This question already has an answer here:
Learning Regular Expressions [closed]
(1 answer)
Closed 6 years ago.
I apologize in advance if this already has an answer but the best I could find relevant was:
Regex to test if a string ends with a number
Which is not exactly what I am looking for.
I am trying to figure a regex for a fixed string ending with number.
So lets say my fixed string is "This is Sparta"
So the regex would match for
"This is Sparta9"
"This is Sparta100"
"This is Sparta87"
"This is Sparta21"
"This is Sparta8"
But will not match for anything else before and after the string so
"This is Sparta7e" would not match
"Hi, This is Sparta7" would not match
"This is Sparta and 7" would not match
So basically a fixed String (CONSTANT) ending with number is the kind of regex I am looking for.
You just need your constant followed by at least one digit (\d+):
private static Pattern SPARTA_REGEX = Pattern.compile("This is Sparta(\\d)+");
Related
This question already has an answer here:
Find 'word' not followed by a certain character
(1 answer)
Closed 2 years ago.
I need an regex that match
"my dog", "My dog", "my &dog"
but not
"my dog#", "My dog#"
for search string "my dog". I have this expression at the moment by I have this:
reg_replace("/\b(my dog)\b/ui",'found','My dog');
But this obviously matches "my dog#" and not "My &dog". Any help would be appreciated.
my..?dog$
. = any Space
.? = 0 or 1 of any Space
$ = end of string
As not casesensitive this doesnt matter.
If you only have these, you can make a ".?" to get this one Dog with "&"
with end of string, you can simply get these other dogs you dont want out there.
Tested with regex101, if only these values are there, this is enough.
Flags = gsmi (Global, Multiline, singleline, insensitive)
This question already has an answer here:
Reference - What does this regex mean?
(1 answer)
Closed 2 years ago.
I have this string like "682_2, 682_3, 682_4". (682 is a random number)
How can i get this string "2, 3, 4" using regex and ruby?
You can do this in ruby
input="682_2, 682_3, 682_4"
output = input.gsub(/\d+_/,"")
puts output
A simple regex could be
/_([0-9]+)$/ and in the match group of the result you will have 2 for 682_2 and 3 for 682_3
Ruby code snippet would be "64532_2".match(/_([0-9]+)/).captures[0]
you can use scan which returns an array containing the matches:
string_code.scan(/(?<=_)\d/)
(?<=_) tells to find a pattern that has a given pattern (_ in this case) before itself but wont capture that, it captures only \d. if it can have more than 1 digit like 682_13,682_33 then \d+ is necessary.
This question already has an answer here:
Reference - What does this regex mean?
(1 answer)
Closed 3 years ago.
Is there anyone who can help me to get the marked pieces out of this file (see image below) with a regular expression? As you can see, it's difficult because the length is not always the same and the part before my goal is sometimes broken down and sometimes not.
Thank you in advance.
Text:
:61:200106D48,66NDDTEREF//00060100142533
/TRCD/01028/
:86:/EREF/SLDD-0705870-5658387529//MARF/11514814-001//CSID/NL59ZZZ390
373820000//CNTP/NL96ABNA0123456789/ABCANL2A/XXXXXXX123///REMI/UST
D//N00814760/
:61:200106D1840,55NDDTEREF//00060100142534
/TRCD/01028/
:86:/EREF/SLDD-0705869-5658387528//MARF/11514814-001//CSID/NL59ZZZ390
373820000//CNTP/NL96ABNA0123456789/ABCANL2A/XXX123XXXX///REMI/UST
D//N00814759/
:61:200106C236,31NTRFEREF//00060100142535
/TRCD/00100/
:86:/EREF/05881000010520//CNTP/NL19INGB0123456789/ABCBNL2A/XX123XXXX//
/REMI/USTD//KLM REF 1000000022/
The length is not always the same but it does not really matter in your case. You can check for a particular pattern at the end of a string.
(?<=\/\/)([\u2022a-zA-Z0-9]+)(?=\/$)
this regex will look for a string of caracter containing bullet (•), numbers, letters (uppercase and lowercase), that followes two front slash (//) and is followed by a slash (/) and the end of the string ( $ ).
You can test more cases here
This question already has answers here:
Match exact string
(3 answers)
Closed 4 years ago.
I have the following regex for a string which starts by a + and having numbers only:
PatternArticleNumber = $"^(\\+)[0-9]*";
However this allows strings like :
+454545454+4545454
This should not be allowed. Only the 1st character should be a +, others numbers only.
Any idea what may be wrong with my regex?
You can probably workaround this problem by just adding an ending anchor to your regex, i.e. use this:
PatternArticleNumber = $"^(\\+)[0-9]*$";
Demo
The problem with your current pattern is that the ending is open. So, the string +454545454+4545454 might appear to be a match. In fact, that entire string is not a match, but the engine might match the first portion, before the second +, and report a match.
This question already has an answer here:
Learning Regular Expressions [closed]
(1 answer)
Closed 5 years ago.
I need a regex to match the groups of characters in a string.
For example this is-a#beautiful^day.
Should result in the following list: this, is, a, beautiful, day.
As a mention I don't know how long the string is or by what characters the words are separated.
Any ideas? I have no clue how to build a regex for this.
If you want find all groups of letters:
import re
string = "this is-a#beautiful^day"
list = re.findall(r'[A-Za-z]+', string)
print list
['this', 'is', 'a', 'beautiful', 'day']