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In my Django project I have 2 apps: core and books. In my core/urls.py, I use python include('books.url') to import the urls from books/urls.py, but I keep getting this error
I have been having this issue now that's bugging me. I had a workaround for it, though I really want to fix this.
core/urls.py
from django.contrib import admin
from django.urls import path
from django.conf.urls import include
# local
urlpatterns = [
path('/', include('books.urls')),
path('admin/', admin.site.urls),
]
books/urls.py
from django.contrib import admin
from django.urls import path
# local
from graphene_django.views import GraphQLView
from books.schema import schema
urlpatterns = [
path('graphql/', GraphQLView.as_view(graphiql=True, schema=schema)),
]
As suggested by SO, I have:
put books.urls inside the single quotes ' '
placed the path('/', include('books.urls')) on top
switch from from django.urls import include to
from django.conf.urls import include
The only workaround I have is place all urls into the core/urls.py, but that seems too chunky in the long run. I don't get why include works for everyone but not me!
Could you help me with this issue? Thank you!
Now GraphQLView is called with the URL 127.0.0.1:8000/graphql/, if you want to call it with the URL 127.0.0.1:8000/, you need to change your code:
core/urls.py
from django.contrib import admin
from django.urls import path
from django.conf.urls import include
# local
urlpatterns = [
path('/', include('books.urls')),
path('admin/', admin.site.urls),
]
books/urls.py
from django.contrib import admin
from django.urls import path
# local
from graphene_django.views import GraphQLView
from books.schema import schema
urlpatterns = [
path('/', GraphQLView.as_view(graphiql=True, schema=schema)),
]
[A similar question was asked, but not marked as answered, here. I considered continuing that thread but the website told me I'm only supposed to post an answer, so it seems I have to start a new topic.] I'm trying to follow this tutorial and I'm having problems with the URL mapping. Specifically with the part described as "So best practice is to create an “url.py” per application and to include it in our main projects url.py file". The relevant, I hope, part of the folder structure, which arose by following steps of the tutorial to the letter (if possible; usage of the 'patterns' module was impossible for example) and using Django 1.10 is the following:
myproject/
myapp/
urls.py
views.py
myproject/
urls.py
The myproject/urls.py is as follows:
from django.conf.urls import include, url
from django.contrib import admin
admin.autodiscover()
from myapp.views import hello
urlpatterns = [
url(r'^admin/', include(admin.site.urls)),
url(r'^myapp/', include(myapp.urls)),
]
The myapp/urls.py is as follows:
from django.conf.urls import include, url
urlpatterns = [
url(r'^hello/', myapp.views.hello),
]
The myapp/views.py is as follows:
from django.shortcuts import render
def hello(request):
return render(request, "hello.html", {})
However, running 'python manage.py runserver' results in the following error:
url(r'^myapp/', include(myapp.urls)),
NameError: name 'myapp' is not defined
INSTALLED_APPS in settings.py contains 'myapp'.
I'd be greatful for any tips on how to deal with the NameError! [Or any tips whatsoever that anyone might consider to be helpful!]
You have the NameError because you are referencing myapp in myproject/urls.py but haven't imported it.
The typical approach in Django is to use a string with include, which means that the import is not required.
url(r'^myapp/', include('myapp.urls')),
Since you have move the hello URL pattern into myapp/urls.py, you can remove from myapp.views import hello from myproject/urls.py.
Once you've made that change, you will get another NameError in myapp/urls.py. In this case, a common approach is to use a relative import for the app's views.
from django.conf.urls import url
from . import views
urlpatterns = [
url(r'^hello/$', views.hello),
]
Make sure you have imported following modules to urls.py.
from django.conf.urls import url
from django.contrib import admin
in django 2.0
use these
from django.contrib import admin
from django.urls import path
from first_app import views
urlpatterns = [
path('',views.index, name="index"),
path('admin/', admin.site.urls),
]
your app URL has to be a string
so, here is how the code should look like.
from django.conf.urls import include, url
from django.contrib import admin
admin.autodiscover()
from myapp.views import hello
urlpatterns = [
url(r'^admin/', include(admin.site.urls)),
url(r'^myapp/', include('myapp.urls')),
]
also, note that from python 2 upward the regular expression is not needed.
change URL to path
from django.conf.URLs import include path
from Django.contrib import admin
admin.autodiscover()
from myapp.views import hello
urlpatterns = [
path('^admin/', include(admin.site.urls)),
path('^myapp/', include('myapp.urls')),
]
In Django 2.1.7 here is the default urls .py file
from django.contrib import admin
from django.urls import path
urlpatterns = [
path('admin/', admin.site.urls),
]
so we need to add this line as well
from django.conf.urls import url
I have followed #Alasdair answers
You have the NameError because you are referencing myapp in myproject/urls.py but haven't imported it.
The typical approach in Django is to use a string with include, which
means that the import is not required.
Unfortunately, it didn't work out(I still got the name X is not defined error). Here is how I do it.
from django.contrib import admin
from django.urls import include
from django.conf.urls import url
from article import urls as article_users
from article import urls as user_urls
urlpatterns = [
path('admin/', admin.site.urls),
path('api/article/', include(article_users)),
path('api/user/', include(user_urls)),
]
Before using the URL command be sure to first import the url from the module Urls. Then try using the runserver.
from django.conf.urls import url
from django.contrib import admin
from django.urls import path
from django.conf.urls import url, patterns, include
from django.contrib import admin
from django.views.generic import TemplateView
from collection import *
#from collection.views import index,thing_detail,edit_thing
urlpatterns = [
url(r'^$', views.index, name='home'),
url(r'^about/$',TemplateView.as_view(template_name='about.html'),name='about'),
url(r'^contact/$',TemplateView.as_view(template_name='contact.html'),name='contact'),
url(r'^things/(?P<slug>[-\w]+)/$', 'views.thing_detail' ,name='thing_detail'),
url(r'^things/(?P<slug>[-\w]+)/edit/$', 'views.edit_thing',name='edit_thing'),
url(r'^admin/', include(admin.site.urls)),
]
After running the server there is an error "NameError: name 'views' is not defined"
Any help ??
You aren't importing your own views.
Try adding this to your urls.py:
from . import views
Or if you are importing them from a specific app, try replacing . with the app name
First thing I notice is the import *, realize that this will/can cause confusion for other Developers reading your scripts. Python has a methodology that insists that explicit is better than implicit. Which in this senario means you should be explicit about what you are importing.
from django.conf.urls import url, patterns, include
from django.contrib import admin
from django.views.generic import TemplateView
from collection import views as collection_views
urlpatterns = [
# Function Based Views
url(r'^$', collection_views.index, name='home'),
url(r'^things/(?P<slug>[-\w]+)/$', collection_views.thing_detail ,name='thing_detail'),
url(r'^things/(?P<slug>[-\w]+)/edit/$', collection_views.edit_thing,name='edit_thing'),
# Class Based Views
url(r'^about/$',TemplateView.as_view(template_name='about.html'),name='about'),
url(r'^contact/$',TemplateView.as_view(template_name='contact.html'),name='contact'),
# Admin
url(r'^admin/', include(admin.site.urls)),
]
Here instead of importing everything from collection I'm importing just your views and assigning them to a variable. Then using that variable in the URL definitions.
Be sure to import your views by
specifying its location and the methods inside the view to be imported on your urls.py.
from . collection import *
(line above means from current location find collection.py and import everything on it)
Happy coding!
hi I started to learn django newly. I want to upload a photo to my website. I did the other parts but in urls part I got error like this. What should I do?
from django.contrib import admin
from django.conf.urls import patterns, include, url
from django.conf import settings
from django.conf.urls.static import static
from bildirge.views import contact, home
from bildirge.urls import *
from django.conf.urls.static import static
from django.conf import settings
from django.contrib import admin
admin.autodiscover()
from bildirge.views import ProfileImageView, ProfileDetailView, ProfileImageIndexView
urlpatterns = patterns[
url(r'^contact/', contact),
url(r'^home/', home),
url(r'^$', ProfileImageIndexView.as_view(), name='home'),
url(r'^upload/', ProfileImageView.as_view(), name='profile_image_upload'),
url(
r'^uploaded/(?P<pk>\d+)/$', ProfileDetailView.as_view(),
name='profile_image'),
url(r'^admin/', include(admin.site.urls))
] + static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
And error is
TypeError: 'function' object has no attribute 'getitem'
thanks in advance
You've got a stray patterns before the opening of the list of URLs. Remove that.
I have a URL that does not work, for some reason. I get a 404, "'new' could not be found". Here is my urls.py:
url(r'^assets/new', 'watershed.views.new_asset', name='new_asset'),
There is a lot more in my urls.py but this is the ONLY one that contains the word, "assets" in it. If I change this url to anything/new, it works. If i misspell assets (assettss/new), it works. If I take out the /new and just use "assets", it also works fine. In my views folder I have an __ init __.py which contains the following:
from groups import *
from members import *
from leave_group import *
from payments import *
from assets import *
I also have an assets.py, which contains the following:
from django.contrib.auth.decorators import login_required
from watershed.models import Member, Org, OrgToMember, Asset
from django.shortcuts import render, redirect
from django.contrib.auth.models import User
def new_asset(request):
return render(request, 'asset_add.html')
I have no idea what Django does not like about assets/new.
UPDATE: Here is my full urls.py
from django.conf.urls import patterns, include, url
from django.contrib import admin
admin.autodiscover()
urlpatterns = patterns('',
# Examples:
url(r'^', include('outside.urls')),
url(r'^blog', include('blog.urls')),
url(r'^admin', include(admin.site.urls)),
url(r'^logout', 'watershed.views.logout', name='logout'),
url(r'^register/create', 'watershed.views.create', name='create'),
url(r'^register', 'watershed.views.register', name='register'),
url(r'^translog/(\d+)', 'watershed.views.translog', name='translog'),
url(r'^settings', 'watershed.views.settings', name='settings'),
# Group URIs
url(r'^groups/(\d+)/leave', 'watershed.views.leave_group', name='leave_group'),
url(r'^groups/(\d+)/dissolve', 'watershed.views.dissolve_group', name='dissolve_group'),
url(r'^groups/new', 'watershed.views.add_group_form', name='add_group_form'),
url(r'^groups/(\d+)', 'watershed.views.dashboard', name='dashboard'),
url(r'^groups/add', 'watershed.views.add_group', name='add_group'),
url(r'^groups', 'watershed.views.groups', name='groups'),
# Member URIs
url(r'^members/(\d+)', 'watershed.views.profile', name='profile'),
url(r'^member/login', 'watershed.views.login', name='login'),
# Payments URIs
url(r'^payments', 'watershed.views.payments', name='payments'),
# Asset URIs
url(r'^assets/new', 'watershed.views.new_asset', name='new_asset'),
You new_assets function containts in assets.py file, buy you import this function from views.py file. Use this:
url(r'^assets/new', 'path.to.assets.new_asset', name='new_asset'),
I figured it out. The problem is that my static url in my settings.py is - wait for it:
STATIC_URL = '/assets/'
So, clearly, one of those must change.