Symbol not loaded into templated function - c++

I created a shared library "A" that use an other shared library "B".
I have a problem when I link my program with the shared library "A".
When I use some function from the other shared library ("B") inside cpp file of the shared library "A", all is fine.
But when I use these functions inside .h file (inside a templated method or an inlined method) of the shared library "A", the symbol is not loaded and I get an error "undefined reference to symbol".
I used g++ 7.2.
I think the option -l forget to load the symbols used in header file.
Do you have an idea to avoid this?
Update 2:
Here a full reproducible example:
A.cpp
#include "A.h"
A.h
#ifndef A_H
# define A_H
#include <type_traits>
#include "B.h"
class A
{
public:
template <typename Type>
std::enable_if_t<std::is_arithmetic<Type>::value,void> funcA(Type value);
};
template <typename Type>
std::enable_if_t<std::is_arithmetic<Type>::value,void> A::funcA(Type value)
{
B tmp;
tmp.funcB(value);
}
#endif
B.cpp
#include "B.h"
#include <iostream>
void B::example()
{
std::cout << "works" << std::endl;
}
B.h
#ifndef B_H
# define B_H
class B
{
public:
void funcB(int value);
private:
void example();
};
inline void B::funcB(int value)
{
value += 1;
example();
}
#endif
main.cpp
#include "A.h"
int main()
{
A tmp;
tmp.funcA(5);
return 1;
}
Compile
g++ -std=c++17 -m64 -O2 -DNDEBUG -Wall -Wextra -Werror -fPIC -o A.o -c A.cpp
g++ -std=c++17 -m64 -O2 -DNDEBUG -Wall -Wextra -Werror -fPIC -o B.o -c B.cpp
g++ -std=c++17 -m64 -O2 -DNDEBUG -Wall -Wextra -Werror -fPIC -o main.o -c main.cpp
g++ -o libB.so B.o -shared
g++ -o libA.so A.o -shared -L. -lB
g++ -o application main.o -L . -lA
Error
main.o: In function `main':
main.cpp:(.text.startup+0x1a): undefined reference to `B::example()'
collect2: error: ld returned 1 exit status
Thank you,
SOLVED:
Finally, I solved my problem with this thread:
GCC 4.5 vs 4.4 linking with dependencies
Thank you!

Related

calling c++ function from c

I need to access a C++ function from C but I get some error like :-
/tmp/ccUqcSZT.o: In function `main':
main.c:(.text+0x5): undefined reference to `load_alert_to_db'
collect2: error: ld returned 1 exit status
My main.c code is:-
#include <stdio.h>
extern void load_alert_to_db(void);
int main(void){
/* Create empty queue */
load_alert_to_db();
return 0;
}
C++ code implementation db_manager.cpp is:-
#include <sstream>
#include <iostream>
#include <sstream>
#include <string>
#include <ctime>
#include <cstdlib>
#include <algorithm>
#include <time.h>
#include <cstring>
#include <fstream>
//using namespace oracle::occi;
#include <iostream>
using namespace std;
extern "C" void load_alert_to_db(void)
{
cout<<"db occi"<<endl;
}
makefile is:-
CC= g++
all:
$(CC) -c -Wall -Werror -fPIC db_manager.cpp
$(CC) -shared -o libdb_manager.so db_manager.o
gcc -L/home/oracle/Desktop/storage/ -Wall main.c -o data -ldb_manager
gcc -o data main.c
clean:
rm -f *.o data
so please help me which one is my problem. I am also include
export LD_LIBRARY_PATH=/home/oracle/Desktop/storage/:$LD_LIBRARY_PATH
environmental variable in .bash_profile
gcc -o data main.c
Not sure why you have this line in your makefile since it will compile main.c without reference to the previously created library and hence cause an undefined-symbol error such as the one you're seeing.
This is especially so, since you appear to have done it the right way on the preceding line:
gcc -L/home/oracle/Desktop/storage/ -Wall main.c -o data -ldb_manager
However, the entire point of using makefiles is so that it figures out the minimum necessary commands for you, based on dependencies. Lumping a large swathe of commands into a single rule tends to defeat that purpose. You would be better off making your rules a little more targeted, such as (untested but should be close):
all: data
data: main.o libdb_manager.so
gcc -o data main.o -ldb_manager
main.o: main.c
gcc -o main.o main.c
libdb_manager.so: db_manager.cpp
g++ -c -Wall -Werror -fPIC -o db_manager.o db_manager.cpp
g++ -shared -o libdb_manager.so db_manager.o
That way, if you make a small change to one part (like main.c), it doesn't have to go and compile/link everything in your build tree.
Your makefile seems to be completely broken and random, and you're not even linking the required object files. You can simplify this:
all:
$(CC) -c -Wall -Werror -fPIC db_manager.cpp
$(CC) -shared -o libdb_manager.so db_manager.o
gcc -L/home/oracle/Desktop/storage/ -Wall main.c -o data -ldb_manager
gcc -o data main.c
to just this:
all:
gcc -Wall -c main.c
g++ -Wall -c db_manager.cpp
g++ main.o db_manager.o -o data
this is what I needed to do:
Supposing the C++ function is called Debug::Write(str)
Then in your hpp file do the following:
#ifdef __cplusplus
extern "C" void DebugTmp(char *str);
#endif
Then in the corresponding cpp file do this:
void DebugTmp(char *str)
{
Debug::Write(str);
}
Then in your C file where you call DebugTmp define the prototype:
void DebugTmp(char *str);
then call it as below:
static void MyFunction( void )
{
DebugTmp("This is debug trace\n");
}

Separate instance of static variable in static library for shared library

Consider the following setup consisting of two shared libraries which both use a static library:
static.cpp
#include "static.h"
static int a = 0;
int getA()
{
return a++;
}
static.h
#pragma once
int getA();
shareda.cpp
#include <iostream>
#include "shareda.h"
#include "static.h"
void printA()
{
std::cout << getA() << std::endl;
}
shareda.h
#pragma once
void printA();
sharedb.cpp
#include <iostream>
#include "sharedb.h"
#include "static.h"
void printB()
{
std::cout << getA() << std::endl;
}
sharedb.h
#pragma once
void printB();
main.cpp
#include "shareda.h"
#include "sharedb.h"
int main()
{
printA();
printA();
printB();
printA();
printB();
return 0;
}
I compiled and ran these files with the following commands (using Clang 3.8.0, compiled from source, and 64-bit Debian with GNU ld 2.25):
clang++ -c static.cpp -o static.o -fPIC
ar rcs libstatic.a static.o
clang++ -c shareda.cpp -o shareda.o -fPIC
clang++ -shared -o libshareda.so shareda.o libstatic.a
clang++ -c sharedb.cpp -o sharedb.o -fPIC
clang++ -shared -o libsharedb.so sharedb.o libstatic.a
clang++ -L. -lshareda -lsharedb -o main main.cpp
LD_LIBRARY_PATH=.:$LD_LIBRARY_PATH ./main
To my surprise, the output was the following:
0
1
2
3
4
My expectation was this:
0
1
0
2
1
Apparently, despite the static keyword in front of a in static.cpp, only one instance of a exists. Is there a way to have two instances of a, one for each of the shared libraries?
Apparently, despite the static keyword in front of a in static.cpp, only one instance of a exists.
That is incorrect: two instances of a exist, but only one is actually used.
And that is happening because (contrary to your expectations) printB calls the first getA available to it (the one from libshareda.so, not the one from libsharedb.so). That is one major difference between UNIX shared libraries and Windows DLLs. UNIX shared libraries emulate what would have happened if your link was:
clang++ -L. -o main main.cpp shareda.o sharedb.o libstatic.a
So what can you do to "fix" this?
You could link libsharedb.so to prefer its own getA, by using -Bsymbolic.
You could hide getA inside libsharedb.so completely (as if it's a private implementation detail):
clang++ -c -fvisibility=hidden -fPIC static.cpp
ar rcs libstatic.a static.o
clang++ -shared -o libsharedb.so sharedb.o libstatic.a
You could achieve similar result using linker version script.
P.S. Your link command:
clang++ -L. -lshareda -lsharedb -o main main.cpp
is completely backwards. It should be:
clang++ -L. -o main main.cpp -lshareda -lsharedb
The order of sources/object files and libraries on command line matters, and libraries should follow object files that reference them.

C++ shared library undefined reference

i'm having something like these files:
libfoo.h
class foo
{
public:
foo() = default;
virtual ~foo();
};
libfoo.cpp
#include "libfoo.h"
foo::~foo() { /* code here */ }
test.cpp
#include <libfoo.h>
int main()
{
foo f;
}
i compile libfoo.h and libfoo.cpp into a shared library and all that is fine.
but when i then try to use the library in test.cpp i get undefined reference to the destructor ~foo().
this error however does not occur if i define the destructor directly in libfoo.h. i have this problem with all functions defined outside the class in my library so im guessing it has something to do with the compilation process (it compiles fine however)
i compile the library like this:
g++ -std=c++0x -Wall -Werror -fPIC -c -o libfoo.o libfoo.cpp
g++ -shared libfoo.o -o libfoo.so
any ideas as to what i might be doing wrong?
(all the functions that i declare inclass, like template functions works fine and causes no undefined reference)
I tried to reproduce the error, but I failed.
I created the files (with slight modifications):
// libfoo.h
struct foo { virtual ~foo(); };
// libfoo.cpp
#include "libfoo.h"
foo::~foo() {}
// test.cpp
#include "libfoo.h"
int main() { foo f; }
Built like this:
$ g++ -std=c++0x -Wall -Werror -fPIC -c -o libfoo.o libfoo.cpp
$ g++ -shared libfoo.o -o libfoo.so
$ g++ test.cpp -L. -lfoo
And ran like this:
$ env LD_LIBRARY_PATH=. ./a.out
I got no errors. Are you sure there is a problem with your code?

What is a fix for a constructor definition error?

So I have a class:
#include "Cool.h"
#include <iostream>
Cool::Cool()
{
//ctor
}
int getVar()
{
int pop = 22;
return pop;
}
and a header file:
#ifndef COOL_H
#define COOL_H
class Cool
{
public:
Cool();
int getVar();
};
#endif
But when I compile, I get an error that says
error: definition of implicitly-declared 'Cool::Cool()'
EDIT:
Don't know if it will help, but I also have a makefile:
program: main.o cool.o
g++ -o program main.o cool.o
cool.o: Cool.cpp Cool.h
g++ -c -o cool.o Cool.cpp
main.o: main.cpp cool.o
g++ main.cpp
EDIT 2: Full Error Message:
Cool.cpp:4:12: error: definition of implicitly-declared ‘Cool::Cool()’
Cool::Cool()
^
This:
cool.o: Cool.cpp Cool.h
g++ Cool.cpp
should be:
cool.o: Cool.cpp Cool.h
g++ -c -o cool.o Cool.cpp
For main.o::
main.o: main.cpp Cool.h
g++ -c -o main.o main.cpp
It is very confusing that you have the same file as both uppercase and lowercase. Does the problem persist after you rename everything to lowercase?
Solved it! I added this to the makefile:
Under main.o:
g++ -c -o main.o main.cpp

Static Libraries which depend on other static libraries

I have a question about making static libraries that use other static libraries.
I set up an example with 3 files - main.cpp, slib1.cpp and slib2.cpp. slib1.cpp and slib2.cpp are both compiled as individual static libraries (e.g. I end up with slib1.a and slib2.a) main.cpp is compiled into a standard ELF executable linked against both libraries.
There also exists a header file named main.h which prototypes the functions in slib1 and slib2.
main.cpp calls a function called lib2func() from slib2. This function in turn calls lib1func() from slib1.
If I compile the code as is, g++ will return with a linker error stating that it could not find lib1func() in slib1. However, if I make a call to lib1func() BEFORE any calls to any functions in slib2, the code compiles and works correctly.
My question is simply as follows: is it possible to create a static library that depends on another static library? It would seem like a very severe limitation if this were not possible.
The source code for this problem is attached below:
main.h:
#ifndef MAIN_H
#define MAIN_H
int lib1func();
int lib2func();
#endif
slib1.cpp:
#include "main.h"
int lib1func() {
return 1;
}
slib2.cpp:
#include "main.h"
int lib2func() {
return lib1func();
}
main.cpp:
#include <iostream>
#include "main.h"
int main(int argc, char **argv) {
//lib1func(); // Uncomment and compile will succeed. WHY??
cout << "Ans: " << lib2func() << endl;
return 0;
}
gcc output (with line commented out):
g++ -o src/slib1.o -c src/slib1.cpp
ar rc libslib1.a src/slib1.o
ranlib libslib1.a
g++ -o src/slib2.o -c src/slib2.cpp
ar rc libslib2.a src/slib2.o
ranlib libslib2.a
g++ -o src/main.o -c src/main.cpp
g++ -o main src/main.o -L. -lslib1 -lslib2
./libslib2.a(slib2.o): In function `lib2func()':
slib2.cpp:(.text+0x5): undefined reference to `lib1func()'
collect2: ld returned 1 exit status
gcc output (with line uncommented)
g++ -o src/slib1.o -c src/slib1.cpp
ar rc libslib1.a src/slib1.o
ranlib libslib1.a
g++ -o src/slib2.o -c src/slib2.cpp
ar rc libslib2.a src/slib2.o
ranlib libslib2.a
g++ -o src/main.o -c src/main.cpp
g++ -o main src/main.o -L. -lslib1 -lslib2
$ ./main
Ans: 1
Please, try g++ -o main src/main.o -L. -Wl,--start-group -lslib1 -lslib2 -Wl,--end-group.
Group defined with --start-group, --end-group helps to resolve circular dependencies between libraries.
See also: GCC: what are the --start-group and --end-group command line options?
The order make the difference. Here's from gcc(1) manual page:
It makes a difference where in the command you write this option; the linker searches and processes libraries and object files in the order they are specified. Thus, foo.o -lz bar.o searches library z after file foo.o but before bar.o. If bar.o refers to functions in z, those functions may not be loaded.