I have a column in data frame which ex df:
A
0 Good to 1. Good communication EI : tathagata.kar#ae.com
1 SAP ECC Project System EI: ram.vaddadi#ae.com
2 EI : ravikumar.swarna Role:SSE Minimum Skill
I have a list of of strings
ls=['tathagata.kar#ae.com','a.kar#ae.com']
Now if i want to filter out
for i in range(len(ls)):
df1=df[df['A'].str.contains(ls[i])
if len(df1.columns!=0):
print ls[i]
I get the output
tathagata.kar#ae.com
a.kar#ae.com
But I need only tathagata.kar#ae.com
How Can It be achieved?
As you can see I've tried str.contains But I need something for extact match
You could simply use ==
string_a == string_b
It should return True if the two strings are equal. But this does not solve your issue.
Edit 2: You should use len(df1.index) instead of len(df1.columns). Indeed, len(df1.columns) will give you the number of columns, and not the number of rows.
Edit 3: After reading your second post, I've understood your problem. The solution you propose could lead to some errors.
For instance, if you have:
ls=['tathagata.kar#ae.com','a.kar#ae.com', 'tathagata.kar#ae.co']
the first and the third element will match str.contains(r'(?:\s|^|Ei:|EI:|EI-)'+ls[i])
And this is an unwanted behaviour.
You could add a check on the end of the string: str.contains(r'(?:\s|^|Ei:|EI:|EI-)'+ls[i]+r'(?:\s|$)')
Like this:
for i in range(len(ls)):
df1 = df[df['A'].str.contains(r'(?:\s|^|Ei:|EI:|EI-)'+ls[i]+r'(?:\s|$)')]
if len(df1.index != 0):
print (ls[i])
(Remove parenthesis in the "print" if you use python 2.7)
Thanks for the help. But seems like I found a solution that is working as of now.
Must use str.contains(r'(?:\s|^|Ei:|EI:|EI-)'+ls[i])
This seems to solve the problem.
Although thanks to #IsaacDj for his help.
Why not just use:
df1 = df[df['A'].[str.match][1](ls[i])
It's the equivalent of regex match.
Related
Getting stuck on how to read and pretty up these values from a multiline cell via arrayformula.
Im using regex as preceding line can vary.
just formulas please, no custom code
The first column looks like a set of these:
```
[config]
name = the_name
texture = blah.dds
cost = 1000
[effect0]
value = 1000
type = ATTR_A
[effect1]
value = 8
type = ATTR_B
[feature0]
name = feature_blah
[components]
0 = comp_one,1
[resources]
res_one = 1
res_five = 1
res_four = 1
<br/>
Where to be useful elsewhere, at minimum it needs each [tag] set ([effect\d], [feature\d], ect) to be in one column each, for example the 'effects' column would look like:
ATTR_A:1000,ATTR_B:8
and so on.
Desired output can also be seen in the included spreadsheet
<br/>
<b>Here is the example spreadsheet:</b>
https://docs.google.com/spreadsheets/d/1arMaaT56S_STTvRr2OxCINTyF-VvZ95Pm3mljju8Cxw/edit?usp=sharing
**Current REGEXREPLACE**
Kinda works, finds each 'type' and 'value' great, just cant figure out how to extract just that from the rest, tried capture (and non-capturing) groups before and after but didnt work
=ARRAYFORMULA(REGEXREPLACE($A3:$A,"[\n.][effect\d][\n.](.)\n(.)","1:$1 2:$2"))
**Current SUBSTITUTE + REGEXEXTRACT + REGEXREPLACE**
A different approach entirely, also kinda works, longer form though and left with having to parse the values out of that string, where got stuck again. Idea was to use this to simplify, then regexreplace like above. Getting stuck removing content around the final matches though, and if can do that then above approach is fine too.
// First ran a substitute
=ARRAYFORMULA(SUBSTITUTE(SUBSTITUTE($A3:$A,char(10),";"),";;",char(10)))
// Then variation of this (gave up on single line 'effect/d' so broke it up to try and get it working)
=ARRAYFORMULA(IF(A3:A<>"",IFERROR(REGEXEXTRACT(A3:A,"(?m)^(?:[effect0]);(.)$")&";;")&""&IFERROR(REGEXEXTRACT(A3:A,"(?m)^(?:[effect1]);(.)$")&";;")&""&IFERROR(REGEXEXTRACT(A3:A,"(?m)^(?:[effect2]);(.)$")&";;"),""))
// Then use regexreplace like above
=ARRAYFORMULA(REGEXREPLACE($B3:$B,"value = (.);type = (.);;","1:$1 2:$2"))
**--EDIT--**
Also, as my updated 'Desired Output' sheet shows (see timestamped comment below), bonus kudos if you can also extract just the values of matching 'type's to those extra columns (see spreadsheet).
All good if you cant though, just realized would need that too for lookups.
**--END OF EDIT--**
<br/>
Ive tried dozens of things, discarding each in turn, had a quick look in version history to grab out two promising attempts and shared them in separate sheets.
One of these also used SUBSTITUTE to simplify input column, im happy for a solution using either RAW or the SUBSTITUTE results.
<br/>
**Potentially Useful links:**
https://github.com/google/re2/wiki/Syntax
<br/>
<b>Just some more words:</b>
I also have looked at dozens of stackoverflow and google support pages, so tried both REGEXEXTRACT and REGEXREPLACE, both promising but missing that final tweak. And i tried dozens of tweaks already on both.
Any help would be great, and hopefully help others in future since examples with spreadsheets are great since every new REGEX seems to be a new adventure ;)
<br/>
P.S. if we can think of better title for OP, please say in comment or your answer :)
paste in B3:
=ARRAYFORMULA(SUBSTITUTE(TRIM(TRANSPOSE(QUERY(TRANSPOSE(
IF(C3:E<>"", C2:E2&":"&C3:E, )),,999^99))), " ", ", "))
paste in C3:
=ARRAYFORMULA(IFNA(REGEXEXTRACT($A3:$A, "(\d+)\ntype = "&C2)))
paste in D3:
=ARRAYFORMULA(IFNA(REGEXEXTRACT($A3:$A, "(\d+)\ntype = "&D2)))
paste in E3:
=ARRAYFORMULA(IFNA(REGEXEXTRACT($A3:$A, "(\d+)\ntype = "&E2)))
paste in F3:
=ARRAYFORMULA(IFNA(REGEXEXTRACT(A3:A, "\[feature\d+\]\nname = (.*)")))
paste in G3:
=ARRAYFORMULA(IFNA(REGEXEXTRACT(A3:A, "\[components\]\n\d+ = (.*)")))
paste in H3:
=ARRAYFORMULA(IFNA(REGEXREPLACE(INDEX(SPLIT(REGEXEXTRACT(
REGEXREPLACE(A3:A, "\n", ", "), "\[resources\], (.*)"), "["),,1), ", , $", )))
spreadsheet demo
This was a fun exercise. :-)
Caveat first: I have added some "input data". Examples:
[feature1]
name = feature_active_spoiler2
[components]
0 = spoiler,1
1 = spoilerA, 2
So the output has "extra" output.
See the tab ADW's Solution.
I'm using textacy's pos_regex_matches method to find certain chunks of text in sentences.
For instance, assuming I have the text: Huey, Dewey, and Louie are triplet cartoon characters., I'd like to detect that Huey, Dewey, and Louie is an enumeration.
To do so, I use the following code (on testacy 0.3.4, the version available at the time of writing):
import textacy
sentence = 'Huey, Dewey, and Louie are triplet cartoon characters.'
pattern = r'<PROPN>+ (<PUNCT|CCONJ> <PUNCT|CCONJ>? <PROPN>+)*'
doc = textacy.Doc(sentence, lang='en')
lists = textacy.extract.pos_regex_matches(doc, pattern)
for list in lists:
print(list.text)
which prints:
Huey, Dewey, and Louie
However, if I have something like the following:
sentence = 'Donald Duck - Disney'
then the - (dash) is recognised as <PUNCT> and the whole sentence is recognised as a list -- which it isn't.
Is there a way to specify that only , and ; are valid <PUNCT> for lists?
I've looked for some reference about this regex language for matching PoS tags with no luck, can anybody help? Thanks in advance!
PS: I tried to replace <PUNCT|CCONJ> with <[;,]|CCONJ>, <;,|CCONJ>, <[;,]|CCONJ>, <PUNCT[;,]|CCONJ>, <;|,|CCONJ> and <';'|','|CCONJ> as suggested in the comments, but it didn't work...
Is short, it is not possible: see this official page.
However the merge request contains the code of the modified version described in the page, therefore one can recreate the functionality, despite it's less performing than using a SpaCy's Matcher (see code and example -- though I have no idea how to reimplement my problem using a Matcher).
If you want to go down this lane anyway, you have to change the line:
words.extend(map(lambda x: re.sub(r'\W', '', x), keyword_map[w]))
with the following:
words.extend(keyword_map[w])
otherwise every symbol (like , and ; in my case) will be stripped off.
val = 345.09874
now i want output like 345.10, 345.09 and 345.099 in python 2.7
Please help me.
Just to encourage you I am providing the answer, but next time you should google first.
Use this:
print round(val,2)
I could get 2 out of 3 values using:
val = 345.09874
print("%.2f" % round(val,2)) #345.10
print("%.3f" % round(val,3)) #345.099
I dont know how to get the output with 345.09
It looks like a simple task, but how would you solve it? I don't get any solution right now.
ls_message-text = 'Pernr. 12345678 (Pete Peterson) is valid (06/2015).
append ls_message to lt_message.
ls_message-text = 'Pernr. 12345678 (Pete Peterson) is valid (07/2015).
append ls_message to lt_message.
This is the code I got, the thing is, this is the message I am showing in my application. The customer says that the 2 messages are the same. The second should be deleted.
How would you compare it to delete the line? The table might contain more then 2 lines and also with another text like "is not valid".
I can't extend the structure to have more fields for comparison, I can only use the string comparison on this one field. Are there string comparisons possible with a regex or something?
Maybe you could solve your requirement using the Levenshtein distance . ABAP has a built-in function "distance" that gives you the number of operations to convert one string into another. Ex:
DATA msg1 type string.
DATA msg2 type string.
msg1 = 'Levehnstein Distance 7/2015'.
msg2 = 'Levehnstein Distance 6/2015'.
data l_distance type i.
l_distance = distance( val1 = msg1 val2 = msg2 ).
if l_distance lt 2 .
"It's almost the same text
endif.
In this case l_distance will be 1, because only one operation is necessary (replacing).
Hope this helps,
Assuming you want to retain only one message for each unique Pernr. in lt_message, you can use regex to filter for the Pernr. and use that as "key". Now you can delete all but the first message of lt_message that matches this key.
Expand your regex if you want to keep only certain messages, e.g. only the "is valid" ones.
have you tried looking to program DEMO_REGEX_TOY.
Gives an idea on how to work with Regular expresion, that probably will save the problem
Hi so I'm trying to use find and replace in notepad++ with regular expression to do the following:
I have two set of lines
first set:
[c][eu][e]I37ANKCB[/e]
[c][eu][e]OIL8ZEPW[/e]
[c][eu][e]4OOEL75O[/e]
[c][eu][e]PPNW5FN4[/e]
[c][eu][e]E2BXCWUO[/e]
[c][eu][e]SD9UQNT8[/e]
[c][eu][e]E6BK6IGO[/e]
second set:
[u]7ubju2jvioks[u2]_261
[u]89j408tah1lz[u2]_262
[u]j673xnd49tq0[u2]_263
[u]dv73osmh1wzu[u2]_264
[u]twz3u4yiaeqr[u2]_265
[u]cuhtg6r71kud[u2]_266
[u]yts0ktvt9a3r[u2]_267
now I want to the second set to by places after each of the first set like this:
[c][eu][e]I37ANKCB[/e][u]7ubju2jvioks[u2]_261
[c][eu][e]OIL8ZEPW[/e][u]89j408tah1lz[u2]_262
[c][eu][e]4OOEL75O[/e][u]j673xnd49tq0[u2]_263
[c][eu][e]PPNW5FN4[/e][u]dv73osmh1wzu[u2]_264
[c][eu][e]E2BXCWUO[/e][u]twz3u4yiaeqr[u2]_265
[c][eu][e]SD9UQNT8[/e][u]cuhtg6r71kud[u2]_266
[c][eu][e]E6BK6IGO[/e][u]yts0ktvt9a3r[u2]_267
any suggestions?
You can mark the second block in column mode using ALT and the left mouse button. Then just copy paste it at the end of the first row.
No need/Not possible using regex.
I would solve this via a simple script written in Python or Ruby or something equally quick. This works, for example:
import os
path = os.path.dirname(__file__)
with open(os.path.join(path, 'file1')) as file1:
with open(os.path.join(path, 'file2')) as file2:
lines = zip(file1.readlines(), file2.readlines())
print ''.join([a.rstrip() + b for a, b in lines])
Running it gives the correct result:
> python join.py
[c][eu][e]I37ANKCB[/e][u]7ubju2jvioks[u2]_261
[c][eu][e]OIL8ZEPW[/e][u]89j408tah1lz[u2]_262
[c][eu][e]4OOEL75O[/e][u]j673xnd49tq0[u2]_263
[c][eu][e]PPNW5FN4[/e][u]dv73osmh1wzu[u2]_264
[c][eu][e]E2BXCWUO[/e][u]twz3u4yiaeqr[u2]_265
[c][eu][e]SD9UQNT8[/e][u]cuhtg6r71kud[u2]_266
[c][eu][e]E6BK6IGO[/e][u]yts0ktvt9a3r[u2]_267
Customize to suit your needs.