Memory occupied by reference to a variable in cpp [duplicate] - c++

This question already has answers here:
How does a C++ reference look, memory-wise?
(9 answers)
Closed 5 years ago.
Declaring pointer:
int a;
int *x=&a;
x occupies 8 bytes of memory
Likewise if we declare a reference to a variable:
int a;
int &x =a;
How much memory does the the reference to a occupy?

That's undefined. Not as in Undefined Behavior, but the question simply doesn't have an answer.

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int* getAddress(int var) {
return &var;
}
How does this function work? The return type is int pointer but the line return &var; returns a memory address not a pointer.
Also, if I understand correctly, a memory address and pointer I different. A memory address is an address to a specific part in memory while a pointer stores a memory address.

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For example, if I have:
int num;
double num2;
int* ptr;
Are these variables just randomly allocated some memory?

different types of array declaration in c++ [duplicate]

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Array as array[n] and as pointer array*
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I have just been starting with C++ and I have come across multiple types of array declaration in C++
int data[3];
and other type is,
int *data= new data[3];
What is the difference between the two?
Since, I have not allocated memory in the first case will I overwrite memory which may already be in use and potentially cause segmentation error?

Is deleting a null pointer in C++ considered undefined behaviour? [duplicate]

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Consider the following piece of code:
int main() {
int *i = nullptr;
delete i;
}
Questions:
Is deleting a null pointer considered undefined behaviour?
Did something changed in C++11 or C++14?
Is deleting a NULL pointer in C++ considered undefined behaviour?
No, this is perfectly legal operation.
From N3242, [expr.delete]
the value of the operand of delete may be a null pointer
value

C C++ difference between & an * [duplicate]

This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
What are the differences between pointer variable and reference variable in C++?
Pointer vs. Reference
I recently started to 'relearn' c++ and encountered a simple question that i always had.
Int *intp = new int(10);
Int& intref = *intp;
intref prints as 10
*intp does so too.
Also do the prints of &intref and intp equal.
Long story short. Is the difference between & and * simply the way you access the value and adress?
Or is there a major difference in usage?
The * notation means what's being pass on the stack is a pointer, ie, address of something. The & says it's a reference.
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