XSLT - Select content between two special characters - regex

Question

I have a xml like this,
<doc>
<p>text1 <xml version="1.0" encoding="UTF-16"
standalone="yes"?> text2</p>
</doc>
I need to remove the text content between < and > form above text using XSLT. So expected output is,
<doc>
<p>text1 text2</p>
</doc>
I tried to use regex but I'm wondering how I can catch text between < and > form regex.
Any idea how I can do this using XSLT?

Answer 1

This Should Work.
(<(?:.?\n?)*>)
Then Replace with "" (empty)
Input:
<doc>
<p>text1 <xml version="1.0" encoding="UTF-16"
standalone="yes"?> text2</p>
</doc>
Output:
<doc>
<p>text1 text2</p>
</doc>
See: https://regex101.com/r/0o9hol/1

Answer 2

Using just XSLT-1.0 you can achieve this by applying the following template:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" />
<xsl:template match="p">
<xsl:value-of select="concat(normalize-space(substring-before(text(), '<')),' ',normalize-space(substring-after(text(), '>')))" />
</xsl:template>
<!-- identity template -->
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*" />
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
This template just copies all nodes with the identity template and applies a special treatment to all <p> elements.
The special treatment of the <p> nodes extracts the text() nodes before < and after > while normalizing the space character occurrence(reducing their count to one) and concatenates the result.
That's all.