My Question:
I have this exercise ;
If the verb ends in e, drop the e and add ing (if not exception: be, see, flee, knee, etc.)
If the verb ends in ie, change ie to y and add ing
For words consisting of consonant-vowel-consonant, double the final letter before adding ing
By default just add ing
Your task in this exercise is to define a function make_ing_form() which given a verb in infinitive form returns its present participle form. Test your function with words such as lie, see, move and hug. However, you must not expect such simple rules to work for all cases.
My code:
def make_ing_form():
a = raw_input("Please give a Verb: ")
if a.endswith("ie"):
newverb = a[:-2] + "y" + "ing"
elif a.endswith("e"):
newverb = a[:3] + "ing"
elif a[1] in "aeiou":
newverb = a + a[-1] + "ing"
else:
newverb = a + "ing"
print newverb
make_ing_form()
With this code all is gut , but when i change the placement ;
def make_ing_form():
a = raw_input("Please give a verb: ")
if a.endswith("e"):
newverb = a[:3] + "ing"
elif a.endswith("ie"):
newverb = a[:-2] + "y" + "ing"
elif a[1] in "aeiou":
newverb = a + a[-1] + "ing"
else:
newverb = a + "ing"
print newverb
make_ing_form()
the answer who i come are not on present participle , how i Understand here http://python.net/~goodger/projects/pycon/2007/idiomatic/handout.html#python-has-names , when the identifier change to another statement ( from If to Elif), it "forget" the if statement .If that's the case , why i to receive this result ?
sorry about my English ....
In the second code it will never enter the first elif ( elif a.endswith("ie"): ) because if a verb ends in ie (ex. lie) it would enter the if, as lie ends in e. You should have the condition as in the first code. If you have more problems with your first code let me know.
Related
First of all, I am sorry about the weird question heading. Couldn't express it in one line.
So, the problem statement is,
If I am given the following string --
"('James Gosling'/jamesgosling/james gosling) , ('SUN Microsystem'/sunmicrosystem), keyword"
I have to parse it as
list1 = ["'James Gosling'", 'jamesgosling', 'jame gosling']
list2 = ["'SUN Microsystem'", 'sunmicrosystem']
list3 = [ list1, list2, keyword]
So that, if I enter James Gosling Sun Microsystem keyword it should tell me that what I have entered is 100% correct
And if I enter J Gosling Sun Microsystem keyword it should say i am only 66.66% correct.
This is what I have tried so far.
import re
def main():
print("starting")
sentence = "('James Gosling'/jamesgosling/jame gosling) , ('SUN Microsystem'/sunmicrosystem), keyword"
splited = sentence.split(",")
number_of_primary_keywords = len(splited)
#print(number_of_primary_keywords, "primary keywords length")
number_of_brackets = 0
inside_quotes = ''
inside_quotes_1 = ''
inside_brackets = ''
for n in range(len(splited)):
#print(len(re.findall('\w+', splited[n])), "length of splitted")
inside_brackets = splited[n][splited[n].find("(") + 1: splited[n].find(")")]
synonyms = inside_brackets.split("/")
for x in range(len(synonyms)):
try:
inside_quotes_1 = synonyms[x][synonyms[x].find("\"") + 1: synonyms[n].find("\"")]
print(inside_quotes_1)
except:
pass
try:
inside_quotes = synonyms[x][synonyms[x].find("'") + 1: synonyms[n].find("'")]
print(inside_quotes)
except:
pass
#print(synonyms[x])
number_of_brackets += 1
print(number_of_brackets)
if __name__ == '__main__':
main()
Output is as follows
'James Gosling
jamesgoslin
jame goslin
'SUN Microsystem
SUN Microsystem
sunmicrosyste
sunmicrosyste
3
As you can see, the last letters of some words are missing.
So, if you read this far, I hope you can help me in getting the expected output
Unfortunately, your code has a logic issue that I could not figure it out, however there might be in these lines:
inside_quotes_1 = synonyms[x][synonyms[x].find("\"") + 1: synonyms[n].find("\"")]
inside_quotes = synonyms[x][synonyms[x].find("'") + 1: synonyms[n].find("'")]
which by the way you can simply use:
inside_quotes_1 = synonyms[x][synonyms[x].find("\x22") + 1: synonyms[n].find("\x22")]
inside_quotes = synonyms[x][synonyms[x].find("\x27") + 1: synonyms[n].find("\x27")]
Other than that, you seem to want to extract the words with their indices, which you can extract them using a basic expression:
(\w+)
Then, you might want to find a simple way to locate the indices, where the words are. Then, associate each word to the desired indices.
Example Test
# -*- coding: UTF-8 -*-
import re
string = "('James Gosling'/jamesgosling/james gosling) , ('SUN Microsystem'/sunmicrosystem), keyword"
expression = r'(\w+)'
match = re.search(expression, string)
if match:
print("YAAAY! \"" + match.group(1) + "\" is a match 💚💚💚 ")
else:
print('🙀 Sorry! No matches! Something is not right! Call 911 👮')
i am new to Python and i cant get this.I have a List and i want to take the input from there and write those in files .
p = ['Eth1/1', 'Eth1/5','Eth2/1', 'Eth2/4','Eth101/1/1', 'Eth101/1/2', 'Eth101/1/3','Eth102/1/1', 'Eth102/1/2', 'Eth102/1/3','Eth103/1/1', 'Eth103/1/2', 'Eth103/1/3','Eth103/1/4','Eth104/1/1', 'Eth104/1/2', 'Eth104/1/3','Eth104/1/4']
What i am trying :
with open("abc1.txt", "w+") as fw1, open("abc2.txt", "w+") as fw2:
for i in p:
if len(i.partition("/")[0]) == 4:
fw1.write('int ' + i + '\n mode\n')
else:
i = 0
while i < len(p):
start = p[i].split('/')
if (start[0] == 'Eth101'):
i += 3
key = start[0]
i += 1
while i < len(p) and p[i].split('/')[0] == key:
i += 1
end = p[i-1].split('/')
fw2.write('confi ' + start[0] + '/' + start[1] + '-' + end[1] + '\n mode\n')
What i am looking for :
abc1.txt should have
int Eth1/1
mode
int Eth1/5
mode
int Eth2/1
mode
int Eth 2/4
mode
abc2.txt should have :
int Eth101/1/1-3
mode
int Eth102/1/1-3
mode
int Eth103/1/1-4
mode
int Eth104/1/1-4
mode
So any Eth having 1 digit before " / " ( e:g Eth1/1 or Eth2/2
)should be in one file that is abc1.txt .
Any Eth having 3 digit before " / " ( e:g Eth101/1/1 or Eth 102/1/1
) should be in another file that is abc2.txt and .As these are in
ranges , need to write it like Eth101/1/1-3, Eth102/1/1-3 etc
Any Idea ?
I don't think you need a regex here, at all. All your items begin with 'Eth' followed by one or more digits. So you can check the length of the items before first / occurs and then write it to a file.
p = ['Eth1/1', 'Eth1/5','Eth2/1', 'Eth2/4','Eth101/1/1', 'Eth101/1/2', 'Eth101/1/3','Eth102/1/1', 'Eth102/1/2', 'Eth102/1/3','Eth103/1/1', 'Eth103/1/2', 'Eth103/1/3','Eth103/1/4','Eth104/1/1', 'Eth104/1/2', 'Eth104/1/3','Eth104/1/4']
with open("abc1.txt", "w+") as fw1, open("abc2.txt", "w+") as fw2:
for i in p:
if len(i.partition("/")[0]) == 4:
fw1.write('int ' + i + '\n mode\n')
else:
fw2.write('int ' + i + '\n mode\n')
I refactored your code a little to bring with-statement into play. This will handle correctly closing the file at the end. Also it is not necessary to iterate twice over the sequence, so it's all done in one iteration.
If the data is not as clean as provided, then you maybe want to use regexes. Independent of the regex itself, by writing if re.match(r'((Eth\d{1}\/\d{1,2})', "p" ) you proof if a match object can be created for given regex on the string "p", not the value of the variable p. This is because you used " around p.
So this should work for your example. If you really need a regex, this will turn your problem in finding a good regex to match your needs without any other issues.
As these are in ranges , need to write it like Eth101/1/1-3, Eth102/1/1-3 etc
This is something you can achieve by first computing the string and then write it in the file. But this is more like a separate question.
UPDATE
It's not that trivial to compute the right network ranges. Here I can present you one approach which doesn't change my code but adds some functionality. The trick here is to get groups of connected networks which aren't interrupted by their numbers. For that I've copied consecutive_groups. You can also do a pip install more-itertools of course to get that functionality. And also I transformed the list to a dict to prepare the magic and then retransformed dict to list again. There are definitely better ways of doing it, but this worked for your input data, at least.
#!/usr/bin/env python3
# -*- coding: utf-8 -*-
from itertools import groupby
from operator import itemgetter
p = ['Eth1/1', 'Eth1/5', 'Eth2/1', 'Eth2/4', 'Eth101/1/1', 'Eth101/1/2',
'Eth101/1/3', 'Eth102/1/1', 'Eth102/1/2', 'Eth102/1/3', 'Eth103/1/1',
'Eth103/1/2', 'Eth103/1/3', 'Eth103/1/4', 'Eth104/1/1', 'Eth104/1/2',
'Eth104/1/3', 'Eth104/1/4']
def get_network_ranges(networks):
network_ranges = {}
result = []
for network in networks:
parts = network.rpartition("/")
network_ranges.setdefault(parts[0], []).append(int(parts[2]))
for network, ranges in network_ranges.items():
ranges.sort()
for group in consecutive_groups(ranges):
group = list(group)
if len(group) == 1:
result.append(network + "/" + str(group[0]))
else:
result.append(network + "/" + str(group[0]) + "-" +
str(group[-1]))
result.sort() # to get ordered results
return result
def consecutive_groups(iterable, ordering=lambda x: x):
"""taken from more-itertools (latest)"""
for k, g in groupby(
enumerate(iterable), key=lambda x: x[0] - ordering(x[1])
):
yield map(itemgetter(1), g)
# only one line added to do the magic
with open("abc1.txt", "w+") as fw1, open("abc2.txt", "w+") as fw2:
p = get_network_ranges(p)
for i in p:
if len(i.partition("/")[0]) == 4:
fw1.write('int ' + i + '\n mode\n')
else:
fw2.write('int ' + i + '\n mode\n')
The following code is for one of my excercises to pass the subject,
This is my code:
rot13=raw_input("Please write your text! ")
This is where i ask the user for a text
for i in range(len(rot13)):
And in this part I check the text letter by letter with for.
if rot13[i]=="a":
rot13[i]="n"
elif rot13[i]=="b":
rot13[i]="o"
elif rot13[i]=="c":
rot13[i]="p"
elif rot13[i]=="d":
rot13[i]="q"
elif rot13[i]=="e":
rot13[i]="r"
elif rot13[i]=="f":
rot13[i]="s"
elif rot13[i]=="g":
rot13[i]="t"
elif rot13[i]=="h":
rot13[i]="u"
elif rot13[i]=="i":
rot13[i]="v"
elif rot13[i]=="j":
rot13[i]="w"
elif rot13[i]=="k":
rot13[i]="x"
elif rot13[i]=="l":
rot13[i]="y"
elif rot13[i]=="m":
rot13[i]="z"
elif rot13[i]=="n":
rot13[i]="a"
elif rot13[i]=="o":
rot13[i]="b"
elif rot13[i]=="p":
rot13[i]="c"
elif rot13[i]=="q":
rot13[i]="d"
elif rot13[i]=="r":
rot13[i]="e"
elif rot13[i]=="s":
rot13[i]="f"
elif rot13[i]=="t":
rot13[i]="g"
elif rot13[i]=="u":
rot13[i]="h"
elif rot13[i]=="v":
rot13[i]="i"
elif rot13[i]=="w":
rot13[i]="j"
elif rot13[i]=="x":
rot13[i]="k"
elif rot13[i]=="y":
rot13[i]="l"
elif rot13[i]=="z":
rot13[i]="m"
print rot13
Does anyone knows why this is not working? I do not want to do it with encode.
There are a couple of issues with your code.
First, you're trying to assign a character to a string, but strings are immutable, so you can't swap out chars using =. Second, you don't need to hardcode each character and its mapping. You should use the modulus operator (%).
The basic solution is to loop through each char, turn it into a number, add 13 to it, and turn it back into a character. You'll have to consider the case where your input is "z" and the resulting character lies beyond the alphabet. That's where you'll have to use the modulus operator to force the character to wrap around.
Here's an example:
def rot13(string):
result = []
for char in string:
shiftBy = 65 # uppercase 'A'
if char.islower():
shiftBy = 97 # lowercase 'a'
newChar = chr(((ord(char) + 13 - shiftBy) % 26) + shiftBy)
result.append(newChar)
return ''.join(result)
print rot13("abcXYZ")
ord converts a character to its numeric representation (e.g. 'a' becomes 97)
chr does the reverse computation (e.g. 97 becomes 'a')
I am trying to create a simple "guess the word" game in Python. My output is something like:
String: _____ _____
Guess a word: 'e'
String:_e__o __e_e
Guess a word: 'h'
(and so on)
String: hello there
I have a function to do this, and within this function I have this code:
def guessing(word):
count = 0
blanks = "_" * len(word)
letters_used = "" #empty string
while count<len(word):
guess = raw_input("Guess a letter:")
blanks = list(blanks)
#Checks if guesses are valid
if len(guess) != 1:
print "Please guess only one letter at a time."
elif guess not in ("abcdefghijklmnopqrstuvwxyz "):
print "Please only guess letters!"
#Checks if guess is found in word
if guess in word and guess not in letters_used:
x = word.index(guess)
for x in blanks:
blanks[x] = guess
letters_used += guess
print ("".join(blanks))
print "Number of misses remaining:", len(word)-counter
print "There are", str(word.count(guess)) + str(guess)
guess is the raw input I get from the user for a guess, and letters_used is just a collection of guesses that the user has already input. What I'm trying to do is loop through blanks based on the word.index(guess). Unfortunately, this returns:
Guess a letter: e
e___
Yes, there are 1e
Help would be much appreciated!
Your code was almost correct. There were few mistakes which I have corrected:
def find_all(needle, haystack):
"""
Finds all occurances of the string `needle` in the string `haystack`
To be invoked like this - `list(find_all('l', 'hello'))` => #[2, 3]
"""
start = 0
while True:
start = haystack.find(needle, start)
if start == -1: return
yield start
start += 1
def guessing(word):
letters_uncovered_count = 0
blanks = "_" * len(word)
blanks = list(blanks)
letters_used = ""
while letters_uncovered_count < len(word):
guess = raw_input("Guess a letter:")
#Checks if guesses are valid
if len(guess) != 1:
print "Please guess only one letter at a time."
elif guess not in ("abcdefghijklmnopqrstuvwxyz"):
print "Please only guess letters!"
if guess in letters_used:
print("This character has already been guessed correctly before!")
continue
#Checks if guess is found in word
if guess in word:
guess_positions = list(find_all(guess, word))
for guess_position in guess_positions:
blanks[x] = guess
letters_uncovered_count += 1
letters_used += guess
print ("".join(blanks))
print "Number of misses remaining:", len(word)-letters_uncovered_count
print "There are", str(word.count(guess)) + str(guess)
else:
print("Wrong guess! Try again!")
I've been working on a small contact importer, and now I'm trying to implement a block that automatically selects the output file format based on the number of contacts to be imported.
However, every time it results in the error:
KeyError: 'q'
I can't figure out for the life of me why this is happening, and I would love any help offered.
My idea of scalability is that the dictionary personDict would be of the format personDict = {nameid:[name,email]}, but nothing works.
Any help is good help,
Thanks
def autoFormat():
while True:
name = input("Enter the person's name \n")
if name == "q":
break
email = input("Enter the person's email \n")
personDict[name] = [name, email]
if len(personDict) <= 10:
keyValue = personDict[name]
for keyValue in personDict:
for key, value in personDict.iteritems():
combined = "BEGIN:VCARD\nVERSION:4.0\n" + "FN:" + name + "\n" + "EMAIL:" + email + "\n" + "END:VCARD"
fileName = name + ".vcl"
people = open(fileName, 'a')
people.write(combined)
people.close()
print("Created file for " + name)
autoFormat()
The main problem is that when the user types "q" your code leaves the while loop
with name keeping "q" as value. So you should remove this useless line:
keyValue = person_dict[name]
Since there is no element with key "q" in your dictionary.
Also in the export part you write in file values different from those you loop with.
Your code becomes:
if len(personDict) <= 10:
for name, email in personDict.values():
combined = "BEGIN:VCARD\nVERSION:4.0\n" + "FN:" + name + "\n" + "EMAIL:" + email + "\n" + "END:VCARD"
fileName = name + ".vcl"
people = open(fileName, 'a')
people.write(combined)
people.close()
print("Created file for " + name)