Copy constructor inheritance dynamically allocated array - c++

Question

I have the following class where I need to make a copy constructor which copies a dynamically allocate array. However, in the code below it uses the constructor of C and not the copy constructor. How do I fix this?
#ifndef B_HH
#define B_HH
#include <iostream>
#include "C.hh"
class B {
public:
B() { std::cout << "Constructor B" << this << std::endl ; array = new C[len];}
B(const B& other): array(other.array) { std::cout << "Copy Constructor B" << this << std::endl ;
array = new C[len];
for(int i=0;i<len;i++)
{
array[i] = other.array[i];
}
}
~B() { std::cout << "Destructor B" << this << std::endl ; delete[] array;}
private:
C *array;
static const int len = 12;
} ;
#endif
And my class C looks like this:
#ifndef C_HH
#define C_HH
#include <iostream>
class C {
public:
C() { std::cout << "Constructor C" << this << std::endl ; }
C(const C&) { std::cout << "Copy Constructor C" << this << std::endl ; }
~C() { std::cout << "Destructor C" << this << std::endl ; }
private:
} ;
#endif

Answer 1

This line will call len number of default C constructors
array = new C[len];
Then this line should actually call the copy assignment operator
array[i] = other.array[i];
Add this line to C and you will see this is a copy assignment
C& operator=(const C&)
{
std::cout << "Copy Assignment Operator C" << this << std::endl;
/* do actual copying here */
}

Answer 2

How do I fix this?
Well, you don't need to. In this case that is the proper behavior. Since you need to make a deep copy when you do
array = new C[len];
In B's copy constructor you default construct len number of C's in the memory location new gives you. You then call copy assignment operator of C len times in
for(int i=0;i<len;i++)
{
array[i] = other.array[i];
}