The "post" method in Django - django

Question

I created three files:
2- view.py :
class AddTeamView(View):
def get (self, request):
form = TeamForm()
context = {'form': form}
return render(request, 'add_team.html', context)
1-forms.py:
class TeamForm(forms.Form):
name = forms.CharField( max_length='100')
details = forms.CharField(max_length='250')
3-add_team.html:
-here there is another file called "base.html"
{% extends 'base.html' %}
{% block title %}
add team
{% endblock %}
{% block content %}
<form action="/add_team/" method="post">
{% csrf_token %}
{{ form }}
<input type="submit" value="Submit">
</form>
{% endblock %}
and i went to cmd and entered the server "python manage.py runserver"
it appeared on the browser:
"This page isn’t working
If the problem continues, contact the site owner.
HTTP ERROR 405"

Answer 1

A view can support methods like GET, POST, PUT, etc. given the corresponding method exists, so the view should have a .get(..), .post(..), .put(..), etc. function.
Here you only implemented a def get(self, request), and so POST requests are not allowed.
Based on the data you however show, this looks like the typical usecase of a CreateView [Django-doc]. The idea of these views is to encapsulate common scenario's such that by overriding a few attributes, one creates a view that is tailored towards a specific case, like:
class AddTeamView(CreateView):
form_class = TeamForm
template_name = 'add_team.html'
success_url = '/some/success_url'
The TeamForm should probably be a ModelForm, or at least a Form where you override the .save(..) function to properly save your data to the database, since right now, the form is not doing anything (well it receives the data, but after validation, it throws it away).
You might want to override the form_valid(..) function in case you do not want to redirect to the success_url. Furthermore it is very common that the success_url is resolved lazily from a given view name, like:
class AddTeamView(CreateView):
form_class = TeamForm
template_name = 'add_team.html'
success_url = reverse_lazy('view_name')

Answer 2

So, we don’t need to do a conditional to check if the request is a POST or if it’s a GET:
Your views.py:
from django.views.generic import View
class AddTeamView(View):
def post(self, request):
form = TeamForm(request.POST)
if form.is_valid():
new_tm = TeamModel(name=form.cleaned_data['name'], details=form.cleaned_data['details'])
new_tm.save()
return redirect('team_list')
return render(request, 'add_team.html', {'form': form})
def get(self, request):
form = TeamForm()
return render(request, 'add_team.html', {'form': form})
Hope this help you...