Flatten nested map into rows [duplicate] - clojure

Given:
{:o {:i1 1
:i2 {:ii1 4}}}
I'd like to iterate over the keys of the map in "absolute" form from the root as a vector. So I'd like:
{
[:o :i1] 1
[:o :i2 :ii1] 4
}
As the result. Basically only get the leaf nodes.

A version that I think is rather nicer, using for instead of mapcat:
(defn flatten-keys [m]
(if (not (map? m))
{[] m}
(into {}
(for [[k v] m
[ks v'] (flatten-keys v)]
[(cons k ks) v']))))
The function is naturally recursive, and the most convenient base case for a non-map is "this one value, with no keyseq leading to it". For a map, you can just call flatten-keys on each value in the map, and prepend its key to each keyseq of the resulting map.

Looks like this is basically a flatten of the nested keys. This also seems to be a 4clojure problem.
A flatten-map search on github yield many results.
One example implementation:
(defn flatten-map
"Flattens the keys of a nested into a map of depth one but
with the keys turned into vectors (the paths into the original
nested map)."
[s]
(let [combine-map (fn [k s] (for [[x y] s] {[k x] y}))]
(loop [result {}, coll s]
(if (empty? coll)
result
(let [[i j] (first coll)]
(recur (into result (combine-map i j)) (rest coll)))))))
Example
(flatten-map {:OUT
{:x 5
:x/A 21
:x/B 33
:y/A 24}})
=> {[:OUT :x] 5, [:OUT :x/A] 21, [:OUT :x/B] 33, [:OUT :y/A] 24}
An even more general version from Christoph Grand:
(defn flatten-map
"Take a nested map (or a nested collection of key-value pairs) and returns a
sequence of key-value pairs where keys are replaced by the result of calling
(reduce f pk path) where path is the path to this key through the nested
maps."
([f kvs] (flatten-map f nil kvs))
([f pk kvs]
(mapcat (fn [[k v]]
(if (map? v)
(flatten-map f (f pk k) v)
[[(f pk k) v]])) kvs)))
Example:
(flatten-map conj [] {:OUT
{:x 5
:x/A 21
:x/B 33
:y/A 24}})
=> ([[:OUT :x] 5] [[:OUT :x/A] 21] [[:OUT :x/B] 33] [[:OUT :y/A] 24])

Related

Get key by first element in value list in Clojure

This is similar to Clojure get map key by value
However, there is one difference. How would you do the same thing if hm is like
{1 ["bar" "choco"]}
The idea being to get 1 (the key) where the first element if the value list is "bar"? Please feel free to close/merge this question if some other question answers it.
I tried something like this, but it doesn't work.
(def hm {:foo ["bar", "choco"]})
(keep #(when (= ((nth val 0) %) "bar")
(key %))
hm)
You can filter the map and return the first element of the first item in the resulting sequence:
(ffirst (filter (fn [[k [v & _]]] (= "bar" v)) hm))
you can destructure the vector value to access the second and/or third elements e.g.
(ffirst (filter (fn [[k [f s t & _]]] (= "choco" s))
{:foo ["bar", "choco"]}))
past the first few elements you will probably find nth more readable.
Another way to do it using some:
(some (fn [[k [v & _]]] (when (= "bar" v) k)) hm)
Your example was pretty close to working, with some minor changes:
(keep #(when (= (nth (val %) 0) "bar")
(key %))
hm)
keep and some are similar, but some only returns one result.
in addition to all the above (correct) answers, you could also want to reindex your map to desired form, especially if the search operation is called quite frequently and the the initial map is rather big, this would allow you to decrease the search complexity from linear to constant:
(defn map-invert+ [kfn vfn data]
(reduce (fn [acc entry] (assoc acc (kfn entry) (vfn entry)))
{} data))
user> (def data
{1 ["bar" "choco"]
2 ["some" "thing"]})
#'user/data
user> (def inverted (map-invert+ (comp first val) key data))
#'user/inverted
user> inverted
;;=> {"bar" 1, "some" 2}
user> (inverted "bar")
;;=> 1

ClojureScript search in nested map and vector

I have an edn in which I have nested maps. I found one very good example for this Clojure: a function that search for a val in a nested hashmap and returns the sequence of keys in which the val is contained
(def coll
{:a "aa"
:b {:d "dd"
:e {:f {:h "hh"
:i "ii"}
:g "hh"}}
:c "cc"})
With this answer
(defn find-in [coll x]
(some
(fn [[k v]]
(cond (= v x) [k]
(map? v) (if-let [r (find-in v x)]
(into [k] r))))
coll))
My problem is that because of some I can't get a path for every result, only for the first logical truth. I tried map an keep but they break the recursion. How could I make this code to give back path to all of its results, not only the first one? Any help is appreciated.
You can use a helper function to turn a nested map into a flat map with fully qualified keys. Then find-in can just filter on the value and returns the matched keys.
(defn flatten-map [path m]
(if (map? m)
(mapcat (fn [[k v]] (flatten-map (conj path k) v)) m)
[[path m]]))
(defn find-in [coll x]
(->> (flatten-map [] coll)
(filter (fn [[_ v]] (= v x)))
(map first)))
With your sample:
(find-in coll "hh")
=>
([:b :e :f :h] [:b :e :g])
filter gives all of the results, where some will only give you the first result, or nil if there aren't any. Oftentimes the same problem can be solved by filtering then taking the first, rather than using some.

Clojure creating a flat map with for

I'm working my way through 4clojure and I'm stuck on Problem 156 (Map Defaults).
I can't figure out why the function bellow doesn't return a flat map
((fn [d k] (for [i k :let [r {}]]
(conj r [i d])))
[:a :b] [:foo :bar])
Current result is ({:foo [:a :b]} {:bar [:a :b]})
But I expected {:foo [:a :b], :bar [:a :b]}
Inside for, r is created anew in every iteration, gets populated with [i d] and gets yielded as an element of the lazy sequence. As a result, you obtain this sequence whose elements are small one-entry maps.
What you need is reduce. It loops over a sequence updating the accumulator using a function you provide:
(defn fun1 [d k]
(reduce
(fn [acc i] (conj acc [i d]))
{}
k))
It starts from an empty map, and for every element i in k it calls the lambda, which adds an entry to the map (passed to the lambda as acc). The result is one big map with all these entries.
Alternatively, you could just generate the key/value pairs with your for expression, and then use the into function to shove them all in a map:
((fn [d k] (into {} (for [i k] [i d])))
[:a :b] [:foo :bar])
; => {:foo [:a :b], :bar [:a :b]}
For those coming here looking for a flatmap function in Clojure, check out mapcat:
Returns the result of applying concat to the result of applying map to
f and colls.

Clojure Multi Maps

Very simple + silly question:
Does clojure provide multi maps? I currently have something like this:
(defn wrap [func]
(fn [mp x]
(let [k (func x)]
(assoc mp k
(match (get mp k)
nil [x]
v (cons v x))))))
(defn create-mm [func lst]
(reduce (wrap func) {} lst))
Which ends up creating a map, where for each key, we have a vector of all elements with that key. However, it seems like multi maps is a very basic data structure, and I wonder if clojure has it built-in.
Thanks
I don't think this is really necessary as a distinct type, as Clojure's flexibility allow you to quickly make your own by just using maps and sets. See here:
http://paste.lisp.org/display/89840
Edit (I should have just pasted this in since it's so small)
Example Code (Courtesy Stuart Sierra)
(ns #^{:doc "A multimap is a map that permits multiple values for each
key. In Clojure we can represent a multimap as a map with sets as
values."}
multimap
(:use [clojure.set :only (union)]))
(defn add
"Adds key-value pairs the multimap."
([mm k v]
(assoc mm k (conj (get mm k #{}) v)))
([mm k v & kvs]
(apply add (add mm k v) kvs)))
(defn del
"Removes key-value pairs from the multimap."
([mm k v]
(let [mmv (disj (get mm k) v)]
(if (seq mmv)
(assoc mm k mmv)
(dissoc mm k))))
([mm k v & kvs]
(apply del (del mm k v) kvs)))
(defn mm-merge
"Merges the multimaps, taking the union of values."
[& mms]
(apply (partial merge-with union) mms))
(comment
(def mm (add {} :foo 1 :foo 2 :foo 3))
;; mm == {:foo #{1 2 3}}
(mm-merge mm (add {} :foo 4 :bar 2))
;;=> {:bar #{2}, :foo #{1 2 3 4}}
(del mm :foo 2)
;;=> {:foo #{1 3}}
)
Extra test for the case pointed out in the comments:
(comment
(-> {} (add :a 1) (del :a 1) (contains? :a))
;;=> false
)

Dissoc multiple descendent keys of a map?

How can I search and dissoc multiple descendent keys.
Example:
(def d {:foo 123
:bar {
:baz 456
:bam {
:whiz 789}}})
(dissoc-descendents d [:foo :bam])
;->> {:bar {:baz 456}}
clojure.walk is useful in this kind of situations:
(use 'clojure.walk)
(postwalk #(if (map? %) (dissoc % :foo :bam) %) d)
If you wanted to implement it directly then I'd suggest something like this:
(defn dissoc-descendents [coll descendents]
(let [descendents (if (set? descendents) descendents (set descendents))]
(if (associative? coll)
(reduce
(fn [m [k v]] (if (descendents k)
(dissoc m k)
(let [new-val (dissoc-descendents v descendents)]
(if (identical? new-val v) m (assoc m k new-val)))))
coll
coll)
coll)))
Key things to note about the implementation:
It makes sense to convert descendents into a set: this will allow quick membership tests if the set of keys to remove is large
There is some logic to ensure that if a value doesn't change, you don't need to alter that part of the map. This is quite a big performance win if large areas of the map are unchanged.