Right now. I have a search function in my page to search for item id. When I click search, I will render the same page with the result items and show item. And in other pages where I also display the item id, I want to add a link to the id to go to the same page where I search for that id.
Example: id: 123, I want the same page when:
1. search '123' in my search page(my search only accept exact match)
2. In other pages, click '123', go to the search page with results
How should I achieve this, I have tried many ways which don't wok.
You need to make use of the GET method that HTML forms provide. When you perform a search from the first page, you must make sure that you are doing so using the GET method in the form. This will append the form data into the URL.
E.g. If you have a 'name' field in your form which has 'John' inputted. The submission of this form will compose a URL like so:
http://someurl.com/?name=John
This can then be accessed using the Django request object:
name = request.GET['name']
You've probably done something similar already for displaying your search results. So, all you need to do is create a link in your second page that redirects to the search page with GET request variables appended.
E.g.
<a href="{% url 'search_page' %}?searchterm=232> Item 232 </a>
Related
I want to create a back button to a page which can be accessed with a link from another page. To do this, I want to put the first page's path to the link, and on the next page I can put it to the back button.
I have this anchor tag:
Go to page
When I try to go to the site I get the following error:
Reverse for 'page' with keyword arguments '{'path': '/my_site/'}' not found. 1 pattern(s) tried: ['notifications\\/(?P<path>[^/]+)\\Z']
If you know the url name of the first page,
path('first_page/', views.first_page, name='first_page'),
then you can simply use:
Go the page
Otherwise, you must add the url of the previous page to the context of the second page's template in order to use that in that template. How to do that depends on your style. For instance, you can somehow keep a log of the visited pages on the client side or server side, and use that collection to determine the previous page.
I have a page item which stores URL.
How do i change its type to URL so that the link becomes clickable.
As of now, there is page subtype url, but setting it doesn't make any difference.
Apex 21.1
A text field is an html input element, that will display text only, you probably could write some javascript to open whatever is in the page item in an url but that is confusing functionality. What should happen if the user clicks in the input element ? Should it open the link or should the user be editing the value ?
This is a possibility.
Create a page item on your page, say P1_URL
Add the following in the "Post Text" attribute of the page item (style it to your own preference):
<span class="fa fa-external-link" aria-hidden="true"></span>
Add a dynamic action on change of the element P1_URL with a true action of "Execute Javascript Code" and the following code:
$("#myurl").attr("href", apex.item( "P13_URL" ).getValue())
Check "Fire on Initialization" for the true action.
That is all there is to it, now when you add something in the page item P1_URL and click the link, it will open the that url in a new window.
UPDATE: Technique for read only text field.
For a read only text field, the input element is hidden and an additional span element is rendered with an the page item name as id, suffixed by _DISPLAY. The trick is to grab the content of that span element and add an anchor with attributes. This can be done with an onload dynamic action:
Create a page item on your page, say P1_URL, set it to "Read-Only: Always"
Add a dynamic action on Page Load with a true action of "Execute Javascript Code" and the following code:
let itemVal = $("#P1_URL_DISPLAY").text()
$("#PP1_URL_DISPLAY").html(`<a href='${itemVal}' target='_blank'>${itemVal}</a>`)
Make sure that when you copy this, the quotes are exactly the same: the outer quotes are backticks, those are needed for the ES6 syntax.
Note: check the page documentation for the subtype url - it explains exactly what it does.
I am building a blog in django and am using django-taggit. I'm trying to figure out how to tie the link of a tag to a search result page that shows all of the posts using that tag.
I already have the search page created, I know how to filter queries to the page to bring the correct results, and know how to link to the page itself {% url 'search' %}. But how would I pass queries to the page from the template?
For instance, if I have a post tagged "dog" I want users to be able to click on the tag "dog" and be taken to the search page that only has results for posts also tagged "dog".
The django documentation for class views does not have examples of this. And every tutorial resource so far has been focused on the filtering and displaying of the search page itself rather than linking to it with desired queries in an <a> tag instead of a <form>.
In short, how do you make an <a> link pass a query into a url, like how an <input> would to a <form> action in Django?
I found the answer. Based on this , it is
<a href="{% url 'myview' %}?q=foobar">
I originally followed this tutorial (https://django-haystack.readthedocs.org/en/latest/tutorial.html), and have so far been able to highlight my query within my returned results. However, I want to highlight this same query when visiting the next page that I load with a separate template. Is there any way to save/access this query so that I can highlight the same results within this other template?
Whenever I try and include a statement like this, I get an error, which I'm thinking is because I'm not trying to access the query properly.
{% highlight section.body with query html_tag "span" css_class "highlighted" %}
You have to send to the next page, the information that you use to highlight the results in the first page. You can use the request.session to store the data and call it in the next page, or you can send the sqs by the url to the next page.
If you want to know how to manage the search query set, and how to edit that kind of stuff, I recommend you to read the views.py forms.py and the elasticsearch_backend in the haystack folder at: "/usr/local/lib/python2.7/dist-packages/haystack"
This is the url for the documentation of Django Session: Django Session
This is the url for the documentation to pass parameters trhough url: URL dispatcher
I have a view that displays some movie data. I thought that it might be a good idea to have a view handle a an URL like movie-id/1234 to search for movie id 1234. Furthermore I would like to be able to enter the ID into a form and send that to a server and search for it. To do that I created a second entry in the urls.py file shown below.
urlpatterns = patterns('',
url(r'movie-id/(?P<movie_id>.+?)/$', 'movieMan.views.detailMovie'),
url(r'movie-id/$', 'movieMan.views.detailMovie', name='movieMan.detailMovie.post'),
)
So if I want to pass data to my view either via a URL or a GET or POST request I have to enter two urls or is there a more elegant way? In the view's code I am then checking if there is any GET data in the incoming request.
To make the second url usable with the template engine, where I wanted to specify the view's url using the {% url movieMan.detailMovie.post %} syntax I had to introduce a name attribute on this url to distinguish between these two.
I am not sure if I am thinking too complicated here. I am now asking myself what is the first url entry good for? Is there a way to get the URL of a movie directly? When do these kinds of URLs come into play and how would they be generated in the template ?
Furthermore I would like to be able to enter the ID into a form and
send that to a server and search for it.
Is this actually a search? Because if you know the ID, and the ID is a part of the URL, you could just have a textbox where the user can write in the ID, and you do a redirect with javascript to the 'correct' URL. If the ID doesn't exist, the view should return a Http404.
If you mean an actual search, i.e. the user submitting a query string, you'll need some kind of list/result view, in which case you'll be generating all the links to the specific results, which you will be sure are correct.
I don't think there is a more elegant way.
I did almost the same thing:
url( r'^movies/search/((?P<query_string>[^/]+)/)?$', 'mediadb.views.search_movies' ),
The url pattern matches urls with or without a search parameter.
In the view-function, you will have to check whether the parameter was defined in the url or in the query string.