I have a huge text file with over 20K lines of content. I am using editplus 4.0 version to achieve my desired result.
What I want to do is;
I want to insert/append a keyword, randomly in the content. Now, the condition is, I want to insert my keyword once for every 60 lines.
If I achieve this, next I have another app which can split my huge content into multiple lines based on line count, which is 60 in this case.
So, end of the day I will have my content into multiple text files and every file includes my keyword which I am going to use it for blog posting.
Please suggest me if I can do this with editplus, other ways of achieving the same will also welcome.
I tried lot of options but no luck.
Thanks in advance !!
AFAIK editplus doesn't work with regex.
I suggest you to use Notepad++, with it you can do:
Ctrl+H
Find what: ((?:[^\r\n]*\R){60})
Replace with: $1KEYWORD\n
Replace all
Don't forget to select Regular expression in search mode.
Related
This probably isn't a VS Code-specific question but it's my tool of choice.
I have a log file with a lot of lines containing the following:
Company.Environment.Security.RightsBased.Policies.RightsUserAuthorizationPolicy
Those are debug-level log records that clutter the file I'm trying to process. I'm looking to remove the lines with that content.
I've looked into Regex but, unlike removing a blank line where you have the whole content in the search criteria (making find/replace easy), here I need to match from line break to line break on some criteria between the two, I think...
What are your thoughts on how criteria like that would work?
If the criteria is a particular string and you don't want to have to remember regexes, there is a few handy keyboard shortcuts that can help you out. I'm going to assume you're on a Mac.
Cmd-F to open find.
Paste your string.
Opt-Enter to select all of the instances of the string on the page.
Cmd-L to broaden the selection to the entire line of each instance on the page.
Delete/Backspace to remove those lines.
I think you should be able to just search for ^.*CONTENT.*$\n, where the content is the text you showed us. That is, search on the following pattern:
^.*Company\.Environment\.Security\.RightsBased\.Policies\.RightsUserAuthorizationPolicy.*$\n
And then just replace with empty string.
I have already up-voted answer of #james. But.. still I found one more easy and many feature available extension in VS Code. Here it is
It have much easy options to apply filters.
To match specific case mentioned in question. I am attaching screenshot which display how to use for it. I am posting this for others who come here in search for same issue. (Like I came)
I've seen people asking stuff related to regex and i thought id ask my quesstion. I have a file with many lines like this:
374327711199385
and I need to make it to this per each line:
3743-277111-99385
It's a big file so can't do it manually. Any ideas on how to make it automatic with regex? Thanks so much!
To perform this, you need to search with this expression:
^(\d{4})(\d{6})(\d{5})$
And replace with this:
$1-$2-$3
I am having a small problem regarding removal of last line from text files. I have over 500 text files and in each of them the last line is simply blank. I want to find some quick method to delete these empty lines. I am looking for some search and replace method to remove these lines.
So far I have tried searching \r\n and other methods but nothing works. Only thing that works is by going to edit->line operations-> Remove Empty Lines but it is cumbersome to do this individually for each file.
So is there any way to achieve this?
Ahmar
Have a try with:
Find what: \n$
Replace with: NOTHING
Use the regular expression \r\n\Z.
Search > Find in Files. You're looking for \r\n\Z, replace with nothing, and make sure Regular Expression is checked at the bottom.
I've been searching a lot in the web and in here but I can't find a solution to this.
I have to make two replacements in all registry paths saved in a text file as follows:
replace all asterisc with: [#42]
replace all single backslashes with two.
I already have two expressions that do this right:
1st case:
Find: (\*) - Replace: \[#42\]
2nd case:
Find: ([^\\])(\\)([^\\]) - Replace: $1$2\\$3
Now, all I want is to join them together into just one expression so that I can do run this in one time only.
I'm using Notepad++ 6.5.1 in Windows 7 (64 bits).
Example line in which I want this to work (I include backslashes but i don't know if they will appear right in the html):
HKLM\SOFTWARE\Classes\*\shellex\ContextMenuHandlers\
I already tried separating it with a pipe, like I do in Jscript (WSH), but it doesn't work here. I also tried a lot of other things but none worked.
Any help?
Thanks!
Edit: I have put all the backslashes right, but the page html seem to be "eating" some of them!
Edit2: Someone reedited my text to include an accent that doesn't remove the backslashes, so the expressions went wrong again. But I got it and fixed it. ;-)
Sorry, but this was my first post here. :)
As everyone else already mentioned this is not possible.
But, you can achieve what you want in Notepad++ by using a Macro.
Go to "Macro" > "Start Recording" menu, apply those two search and replace regular expressions, press "Stop Recording", then "Save Current Recorded Macro", there give it a name, assign a shortcut, and you are done. You now can reuse the same replacements whenever you want with one shortcut.
Since your replacement strings are totally different and use data that come not from any capture (i.e. [#42]), you can't.
Keep in mind that replacement strings are only masks, and can not contain any conditional content.
Problem:
^.+ matches only the first line of the source code in dreamweaver. I need it to match each line so that I can wrap each full line in P tags. I have 500 files to do this in.
I know ^ should match the beginning of a line and I also know that multi-line mode must be enabled for it to work on each line and not just at the beginning of the file. I also know dreamweaver uses javascript source code.
Is lack of multi-line mode the problem? Is there any way to turn it on in dreamweaver? I tried using /m at the beginning search to enable multi-line mode, but that didn't work either.
I'm open to any solution for my current problem, even if it involves a different program. However, a fix for dreamweaver is ideal, 2nd place is a way to do this in notepad++, 3rd place is a way do to this in python or something (I only know javascript, you'll have to spell it out exactly in another language).
Thank you,
robert
p.s.
I found I can "select all > right click > selection > indent" to add two spaces to the beginning of each line in dreamweaver. This allows me to find the beginning of each line with / {2,}/. I really don't want to select all > indent on all 500 files, but i'm about to start since I've already spent a few hours bludgeoning dreamweaver.
Don't use Dreamweaver for this - use Notepad++ (since you are familiar with it) at its regular expression support is superior.
If you are comfortable with a more robust scripting language (Python, Ruby, Perl, etc.) then that would be an ever better way to do it.
The way that I might do this in DW would not involve using the find-replace tool's "Regular Expression" option, but instead using just plain old matching on a CrLf.
In the Find portion, since you can't directly enter a CrLf, you'll have to copy one to your clipboard beforehand and paste it in where needed.
In the Replace portion, replace with:
</p>[CrLf]
<p>
Again, be sure to paste in a proper "[CrLf]". This will work on all but the very first and very last lines of your document, so I know this isn't a 100% solution. There are probably better solutions using other tools that someone else can recommend!
Good luck!
-Mike
I had a flash of insight right after posting. (isn't that the way of it?)
Dreamweaver can find the end of each line with \r\n so instead of trying to work forward, i should have just worked backwards.
search: (.+)(\r\n)
replace: <p>$1</p>$2
[\w\W]* matches anything, including a newline. Its greedy, so it fact it matches everything.