This question already has answers here:
How can I read an input string of unknown length?
(11 answers)
Closed 6 years ago.
I want to know if it's possible to read a string of unknown size, until space or until newline is reached. What I did in c++ is this:
char * dynStr;
char buffer[20];
cin >> buffer;
dynStr = new char[strlen(buffer) +1];
strcpy(dynStr, buffer);
But the problem is, what if the entered input is bigger than 20? So I think it should be something like this:
do
{
cin.get ( buffer, 20, ' '); //im not sure this is the right approach
strcpy(.....); // if is not a first iteration
//add the new buffer to the end of dyn str..
} while( ! read ' ' or '\n' ) <--- this is what I have problem doing
I know in c++ I can use std::string , but I'd like to know how to do this thing, so if you have any ideas, tell me :)
get() and several other methods, can only read until a single specific character has been read. You want to read until either a newline or a space is received.
For a simple situation like that, it is better to simply use
cin.get();
to read one character at a time, appending it to your string, checking each character for a space or a newline is read. Depending on your specific situation you might need to use peek(); also.
This may not be very efficient, but for a simple excersize in reading from a stream this would be a good starting point. After you get that working, you could then read the documentation for the read() method, and implement a more sophisticated algorithm for reading and buffering larger chunks of text, from the stream, and then manually searching each read buffer for the next space or newline, and if found save the remaining text in the buffer to be processed later.
Start with a simple initial logic that reads one character at a time, and then progress to a more sophisticated approach.
Related
I want to read an entire line of a file character by character using gzgetc and stop when the newline is encountered. I know there is a function to grab the entire line but I would like to try to do it this way first. I tried:
Int c;
do {
c = gzgetc((gzFile) fp);
cout << c;
} while (c != '\n');
The result was an infinite loop. I tried adding (char) before c, still the same result. What am I doing wrong? The data file I am trying to read is encoded in base64 and I want to read in each token separated by space. Some of the lines are variable length and have a mixture of encoded and not encoded data which I set up an algorithm for I just need to know how to stop at newline.
You need to also check for gzgetc() returning -1, which indicates an error or end of file, and exiting the loop in that case. Your infinite loop is likely due to one of those.
I have a secret "mission" to write Vigenère cipher with it's analysis with ascii alphabet.
I have some troubles with encrypting text.
There are two kinds of them:
1) If I use whole ascii table, there are some troubles with decrypting text, because i use "system" chars that kills my text (by the way, it is "War and Peace" written by Tolstoy). Should i use it truncated version?
if yes, so - could i do operations from next question with truncated ascii table?
2) I want to have whole my text in one string. I can do it by this:
string s;
string p = "";
ifstream in("text_for_encryption.txt");
while (getline(in, s))
{
p+=s;
p+="\n";
}
"s" is the temporary string, and "p" is the string that has all text from file in it (with endl's and, of course, EOF)
i will make a cycle for "p" which looks like as
while (not eof in p)
{
take first keyword.length() chars from "p"? check every of them for EOF and encrypt them. (they will be deleted from p)
kick them in file "encrypted_text.txt"
}
in pseudocode (yeah, it is shit-like :( ).
so, the question is - how can i compare a string element with eof?
maybe, i can't google good, but i couldn't find the answer for this question.
Thanks in advance for every advice!
Update:
if i will encrypt string-by-string, it wll be easy to get a length of a key by Fridman's method (if the key is quite small).
so i want to encrypt text with endl's for more security
For encrypting, it depends largely on what you want to encrypt,
and what you want to do with the encrypted text. The usual
solution is to encrypt the bytes values (not the characters);
this means that you'll have to read and write the encrypted file
in binary mode, but since it's not meant to be readable anyway,
that's usually not an issue.
For the rest, strings do not have "EOF" characters. In fact,
there is no such thing as an EOF character[1]. (Nor en endl
character, either.) EOF is, in fact, an "event" which occurs
when reading from a stream; in C++, it is, in fact, treated as
a sort of an error. std::istream functions which can return
EOF (e.g. std::istream::get()) return int, and not char,
in order to be able to return an out of band value.
Strings do have a known length. To visit all of the characters
in a string:
for ( std::string::const_iterator current = s.begin();
current != s.end();
++ current ) {
// Do something with *current...
}
(If you have C++11, you can replace
std::string::const_iterator with auto. This is much simpler
to type, but until you master the iterator idioms, it's probably
better to write the type out, to ensure you understand what is
going on.)
[1] Historically, text files have had EOF characters on some
systems. This is not the end of file that you see with
std::istream::get(), but even today, if you open a file in
text mode under Windows, a 0x1A in the file will trigger the end
of file event in the input.
Hi this might seem a bit noobie, but here we go. Im developing a program that downloads leaderboards of a certain game from the internet and transforms it into a proper format to work with it (elaborate rankings, etc).
The files contains the names, ordered by rank, but between each name there are 7 random control codes (obivously unprintable). The txt file looks like this:
..C...hName1..)...&Name2......)Name3..é...þName4..Ü...†Name5..‘...QName6..~...bName7..H...NName8..|....Name9..v...HName10.
Checked via an hexEditor and saw the first control code after each name is always a null character (0x00). So, what I do is read everything, and then cout every character. When a 0x00 character is found, skip 7 characters and keep couting. Therefore you end up with the list, right?
At first I had the problem that on those random control codes, sometimes you would find like a "soft EOF" (0x1A), and the program would stop reading there. So I finally figured out to open it in binary mode. It worked, and then everything would be couted... or thats what I thought.
But I came across another file which still didn't work, and finally found out that there was an EOF character! (0x0A) Which doesn't makes sense since Im opening it in binary mode. But still, after reading that character, C++ interprets that as a new file, and hence skips 7 characters, so the name after that character will always appear cut.
Here's my current code:
#include <cstdlib>
#include <iostream>
#include <fstream>
using namespace std;
int main () {
string scores;
system("wget http://certainwebsite/001.txt"); //download file
ifstream highin ("001.txt", ios::binary);
ofstream highout ("board.txt", ios::binary);
if (highin.is_open())
{
while ( highin.good() )
{
getline (highin, scores);
for (int i=0;i<scores.length(); i++)
{
if (scores[i]==0x00){
i=i+7; //skip 7 characters if 'null' is found
cout << endl;
highout << endl;
}
cout << scores[i];
highout << scores[i]; //cout names and save them in output file
}
}
highin.close();
}
else cout << "Unable to open file";
system("pause>nul");
}
Not sure how to ignore that character if being already in binary mode doesn't work. Sorry for the long question but I wanted to be detailed and specific. In this case, the EOF character is located before the Name3, and hence this is how the output looks like:
http://i.imgur.com/yu1NjoZ.png
By default getline() reads until the end of line and discards the newline character. However, the delimiter character could be customized (by supplying the third parameter). If you wish to read until the null character (not until the end of line), you could try using getline (highin, scores, '\0'); (and adjusting the logic of skipping the characters).
I'm glad you figured it out and it doesn't surprise me that getline() was the culprit. I had a similar issue dealing with the newline character when I was trying to read in a CSV file. There are several different getline() functions in C++ depending on how you call the function and each seems to handle the newline character differently.
As a side note, in your for loop, I'd recommend against performing a method call in your test. That adds unnecessary overhead to the loop. It'd be better to call the method once and put that value into a variable, then enter the loop and test i against the length variable. Unless you expect the length to change, calling the length() method each iteration is a waste of system resources.
Thank you all guys, it worked, it was the getline() which was giving me problems indeed. Due to the 'while' loop, each time it found a new line character, it restarted the process, hence skipping those 7 characters.
When accessing a text file, I want to read from a specific line. Let's suppose that my file has 1000 rows and I want to read row 330. Each row has a different number of characters and could possibly be quite long (let's say around 100,000,000 characters per row). I'm thinking fseek() can't be used effectively here.
I was thinking about a loop to track linebreaks, but I don't know how exactly how to implement it, and I don't know if that would be the best solution.
Can you offer any help?
Unless you have some kind of index saying "line M begins at position N" in the file, you have to read characters from the file and count newlines until you find the desired line.
You can easily read lines using std::getline if you want to save the contents of each line, or std::istream::ignore if you want to discard the contents of the lines you read until you find the desired line.
There is no way to know where row 330 starts in an arbitrary text file without scanning the whole file, finding the line breaks, and then counting.
If you only need to do this once, then scan. If you need to do it many times, then you can scan once, and build up a data structure listing where all of the lines start. Now you can figure out where to seek to to read just that line. If you're still just thinking about how to organize data, I would suggest using some other type of data structure for random access. I can't recommend which one without knowing the actual problem that you are trying to solve.
Create an index on the file. You can do this "lazily" but as you read a buffer full you may as well scan it for each character.
If it is a text file on Windows that uses a 2-byte '\n' then the number of characters you read to the point where the newline occurs will not be the offset. So what you should do is a "seek" after each call to getline().
something like:
std::vector< off_t > lineNumbers;
std::string line;
lineNumbers.push_back(0); // first line begins at 0
while( std::getline( ifs, line ) )
{
lineNumbers.push_back(ifs.tellg());
}
last value will tell you where EOF is.
I think you need to scan the file and count the \n occurrences since you find the desired line. If this is a frequent operation, and you are the only one you write the file, you can possibly mantain an index file containing such information side by side with the one containing the data, a sort of "poor-man-index", but can save a lot of time.
Try running fgets in a loop
/* fgets example */
#include <stdio.h>
int main()
{
FILE * pFile;
char mystring [100];
pFile = fopen ("myfile.txt" , "r");
if (pFile == NULL) perror ("Error opening file");
else {
fgets (mystring , 100 , pFile);
puts (mystring);
fclose (pFile);
}
return 0;
}
I am reading in a file with multiple lines of data like this:
:100093000202C4C0E0E57FB40005D0E0020C03B463
:1000A3000105D0E0022803B40205D0E0027C03027C
:1000B30002E3C0E0E57FB40005D0E0020C0BB4011D
I am reading in values byte by byte and storing them in an array.
fscanf_s(in_file,"%c", &sc); // start code
fscanf_s(in_file,"%2X", &iByte_Count); // byte count
fscanf_s(in_file,"%4X", &iAddr); // 2 byte address
fscanf_s(in_file,"%2X", &iRec_Type); // record type
for(int i=0; i<iByte_Count; i++)
{
fscanf_s(in_file,"%2X", &iData[i]);
iArray[(iMaskedAddr/16)][iMaskedNumMove+3+i]=iData[i];
}
fscanf_s(in_file,"%2X", &iCkS);
This is working great except when I get to the end of the first line. I need this to repeat until I get to the end of the file but when I put this in a loop it craps out.
Can I force the position to the begining of the next line?
I know I can use a stream and all that but I am dealing with this method.
Thanks for the help
My suggestion is to dump fscanf_s and use either fgets or std::getline.
That said, your issue is handling the newlines, and the next beginning of record token, the ':'.
One method is to use fscanf_s("%c") until the ':' character is read or the end of file is reached:
char start_of_record;
do
{
fscanf_s(infile, "%c", &start_of_record);
} while (!feof(infile) && (start_of_record != ':'));
// Now process the header....
The data the OP is reading is a standard format for transmitting binary data, usually for downloading into Flash Memories and EPROMs.
Your topic clear states that you are using C++ so, if I may, I suggest you use the correct STL stream manipulators.
To read line-by-line, you can use ifstream::getline. But again, you are not reading the file line by line, you are reading it field by field. So, you should try using ifstream::read, which lets you choose the amount of bytes to read from the stream.
UPDATE:
While doing an unrelated search over the net, I found out about a library called IOF which may help you with this task. Check it out.