceptions.
Note that I have not taken into consideration any changes that are performed by your stylesheet but not listed as a requirement (i.e. changing quote_error_note and quote_response_status).
This line:
<xsl:template match="text()[parent::ori:message_type]">
meets your first requirement, the one you were unable to code. It matches the text content of message_type and outputs "Response" instead.
But this solution differs from yours in another way: it does not match elements along the lines of:
<xsl:template match="//*[contains(name(),'m_control')]">
Rather, their correct namespace is identified:
<xsl:template match="ori:m_control">
Now, what's the difference? Your way of describing the template match allows elements of any namespace to be matched. This might not be a problem in your case (no conflicting namespaces) but it could be one in general.
Full stylesheet
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:ori="http://www.origoservices.com"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
exclude-result-prefixes="ori xsi">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="ori:m_control">
<xsl:copy>
<xsl:apply-templates/>
<message_status>
<xsl:text>User not allowed access</xsl:text>
</message_status>
</xsl:copy>
</xsl:template>
<xsl:template match="text()[parent::ori:message_type]">
<xsl:text>Response</xsl:text>
</xsl:template>
</xsl:stylesheet>
The requirement is to find the duplicate element(BaseName) in XML and marked the parent element(Account) with isDuplicate attribute. The XSL is working correctly when the input XML RootElement has no namespaces. When the root element has namespace then I get empty object. I am not sure why the namespace is causing XSL to generate empty output. Any help to get the right output would be greatly appreciated.`
Input XML WITH NAMESPACE
<?xml version="1.0"?>
<objects xmlns="urn:s.sexmaple.com" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<Account>
<Id>001A00F</Id>
<RecordTypeId>012A00</RecordTypeId>
<BaseName>EFGH</BaseName>
</Account>
<Account>
<Id>001A0</Id>
<RecordTypeId>012A0</RecordTypeId>
<BaseName>ABCD</BaseName>
</Account>
<Account>
<Id>001A</Id>
<RecordTypeId>012A</RecordTypeId>
<BaseName>ABCD</BaseName>
</Account>
</objects>
XSL
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
<xsl:output method="xml"
version="1.0"
encoding="UTF-8"
indent="yes"/>
<xsl:strip-space elements="*" />
<xsl:template match="node()|#*">
<xsl:copy copy-namespaces="no">
<xsl:apply-templates select="node()|#*" />
</xsl:copy>
</xsl:template>
<xsl:template match="/">
<xsl:variable name="Accounts">
<objects>
<xsl:for-each select="//Account">
<xsl:sort select="BaseName" />
<xsl:apply-templates select="." />
</xsl:for-each>
</objects>
</xsl:variable>
<xsl:variable name="unqentity">
<objects>
<xsl:for-each select="$Accounts/objects/Account">
<xsl:choose>
<xsl:when test="not(following-sibling::Account/BaseName=./BaseName) and not(preceding-sibling::Account/BaseName=./BaseName) ">
<xsl:copy-of select="." />
</xsl:when>
<xsl:otherwise>
<Account>
<xsl:attribute name="isDuplicate">yes</xsl:attribute>
<xsl:for-each select="child::*">
<xsl:element name="{name()}">
<xsl:copy-of select="#*|node()" />
</xsl:element>
</xsl:for-each>
</Account>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
</objects>
</xsl:variable>
<xsl:copy-of select="$unqentity" />
</xsl:template>
</xsl:stylesheet>
Output XML WHEN INPUT XML HAS NAMESPACE
<?xml version="1.0" encoding="UTF-8"?>
<objects/>
Output XML when Input has no Namespaces
<?xml version="1.0" encoding="UTF-8"?>
<objects>
<Account>
<Id>001A00F</Id>
<RecordTypeId>012A00</RecordTypeId>
<BaseName>EFGH</BaseName>
</Account>
<Account isDuplicate="yes">
<Id>001A0</Id>
<RecordTypeId>012A0</RecordTypeId>
<BaseName>ABCD</BaseName>
</Account>
<Account isDuplicate="yes">
<Id>001A</Id>
<RecordTypeId>012A</RecordTypeId>
<BaseName>ABCD</BaseName>
</Account>
</objects>
When you have a namespace, it means the element within the namespace is not the same as an element without a namespace (or indeed an element in a different name space).
This means when you do this in your XSLT...
<xsl:for-each select="//Account">
You are looking for an Account element with no namespace, and so it will not match the Account element in your source XML, which is in the amusingly titled "urn:s.sexmaple.com" (which I suspect is a misspelling)
As you are using XSLT2.0 though, there is a simple way to get around this, by specifying a default namespace for any xpath expressions, using the xpath-default-namespace. Normally, this may be enough, but you have slightly complicated matters by creating new elements within a variable, which you then later try to select.
<xsl:for-each select="$Accounts/objects/Account">
This means when you create the objects and Account elements in the $Accounts variable, they will need to be part of the namespace too.
To cut to the chase, this is what your xsl:stylesheet element needs to look like
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"
xmlns="urn:s.sexmaple.com"
xpath-default-namespace="urn:s.sexmaple.com">
So, the xpath-default-namespace="urn:s.sexmaple.com" is used to match elements in your source XML, whilst the xmlns="urn:s.sexmaple.com" is used to ensure the elements you create in the variable have this namespace and can be matched later on.
Having said all that, you have rather over-complicated your whole XSLT. Are you simply trying to add an IsDuplicate attribute to Account elements with the same BaseName? Well, create a key to look up duplicates, like so
<xsl:key name="account" match="Account" use="BaseName" />
Then you can look up duplicates like so:
<xsl:if test="key('account', BaseName)[2]">
<xsl:attribute name="isDuplicate">Yes</xsl:attribute>
</xsl:if>
Try this XSLT, which should give the same results
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xpath-default-namespace="urn:s.sexmaple.com">
<xsl:output method="xml" indent="yes"/>
<xsl:key name="account" match="Account" use="BaseName" />
<xsl:template match="Account">
<xsl:copy>
<xsl:if test="key('account', BaseName)[2]">
<xsl:attribute name="isDuplicate">Yes</xsl:attribute>
</xsl:if>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Note how this only needs to use xpath-default-namespace as it is not creating whole new elements, just copying existing ones (which get their namespace copied across too).
The reason your input XML without a namespace works were the one with a namespace doesn't, isn't because of the input XML, but because of the XSLT stylesheet.
When your XML file has a default namespace, that namespace will need to be declared in the stylesheet itself.
For example, with the following XML:
<test xmlns="test.xml.schema">
<element>Content</element>
</test>
When I apply the following XSLT:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
<xsl:template match="/">
<out>
<namespace>None</namespace>
<xsl:apply-templates />
</out>
</xsl:template>
<xsl:template match="test">
<test out="True">hello</test>
</xsl:template>
<xsl:template match="*"/>
</xsl:stylesheet>
The output is just:
<out><namespace>None</namespace></out>
The <xsl:template match="test"> can't match on the test element in the input xml, as it is actually test.xml.schema:test while the match in the stylesheet, with no namespace is actually :test. Thus no match is possible.
However, when we just add a namespace for the input document adn modify the template, like so:
<xsl:stylesheet xmlns:t="test.xml.schema" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
<xsl:template match="/">
<out>
<namespace>test.xml.schema</namespace>
<xsl:apply-templates />
</out>
</xsl:template>
<xsl:template match="t:test">
<test out="True">hello</test>
</xsl:template>
<xsl:template match="*"/>
</xsl:stylesheet>
The output becomes:
<out xmlns:t="test.xml.schema">
<namespace>test.xml.schema</namespace>
<test out="True">hello</test>
</out>
Its important to note that the namespace abbreviation in the input document and XSL don't need to be the same (eg. blank vs. "t"), but the namespaces themselfs do: (e.g both blank and "t" must be bound to test.xml.schema).
Also note, that using a default namespace in XSLT can be fraught with issues. So its best to use declared namespaces in XSLT.
I am using Microsoft's XSLT processor (1.0 only)
XML opening lines:
<?xml version="1.0" encoding="utf-8"?>
<Header xmlns="http:\\OldNameSpace.com">
<Detail>
Have the following XSLT template to pick up the <Header> element of my document and change its namespace.
<xsl:template match="*">
<xsl:element name="{name()}" xmlns="http:\\NewNameSpace.com">
<xsl:copy-of select="#*"/>
<xsl:apply-templates />
</xsl:element>
</xsl:template>
Which turns <Header xmlns="http:\\OldNameSpace.com"> Into <Header xmlns="http:\\NewNameSpace.com">
However I now need to add a second namespace to this so that I get the following output:
<Header xmlns="NewNameSpace.com" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
I have tried using:
<xsl:template match="*">
<xsl:element name="{name()}" xmlns="NewNameSpace.com" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<xsl:copy-of select="#*"/>
<xsl:apply-templates />
</xsl:element>
</xsl:template>
However I still only get the same output as the original XSLT template.
Can anyone enlighten to me as to why this is?
This transformation:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:old="http:\\OldNameSpace.com"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
exclude-result-prefixes="old xsi">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:param name="pNewNamespace" select="'http:\\NewNameSpace.com'"/>
<xsl:variable name="vXsi" select="document('')/*/namespace::*[name()='xsi']"/>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="old:*">
<xsl:element name="{local-name()}" namespace="{$pNewNamespace}">
<xsl:copy-of select="$vXsi"/>
<xsl:copy-of select="#*"/>
<xsl:apply-templates />
</xsl:element>
</xsl:template>
</xsl:stylesheet>
when applied on the following XML document:
<Header xmlns="http:\\OldNameSpace.com">
<Detail/>
</Header>
produces (what I guess is) the wanted, correct result:
<Header xmlns="http:\\NewNameSpace.com"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<Detail/>
</Header>
xsl:element (unlike literal result elements) does not copy all in scope namespaces to the result, just the namespace required for the element name 9either implicitly from its name or as specified with the namespace argument).
xslt2 adds an xsl:namespace instruction for this case but in xslt1 the easiest thing to do is
where
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
somewhere on an ancestor (eg on xsl:stylesheet.)
that will add a spurious xsi:tmp="" to the output but also then a namespace declaration,
If you actually need an attribute in this namespace eg xsi:type use that instead of tmp in the above and you are done. If you don't mind the extra, possibly invalid attribute in the xsi namespace you are done. Otherwise do the above in a variable, then use msxsl:node-set to query in to the variable and remove the spurious extra attribute.
If you know statically what namespace you want to generate, then the easiest way to do it in XSLT 1.0 is using xsl:copy-of. Create a source document <dummy xmlns:xsi="http://whatever"/>,
and then do <xsl:copy-of select="document('dummy.xml')/*/namespace::xsi"/> inside your call of xsl:element.