"cin.get" stopped another input function like "cin" .. c++ - c++

Question

I want to request the a username and password from 6 users,
and then save this username and password into a text file on my desktop.
I built a structure that has one variable to store the password and a char array with a length of 25.
struct users {
int password;
char username[25];
}
When I want to request the username in the main() function, I use the cin.get() function.
cin.get(username,25);
The program stops after the second cin function when it is storing the password. Why is that?
#include <iostream>
#include <fstream>
struct users {
char username[25];
int password;
} user[6];
using namespace std;
int main() {
cout << "Sign up x6" << endl;
for(int i=0;i<6;i++){
cout << "Username:";
cin.get(user[i].username,20);
cout << "Password:";
cin >> user[i].password;
}
std::ofstream file;
file.open("C:/Users/Programmer/Desktop/sa.txt",ios::app);
for(int i=0;i<6;i++){
file << "first user\n" << user[i].username << endl << user[i].password << endl;
cout << "\n \n \n";
}
}

Answer 1

i found solution that using "gets" function .. which inside stdio.h library:
function "gets" will request the user of value then store the value of variable. (username)
char username[25];
gets(username[25]);
but this function "gets" get only value of "char" type variables so i changed "password" variable type to char
char password[25];
gets(password[25]);
#include<iostream>
#include <fstream>
#include<stdio.h>
struct users
{
char username[25];
char password[25];
} user[6];
using namespace std;
int main()
{
cout << "Sign up x6" << endl;
for (int i = 0; i < 6; i++)
{
cout << "username:";
gets(user[i].username);
cout << "Password:";
gets(user[i].password);
}
std::ofstream file;
file.open("C:/Users/Programmer/Desktop/sa.txt", ios::app);
for (int i = 0; i < 6; i++)
{
file <<"("<<i<<") user\n" << user[i].username << endl << user[i].password<< endl;
cout << "\n \n \n";
}
}

Answer 2

use std::cin.getline(user[i].username,20) instead.