I have a text (see below) where
I would like to extract the date only for the specific status, when the date appears after "New on Date".
I want the formula to answer: if the status is "New" then extract the "date".
I tried this: =If(A2 = "New",REGEXEXTRACT(A2,"(\d{1,}?\/\d{1,}?\/\d{4})"),)
I also tried the same by adding Find and Search but still unsuccessful.
I know that this part of the formula works: REGEXEXTRACT(A2,"(\d{1,}?\/\d{1,}?\/\d{4})")
But I do not manage to find the other part: Would anyone have a guess?
Contract Rejected/Contract Withdrew on Date: 11/11/2016 6:23:33 AM and Modified by: Eletttt|| Offer Negotiation on Date: 6/2/2016 5:36:04 AM and Modified by: Dexx|| HR Screening on Date: 4/14/2016 2:30:57 AM and Modified by: Dexxx|| New on Date: 4/14/2016 2:24:58 AM and Modified by: Dexxx|| Contract sent on Date: 6/7/2016 11:03:58 AM and Modified by: Chrisyyy|| Pending Contract Approval on Date: 6/7/2016 4:56:55 AM and Modified by: Debxxx|| HM Interview on Date: 5/10/2016 12:40:30 AM and Modified by: Debxxx
If you need to extract the date after New on Date, you need to add this text to the pattern and keep the capturing group where it is now:
=REGEXEXTRACT(A2, "New on Date:\s*(\d{1,2}/\d{1,2}/\d{4})")
See the screenshot (with the data inside B29 cell):
See the regex demo.
Here is a simpler one for you:
=REGEXEXTRACT(A1,"New on Date:\s(\d\S+)")
Related
when inspecting content of email body I want to detect when a distribution list name contains "DL" in the "To" field or the "CC" field but not in the subject.
Basically i want my text (DL) detected when found between the closest "To:" and the closest "Subject".
The best I can do is the following but it detects everything from the very first instance of "To:" with a subsequent DL until the very last instance of "Subject"
(?<=To: )(?s:.)*?( DL | DL-)(?s:.)*?(?=Subject:)
expected results: "DL-" from DL-Musketeers but not the "DL" in the subject line if the distribution list wasn't present
From: Mouse, Mickey <JMouse#Disney.com<mailto:JMouse#Disney.com>>
Sent: Thursday, May 26, 2022 8:14 AM
To: Mouse, Minnie <DMouse#Disney.com<mailto:DMouse#Disney.com>>
Cc: Disney, Joseph R <JDisney#Disney.com<mailto:JDisney#Disney.com>> DL-Musketeers#Disney.com
Subject: RE: DL commission
Thanks in advance.
I was able to find a solution with help from #Barmar.
What I'm using is:
(?<=To:)(.)*?( DL | DL-)(?s:.)*?(?=Subject:)|(?<=Cc:)(.)*?( DL | DL-)(?s:.)*?(?=Subject:)
In Google Sheets i want to reformat this datetime Mon, 08 Mar 2021 10:57:15 GMT into this 08/03/2021.
Using RegEx i achieve the goal with
=to_date(datevalue(REGEXEXTRACT("Mon, 08 Mar 2021 10:57:15 GMT","\b[0-9]{2}\s\D{3}\s[0-9]{4}\b")))
But how can i do it without RegEx? This datetime format seems to be a classic one - can it really be, that no onboard formula can't do it? I rather think, i miss the right knowledge here...
Please try the following formula and format as date
=TRIM(LEFT(INDEX(SPLIT(K13,","),,2),12))*1
(do adjust according to your locale)
Another option is to use Custom Script.
Example:
Code:
function formatDate(date) {
return Utilities.formatDate(new Date(date), "GMT", "dd/MM/YYYY")
}
Formula in B1: =formatDate(A1)
Output:
Reference:
Custom Functions in Google Sheets
I have a text file with data formatted as below. Figured out how to format the second part of the file to format it for upload into a db table. Hitting a wall trying to get the just the first 7 lines to format in the same way.
If it wasn't obvious, I'm trying to get it pipe delimited with the exact same number of columns, so I can easily upload it to the db.
Year: 2019 Period: 03
Office: NY
Dept: Sales
Acct: 111222333
SubAcct: 11122234-8
blahblahblahblahblahblahblah
Status: Pending
1000
AAAAAAAAAA
100,000.00
2000
BBBBBBBBBB
200,000.00
3000
CCCCCCCCCC
300,000.00
4000
DDDDDDDDDD
400,000.00
some kind folks answered my question about the bottom part, using the following code I can format that to look like so -
(.*)\r?\n(.*)\r?\n(.*)(?:\r?\n|$)
substitute with |||||||$1|$2|$3\n
|||||||1000|AAAAAAAAAA|100,000.00
|||||||2000|BBBBBBBBBB|200,000.00
|||||||3000|CCCCCCCCCC|300,000.00
|||||||4000|DDDDDDDDDD|400,000.00
just need help formatting the top part - to look like this, so the entire file matches with the exact same number of columns.
Year: 2019|Period: 03|Office: NY|Dept: Sales|Acct: 111222333|SubAcct: 11122234-8|blahblahblahblahblahblahblah|Status: Pending|||
I'm ok with having multiple passes on the file to get the desired end result.
I've helped you on your previous question, so I will focus now on the first part of your file.
You can use this regex:
\n|\b(?=Period)
Working demo
And use | as the replacement string
If you don't want the previous space before Period, then you can use:
\n|\s(?=Period)
I want to display friendly format date just like whatsapp and telegram do. For example, for today's date it shows "today" and yesterday date it shows "yesterday". But I don't want to show three days before as "3 days ago". It should be the regular date like this "Sun, 7 Jul 2019".
I don't have any custom to the current code because it still uses the example from the repo. But I tried to change the format but none of that works.
What does your code look like? You'd have to do some logic like
if (daysAgo > -2) {
return <FormattedRelativeTime numeric="auto" unit="day" value={daysAgo} />
}
return <FormattedDate weekday="short" day="numeric" month="short" year="numeric" value={ts} />
I wanted to separate the time and date from this string using REGEX because I feel like it is the only way I can separate it. But I am not really familiar on how to do it maybe someone can help me out here.
The original string: Your item was delivered in or at the mailbox at 3:34 pm on September 1, 2016 in TEXAS, MT 59102
The output i want to achieve/populate:
lv_time = 3:34 pm
lv_date = September 1, 2016
Here's the code I was trying to do but I am only able to cut it like this:
lv_status = Your item was delivered in or at the mailbox at
lv_time = 3
lv_date = :34 pm on September 1, 2016 in TEXAS, MT 59102.
Here's the code I have so far:
DATA: lv_status TYPE string,
lv_time TYPE string,
lv_date TYPE string,
lv_off TYPE i.
lv_status = 'Your item was delivered in or at the mailbox at 3:34 pm on September 1, 2016 in TEXAS, MT 59102.'.
FIND REGEX '(\d+)\s*(.*)' IN lv_status SUBMATCHES lv_time lv_date MATCH OFFSET lv_off.
lv_status = lv_status(lv_off).
You asked for it, here it comes:
\b((1[0-2]|0?[1-9]):([0-5][0-9]) ([AaPp][Mm])) on (January|February|March|April|May|June|July|August|September|October|November|December)\D?(\d{1,2}\D?)?\D?((?:19[7-9]\d|20\d{2})|\d{2})
This accepts time in HH:MM am/pm format, and dates in Jan-Dec, dd 1970-2999.
Each part is captured in its own group.
The demo shows a version that allows abbreviated month names:
Demo