Counter adding items to array with remainder - c++

Question

I am creating an RPG shop. It must have items, gold, and item price. Essentially creating an inventory. What i am trying to accomplish is, where the players gold is 0 they cannot add any more items to their inventory, and cannot have negative gold.
When running my code in debug mode it appears to be doing what i want, but when the function exits the amount the player requested has not been countered.
Keep in mind i am still new to c++.
Thanks
#include <iostream>
#include <string>
using namespace std;
// Global consts
const int numItems = 4;
const string items[numItems] = {"boots", "hats", "cats", "bats"}; // create string array of numItems items.
// Create stuct, that holds:
// Item, gold, price.
struct Inv {
int pInv[numItems] = {0, 0, 0, 0};
int gold = 100;
int itemPrice[numItems] = { 10, 6, 12, 15 };
}inv;
void iniItems();
void printItems();
bool buyItems();
bool sellItems();
int main() {
bool isDone = false;
iniItems();
while (isDone == false) {
printItems();
int choice;
bool x = false;
cout << "\nWhat would you like to do? Enter (" << 1 << "-" << 2 << "): " << endl;
cout << "1: Buy Items. \n2: Sell Items." << endl; cin >> choice; cout << endl;
while (x == false) {
if (choice == 1) {
x = buyItems();
}
if (choice == 2) {
x = sellItems();
}
}
}
system("pause");
// dynamic memory not implemented yet. Must wait for working fix of shoppe.cpp
}
void iniItems() {
cout << "** Shop Inventory: **" << endl;
for (int i = 0; i < numItems; i++) {
cout << i + 1 << " - " << items[i] << " - price: $" << inv.itemPrice[i] << endl;
}
}
void printItems() {
cout << "\n** Player Inventory: **" << endl;
cout << "Gold: $" << inv.gold << endl;
for (int i = 0; i < numItems; i++) {
cout << inv.pInv[i] << " x " << items[i] << endl;
}
}
bool buyItems() {
bool exit = false;
int amount;
const int remainder = 10;
printItems();
cout << "\nEnter -1 to quit." << endl;
cout << "What would you like to buy? Enter (" << 1 << "-" << 4 << "): " << endl;
// Get item info.
while (exit == false) {
int inp;
cout << "Item: "; cin >> inp; cout << endl;
cout << "Amount: "; cin >> amount; cout << endl;
// Check if input is valid.
if (inp > 0 && inp <= numItems) {
if (amount >= 0) {
inv.pInv[inp - 1] = 1 * amount;
inv.gold = inv.itemPrice[inp - 1] / amount;
}
// If gold is 0, make sure the user cannot gain more items.
if (inv.gold <= 0) {
int tmp;
inv.gold = 0;
tmp = remainder - amount;
for (int i = tmp; i >= 0; i++) {
inv.pInv[inp - 1]--;
}
return inv.pInv[inp - 1];
}
if (inp == -1) {
return true;
}
if (inp > numItems) {
cout << "Enter valid number." << endl;
return false;
}
else return false;
}
}
if (exit == true) {
return true;
}
}

Answer 1

So i limited the code down into a do while loop with a counter for the gold, in the buyItems() function.
Here it is, if anyone is interested.
do {
inv.gold -= inv.itemPrice[inp - 1];
++(inv.pInv[inp - 1]);
} while (inv.gold > 0);
if (inv.gold < 0) {
inv.gold = 0;
inv.pInv[inp - 1]--;
}
printItems();