I'm importing some stuff from a google form into a google sheet. I want to delete the 'time' part of the timestamp, and copy it to another spreadsheet. I'm trying to use REGEXREPLACE to do this, but REGEXREPLACE is throwing a Formula parse error. It seems like REGEX is a different programming language altogether, so am I not using REGEXREPLACE correctly? Or am I not putting the arguments in correctly? (Btw, I'm using the more general expression so that I can use it for any "entries")
Here's the actual doc:
https://docs.google.com/spreadsheets/d/1YcHk5ylw3w7-V2AusaY2ktsyDEbtKzlIkFdS9quM8rE/edit?usp=sharing
Just replace single quotes ('') with double quotes ("").
To extract the date, you can use the INT-function
= INT(A2)
Then, formatted as Date, the time component is gone.
This works because the value of 1 represents 1 day of a DateTime. Time is a fraction of a day, for example, 0.33333 is 8 hours (1/3 of a day). The INT-function removes the decimal part and therefore only the date without time remains.
Related
I can't get my regexextract to work properly on google sheets.
I have imported data from one tab to another, like this:
=IMPORTRANGE("https://docs.google.com/spreadsheets/d/1o52z55YdNha4T_tCsKcHkrbA5sR4C1GyxYuBmMGGqu0/edit#gid=0"; "SheetName 1!A2:G103")
This works fine and what Im importing are percentages. Now, what I'm trying to do is to use regex to extract the numbers and omit the '%' symbol.
Normally I would type: =VALUE(REGEXEXTRACT(A11,"\D+"))but it doesn't work. However, if I use this exact Regex on any 'normal' cell (cell that is not an import from another tab), it works.
Is there a reasong regex doesn't work on an imported value?
Edit:
I have to send surveys to clients to know if they are satisfied with the provided service. Customers will choose between a few options. I do that using google forms by creating one form, and I link it to a google sheet where the answers from the form are pasted:
On the same sheet, I've added a tab where I import the data from the previous tab, by using importrange:
As you can see, it works. But I want to take out the letters and the '%' symbol. I just want the numbers so I can run an AVG function.
Is there a way to do that?
Thanks
You can try the following:
=REGEXEXTRACT(A11,"(\d+)")
Here is the sample input and output data using the previous function:
I think the problem is just related to the capital "D" since you need to use "d" instead.
You can check this other post as a reference:
What does \d+ mean in regular expression terms?
I've got this string:
{"success":true,"lowest_price":"1,49€","volume":"1,132","median_price":"1,49€"}
Now I want the value for median_price being displayed in a cell. HHow can I achive this with Regex?
With regex101.com I've came to this solution:
(?<=median_price":")\d{0,4},\d{2}€
But this one does not seem to be working in LibreOffice calc.
I'd advise to discard the Euro-symbol at first since you'd probably want to retrieve a value to calculate with, a numeric value. Therefor try:
Formula in B1:
=--REGEX(A1;".*median_price"":""(\d+(?:,\d+)?)€.*";"$1")
The double unary will transform the result from the 1st capture group into a number. I then went ahead and formatted the cell to display currency (Ctrl+Shift+4).
Note: I went with a slightly different regular pattern. But go with whatever works for your data I supppose.
Using this documentation for reference as well as url escaping certain characters, I have the following spreadsheet being read via Spreadsheet API and I'm trying to fetch specific rows only: https://docs.google.com/spreadsheets/d/1E5ROfSQAuQvqx7o61Au9eEd-6B7W35gfj3g7C6VhpGY/
If I try to filter by badgenumber I get zero results back
https://spreadsheets.google.com/feeds/list/1E5ROfSQAuQvqx7o61Au9eEd-6B7W35gfj3g7C6VhpGY/od6/public/values?sq=badgenumber%3D%2212345%22
<openSearch:totalResults>0</openSearch:totalResults>
sq=badgenumber="12345"
Your current parameter has double quotes. Try removing them. This query string worked for me:
?sq=badgenumber%3D12345
It also worked with the first and last name columns, which are clearly strings. So it seems like quotes are not required:
?sq=firstname%3DDan
?sq=lastname%3DKusanago
I write a regular expression to determine the date time.(the assumption are every month has 31 days and the year only contain 1900 to 2099)
^(((((0?[1-9]|1[012])[- /.\\](0?[1-9]|[12][0-9]|3[01]))|((0?[1-9]|(1|2)[0-9]|3[01])[- /.\\](0?[1-9]|[1][012])))([- /.\\](19|20)\d{2})))$
the format of date time are:
dd-mm-yyyy
mm-dd-yyyy
0m-0d-yyyy
0d-0m-yyyy
m-d-yyyy
d-m-yyyy
everything works fine except one thing; if the date time like 32-10-2010, in my thought it should not be recognized, but in regex tester 2-10-2010 has been recognized. I wonder if there is any way to modify the regular expression to prevent it.
After removing the / at the end, your RegEx is working for me. Here's a simple Sublime Text RegEx Find/Replace:
Here is the adjusted regex:
^(((((0?[1-9]|1[012])[- /.\\](0?[1-9]|[12][0-9]|3[01]))|((0?[1-9]|(1|2)[0-9]|3[01])[- /.\\](0?[1-9]|[1][012])))([- /.\\](19|20)\d{2})))$
But a better solution would be to use the languages native date functionality. I can't think of a language that doesn't have inbuilt methods for these sorts of things.
For example, using JavaScript's Date object, or some such...
Try this one:
^((3[01]|0?[1-9]|[1-2][0-9])-(1[012]|0?[1-9])|((1[012]|0?[1-9])-(3[01]|0?[1-9]|[1-2][0-9])))-(19|20)[0-9][0-9]$
I've already given such an answer here.
This match one invalid date : 29-02-1900 but is correct for any date between 01-01-1900 and 31-12-2099
The valid date format pattern in your case is:
/^\d{1,2}-\d{1,2}-\d{4}$/
With RegEx you can validate only format of date, not a correct date, because it's a bad practice! Months can be with different days, so good luck to write pattern that will be consider it.
If You want to validate is date correct, use other build-in functions in your language. For example checkdate for PHP or etc.
I'm looking for some RegEx for a custom pattern validation for a date field in InfoPath 2010. The accepted date format is m/d/yyyy or mm/dd/yyyy.
Attempt 1: (\d{1,2})/(\d{1,2})/(\d{4})
Attempt 2: (0?[1-9]|[12][0-9]|3[01])/(0?[1-9]|1[012])/((19|20)\d\d)
Had better luck with attempt 1, and not much at all with attempt 2.
I've been having some date and time validation issues with InfoPath 2010 and regex pattern matching can be a useful approach. A basic regex for validating m/d/yyyy (without catering for the specific days in a month and allowing for '0' prefix to month or day) would be something like the following (untested):
(0?[1-9]|1[012])\/(0?[1-9]|[12][0-9]|3[01])\/\d{4}
For something more sophisticated you could have a look at this SO answer.
However, in InfoPath the format of the date displayed can be completely different to the internal format and it is this internal format that your regex needs to match. If you drop a calculated field on your form and set it to the date field you want to validate you will see something like:
2013-05-08T12:13:14
So a regular expression (again ignoring specific days per month) required to validate the date component of this is:
\d{4}-(0[1-9]|1[012])-(0[1-9]|[12][0-9]|3[01])
But this won't match against the example date because it doesn't account for the time portion following the "T". So the trick is to use an expression to perform the match against the date substring only, e.g. in my case the following works:
not(xdUtil:Match(substring-before(dfs:dataFields/my:SharePointListItem_RW/my:DateCreated, "T"), "\d{4}-(0[1-9]|1[012])-(0[1-9]|[12][0-9]|3[01])"))
I tried the following and it worked:
\d{4}-\d{1,2}-\d{1,2}
As David pointed out the internal format might be different than the one displayed because when I tried \d\d/\d\d/\d\d\d\d it didn't work even though it caters to the displayed format of the date.
I had the same problem.
I used a rule on the date field to set another hidden text field to
string(datefield).
That always came out YYYY-MM-DD which is not too hard to create a regex against. I used this one.
((19|20)\d\d)-(0?[1-9]|1[012])-(0?[1-9]|[12][0-9]|3[01])
Remember that it has to be an XML Regex which has some restrictions.
Then I set another rule on the hidden field to set a Boolean IsDateValid.