I've looked at a couple of other post with issues of adding a target to not just tap gestures and buttons and I think I am following the formatting correctly but am still getting the 'has no member' error, here's my pseudo code:
let tapGesture = UITapGestureRecognizer(target: self, action: #selector(self.handlTap(_:)))
func handleTap(_ sender: AnyObject) {
}
add the gesture to your view:
view.addGestureRecognizer(yourGesture)
To access any object with UITapGestureRecognizer
let recognizer = UITapGestureRecognizer(target: self, action: #selector(self.expand))
view.addGestureRecognizer(recognizer)
func expand(sender:UITapGestureRecognizer){
if let myImg = sender.view as? UIImageView //or AnyObject you want {
}
}
Related
I tried looking for a solution in posts such as this and this where people asked this very same question: How to share a url to Facebook using SwiftUI?
I even tried this post where somebody asked how to export a file using SwiftUI, but my problem is specifically with Facebook since I have no problem sharing urls to apps such as Whatsapp.
However, I found no answers...
UIKit
By reading Facebook's Developer documentation, I found a way to share a post using UIKit.
I created a very simple sample project to make sure I understood the topic.
Here is the sample project in UIKit:
import UIKit
import FBSDKShareKit
class ProfileViewController: UIViewController {
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view.
}
#IBAction func share(_ sender: UIButton) {
shareLink(url: URL(string: "http://www.apple.com")!)
}
func shareLink(url: URL) {
let content = ShareLinkContent()
content.contentURL = url
let dialog = ShareDialog(
fromViewController: self,
content: content,
delegate: nil
)
dialog.show()
}
}
Luckily, this worked right away.
By making this project work, I confirmed that I wasn't forgetting to link my AppBundleID to Facebook, or forgetting to add my FacebookAppID or any other needed files inside my info.plist.
SwiftUI
I then tried to replicate the same project in SwiftUI to see if I could get it to work.
I used ViewControllerRepresentable to be able to include UIActivityViewController into SwiftUI.
The reason for using UIActivityViewController is because I want the user to choose where they want to share the URL (Whatsapp, Twitter, Facebook, etc).
Here is the code:
ContentView
struct ContentView: View {
#State var showSharingView = false
var body: some View {
Button("Share Link") {
showSharingView.toggle()
}
.sheet(isPresented: $showSharingView) {
ActivityViewController(activityItems: [URL(string: "https://www.apple.com/")!])
}
}
}
UIViewControllerRepresentable
struct ActivityViewController: UIViewControllerRepresentable {
var activityItems: [URL]
var applicationActivities: [UIActivity]? = nil
func makeUIViewController(context: UIViewControllerRepresentableContext<ActivityViewController>) -> UIActivityViewController {
let controller = UIActivityViewController(activityItems: activityItems, applicationActivities: applicationActivities)
controller.completionWithItemsHandler = { (activityType, completed, returnedItems, error) in
if activityType == .postToFacebook {
shareLink(from: activityItems.first!)
}
}
return controller
}
func updateUIViewController(_ uiViewController: UIActivityViewController, context: UIViewControllerRepresentableContext<ActivityViewController>) {}
func shareLink(from url: URL) {
// controller was created so I would have a UIViewControllerType to put as a parameter for fromViewController in ShareDialog, even though I don't think it fits
let controller = UIActivityViewController(activityItems: activityItems, applicationActivities: applicationActivities)
let content = ShareLinkContent()
content.contentURL = url
let dialog = ShareDialog(fromViewController: controller, content: content, delegate: nil)
dialog.show()
}
}
This code doesn't work because of what I assume is the controller variable used when initializing ShareDialog. (self doesn't work either because "XCode cannot convert value of type 'ActivityViewController' to expected argument type 'UIViewController?'")
Question
Facebook Developer's documentation tells me that I need to write the following code in order to share a link:
guard let url = URL(string: "https://developers.facebook.com") else {
// handle and return
}
let content = ShareLinkContent()
content.contentURL = url
let dialog = ShareDialog(
viewController: self, //<--this has been changed to 'fromViewController'
content: content,
delegate: self
)
dialog.show()
However, SwiftUI doesn't work with ViewControllers. How can I create a ViewController to use as a parameter in fromViewController in ShareDialog in order to successfully share my URL to Facebook?
Use like this,
guard let url = URL(string: "https://developers.facebook.com") else {
// handle and return
}
let content = ShareLinkContent()
content.contentURL = url
let dialog = ShareDialog(
viewController: UIApplication.shared.windows.first!.rootViewController,
content: content,
delegate: UIApplication.shared.windows.first!.rootViewController
)
dialog.show()
So I have an image view titled cashOrCredit and have am trying to set it's image programatically but somehow not able to.
First I set the image like this
cell.cashOrCredit.image = UIImage(named: "cash1.png")
and I get an error saying a separator of "," is needed.
Then I tried it this way
var cashImage: UIImage?
cashImage = "cash1.png"
cell.cashOrCredit.image = cashImage
But I get a THREAD 1 EXC BAD INSTRUCTION error.
I can't seem to understand what is going wrong ?
Here is the error
Updated for Swift 3:
use below simple code, to set the image to UIImageView;
class YourViewControllerName: UIViewController {
var mYourImageViewOutlet: UIImageView?
func addImageToUIImageView{
var yourImage: UIImage = UIImage(named: "Birthday_logo")!
mYourImageViewOutlet.image = yourImage
} // call this function where you want to set image.
}
Note: "Birthday_logo" type of image must be present in your Assets.xcassets of your project.
I attached the screenshot if you want any help please refer it.
****// used anywhere you want to add an image to UIImageView. [Here I used one function & in that function, I write a code to set image to UIImageView]****
Enjoy..!
Try this:
cell.cashOrCredit.image = UIImage(named: "cash1")
and check "cash1.png" image is available in Assets.xcassets or not.
If you get solution, then give upvote to my answer.
Delete ".png":
cell.cashOrCredit.image = UIImage(named: "cash1")
You can also set it all programmatically:
let cellImage = UIImageView(frame: CGRect(x: X, y: Y, width: WIDTH, height: HEIGHT))
cellImage.image = UIImage(named: "cash1")
cell.addSubview(cellImage)
Take Outlet of ImageView
#IBOutlet weak var imgProfile: UIImageView!
Go through the following code which contains will be helpful you to pick image or capture image from the camera.
func choosePicker() {
let alertController = UIAlertController(title: "Select Option", message: nil, preferredStyle: (IS_IPAD ? UIAlertControllerStyle.alert : UIAlertControllerStyle.actionSheet))
let cancelAction = UIAlertAction(title: "Cancel", style: UIAlertActionStyle.cancel, handler: { action -> Void in
})
let gallery = UIAlertAction(title: "From Gallery", style: UIAlertActionStyle.default
, handler: { action -> Void in
self.openPicker(isCamera: false)
})
let camera = UIAlertAction(title: "Take Photo", style: UIAlertActionStyle.default
, handler: { action -> Void in
self.openPicker(isCamera: true)
})
alertController.addAction(gallery)
alertController.addAction(camera)
alertController.addAction(cancelAction)
self.present(alertController, animated: true, completion: nil)
}
func openPicker(isCamera : Bool) {
let picker:UIImagePickerController?=UIImagePickerController()
if isCamera {
picker!.sourceType = UIImagePickerControllerSourceType.camera
} else {
picker!.sourceType = UIImagePickerControllerSourceType.photoLibrary
picker!.allowsEditing = true
}
picker?.delegate = self
if UIDevice.current.userInterfaceIdiom == .phone {
self.present(picker!, animated: true, completion: nil)
}
else {
picker!.modalPresentationStyle = .popover
present(picker!, animated: true, completion: nil)//4
picker!.popoverPresentationController?.sourceView = imgProfile
picker!.popoverPresentationController?.permittedArrowDirections = UIPopoverArrowDirection.up
}
}
// MARK: - UIImagePickerControllerDelegate Methods
func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [String : Any]) {
if let image = info[UIImagePickerControllerOriginalImage] as? UIImage {
self.imgProfile.image = image
}
picker.dismiss(animated: true, completion: nil);
}
func imagePickerControllerDidCancel(_ picker: UIImagePickerController) {
dismiss(animated: true, completion: nil)
}
Call choosePicker method wherever you want to call.
Check if cashOrCredit is uiimageview.
Secondly,
cashImage = UIImage(named: "cash1.png")
If that doesnot work, try
cell?. cashOrCredit.image
check if cell is nil?
In the context of Swift code, EXC_BAD_INSTRUCTION usually means you’ve hit a compiler trap, that is, an undefined instruction inserted into the code by the compiler because of a bug detected at runtime. The most common cause of these are:
failure to unwrap an optional — This can be a forced unwrap (!) or an implicit unwrap (accessing an implicitly unwrapped optional that’s nil).
array out of bounds
a failed forced cast (as!), either because the value was a nil optional or because the value was of the wrong type
I have a storyboard with some text views on it. When I try to localize the storyboard (creating Storyboard.strings file), all of the UITextViews don't localize at all. UILabels are fine.
My config is as follow:
1 Base Storyboard file with 2 Storyboard.strings files
Storyboard Configuration
Storyboard.strings files are ok, its working with UILabels after all:
Storyboard.strings file
Have you found a solution for this problem?
I'm using Xcode 8.3, Swift 3, iOS 10.
You could just make a IBOutlet in Xcode and set the initial UITextView value in the didSet function.
E.g.
#IBOutlet var textView: UITextView {
didSet {
textView.text = NSLocalizedString("CUSTOM_LOCALISED_STRING", comment: "Comment.")
}
}
I ended up with this solution:
In a UIViewController I can access my UITextView-objects and force the localized text from Storyboard.strings to be used.
func fixTextViewStoryboardLocalization() {
guard storyboard != nil else {
return // No need to fix it if storyboard is not presented
}
let storyboardName = storyboard!.value(forKey: "name") as! String
for case let textView as UITextView in view.subviews {
if let ident = textView.restorationIdentifier {
textView.text = NSLocalizedString("\(ident).text", tableName: storyboardName, bundle: Bundle.main, value: "", comment: "")
}
}
}
Create a custom MyViewController (pick whatever name you want), call this function in viewDidLoad:
class MyViewController: UIViewController {
override func viewDidLoad() {
super.viewDidLoad()
fixTextViewStoryboardLocalization()
}
}
Make sure the storyboard view controller is from class MyViewController:
MyViewController custom class in Storyboard
In order the code above to work, I need to set the Restoration ID for each UITextView in my Storyboard:
UITextView Restoration ID
Final step - localize the text view in Storyboard.strings:
/* Class = "UITextView"; text = "Base text"; ObjectID = "MyTextView-Restoration-ID"; */
"MyTextView-Restoration-ID.text" = "Localized text comes here";
This works for all my UITextViews in all my storyboards.
I've tried to expand the default Apple MasterDetail Template by adding a UITabbarController in front of the UINavigationController of the MasterView, so there is a structure like this:
UISplitViewController (Master) > UITabbarController > UINavigationController > UITableViewController
But if I run the App, after changing application(didFinishLaunchingWithOptions) to use the correct ViewController, and try to perform the ShowDetails Segue the DetailsView ist presented Modally on the iPhone. On the other side the iPad Version is working as expected.
What am I forgot to do? Or how can I fix it?
I figured out how to put the detail on to the master's UINavigationController instead of presenting it modally over the UITabBarController.
Using the UISplitViewControllerDelegate method
- splitViewController:showDetailViewController:sender:
In case the UISplitViewController is collapsed get the masters navigation controller and push the detail view onto this navigation controller:
- (BOOL)splitViewController:(UISplitViewController *)splitViewController
showDetailViewController:(UIViewController *)vc
sender:(id)sender {
NSLog(#"UISplitViewController collapsed: %d", splitViewController.collapsed);
// TODO: add introspection
if (splitViewController.collapsed) {
UITabBarController *master = (UITabBarController *) splitViewController.viewControllers[0];
UINavigationController *masterNavigationController = (UINavigationController *)master.selectedViewController;
// push detail view on the navigation controller
[masterNavigationController pushViewController:vc animated:YES];
return YES;
}
return NO;
}
Just to update the answers above. Since you can't push navigation controllers anymore, you have to push its top view controller instead.
func splitViewController(splitViewController: UISplitViewController, showDetailViewController vc: UIViewController, sender: AnyObject?) -> Bool {
if splitViewController.collapsed {
let tabBarController = splitViewController.viewControllers.first as! UITabBarController
let selectedNavigationViewController = tabBarController.selectedViewController as! UINavigationController
// Push view controller
var viewControllerToPush = vc
if let navController = vc as? UINavigationController {
viewControllerToPush = navController.topViewController
}
selectedNavigationViewController.pushViewController(viewControllerToPush, animated: true)
return true
}
return false
}
Here's my solution. Place in MasterViewController.m and remember to give your detail view a Storyboard ID in IB. In my case 'detail'.
-(BOOL)shouldPerformSegueWithIdentifier:(NSString *)identifier sender:(id)sender {
if ([identifier isEqualToString:#"showDetail"] && self.splitViewController.collapsed) {
DetailViewController *myController = (DetailViewController *)[self.storyboard instantiateViewControllerWithIdentifier:#"detail"];
NSIndexPath *indexPath = [self.tableView indexPathForSelectedRow];
NSManagedObject *object = [[self fetchedResultsController] objectAtIndexPath:indexPath];
[myController setDetailItem:object];
[self.navigationController showViewController:myController sender:self];
return NO;
}
return YES;
}
There is another way to do it without code.
After you embedded the the UINavigationController in the TabBarController embed the TabBarController in another UINavigationController. So you will have: SplitViewController -> Master -> NavCon -> TabBar -> NavCon -> TableViewController.
It's much easier doing like this, but there a bug that I haven't found out how to fix. The navigation bar presented will be that of the TabBarController, not the TableViewController. Any ideas how to fix that?
Subclass TabBarController like this:
- (void)showViewController:(UIViewController *)vc sender:(id)sender
{
if ([self.selectedViewController isKindOfClass:UINavigationController.class])
[self.selectedViewController showViewController:vc sender:sender];
else
[super showViewController:vc sender:sender];
}
- (UIViewController*)separateSecondaryViewControllerForSplitViewController:(UISplitViewController *)splitViewController
{
return [self.selectedViewController separateSecondaryViewControllerForSplitViewController:splitViewController];
}
- (void)collapseSecondaryViewController:(UIViewController *)secondaryViewController forSplitViewController:(UISplitViewController *)splitViewController
{
[self.selectedViewController.navigationController collapseSecondaryViewController:secondaryViewController forSplitViewController:splitViewController];
}
See this question for complete explanation.
Here is an alternative that is based on testing the size classes of the splitViewController :
Use a custom UISplitViewController (subclass)
Override the showDetailViewController operation
Use the traitCollection to determine the class of the UISplitViewController
If the horizontal class is Compact, get the navigationController to call showViewController
Here is the the code of the custom UISplitViewController :
import UIKit
class CustomSplitViewController: UISplitViewController {
override func showDetailViewController(vc: UIViewController!, sender: AnyObject!) {
if (self.traitCollection.horizontalSizeClass == UIUserInterfaceSizeClass.Compact) {
if let tabBarController = self.viewControllers[0] as? UITabBarController {
if let navigationController = tabBarController.selectedViewController as? UINavigationController {
navigationController.showViewController(vc, sender: sender)
return
}
}
}
super.showDetailViewController(vc, sender: sender)
}
}
Do not forget to the set the custom class in the storyboard.
Tested in the simulator of iPhone 6, iPhone 6+ and iPad Air and worked as expected.
I haven't been able to find a tutorial on how to properly setup a gesture recognizer for iOS.
I need to detect swipe up & down, and the callbacks for them.
Any help, appreciated. Thanks.
You need two recognizers, one for swiping up, and the other for swiping down:
UISwipeGestureRecognizer* swipeUpGestureRecognizer = [[UISwipeGestureRecognizer alloc] initWithTarget:self action:#selector(handleSwipeUpFrom:)];
swipeUpGestureRecognizer.direction = UISwipeGestureRecognizerDirectionUp;
and for the handler:
- (void)handleSwipeUpFrom:(UIGestureRecognizer*)recognizer {
}
Finally, you add it to your view:
[view addGestureRecognizer:swipeUpGestureRecognizer];
The same for the other direction (just change all the Ups to Downs).
This worked for me in Xcode 7.3. , Swift 2.2.
import UIKit
class Viewcontroller: UIViewController
{
override func viewDidLoad()
{
super.viewDidLoad()
createAndAddSwipeGesture()
}
private func createAndAddSwipeGesture()
{
let swipeGesture = UISwipeGestureRecognizer(target: self, action: #selector(Viewcontroller.handleSwipeLeft(_:)))
swipeGesture.direction = UISwipeGestureRecognizerDirection.Left
view.addGestureRecognizer(swipeGesture)
}
#IBAction func handleSwipeLeft(recognizer:UIGestureRecognizer)
{
print(" Handle swipe left...")
}
}