I am calling the function below by a character 'a', I want to call another function by char 'b' to make a file after displayEntry(i); I am confused to create a file from display fun(), can anyone please help me out ?
In my assignment it is written as below :
(a) Search a certain last name
(b) Save the search result in a file
Where (a) is done but got stuck with (b)...........
// My code is :
void addBook::searchEntry() {
char lastname[32];
cout << "Enter last name : ";
cin >> lastname;
for(int i = 0;i < count;++i) {
if(strcmp(lastname, entries[i].lastName) == 0) {
cout << "Found ";
displayEntry(i);
}
cout<<endl;
}
}
use fstream to write and read from/to files:
#include <fstream> // add this to your inclusion
// My code is :
void addBook::searchEntry()
{
ofstream out("example.txt", ios::out);
char lastname[32];
cout << "Enter last name : ";
cin >> lastname;
for(int i = 0; i < count; ++i)
{
if(strcmp(lastname, entries[i].lastName) == 0)
{
cout << "Found ";
displayEntry(i);
out << lastname << endl;
}
cout<<endl;
}
out.close(); // don't forget to close files after you're done with using them
}
Related
I would like to write the words in the file until I type the word "stop", but only the first word is saved to the file.
What's the problem?
int main(int i)
{
ofstream file;
string file_name,message;
cout << "\nFilename: ";
cin >> file_name;
cout << "Write 'stop' to end writig to file" << endl;
for(i=0; message!="stop"; i++)
{
cout << "\nYour message: ";
cin >> message;
file.open(file_name.c_str());
file << message.c_str() << "\t" ;
}
file.close();
return 0;
}
It should be,
int main()
{
int i;
ofstream file;
string file_name,message;
cout << "\nFilename: ";
cin >> file_name;
cout << "Write 'stop' to end writig to file" << endl;
file.open(file_name.c_str());
for(i=0; message!="stop"; i++)
{
cout << "\nYour message: ";
cin >> message;
if(message == "stop"){ //If you dont want word stop
break;
}
file << message.c_str() << "\t" ;
}
file.close();
return 0;
}
It would be better if you do something like,
do{
//do stuff
if (message == "stop")
break;
}while(message != "stop");
In this case, you better switch to a while loop of the form: while (!file.eof()), or while (file.good()).
Apart from that, the for loop has to define the variable, in your case i is undefined, and must contain the range of the variable and no other variable definition (condition on message must not be inside it. It has to be an if condition inside the for loop).
...
char word[20]; // creates the buffer in which cin writes
while (file.good() ) {
cin >> word;
if (word == "stop") {
break;
...
}
}
...
Actually, I am not sure how it compiles at all in your case :) For future reference: for loop should look like this: for (int i = 0; i<100; i++) {};
I hope it is clear!
c++ Microsoft visual studio on a windows.
im very new to coding. currently going through Programming -- Principles and Practice Using C++ by Stroupstrup and I came across a difficulty. I am to create a "score chart" with vector name and vector score from the user input. I used for-loop to get the input. now I am to modify the program so that with 2nd input from the user I can search the list and "cout<<" the score for a person. the problem is the the program completely ignores the 2nd "cin>>" command.
I search online and could not find a reasonable answer to this problem. Is there any special interaction between a for-loop input being terminated and another input (not looped)
syntax:
#include "stdafx.h"
#include <iostream>
#include <vector>
#include <string>
using namespace std;
int main()
{
vector<string> name;
vector<int> score;
string temp2;
int i;
for (string temp; cin >> temp >> i;) //input terminated with "Ctrl+Z"
name.push_back(temp), score.push_back(i);
for (int i = 0; i < name.size(); ++i) {
for (int j = i + 1; j < name.size(); ++j) {
if (name[i] == name[j]) {
name[j] = "error";
score[j] = 0;
}
}
}
for (int i = 0; i < name.size(); ++i) {
cout << name[i] << "------" << score[i] << "\n";
}
cout << "name"; //this line shows in the console
cin >> temp2; //but I cannot prompt the user to input again?
return 0;
}
CTRL-Z is interpreted as "End-Of-File", such that any subsequent access to this stream will not read in items any more. The only secure way is to change program logic such that the list of names is terminated by, let's say "END", and not a CTRL-Z. Then you can continue in a save manner.
Often input from a terminal is read in line by line and parsed afterwards. This makes error handling easier. See the following code following such an approach:
#include <sstream>
int main() {
string line;
map<string,int> scoreboard;
cout << "enter name score (type END to finish):" << endl;
while (std::getline(cin, line) && line != "END") {
stringstream ss(line);
string name;
int score;
if (ss >> name >> score) {
scoreboard[name] = score;
} else {
cout << "invalid input. Type END to finish" << endl;
}
}
cout << "enter name:" << endl;
string name;
if (cin >> name) {
auto item = scoreboard.find(name);
if (item != scoreboard.end()){
cout << "score of " << name << ":" << item->second << endl;
}
else {
cout << "no entry for " << name << "." << endl;
}
}
}
my text file was like
123456123456
Jason
uk
012456788
1000
456789456789
david
uk
012456788
1000
i'm trying to get the data from a text file and save it into arrays
however when i want to store the data from the text file into array it loop non-stop.
what should i do ?
the problem exiting in looping or the method i get the data from text file ?
code:
#include <iostream>
#include <fstream>
using namespace std;
typedef struct {
char acc_no[12];
char name[30];
char address[50];
char phone_no[12];
double balance;
} ACCOUNT;
//function prototype
void menu();
void read_data(ACCOUNT record[]);
int main() {
ACCOUNT record[31]; //Define array 'record' which have maximum size of 30
read_data(record);
}
//--------------------------------------------------------------------
void read_data(ACCOUNT record[]) {
ifstream openfile("list.txt"); //open text file
if (!openfile) {
cout << "Error opening input file\n";
return 0;
} else {
int loop = -1; //size of array
cout << "--------------Data From File--------------"<<endl;
while (!openfile.eof()) {
if (openfile.peek() == '\n')
openfile.ignore(256, '\n');
openfile.getline(record[++loop].acc_no, 12);
openfile.getline(record[loop].name, 30);
openfile.getline(record[loop].address, 50);
openfile.getline(record[loop].phone_no, 12);
openfile >> record[loop].balance;
}
openfile.close(); //close text file
for (int i = 0; i <= loop + 1; i++) {
cout << "Account " << endl;
cout << "Account No. : " << record[i].acc_no << endl;
cout << "Name : " << record[i].name << endl;
cout << "Address : " << record[i].address << endl;
cout << "Phone Number : " << record[i].phone_no << endl;
cout << "Balance : " << record[i].balance << endl;
}
}
}
UPDATE:
The OP didn't properly cite the correct format in his data file. This answer is only valid up until the last iteration.
Don't use .eof() - that's more applicable to when you want to open the file and read it by characters.
A better way would be to use the insertion operator >> as follows:
#define ARR_SIZE 31
ACCOUNT temp;
ACCOUNT record[ARR_SIZE];
int i=0;
while(i < ARR_SIZE) {
openfile >> temp.acc_no >> temp.name >> temp.address >> temp.phone_no >> temp.balance;
record[i] = temp;
i++;
}
Of course, even better is to use std::string to hold the values from the input file, in addition to using std::vectors instead of arrays.
The program works all the way up until it checks for the name the user enters. When you enter the name you wish to search for in the array of structures that have been imported from a file full of customer info) it comes back segmentation fault core dumped. This puzzles me.
#include <iostream>
#include <string>
#include <fstream>
#include <cstring>
using namespace std;
struct AccountsDataBase{
char name[50];
string email;
long int phone;
string address;
};
#define MAX 80
AccountsDataBase * account = new AccountsDataBase[MAX];
void readIn(ifstream& file){
int i=0;
while(!file.eof()){
file >> account[i].name >> account[i].email >> account[i].phone >> account[i].address;
}
}
void getAccount(){
char userPick[50];
char streamName[50];
cout << " What account will we be using? " << endl;
cin.getline(streamName, 50);
for(int i=0; strcmp(account[i].name, streamName)!=0; i++){
if( strcmp(account[i].name, streamName)==0){
cout << "\n\n FOUND IT!! \n\n";
cout << account[i].name << "\n" << account[i].email << "\n" << account[i].phone << "\n" << account[i].address << endl;
}
}
}
int main(){
ifstream file;
file.open("2.dat"); //opens data account records text
readIn(file);
getAccount();
delete account;
return 0;
}
Your loop keeps reading everything into the initial element of the array:
while(!file.eof()){
file >> account[i].name >> account[i].email >> account[i].phone >> account[i].address;
}
because the value of i is never incremented. You can convert this to a for loop, like this:
for (count = 0 ; count < MAX && !file.eof() ; count++) {
file >> account[count].name >> account[count].email >> account[count].phone >> account[count].address;
}
Note that I changed i to count:
AccountsDataBase * account = new AccountsDataBase[MAX];
int count = 0;
This will help you solve another problem - determining when the array ends in the getAccount function. Currently, you assume that the record is always there, so the outer loop keeps going on. Now that you have count, you could change the loop like this:
for(int i=0; i < count && strcmp(account[i].name, streamName)!=0; i++){
if( strcmp(account[i].name, streamName)==0){
cout << "\n\n FOUND IT!! \n\n";
cout << account[i].name << "\n" << account[i].email << "\n" << account[i].phone << "\n" << account[i].address << endl;
break;
}
}
if (i == count) {
cout << "Not found." << endl;
}
How can I read input line(type string) with whitespace? I tried getline but it goes into infinite loop. Following is my code.
#include <iostream>
#include <cstring>
#define MAX 50 //size of array
//Used G++ 4.6.3 compiler
using namespace std;
int main() {
struct Manager {
string name;
int age;
int working_years;
string phone;
int salary;
}info[MAX];
char inp; //To choose options
int array_pos = 0; //Current position in array of Manager structure
string search_name; //Manager name you want to search
cout << "Press 'i' to insert manager information or 's' to search for manager information by name or 'a' to abort: ";
cin >> inp;
while(inp != 'a') {
int search_num = 0; //array position at which search result is found
int found = 0;
if (inp == 'i' || inp == 's') {
if (inp == 'i') {
int k = array_pos;
cout << "Enter the information of the manager no "<<k+1<<" is : ";
cout << "Enter the Name : ";
//infinte loop occurs
getline(info[array_pos].name, '\n');
//cin >> info[array_pos].name;
cout<<"Enter manager age : ";
cin >> info[array_pos].age;
cout << "Enter manage working years : ";
cin >> info[array_pos].working_years;
cout << "Enter manager phone no. : ";
cin >> info[array_pos].phone;
cout << "Enter manager salary : ";
cin >> info[array_pos].salary;
array_pos++;
}
if (inp == 's') {
cout << "Enter the manager name you want to search : ";
cin >> search_name;
for(int i = 0; i < array_pos; i++) {
//using str1.compare(str2) to compare manager name
if(info[i].name.compare(search_name) == 0) { //manager name found in array of structure
found = 1;
search_num = i;
cout << "Name : " << info[search_num].name << "\n";
cout << "Age: " << info[search_num].age << "\n";
cout << "Working Years: " << info[search_num].working_years << "\n";
cout << "Phone No. : " << info[search_num].phone << "\n";
cout << "Salary : " << info[search_num].salary << "\n";
} //end of if loop for comparing string
} //end of for loop for searching
if(found == 0)
cout << "No Manager by this name exist in record" << "\n";
} //end of if loop
} //end of if loop for searching or insertion
if(inp == 'a')
break;
cout << "Press 'i' to insert manager information or 's' to search for manager information by name or 'a' to abort: ";
cin >> inp;
} //end of while loop
return 0;
}
How can I read input line(type string) with whitespace?
std::string line;
if (std::getline(std::cin, line)) {
...
}
Note that apart from checking the return value of std:getline call, you should also avoid mixing >> operator with std::getline calls. Once you decide reading the file line by line, it seems to be cleaner and more reasonable to just make one huge loop and do the additional parsing while using string stream object, e.g.:
std::string line;
while (std::getline(std::cin, line)) {
if (line.empty()) continue;
std::istringstream is(line);
if (is >> ...) {
...
}
...
}
Simplest way to read string with spaces without bothering about std namespace is as follows
#include <iostream>
#include <string>
using namespace std;
int main(){
string str;
getline(cin,str);
cout<<str;
return 0;
}
Solution #1:
char c;
cin >> noskipws; // Stops all further whitespace skipping
while (cin >> c) { // Reads whitespace chars now.
count++;
}
Solution #2:
char c;
while (cin.get(c)) { // Always reads whitespace chars.
count++;
}