I'm trying to use a .ini file as a configuration file, and to do so I'm using regex.
What I currently do is a getline of my file and for each line I get, I'm trying to determine if it is corresponding to a scope or not with the following regex : "^\[[a-zA-Z0-9]+\]$"
This regex works well according to https://regex101.com/ and Unix, but crash on my windows application (yes I try to make this app cross-platform)
So I'm wondering what is going wrong here, and why does this regex make the program crash, and how to solve this problem...
Thank everybody !
You've missed the quoting of the outer brackets. Try
^\[[a-zA-Z0-9]+\]$
or simpler
^\[\w+\]$
And don't forget to escape the \s in the c++ string ;)
See it here at regex101.
Related
I would need a regex to match my files named "something".Title"numberFrom1to99".mp4 on Windows' File Explorer, my first approach as a regex newbie was something like
"..mp4"
, but it didn't work, so i tried
"*.Title[1-9][0-9].mp4"
, that also did not work.
I would also like a tip on how to search regex related advices on Stackoverflow archive but also on the web, so that i can be specific, but without having the regex in the searching bar interact.
Thank you!
EDIT
About the second part of the question: in the question itself there is written "..mp4" but i wrote "asterisk"."asterisk".mp4, is there any universal way to write regex on the web without it having effect and without escaping the characters? (in that way the backslash shows inside the regex, and that could be misunderstood)
Try something like this:
(.*)\.[A-za-z]+\d+\.mp4
See this Regex Demo to get an explanation on the regex.
Use regex101.com to test your regexs
Here it is:
^[\s\S]*\.Title[1-9][0-9]?\.mp4$
I suggest regexr.com to find many interesting regexes(Favourites tab) and simple tutorial.
About the second part of the question: in the question itself there is written "..mp4" but i wrote "asterisk"."asterisk".mp4, is there any universal way to write regex on the web without it having effect and without escaping the characters? (in that way the backslash shows inside the regex, and that could be misunderstood)
I have written this regex that works, but honestly, it’s like 75% guesswork.
The goal is this: I have lots of imports in Xcode, like so:
#import <UIKit/UIKit.h>
#import "NSString+MultilineFontSize.h"
and I only want to return the categories that contain +. There are also lots of lines of code throughout the source which include + in other contexts.
Right now, this returns all of the proper lines throughout the Xcode project. But if there is one thing I’ve learned from googling and searching Stack Overflow for regex tutorials, it is that there are LOTS of different ways to do things. I’d love to see all of the different ways you guys can come up with that make it either more efficient or more bulletproof regarding potential spoofs or misses.
^\#import+.[\"]*+.(?:(?!\+).)*+.*[\"]
Thanks in advance for all of your help.
Update
Also I suppose I’ll accept the answer of whoever does this with the shortest string, without missing any possible spoofs. But again, thanks to everyone who participates in this learning experience.
Resources from answers
This is an awesome resource for practicing regex from Dan Rasmussen: RegExr
The first thing I notice is that your + characters are misplaced: t+. matches t one or more times, followed by a single character .. I'm assuming you wanted to match the end of import, followed by one or more of any character: import.+
Secondly, # doesn't need to be escaped.
Here's what I came up with: ^#import\s+(.*\+.*)$
\s+ matches one or more whitespace character, so you're guaranteed that the line actually starts with #import and not #importbutnotreally or anything else.
I'm not familiar with xcode syntax, but the following part of the expression, (.*\+.*), simply matches any string with a + character somewhere in it. This means invalid imports may be matched, but I'm working under the assumption your trying to match valid code. If not, this will need to be modified to validate the importer syntax as well.
P.S. To test your expression, try RegExr. You can hover over characters to check what they do.
sed 's:^#import \(.*[+].*\):\1:' FILE
will display
"NSString+MultilineFontSize.h"
for your sample.
I tried to make regex syntax for that but I failed.
I have 2 variables
PlayerInfo[playerid][pLevel]
and
Character[playerid]
and I want to catch only the second variable,I mean only the world what don't contain PlayerInfo, but cointains [playerid]
"(\S+)\[playerid\]" cath both words and (\S+[^PlayerInfo])\[playerid\] jump on some variables- they contais p,l,a,y ...
I need to replace in notepad++,all variables like Text[playerid] to ExClass [playerid][Text]
Couple Pluasible solutions.
List item
Notepad has a plugin called python script. Running regex from there
gives full regex functionality, the python version anyway, and a lot
of powerful potential beyond that. And I use the online python regex tester to help out.
RegRexReplace plugin helps create regex plugins in Notepad++, so when you do hit a limitation, you find out a lot quicker.
Or of course default to your alternate editor (I'm assuming you have
one?) or this online regex tool is absolutely amazing. You
can perform the action on the text online as well.
(I'd try to build a regex for you, but I'm a bit lost as to what you're looking for. Unless the Ivo Abeloos got it. If you're still coming up short, maybe a code example along with values displayed?)
Good luck!
It seems that Notepad++ support negative lookbehind since v6.
In notepad++ you could try to replace (.+)\[(.+)\] with ExClass\[\2\]\[\1\]
Try to use negative lookbehind.
(?<!PlayerInfo)\[playerid\]
EDIT: unfortunately notepad++ does not support negative lookbehind.
I tried to make a workaround based on the following naive idea:
(.[^o]|[^f]o)[playerid]
But this expression does not work either. Notepad++ seems to fail in alternative operator. Thus the answer is: it is impossible to do exactly what you want. Try to solve the problem in other way or use alternative tool.
In a LaTeX report I am making I have to write a regex. There is only one in the whole report, so I don't really want to use packages and so on.
This is the regex I am talking about:
^\"((\w|\s)+)\"$
I came up with this for LaTeX:
\grave{ }\backslash\"'((\backslash w\| \backslash s)+)\backslash \"' \backslash \$
This gives me like 10 errors, and I can't really see what is wrong. Okay, it looks pretty bad but all the commands should work.
Thanks in advance,
Harm
Use \verb/^\"((\w|\s)+)\"$/
Perhaps the problem is that some of those commands (\backslash, \grave) want to be in math mode, but \" doesn't. Have you tried using \verb to include the regexp verbatim? I'm not sure if it'll look like you want (it'll be typeset in a tt font), but you could do this with something like:
...
In my project I'm using a regexp \verb#^\"((\w|\s)+)\"# to do a thing.
...
Problem:
^.+ matches only the first line of the source code in dreamweaver. I need it to match each line so that I can wrap each full line in P tags. I have 500 files to do this in.
I know ^ should match the beginning of a line and I also know that multi-line mode must be enabled for it to work on each line and not just at the beginning of the file. I also know dreamweaver uses javascript source code.
Is lack of multi-line mode the problem? Is there any way to turn it on in dreamweaver? I tried using /m at the beginning search to enable multi-line mode, but that didn't work either.
I'm open to any solution for my current problem, even if it involves a different program. However, a fix for dreamweaver is ideal, 2nd place is a way to do this in notepad++, 3rd place is a way do to this in python or something (I only know javascript, you'll have to spell it out exactly in another language).
Thank you,
robert
p.s.
I found I can "select all > right click > selection > indent" to add two spaces to the beginning of each line in dreamweaver. This allows me to find the beginning of each line with / {2,}/. I really don't want to select all > indent on all 500 files, but i'm about to start since I've already spent a few hours bludgeoning dreamweaver.
Don't use Dreamweaver for this - use Notepad++ (since you are familiar with it) at its regular expression support is superior.
If you are comfortable with a more robust scripting language (Python, Ruby, Perl, etc.) then that would be an ever better way to do it.
The way that I might do this in DW would not involve using the find-replace tool's "Regular Expression" option, but instead using just plain old matching on a CrLf.
In the Find portion, since you can't directly enter a CrLf, you'll have to copy one to your clipboard beforehand and paste it in where needed.
In the Replace portion, replace with:
</p>[CrLf]
<p>
Again, be sure to paste in a proper "[CrLf]". This will work on all but the very first and very last lines of your document, so I know this isn't a 100% solution. There are probably better solutions using other tools that someone else can recommend!
Good luck!
-Mike
I had a flash of insight right after posting. (isn't that the way of it?)
Dreamweaver can find the end of each line with \r\n so instead of trying to work forward, i should have just worked backwards.
search: (.+)(\r\n)
replace: <p>$1</p>$2
[\w\W]* matches anything, including a newline. Its greedy, so it fact it matches everything.