Remove object from vector using its index - c++

I have a class with a private member type with a getType in it, in a second class I have a vector of such class that I can add to as many classes as I want, now want I want to do is if I was given a "Type" I want to remove the whole Object from such vector by finding that object using that string and erase it. I have tried the way below but did not work, also tried iterators and templates yet none seem to work. * This is simplified for the sake of it*
class AutoMobile{
private:
string type;
public:
AutoMobile(string type){
this->type = type;
}
string getType(){return type;}
};
class Inventory{
private:
vector<AutoMobile> cars;
public:
void removeFromInventory(string type){ // No two cars will have the same milage, type and ext
AutoMobile car("Ford");
cars.push_back(car);
for( AutoMobile x : cars){
cout<<x.getType();
}
for( AutoMobile x : cars){
if(x.getType() == "Ford"){
cars.erase(*x); // Problem i here, this does not work!
}
}
}
};
int main(void) {
Inventory Inven;
Inven.removeFromInventory("Ford");
return 0;
}

Use of range for loop is not appropriate when you intend to remove items from a std::vector. Use an iterator instead.
vector<AutoMobile>::iterator iter = cars.begin();
for ( ; iter != cars.end(); /* Don't increment the iterator here */ )
{
if ( iter->getType() == "Ford" )
{
iter = cars.erase(iter);
// Don't increment the iterator.
}
else
{
// Increment the iterator.
++iter;
}
}
You can simplify that block of code by using standard library functions and a lambda function.
cars.erase(std::remove_if(cars.begin(),
cars.end(),
[](AutoMobile const& c){return c.getType() ==
"Ford";}),
cars.end());

You can use remove_if
cars.erase(std::remove_if(cars.begin(),
cars.end(),
[=](AutoMobile &x){return x.getType()==type;}),
cars.end());

Related

Strange issue when iterating a STL set<CStudent> in C++

I have class CStudent and class CStudentGroup which has one member set<CStudent>. I populate the set of an object from the class CStudentGroup. I want to iterate this set and print via the getter of the CStudent class the points of all the students in the set. I do this by assigning the set to a new one. Then I iterate the set with an iterator it. However the compiler gives an error *the object has type qualifiers that are not compatible with the member function CStudent::getP; object type is const CStudent* I would like to ask how can I do this? Thank you in advance.
#include <iostream>
#include <string>
#include <set>
using namespace std;
class CStudent {
string m_strFN;
int m_iPoints;
public:
void setP(int p) {
m_iPoints = p;
}
void setFN(string f) {
m_strFN = f;
}
int getP() {
return m_iPoints;
}
string getFN() {
return m_strFN;
}
CStudent() {
m_strFN = "123456789";
m_iPoints = 70;
}
CStudent(const CStudent& stud) {
m_strFN = stud.m_strFN;
m_iPoints = stud.m_iPoints;
};
CStudent(int p) {
m_iPoints = p;
}
};
class CStudentGroup {
set<CStudent> m_setStudents;
public:
CStudentGroup(const CStudentGroup& grp) {
m_setStudents = grp.m_setStudents;
};
CStudentGroup(set<CStudent> st) {
m_setStudents = st;
}
CStudentGroup() {
CStudent s1(50), s2, s3(s2);
m_setStudents.insert(s1);
m_setStudents.insert(s2);
m_setStudents.insert(s3);
}
set<CStudent> gets() {
return m_setStudents;
}
};
int main()
{
CStudentGroup group;
set<CStudent> stt = group.gets();
for (set<CStudent>::iterator it = stt.begin(); it != stt.end(); it++) {
cout << it->getP() << endl;
}
}
std::set stores keys as constant value, as a change of a key can be a cause of change to its position in red-black tree (typical std::set implementation).
In other words, your CStudent object are considered const or unchangeable.
It's possible to problem here using std::set::const_iterator as a type of iterator inside the loop in combination with std::set::cbegin() and std::set::cend() calls.
Another possible solution is to use foreach-loop:
for (CStudent const& student : stt)
std::cout << student.getP() << '\n';
Moreover, you would need to change CStudent::getP() declaration to be a constant method.
Objects inside a std::set are always const. That is to protect them, in case you decide you change any key field, the sorting order changes and the set invariant is broken.
So basically the set<CStudent>::iterator is a const_iterator and you get a const CStudent& reference. Since your CStudent::getP is not a const member function, you cannot use it.
Solution, make it const:
int getP() const {
return m_iPoints;
}
Naturally, you want to mark as const any function that does not change the contents of your object, not only the ones std::set requires you to do so. This is sometimes called const-correctness and is always a good practice.

C++ OOP: Class knows its index in the container - prevent overwrite?

I have a class idx_aware that goes into a container container, which wraps around a std::vector. When the class is added to container, container sets a pointer to itself in idx_aware, as well as the index of idx_aware in its internal memory storage.
The index is not going to change until the container is destroyed or idx_aware is removed; idx_aware needs to know about its container and its index, because it has some methods that require both to work.
Now this introduces the following problem: when I get a non-const reference to an idx_aware class contained in container, I could assign to it another idx_aware class, which could have a different index. The intention would be assigning all the fields and keeping the index as it is.
#include <vector>
#include <limits>
#include <iostream>
class container;
// Stores a std::size_t field, which can be set only by subclasses.
class with_idx {
std::size_t _i;
public:
with_idx() : _i(std::numeric_limits<std::size_t>::max()) {}
operator std::size_t() const { return _i; }
protected:
void set_idx(std::size_t i) { _i = i; }
};
// Knows its index and its container
class idx_aware : public with_idx {
container const *_container;
int _some_field1;
float _some_field2;
public:
void foo() {
// Do stuff using _container and _i
}
private:
friend class container;
};
// Wraps around a std::vector
class container {
std::vector<idx_aware> _data;
public:
idx_aware &operator[](std::size_t idx) {
// Need non-const access to call foo
return _data[idx];
}
idx_aware const &operator[](std::size_t idx) const {
return _data[idx];
}
std::size_t add(idx_aware const &item) {
// Here it could potentially reuse a freed position
std::size_t free_slot = _data.size();
// Ensure _data is big enough to contain free_slot
if (_data.size() <= free_slot) {
_data.resize(free_slot + 1);
}
// Assign
_data[free_slot] = item;
_data[free_slot].set_idx(free_slot);
_data[free_slot]._container = this;
return free_slot;
}
};
int main() {
container c;
idx_aware an_item;
std::size_t i = c.add(an_item);
std::cout << c[i] << std::endl; // Prints 0
idx_aware another_item; // Created from somewhere else
// I want to set all the data in idx_aware, but the
// index should stay the same!
c[i] = another_item;
std::cout << c[i] << std::endl; // Prints numeric_limits<size_t>::max()
// Now container[i] is broken because it doesn't know anymore its index.
return 0;
}
One possible workaround would be to change with_idx in such a way that when set_idx is called, a flag is set that prevents assignment and copy operator to overwrite the _i property, like this:
class with_idx {
std::size_t _i;
bool _readonly;
public:
with_idx() : _i(std::numeric_limits<std::size_t>::max()), _readonly(false) {}
with_idx(with_idx const &other) : _i(other._i), _readonly(false) {}
with_idx &operator=(with_idx const &other) {
if (!_readonly) {
_i = other._i;
}
return *this;
}
operator std::size_t() const { return _i; }
protected:
void set_idx(std::size_t i) {
_i = i;
if (i != std::numeric_limits<std::size_t>::max()) {
// This has been set by someone with the right to do so,
// prevent overwriting
_readonly = true;
} else {
// Removed from the container, allow overwriting
_readonly = false;
}
}
};
This would have the consequence of returning, after assignment, a reference to an idx_aware class with unchanged index.
idx_aware &not_in_container1 = /* ... */;
idx_aware &not_in_container2 = /* ... */;
idx_aware &in_container = /* ... */;
not_in_container1 = in_container = not_in_container2;
// std::size_t(not_in_container_1) != std::size_t(not_in_container_2)
Is there a design pattern that can model this situation in a better way? My searches were not successful.
Are there other unwanted consequences of overriding the assignment operator in this way? The limitation I pointed out in the previous example does not look too "bad".
Is there an easier solution? I thought about writing some proxy object to replace the idx_aware & return type of operator[].
Experience tells that when C++ does not do what you intend, you are likely to be misusing OOP...
Robert's comment suggested me this solution.
Why would the contained object know about its container? To be able to perform actions such as foo and provide shorthand methods that otherwise would require to have access to the container.
Let's take this functionality away from the contained object; the contained object is just data payload. Instead, let's make operator[] return not the contained object, but some sort of iterator, a wrapper around the contained object, which knows the container and the index, and once dereferenced returns the actual contained object.
class was_idx_aware {
int _some_field1;
float _some_field2;
};
class container {
std::vector<idx_aware> _data;
public:
class idx_aware_wrapper {
container const *_container;
std::size_t _idx;
public:
idx_aware_wrapper(container const &c, std::size_t i)
: _container(&c)
, _idx(i)
{}
was_idx_aware const &operator*() const {
return _container->_data[_idx];
}
was_idx_aware &operator*() {
return _container->_data[_idx];
}
void foo() {
// Do stuff using _container and _idx.
}
};
idx_aware_wrapper operator[](std::size_t i) {
return idx_aware_wrapper(*this, i);
}
/* .... */
};
This allows quick access to any data in was_idx_aware, and the wrapper class can be augmented with all the methods that require interaction with the container. No need to store and keep indices up to date or override assignment operators.

C++ typedef, map, iterator

Can anybody help me with an iterator problem? I'm having something like this:
class SomeClass{
public:
//Constructor assigns to m_RefPtr a new t_Records
//Destructor deletes m_RefPtr or decreases m_RefCnt
//Copy Constructor assigns m_RefPtr to new obj, increases m_RefCnt
bool Search(const string &);
private:
//Some private variables
struct t_Records{ //For reference counting
int m_RefCnt; //Reference counter
typedef vector<int> m_Vec;
typedef map<string, m_Vec> m_Map;
m_Map m_RecMap;
t_Records(void){
m_RefCnt = 1;
}
};
t_Records * m_RefPtr;
};
//Searchs through the map of m_RefPtr, returns true if found
bool SomeClass::Search(const string & keyword){
//How to create and use an iterator of m_Map???
return true;
}
As how I mentioned, I'm having troubles with creating (defining) map iterator outside of the struct. The map is initalized and contains some records. Thanks for your reply.
Like this:
// assuming m_RefPtr is properly initialized:
t_Records::m_Map::iterator it = m_RefPtr->m_RecMap.begin();
++it; // etc.
By the way, m_Map is a bad name for a type. By common convention, names prefixed with m_ are used for data members.
You can iterate like this
for (m_Map::iterator it = m_RecMap.begin(); it != m_RecMap.end(); ++it)
{
// do stuff with *it
}
Or even easier
for (auto it = m_RecMap.begin(); it != m_RecMap.end(); ++it)
{
// do stuff with *it
}

Sorting a vector of a class

I have class called "UltrasoundTemplate". These UltrasoundTemplate objects contain an int parameter, which shows when they where defined (something like a time stamp). And I have a class called "UltrasoundTarget" which contains a vector of UltrasoundTemplate's.
I add UltrasoundTemplates to the vector with push_back(ultrasoundTemplate).
Now I want to sort the vector by the order of time stamps instead of the order I added them to the vector.
I found a lot of answers in google, which all show me the same solution, but obviously I'm still doing something wrong. Here are the code snippets I think are necessary for finding a solution:
ultrasoundTemplate.h
class UltrasoundTemplate
{
public:
UltrasoundTemplate(/*...*/);
int getVolumePos() { return volume_; }
private:
int volume_;
};
ultrasoundTarget.h
//the sort algorithm
struct MyTemplateSort {
bool operator() ( UltrasoundTemplate t1, UltrasoundTemplate t2){
int it1 = t1.getVolumePos();
int it2 = t2.getVolumePos();
if (it1 < it2)
return true;
return false;
}
};
class UltrasoundTarget
{
public:
UltrasoundTarget(/*...*/);
vector<UltrasoundTemplate> getTemplates() { return USTemplateVector_; }
private:
vector<UltrasoundTemplate> USTemplateVector_;
};
FMainWindow.cpp
void FMainWindow::match_slot()
{
int i;
//here I get the name of the target I'm looking for
QTreeWidgetItem *item = targetInfoWidget_->treeWidget->currentItem();
int index = targetInfoWidget_->treeWidget->indexOfTopLevelItem(item);
QString itemToAppendName = item->text(0);
for(i = 0; i < USTargetVector.size(); i++){
if(USTargetVector.at(i).getName() == itemToAppendName) {
//here I try to sort
MyTemplateSort tmpltSrt;
std::sort(USTargetVector.at(i).getTemplates().begin(),
USTargetVector.at(i).getTemplates().end(), tmpltSrt);
break;
}
}
As an example: I define Template1 in Volume(0), Template2 in Volume(70) and Template3 in Volume(40). The order now is (Template1, Template2, Template3) but I want it to be (Template1, Template3, Template2). But this code is not doing it.
If there's Information missing, just tell me and I'll provide more code.
Thanks alot.
Your getTemplates() method returns by value, making a mess here:
std::sort(USTargetVector.at(i).getTemplates().begin(),
USTargetVector.at(i).getTemplates().end(), tmpltSrt);
You are sorting an incompatible iterator range. You can fix that particular problem by returning a reference:
vector<UltrasoundTemplate>& getTemplates() { return USTemplateVector_; }
It is common practice to add a const overload to such a method:
const vector<UltrasoundTemplate>& getTemplates() const { return USTemplateVector_; }
You can also modify your comparison functor to avoid unnecessary copies (and for general readability and const correctness):
struct MyTemplateSort {
bool operator() const ( const UltrasoundTemplate& t1, const UltrasoundTemplate& t2)
{
return t1.getVolumePos() < t2.getVolumePos();
}
};
This will require that you make getVolumePos() a const method, which it should be anyway:
class UltrasoundTemplate
{
public:
...
int getVolumePos() const { return volume_; }
...
};
Note that is is not generally good practice to provide references to the private data of a class. If possible, you should find a way to remove that from the UltraSoundTarget interface. You could, for instance, expose a pair of iterators, and/or give the class a sort method.
juanchopanza answer is correct, the problem is the way you are returning the vector from UltrasoundTarget. Just to touch another topic, maybe it would be nice to change a little the designing of your implementation. As UltrasoundTarget is a container of Ultrasound's, it makes sense to implement the sort as a method of this class, this way you have direct access to USTemplateVector_ and will save unecessary copies. Something like:
class UltrasoundTarget
{
public:
UltrasoundTarget(/*...*/);
vector<UltrasoundTemplate> getTemplates() { return USTemplateVector_; }
void sort();
private:
vector<UltrasoundTemplate> USTemplateVector_;
};
void UltrasoundTarget::sort()
{
std::sort(USTemplateVector_.begin(), USTemplateVector_.end(), tmpltSrt);
}
void FMainWindow::match_slot()
{
int i;
//here I get the name of the target I'm looking for
QTreeWidgetItem *item = targetInfoWidget_->treeWidget->currentItem();
int index = targetInfoWidget_->treeWidget->indexOfTopLevelItem(item);
QString itemToAppendName = item->text(0);
for(i = 0; i < USTargetVector.size(); i++){
if(USTargetVector.at(i).getName() == itemToAppendName)
{
//here I try to sort
MyTemplateSort tmpltSrt;
USTargetVector.at(i).sort();
break;
}
}

returning c++ iterators

I have a function that returns an iterator if an object is found.
Now i have a problem. How do i fix the problem of informing the object that called this function that the object was not found?
vector<obj>::iterator Find(int id, int test)
{
vector<obj>::iterator it;
aClass class;
for(it = class.vecCont.begin(); it != class.vecCont.end(); ++it)
{
if(found object) //currently in psuedo code
return it;
}
return ???? // <<< if not found what to insert here?
}
Do i need to change my data structure in this instead?
Thanks in advance! :)
Return vector::end(), throw an exception, or return something other than a plain iterator
Better yet, don't implement your own Find function. That is what the <algorithm> library is for. Based on your psudocode, you can probably use std::find or std::find_if. find_if is particularly useful in cases where equality doesn't necessarily mean operator==. In those cases, you can use a [C++11] lambda or if C++11 isn't available to you, a functor class.
Since the functor is the lowest common denominator, I'll start with that:
#include <cstdlib>
#include <string>
#include <algorithm>
#include <vector>
#include <functional>
using namespace std;
class Person
{
public:
Person(const string& name, unsigned age) : name_(name), age_(age) {};
string name_;
unsigned age_;
};
class match_name : public unary_function <bool, string>
{
public:
match_name(const string& rhs) : name_(rhs) {};
bool operator()(const Person& rhs) const
{
return rhs.name_ == name_;
}
private:
string name_;
};
#include <iostream>
int main()
{
vector<Person> people;
people.push_back(Person("Hellen Keller", 99));
people.push_back(Person("John Doe", 42));
/** C++03 **/
vector<Person>::const_iterator found_person = std::find_if( people.begin(), people.end(), match_name("John Doe"));
if( found_person == people.end() )
cout << "Not FOund";
else
cout << found_person->name_ << " is " << found_person->age_;
}
found_person now points to the person whose name is "John Doe", or else points to people_.end() if that person wasn't found.
A C++11 lambda is new language syntax that makes this process of declaring/defining a functor and using is somewhat simpler for many cases. It's done like this:
string target = "John Doe";
vector<Person>::const_iterator found_person = std::find_if(people.begin(), people.end(), [&target](const Person& test) { return it->name_ == target; });
You can return an iterator to the end, i.e. return class.vecCont.end() to indicate that.
How about just returning the end iterator?
Your code becomes:-
vector<obj>::iterator Find(int id, int test)
{
vector<obj>::iterator it;
aClass class;
for(it = class.vecCont.begin(); it != class.vecCont.end(); ++it)
{
if(found object) //currently in psuedo code
break;
}
return it;
}
or just use std::find.
You should return class.vecCont.end() if the object was not found. But #chris is right - this is exactly what std::find is for.
Something like this
std::vector<obj>::iterator pos;
pos = find(coll.begin(),coll.end(), val);
And don't forget to these check for presence of your element or not in the container
if (pos != coll.end())
Don't return an iterator to a hidden container. Return simply what it is that you want, namely a means to access an object if it exists. In this example, I store the objects in the container via pointer. If your objects only exist temporarily, then new one up and copy the object over!
class AClass;
//...some time later
std::vector<AClass*> vecCont; //notice, store pointers in this example!
//..some time later
AClass * findAClass(int id, int test)
{
vector<AClass*>::iterator it;
for(it = class.vecCont.begin(); it != class.vecCont.end(); ++it)
{
if(found object) //currently in psuedo code
return it;
}
return NULL;
}
//later still..
AClass *foundVal = findAClass(1, 0);
if(foundVal)
{
//we found it!
}
else
{
//we didn't find it
}
edit: the intelligent thing to do is to write a comparator for your class and use the std algorithms sort and to find them for you. However, do what you want.
Never emulate std::algorithm functions inside a class. They are free functions for a reason. It usually is enough to expose begin and end member function that return the right iterators (and possibly a boost::iterator_range). If you need to do a fancy find with a functor, expose the functor as well.