Can you please help with the regular expression for the below problem pattern. I am unable to perform replace operation using regex.
Source string:
/search/zip-12345/district-324
Replacement expression would be /search.html?$1
The following regex /search/((?:"[^"]*"|[^:,])*) provides output as
/search.html?zip-12345/district-324
But the expected output is
/search.html?zip=12345&district=324
Use the following regex pattern:
(\/search)\/([^\/-]+)-([^\/]+)\/([^-]+)-(.*)
With substitution:
$1.html?$2=$3&$4=$5
https://regex101.com/r/m5lkw6/4
Related
I am pretty new in Regular Expression.
Input
/shop/earrings
/shop/yellow-gold-earrings
/shop/white-gold-earrings
/shop/rose-gold-earrings
/shop/necklaces
/shop/yellow-gold-necklaces
/shop/white-gold-necklaces
/shop/rose-gold-necklaces
/shop/best-buy-earrings
Regular Expression I used
\/shop\/[a-z-]*-?earrings
Desired Result
/shop/earrings
/shop/yellow-gold-earrings
/shop/white-gold-earrings
/shop/rose-gold-earrings
Actual Result
/shop/earrings
/shop/yellow-gold-earrings
/shop/white-gold-earrings
/shop/rose-gold-earrings
/shop/best-buy-earrings
I do not want /shop/best-buy-earrings to be in the result. Please help me to fix the Regular Expression. Thank you.
Simply add gold to the regex before the - and surround with parenthesis:
\/shop\/([a-z-]*gold-)?earrings
Assuming PCRE flavour, you can use:
\/shop\/(?!best-buy)(?:\w+-)*earrings
Or, if you can use other delimiter than slash:
/shop/(?!best-buy)(?:\w+-)*earrings
Demo
i have this txt
02/02
z/2019
i want it to look like this
02/02/2019
how can i achieve this using notepad++ regular expression function
This is possible with the "Extended" syntax only, you don't even need regular expressions.
Find: \r\nz
Replace:
In the following String:
Events('1234', '123456', '', 'QW233Cdse');
I need to extract "QW233Cdse"
Any suggestion?
When we are working with regular expressions then its very important that we should look for the static text in the test string that can help to create a strong regular expression.
As in your case, "Events()" seems to be a static text containing dynamic value in the round parenthesis so in order to generate the regular expression you need to keep 'Events()' text and add the expression in the round parenthesis as mentioned below:
Test String: Events('1234', '123456', '', 'QW233Cdse');
Regular Expression can be:
Events(.'(.)');
Events(.* '(.+?)');
Note: The backslash before round parentheses would avoid interpreting the round braces as unescaped character. For example, a parenthesis "(" begins the definition of a quantifier, but the leading backslash of parenthesis "(" indicates that the regular expression should match the parenthesis.
Regular expression is most important item to learn when you are working with load testing tools and you can refer to below blog post to get more information on regular expression:
https://www.redline13.com/blog/2016/01/jmeter-extract-and-re-use-as-variable/
Let me know if you have any further question
The relevant regular expression would be something like:
Events\(.* '(.+?)'\);
Demo:
References:
JMeter: Regular Expressions
Using Regular Expressions in JMeter
Perl 5 Regex Cheat sheet
Try using this regex:
\w+(?='\))
Regex would be:
, '([^']+?)');
Configuration would be:
I have the following part of a JSON response:
"created_at":"2017-05-08T14:01:25.903Z"
How should I configure my "Regular Expression Extractor" in JMeter to extract the first 10 characters from this JSON response: 2017-05-08.
Try the following pattern:
"created_at":"([0-9]{4}-[0-9]{2}-[0-9]{2}).*?"
If the syntax is always the same, you can use this one :
\d{4}-\d{2}-\d{2}
Demo here
If you need first 10 characters only the relevant regular expression would be as simple as
"created_at":"(.{1,10})
Demo:
References:
Apache JMeter: Regular Expressions
Perl 5 Regex Cheat sheet
Using RegEx (Regular Expression Extractor) With JMeter
the latex sample is as follows:
$F=K$,balalalala,balablal Bi$_x$Sb$_{1-x}$，balabla $abcd$ balabala
What I want to match is inline math expressions like $F=K$, $abcd$, while not those expressions with "_" after "$", like $_x$ and $_{1-x}$
So I write regex expression like this
\$[^_][^\$]+\$(?!_)
I add (?!_) because $Sb$ in the middle of Bi$_x$Sb$_{1-x}$ should not be considered as an math expression.
But the code is not working properly. It returns two expression
$F=K$ and $，balabla $.
What is the right regex expression for this problem?
your desired match needs a Lookbehind regex, somthing like:
\$[^$]+\$(?<!\$_[^$]+)
but we know that regex inside could not use + or * (must be fix-length), so the above regex is invalid.
I suggest to process the text in 2-pass. in first pass remove any $_xxx$ pattern :
perl -ne 's/(\$_[^\$]+\$)//g;print;'
and then match your desired pattern:
grep -oP '\$[^$]+\$'