Oracle Apex How to display page item as url - oracle-apex

I have a page item which stores URL.
How do i change its type to URL so that the link becomes clickable.
As of now, there is page subtype url, but setting it doesn't make any difference.
Apex 21.1

A text field is an html input element, that will display text only, you probably could write some javascript to open whatever is in the page item in an url but that is confusing functionality. What should happen if the user clicks in the input element ? Should it open the link or should the user be editing the value ?
This is a possibility.
Create a page item on your page, say P1_URL
Add the following in the "Post Text" attribute of the page item (style it to your own preference):
<span class="fa fa-external-link" aria-hidden="true"></span>
Add a dynamic action on change of the element P1_URL with a true action of "Execute Javascript Code" and the following code:
$("#myurl").attr("href", apex.item( "P13_URL" ).getValue())
Check "Fire on Initialization" for the true action.
That is all there is to it, now when you add something in the page item P1_URL and click the link, it will open the that url in a new window.
UPDATE: Technique for read only text field.
For a read only text field, the input element is hidden and an additional span element is rendered with an the page item name as id, suffixed by _DISPLAY. The trick is to grab the content of that span element and add an anchor with attributes. This can be done with an onload dynamic action:
Create a page item on your page, say P1_URL, set it to "Read-Only: Always"
Add a dynamic action on Page Load with a true action of "Execute Javascript Code" and the following code:
let itemVal = $("#P1_URL_DISPLAY").text()
$("#PP1_URL_DISPLAY").html(`<a href='${itemVal}' target='_blank'>${itemVal}</a>`)
Make sure that when you copy this, the quotes are exactly the same: the outer quotes are backticks, those are needed for the ES6 syntax.
Note: check the page documentation for the subtype url - it explains exactly what it does.

Related

Oracle APEX - hyperlink shown as text on a static region

I have a static region and I want to set it to some text with a hyperlink. Text comes from the database - returned by a function.
So I added a page item (P1_LINK_TEXT) to the page and added a computation to my page item that is set to PL/SQL expression:
MyFunction('MY_TEXT')
The region Header Text to &P1_LINK_TEXT.
It works great, except the hyperlink displayed as is - Click here
instead of displaying the link. I made sure that Attributes->Settings->Output As is set to HTML but still, the hyperlink is not displayed correctly. What am I doing wrong?
Use the escape filter to ensure html characters are not escaped. To display the item as html use this notation:
&P1_LINK_TEXT!RAW.

APEX - double click on interactive gird

Below is my interactive grid. It shows data from v$sql_monitor view based on sql_id from list .
What I would like to do is to create double-click dynamic action on a record. This action would open new modal dialog and pass two parameters : 1. sql_id from list above 2.sql_exec_id from clicked record. Would you give me a few hints how to do it ? I guess a piece of Javascript code will be necessary :(
There are multiple options to do this - here is one way, by using javascript custom events. I created a sample with an IG on the EMP/DEPT sample dataset with page 88 as IG and page 90 as modal. The column ENAME is a link to page 90 that sets a column value and a page item in the link.
Page 88 has an IG and 2 page items:
P88_PAGE_ITEM (a value entered on the page like the list in your screenshot)
P88_ENAME (to hold the selected report column value
Page 90 has 2 page items: P90_PAGE_ITEM and P90_REPORT_COLUMN
Create IG on page 90 on table EMP
On column ENAME, add the following under "JavaScript Initialization Code"
function(config) {
config.defaultGridColumnOptions = {
cellTemplate: '<button type="button" class="t-Button t-Button--link my-ename-js" data-ename="&ENAME.">&ENAME.</button>'
};
return config;
}
This is a button of type "display as link", created with the universal theme button builder that has 2 extra attributes: a class my-ename-js and a data attribute "ename" data-ename="&ENAME."
Create a dynamic action to capture the click and set the page item:
Make sure to set the scope to "Dynamic". This is needed because the event listener needs to be added again after a dom change (a search or filter of the IG).
add a true action of type "Set Value" to set the value of P88_ENAME to the value of the selected row
add a second true action to trigger a custom javascript event:
Create a dynamic action of type "Event: Custom" to capture the custom event triggered in the previous DA.
add a true action of type "Submit Page". Note that "Show Processing" needs to be unchecked.
Almost there. One last thing is to create a branch to the modal page:
Create a branch (process point "After Processing") with server-side condition of "Request = Value" with value OPENMODAL and link attributes below:
And this should be the result:
Well, I modified a bit your scenario.
I added new SelectList P88_FILTER
and added dynamic action ON_CHANGE :
with action
I modified source if IG:
These changes allowes me to filter IG . In our case filter returns always only one record like below.
and now my problem begins. In your scenario clicking the link "ename" updates field P88_ENAME and opens modal dialog with proper values. After my modification neither P88_ENAME updates nor modal dialog opens :(

ORACLE APEX: Getting the value from page item and use it to another page item

I have two forms:
first one:
5000_Works,
with items:
P5000_ID,
P5000_Working_Date,
P5000_QTY
and the second form:
5001_Tasks,
with items:
P5001_ID,
P5001_QTY
I open the second form from the first one and i want to put the value of P5000_QTY to the second page item P5001_QTY.
How can i do that?
Thank you
One option is to create a button which - when pushed - redirects to another page in this application. When you click on the "Target" (in "Behavior" properties section), you can tell Apex to:
navigate to page 5001
set item P5001_QTY to value &P5000_QTY. Note leading ampersand & and trailing dot .
And that's it ...
If it isn't a button but a branch, the principle is the same - using the Link Builder you'd do exactly the same.

Django redirect to form page and submit the form?

Right now. I have a search function in my page to search for item id. When I click search, I will render the same page with the result items and show item. And in other pages where I also display the item id, I want to add a link to the id to go to the same page where I search for that id.
Example: id: 123, I want the same page when:
1. search '123' in my search page(my search only accept exact match)
2. In other pages, click '123', go to the search page with results
How should I achieve this, I have tried many ways which don't wok.
You need to make use of the GET method that HTML forms provide. When you perform a search from the first page, you must make sure that you are doing so using the GET method in the form. This will append the form data into the URL.
E.g. If you have a 'name' field in your form which has 'John' inputted. The submission of this form will compose a URL like so:
http://someurl.com/?name=John
This can then be accessed using the Django request object:
name = request.GET['name']
You've probably done something similar already for displaying your search results. So, all you need to do is create a link in your second page that redirects to the search page with GET request variables appended.
E.g.
<a href="{% url 'search_page' %}?searchterm=232> Item 232 </a>

Sitecore Page Editor Publishing items related to content

I have a "Product Page",Product page maps to "ProductPage" Sitecore item. Website/Pages/ProductPage.
I have a text area in that page with page editor, which loads text from "Product Example Text" Sitecore item's "Description" text from Web database. (Sitecore.../CommonText/Product Example Text)
In my ascx file, mark up is pretty straigh forwad,
<sc:FieldRenderer ID="FieldRenderer1" runat="server" />
Codebehind,
FieldRenderer1.Item = //"Product Example Text" Sitecore item
FieldRenderer1.FieldName = "Description";
When I open the page in Page Editor(as a system admin), it allows me to change the "Product Example Text", and when I save using the "Save" button on the Page Editor it get saved to the master database. "Product Example Text" item get saved.
Now, when I try to publish the item using the "Publish" item in the Page Editor ribbon, these changes do not get reflected,reason is "Product Example Text" item does not get published.
When I save the page, somehow Sitecore understands the "Product Example Text" item has to be saved. But why does not it get published?
Am I doing anything wrong.... How can I solve this issue?
While saving an item in Page Editor, Sitecore saves all the field renderers which are displayed on the page, so if you set the Item property of a FieldRenderer1 to "Product Example Test" Sitecore Item, Page Editor know which item should be saved.
The problem with publishing is that you enqueue the current item in the publishing queue, but this item has no link to the "Product Example Test" Sitecore Item in any of its properties cause you're setting the Item property of the field renderer dynamically in the code.
The option would be to add another button to Page Editor next to Edit Related Item button and create a command that will Publish Related Item. The complete description how to add such a command can be found in the answer Sitecore page editor - how to extend page editor item editing panel
Another approach would be to create the "Product Example Test" content item under the "ProductPage" as a sub item. In publish options you can use publish sub items, which will publish all content you want.
But the problem is, if you want a particular content to be shared in several places, this won't work.
Maras's answer is a better solution.