Suppose I have the following table:
id | car | sex | income
-------------------------------
1 | European | Male | 45000
2 | Japanese | Female | 48000
3 | American | Male | 53000
I would like to create the one below:
| id | car | choice | sex | income
--------------------------------------------
1.| 1 | European | 1 | Male | 45000
2.| 1 | American | 0 | Male | 45000
3.| 1 | Japanese | 0 | Male | 45000
| ----------------------------------------
4.| 2 | European | 0 | Female | 48000
5.| 2 | American | 0 | Female | 48000
6.| 2 | Japanese | 1 | Female | 48000
| ----------------------------------------
7.| 3 | European | 0 | Male | 53000
8.| 3 | American | 1 | Male | 53000
9.| 3 | Japanese | 0 | Male | 53000
I would like to fit an asclogit and according to Example 1 in Stata's Manual, this table format seems necessary. However, i have not found a way to create this easily.
You can use the cross command to generate all the possible combinations:
clear
input byte id str10 car str8 sex long income
1 "European" "Male" 45000
2 "Japanese" "Female" 48000
3 "American" "Male" 53000
end
generate choice = 0
save old, replace
keep id
save new, replace
use old
rename id =_0
cross using new
replace choice = 1 if id_0 == id
replace sex = cond(id == 2, "Female", "Male")
replace income = cond(id == 1, 45000, cond(id == 2, 48000, 53000))
Note that the use of the cond() function here is equivalent to:
replace sex = "Male" if id == 1
replace sex = "Female" if id == 2
replace sex = "Male" if id == 3
replace income = 45000 if id == 1
replace income = 48000 if id == 2
replace income = 53000 if id == 3
The above code snipped produces the desired output:
drop id_0
order id car choice sex income
sort id car
list, sepby(id)
+------------------------------------------+
| id car choice sex income |
|------------------------------------------|
1. | 1 American 0 Male 45000 |
2. | 1 European 1 Male 45000 |
3. | 1 Japanese 0 Male 45000 |
|------------------------------------------|
4. | 2 American 0 Female 48000 |
5. | 2 European 0 Female 48000 |
6. | 2 Japanese 1 Female 48000 |
|------------------------------------------|
7. | 3 American 1 Male 53000 |
8. | 3 European 0 Male 53000 |
9. | 3 Japanese 0 Male 53000 |
+------------------------------------------+
For more information, type help cross and help cond() from Stata's command prompt.
Please see dataex in Stata for how to produce data examples useful in web forums. (If necessary, install first using ssc install dataex.)
This could be an exercise in using fillin followed by filling in the missings.
* Example generated by -dataex-. To install: ssc install dataex
clear
input byte id str10 car str8 sex long income
1 "European" "Male" 45000
2 "Japanese" "Female" 48000
3 "American" "Male" 53000
end
fillin id car
foreach v in sex income {
bysort id (_fillin) : replace `v' = `v'[1]
}
list , sepby(id)
+-------------------------------------------+
| id car sex income _fillin |
|-------------------------------------------|
1. | 1 European Male 45000 0 |
2. | 1 American Male 45000 1 |
3. | 1 Japanese Male 45000 1 |
|-------------------------------------------|
4. | 2 Japanese Female 48000 0 |
5. | 2 European Female 48000 1 |
6. | 2 American Female 48000 1 |
|-------------------------------------------|
7. | 3 American Male 53000 0 |
8. | 3 European Male 53000 1 |
9. | 3 Japanese Male 53000 1 |
+-------------------------------------------+
A provisional solution using Pandas in Python is the following:
1) Open the base with:
df = pd.read_stata("mybase.dta")
2) Use the code of the accepted answer of this question.
3) Save the base:
df.to_stata("newbase.dta")
If one wants to use dummy variables, reshape also is an option.
clear
input byte id str10 car str8 sex long income
1 "European" "Male" 45000
2 "Japanese" "Female" 48000
3 "American" "Male" 53000
end
tabulate car, gen(choice)
reshape long choice, i(id)
label define car 2 "European" 3 "Japanese" 1 "American"
drop car
rename _j car
label values car car
list, sepby(id)
+------------------------------------------+
| id car sex income choice |
|------------------------------------------|
1. | 1 American Male 45000 0 |
2. | 1 European Male 45000 1 |
3. | 1 Japanese Male 45000 0 |
|------------------------------------------|
4. | 2 American Female 48000 0 |
5. | 2 European Female 48000 0 |
6. | 2 Japanese Female 48000 1 |
|------------------------------------------|
7. | 3 American Male 53000 1 |
8. | 3 European Male 53000 0 |
9. | 3 Japanese Male 53000 0 |
+------------------------------------------+
Related
I have a list of places with population, much like in the example data below:
sysuse census, clear
How can I combine (sum) only two observations to create a new observation, while maintaining the rest of the data?
In the below example I would like to combine Alabama and Alaska to create a new observation called 'Alabama & Alaska' with the sum of their populations.
With the new observation, the previous records will need to be deleted.
+----------------------------+
| state pop |
|----------------------------|
1. | Alabama 3,893,888 |
2. | Alaska 401,851 |
3. | Arizona 2,718,215 |
4. | Arkansas 2,286,435 |
5. | California 23,667,902 |
+----------------------------+
+-----------------------------------+
| state pop |
|-----------------------------------|
1. | Alabama & Alaska 4,295,739 | <--Alabama & Alaska combined
2. | Arizona 2,718,215 | <--Retain other observations and variables
3. | Arkansas 2,286,435 |
4. | California 23,667,902 |
+-----------------------------------+
This is my original toy data example and its expected output:
PlaceName Population
Town 1 100
Town 2 200
Town 3 100
Town 4 100
PlaceName Population
Town 1 & Town 2 300
Town 3 100
Town 4 100
Using your original toy example, the following works for me:
clear
input str6 PlaceName Population
"Town 1" 100
"Town 2" 200
"Town 3" 100
"Town 4" 100
end
generate PlaceName2 = cond(_n == 1, PlaceName + " & " + PlaceName[_n+1], PlaceName)
generate Population2 = cond(_n == 1, Population[_n+1] + Population, Population)
replace PlaceName2 = "" in 2
replace Population2 = . in 2
gsort - Population2
list, abbreviate(12)
+--------------------------------------------------------+
| PlaceName Population PlaceName2 Population2 |
|--------------------------------------------------------|
1. | Town 1 100 Town 1 & Town 2 300 |
2. | Town 4 100 Town 4 100 |
3. | Town 3 100 Town 3 100 |
4. | Town 2 200 . |
+--------------------------------------------------------+
This is how to do it with collapse. As you ask, this combines two observations into one, and thus changes the dataset.
clear
input str6 PlaceName Population
"Town 1" 100
"Town 2" 200
"Town 3" 100
"Town 4" 100
end
replace PlaceName = "Towns 1 and 2" in 1/2
collapse (sum) Population , by(PlaceName)
list
+--------------------------+
| PlaceName Popula~n |
|--------------------------|
1. | Town 3 100 |
2. | Town 4 100 |
3. | Towns 1 and 2 300 |
+--------------------------+
Assume I have a list_a variable with all possible sports played in the world:
football
tennis
hockey
cricket
croquet
racquetball
cricket
pingpong
squash
rugby
swimming
swimming
soccer
Also assume I have another variable list_b of only three sports:
cricket
hockey
swimming
I want to create a new variable Cont, which will equal 1 when the sports in list_a are found in list_b, and equal to 0 when the sport is not in list_b.
This is what variable Cont would look like:
0
0
1
1
0
0
1
0
0
0
1
1
0
Will the following work:
gen Cont = 0
replace Cont = 1 if (strmatch( list_a, ( list_b)))
EDIT:
Suppose list_a also contained hoccckey (which is a typo) but I still want it to get counted.
Is there a way to do that?
The answer is no because your approach will compare the values of the two variables in each observation. Instead, you need to compare the value at each row of list_a, with all values of variable list_b.
Using your toy example:
clear
input strL(list_a list_b)
football cricket
tennis hockey
hockey swimming
cricket
croquet
racquetball
cricket
pingpong
squash
rugby
swimming
swimming
soccer
end
The following illustrates the philosophy:
local obs = _N
generate Cont = 0
forvalues i = 1 / `obs' {
forvalues j = 1 / `obs' {
replace Cont = 1 if list_a[`i'] == list_b[`j'] in `i'
}
}
list
+-------------------------------+
| list_a list_b Cont |
|-------------------------------|
1. | football cricket 0 |
2. | tennis hockey 0 |
3. | hockey swimming 1 |
4. | cricket 1 |
5. | croquet 0 |
|-------------------------------|
6. | racquetball 0 |
7. | cricket 1 |
8. | pingpong 0 |
9. | squash 0 |
10. | rugby 0 |
|-------------------------------|
11. | swimming 1 |
12. | swimming 1 |
13. | soccer 0 |
+-------------------------------+
EDIT:
If you have certain typos that you additionally want to take into account, you can combine my solution with #NickCox's. In the above loop use instead:
replace Cont = 1 if inlist(list_a, "hoccckey") | list_a[`i'] == list_b[`j'] in `i'
There is a simple technique that works fine for your toy example:
clear
input strL list_a
football
tennis
hockey
cricket
croquet
racquetball
cricket
pingpong
squash
rugby
swimming
swimming
soccer
end
gen wanted = inlist(list_a, "cricket", "hockey", "swimming")
list, sepby(wanted)
+----------------------+
| list_a wanted |
|----------------------|
1. | football 0 |
2. | tennis 0 |
|----------------------|
3. | hockey 1 |
4. | cricket 1 |
|----------------------|
5. | croquet 0 |
6. | racquetball 0 |
|----------------------|
7. | cricket 1 |
|----------------------|
8. | pingpong 0 |
9. | squash 0 |
10. | rugby 0 |
|----------------------|
11. | swimming 1 |
12. | swimming 1 |
|----------------------|
13. | soccer 0 |
+----------------------+
If you had many more values, you could loop over the distinct values sought, using levelsof if they are in a second variable, or put the candidates in a separate dataset and merge as explained in this FAQ.
All these techniques depend on exact equality of strings, so watch out for variations between upper and lower case, leading and trailing spaces and inconsistencies in spelling.
I would like to calculate the sum of variable boasav:
clear
input id boasav
1 2500
1 2900
1 4200
2 5700
2 6100
3 7400
3 7600
3 8300
end
I know that the tabulate command can be used to summarize data but it only counts:
bys id: tab boasav
-> id = 1
boasav | Freq. Percent Cum.
------------+-----------------------------------
2500 | 1 33.33 33.33
2900 | 1 33.33 66.67
4200 | 1 33.33 100.00
------------+-----------------------------------
Total | 3 100.00
-> id = 2
boasav | Freq. Percent Cum.
------------+-----------------------------------
5700 | 1 50.00 50.00
6100 | 1 50.00 100.00
------------+-----------------------------------
Total | 2 100.00
-> id = 3
boasav | Freq. Percent Cum.
------------+-----------------------------------
7400 | 1 33.33 33.33
7600 | 1 33.33 66.67
8300 | 1 33.33 100.00
------------+-----------------------------------
Total | 3 100.00
However, what I want is the following:
1 9600
2 11800
3 23300
Is there a function that can do this in Stata?
Here are three more.
clear
input id boasav
1 2500
1 2900
1 4200
2 5700
2 6100
3 7400
3 7600
3 8300
end
* Method 4: use summarize
forval g = 1/3 {
su boasav if id == `g', meanonly
di "`g' " %5.0f r(sum)
}
1 9600
2 11800
3 23300
* Method 5: tabstat
tabstat boasav, by(id) stat(sum)
Summary for variables: boasav
by categories of: id
id | sum
---------+----------
1 | 9600
2 | 11800
3 | 23300
---------+----------
Total | 44700
--------------------
* Method 6: use rangestat (SSC)
rangestat (sum) boasav, int(id 0 0)
tabdisp id, c(boasav_sum)
-------------------------
id | sum of boasav
----------+--------------
1 | 9600
2 | 11800
3 | 23300
-------------------------
I have two variables in Stata, id and price:
id price
1 4321
1 7634
1 7974
1 7634
1 3244
2 5943
2 3294
2 5645
2 3564
2 4321
2 4567
2 4567
2 4567
2 4567
3 5652
3 9586
3 5844
3 8684
3 2456
4 7634
Usually I can use the duplicates command to get the duplicate observations of a variable.
However, how can I create a new variable that will save the duplicates
of price for each id?
There is no reason that I can see for duplicates to work with by:. duplicates whatever price id is the general recipe with your example, to examine duplicates jointly for two variables. Consider
clear
input id price
1 4321
1 7634
1 7974
1 7634
1 3244
2 5943
2 3294
2 5645
2 3564
2 4321
2 4567
2 4567
2 4567
2 4567
3 5652
3 9586
3 5844
3 8684
3 2456
4 7634
end
. duplicates example id price
Duplicates in terms of id price
+------------------------------------+
| group: # e.g. obs id price |
|------------------------------------|
| 1 2 2 1 7634 |
| 2 4 11 2 4567 |
+------------------------------------+
. duplicates tag id price, gen(tag)
Duplicates in terms of id price
. list id price if tag , sepby(id)
+------------+
| id price |
|------------|
2. | 1 7634 |
4. | 1 7634 |
|------------|
11. | 2 4567 |
12. | 2 4567 |
13. | 2 4567 |
14. | 2 4567 |
+------------+
Beyond that, I am not clear exactly what output or data result you wish to see.
EDIT In response to comment, here are two more direct approaches. duplicates is based on the idea that duplicates are mostly unwanted; you seem to have the opposite point of view, in which case duplicates is oblique to your wants.
* approach 1
bysort price id : gen wanted = _n == 1 & _N > 1
list if wanted
+---------------------+
| id price wanted |
|---------------------|
7. | 2 4567 1 |
15. | 1 7634 1 |
+---------------------+
* approach 2
drop wanted
bysort price id : keep if _n == 1 & _N > 1
list
+------------+
| id price |
|------------|
1. | 2 4567 |
2. | 1 7634 |
+------------+
Naturally if you want to duplicate data yet further (why?) then after approach 1
gen duplicated_price = price if wanted
gives you one copy of each of the duplicated values in a new variable. This is a slightly simpler equivalent of #Pearly Spencer's approach.
bysort price id : gen duplicated_price = price if _n == 1 & _N > 1
does it in one line.
I am doing reports with proc tabulate, but unable to add total in a report.
Example
+--------+------+----------+--------+---+---+---+
| Shop | Year | Month | Family | A | B | C |
+--------+------+----------+--------+---+---+---+
| raoas | 2006 | january | TA12 | 5 | 6 | 0 |
| taba | 2008 | january | TS01 | 0 | 1 | 1 |
| suptop | 2008 | april | TZ05 | 0 | 0 | 1 |
| taba | 2006 | December | TA12 | 5 | 6 | 0 |
| raoas | 2008 | january | TA15 | 0 | 2 | 0 |
| sup | 2008 | april | TQ05 | 0 | 1 | 1 |
+--------+------+----------+--------+---+---+---+
code
proc tabulate data=REPORTDATA_T6 format=12.;
CLASS YEAR;
var A C;
table (A C)*SUM='',YEAR=''
/box = 'YEAR';
TITLE 'FORECAST SUMMARY';
run;
output
YEAR 2006 2008 2009
A 800 766 813
C 854 832 812
I tried with... table(A C)*sum,year all... it will sum up for all the years but I want by year.
I tried with all the possible ways and tried... table(A C)*sum all,year. It will give number of observations ie N.. Thanx JON CLEMENTS But I dont want to add as TOTAL VARIABLE in the table, becoz this is a sample data but the number of variables are more then 10, some time I need to change variables, So, every time i dont want to add new variable as total.
I'm not sure if it's possible to do what you want in one step using only original data. Keyword ALL works only for summing up categories of CLASS-variables, but you want to sum up two different variables.
But it's easy enough with interim step, creating dataset where A, B, C variables will become categories of one variable:
data REPORTDATA_T6;
input Shop $ Year Month $ Family $ A B C;
datalines;
raoas 2006 january TA12 5 6 0
taba 2008 january TS01 0 1 1
suptop 2008 april TZ05 0 0 1
taba 2006 December TA12 5 6 0
raoas 2008 january TA15 0 2 0
sup 2008 april TQ05 0 1 1
;
run;
proc sort data=REPORTDATA_T6; by Shop Year Month Family; run;
proc transpose data=REPORTDATA_T6 out=REPORTDATA_T6_long;
var A B C;
by Shop Year Month Family;
run;
proc tabulate data=REPORTDATA_T6_long;
class _NAME_ YEAR;
var COL1;
table (_NAME_ all)*COL1=' '*SUM=' ', YEAR=' '
/box = 'YEAR';
TITLE 'FORECAST SUMMARY';
run;