I've been trying to get this to work for an hour now but can't seem to do it, neither with the help of SO articles, or Regex101.com.
Have have some data and would like to return the lines that does not contain "/Common/http". Example data:
/Common/http and /Common/Another
/Common/http-mymon
/Common/another /Common/http
another line
The result I am looking for is:
/Common/http-mymon
another line
Any regex I use must match the whole line or it fails in the engine I use (https://github.com/jayway/JsonPath). This means that http would not work, but .*http.* would.
Hope this is fairly clear?
/Patrik
You can use a negative lookahead regex like this:
^(?:.*?/Common/http-mymon|(?!.*/Common/http)).*$
RegEx Demo
Update:
As per comment below OP wants to exclude /Common/http followed by / or a whitespace. In that case try this regex:
^(?!.*/Common/http(?:/|\s)).*$
RegEx Demo 2
I think you can go with the following regex
^(?!.*\/Common\/http(?:\s))(.*?)$
This one is checking for no /Common/http in front before space using negative lookahead (?!.*\/Common\/http(?:\s))
Related
I am trying to remove a whole phrase from my regex(PCRE) matches
if given the following strings
test:test2:test3:test4:test5:1.0.department
test:test2:test3:test4:test5:1.0.foo.0.bar
user.0.display
"test:test2:test3:test4:test5:1.0".division
I want to write regex that will return:
.department
.foo.0.bar
user.0.display
.division
Now I thought a good way to do this would be to match everything and then remove test:test2:test3:test4:test5:1.0 and "test:test2:test3:test4:test5:1.0" but I am struggling to do this
I tried the following
\b(?!(test:test2:test3:test4:test5:1\.0)|("test:test2:test3:test4:test5:1\.0"))\b.*
but this seems to just remove the first tests from each and thats all. Could anyone help on where I am going wrong or a better approach maybe?
I suggest searching for the following pattern:
"?test:test2:test3:test4:test5:1\.0"?
and replacing with an empty string. See the regex demo and the regex graph:
The quotation marks on both ends are made optional with a ? (1 or 0 times) quantifier.
I'm having an issue with Regex.
I'm trying to match T0000001 (2, 3 and so on).
However, some of the lines it searches has what I can describe as positioners. These are shown as a question mark, followed by 2 digits, such as ?21.
These positioners describe a new position if the document were to be printed off the website.
Example:
T123?214567
T?211234567
I need to disregard ?21 and match T1234567.
From what I can see, this is not possible.
I have looked everywhere and tried numerous attempts.
All we have to work off is the linked image. The creators cant even confirm the flavour of Regex it is - they believe its Python but I'm unsure.
Regex Image
Update
Unfortunately none of the codes below have worked so far. I thought to test each code in live (Rather than via regex thinking may work different but unfortunately still didn't work)
There is no replace feature, and as mentioned before I'm not sure if it is Python. Appreciate your help.
Do two regex operations
First do the regex replace to replace the positioners with an empty string.
(\?[0-9]{2})
Then do the regex match
T[0-9]{7}
If there's only one occurrence of the 'positioners' in each match, something like this should work: (T.*?)\?\d{2}(.*)
This can be tested here: https://regex101.com/r/XhQXkh/2
Basically, match two capture groups before and after the '?21' sequence. You'll need to concatenate these two matches.
At first, match the ?21 and repace it with a distinctive character, #, etc
\?21
Demo
and you may try this regex to find what you want
(T(?:\d{7}|[\#\d]{8}))\s
Demo,,, in which target string is captured to group 1 (or \1).
Finally, replace # with ?21 or something you like.
Python script may be like this
ss="""T123?214567
T?211234567
T1234567
T1234434?21
T5435433"""
rexpre= re.compile(r'\?21')
regx= re.compile(r'(T(?:\d{7}|[\#\d]{8}))\s')
for m in regx.findall(rexpre.sub('#',ss)):
print(m)
print()
for m in regx.findall(rexpre.sub('#',ss)):
print(re.sub('#',r'?21', m))
Output is
T123#4567
T#1234567
T1234567
T1234434#
T123?214567
T?211234567
T1234567
T1234434?21
If using a replace functionality is an option for you then this might be an approach to match T0000001 or T123?214567:
Capture a T followed by zero or more digits before the optional part in group 1 (T\d*)
Make the question mark followed by 2 digits part optional (?:\?\d{2})?
Capture one or more digits after in group 2 (\d+).
Then in the replacement you could use group1group2 \1\2.
Using word boundaries \b (Or use assertions for the start and the end of the line ^ $) this could look like:
\b(T\d*)(?:\?\d{2})?(\d+)\b
Example Python
Is the below what you want?
Use RegExReplace with multiline tag (m) and enable replace all occurrences!
Pattern = (T\d*)\?\d{2}(\d*)
replace = $1$2
Usage Example:
I have lines like this:
example.com/p/stuff/...
example.com/page/thing/...
example.com/page/stuff/...
example.com/page/other-stuff/...
etc
where the dots represent continuing URL paths. I want to select URLs that contain /page/ and are NOT followed by thing/. So from the above list we would select:
example.com/page/stuff/...
example.com/page/other-stuff/...
.*?\/page\/[^(thing)].*
this is the regex for matching a string which has /page/ not followed by thing
adding the lazy evalation is suggested because you advance a char at the time, better performance!
You need to use negative lookahead:
example\.com\/page\/(?!thing\/).*
Demo
Use the following regex pattern:
.*?\/page\/(?!thing\/).*
https://regex101.com/r/19wh1w/2
(?!thing\/) - negative lookahead assertion ensures that page/ section is not followed by thing/
I use service kimono to parse some data and this service has specific 3-group regular expression tool.
first group is text before the needed one, than expression for text I need, and third is expression after the needed text.
So, by default it looks like: /^()([^]*?)()$/
I have a sentence like {Olive oil in glass bottle 500 ml.} and I need to get only text after second space from the end, except last point, so that result should be: 500 ml
Any of my tries have not succeeded.
If you have support of lookahead you can try this.
^(.*?(?=\s[^ ]*\s[^ ]*$))([^.]*?)(.)$
See demo.
https://regex101.com/r/vD5iH9/35
or
^([^\d]*)([^.]*?)(.)$
See demo.
https://regex101.com/r/vD5iH9/36
or
^(.*?\s)([^\s]*\s[^\s]*)(\.)$
See demo.
https://regex101.com/r/vD5iH9/37
Use the below regex and then get the string you want from group index 1.
^.*?\s(?=\S*\s\S*$)([^.]*)\.
(?=\S*\s\S*$) positive lookahead asserts that there must be a single space exists.
DEMO
How about:
(\S+\s+\S+)\.$
The text you want is in the group 1.
I am writing a parser for some Oracle commands, like
LOAD DATA
INFILE /DD/DATEN
TRUNCATE
PRESERVE BLANKS
INTO TABLE aaa.bbb
( some parameters... )
I already created a regex to match the entire command. I am now looking for a way to capture the name of the input file ("/DD/DATEN" for instance here).
My problem is that using the following regex will only return the last character of the first group ("N").
^\s*LOAD DATA\s*INFILE\s*(\w|\\|/)+\s*$
Debuggex Demo
Any ideas?
Many thanks in advance
EDIT: following #HamZa 's question, here would be the entire regex to parse Oracle LOAD DATA INFILE command (simplified though):
^\s*LOAD DATA\s*INFILE\s*((?:\w|\\|/)+)\s*((?:TRUNCATE|PRESERVE BLANKS)\s*){0,2}\s*INTO TABLE\s*((?:\w|\.)+)\s*\(\s*((\w+)\s*POSITION\s*\(\s*\d+\s*\:\s*\d+\s*\)\s*((DATE\s*\(\s*(\d+)\s*\)\s*\"YYYY-MM-DD\")|(INTEGER EXTERNAL)|(CHAR\s*\(\s*(\d+)\s*\)))\s*\,{0,1}\s*)+\)\s*$
Debuggex Demo
Let's point out the wrongdoer in your regex (\w|\\|/)+. What happens here ?
You're matching either a word character or a back/forwardslash and putting it in group 1 (\w|\\|/) after that you're telling the regex engine to do this one or more times +. What you actually want is to match those characters several times before grouping them. So you might use a non-matching group (?:) : ((?:\w|\\|/)+).
You might notice that you could just use a character class after all ([\w\\/]+). Hence, your regex could look like
^\s*LOAD DATA\s*INFILE\s*([\w\\/]+)\s*$
On a side note: that end anchor $ will cause your regex to fail if you're not using multiline mode. Or is it that you intentionally didn't post the full regex :) ?
Not tested but...
^\s*LOAD DATA\s*INFILE\s*(\S+)\s*$