How can I use a variable to lookup in a tuple? (Django) - django

I have a tuple, such that
{{VISIBILITY_CHOICES.1.1}}
Outputs "hello".
I have model "task" with a attribute "visibility_status", and in a loop, say all the iterations of task.visibility_status outputs 1
{{task.visibility_status}}
Outputs 1.
How do I use this task.visibility_status inside the lookup of the tuple? Something like VISIBILITY_CHOICES[task.visibility_status][1] in a different language.
I'm very new to django... Thanks a lot.
edit:
The code I was running:
{% for task in tasks %}
<div class="post">
<h1>{{ task.subject }}</h1>
<div class="date">
<p>Due: {{ task.due_date }}</p>
<p>Assigned to: {{task.assigned_to}}</p>
</div>
<p>{{ task.text_area|linebreaks }}</p>
{% with args=""|add:task.visibility_status|add:",1" %}
<p>Visibility Status: {{VISIBILITY_CHOICES|get_index:args}}({{ task.visibility_status }})</p>
{% endwith %}
<p>Case Status: {{ task.case_status }}</p>
<div class="date">
<p>Created: {{ task.created_date }} by {{ task.author }}</p>
</div>
</div>
{% endfor %}

Although the builtin name tuple may not have any syntactic meaning in a template, I'll use my_tuple in its place in the code below.
I've used with to create a context that builds the args for indexing my_tuple (i.e task.visibility_status and 1): :
{% with x=task.visibility_status|stringformat:"s" %}
{% with args=x|add:",1" %}
{{ my_tuple|get_index:args }}
{% endwith %}
{% endwith %}
And in the custom template filter, I've splitted and recreated the arguments and used indexing in plain python to return the item at the index:
from django import template
register = template.Library()
#register.filter
def get_index(my_tuple, args):
arg1, arg2 = args.split(',') # split on the comma separator
try:
i = int(arg1)
j = int(arg2)
return my_tuple[i][j] # same as my_tuple[task.status][1]
except:
return None

Related

Iterate context variables in Django templates based on user's attributes

Is it possible to iterate over a list of three context variables shown below so that depending on the user's attribute (in this instance grade, Grade 10, Grade 11, Grade 12). If current user's grade attribute is Grade 10 then they only get: context['grade10'] from below.
Current view:
class SumListView(ListView):
model = Summaries
template_name = 'exam/summary.html'
def get_context_data(self, **kwargs):
context = super().get_context_data(**kwargs)
context['grade10'] = Summary.objects.filter(grade='Grade 10')
context['grade11'] = Summary.objects.filter(grade='Grade 11')
context['grade12'] = Summary.objects.filter(grade='Grade 12')
return context'''
Current html template block:
{% block content %}
{% for summary in grade10 %}
<div class="container>
{{ summary.content }}
</div>
{% endfor %}
{% endblock content %}
I tried this but it breaks the code since for loops and iterations are mixing:
{% block content %}
{% if grade10 %}
{% for summary in grade10 %}
<div class="container>
{{ summary.content }}
</div>
{% endfor %}
{% elif grade11 %}
{% for summary in grade10 %}
<div class="container>
{{ summary.content }}
</div>
{% endfor %}
{% else grade12 %}
{% for summary in grade10 %}
<div class="container>
{{ summary.content }}
</div>
{% endfor %}
{% enif %}
{% endblock content %}
What is the best way to go about this?
I know I can write different urls for each context which in turn renders a different template but that does not seem efficient and I hope there is a better way to do that. Any help highly appreciated, including documentation pointers.
You can perform this logic in your view, you can use a single context variable but change it's contents based on your logic
def get_context_data(self, **kwargs):
context = super().get_context_data(**kwargs)
user_grade = self.request.user.get_grade() # Replace with how you access the user's grade
context['grades'] = Summary.objects.filter(grade=user_grade)
return context
Then loop over grades in your template

Django nested QuerySet yielding nothing

I am using Django 1.8 with Postgres 9.2 on a Windows 8 machine.
I have two pieces of nearly identical code from two of my projects. One works and the other doesn't.
Here's the code that works:
# views.py
from django.shortcuts import render
from models import Artist, Track
def music(request):
artists = Artist.objects.all().order_by('orderName')
artistTrackCollections = []
for artist in artists:
artist.tracks = Track.objects.filter(artist=artist).order_by('order')
artistTrackCollections.append(artist)
return render(request, 'music.html', {'artistTrackCollections': artistTrackCollections,})
And the relevant template code:
{% for artist in artistTrackCollections %}
<dl>
<dt>
{% if artist.website %}
<h2>{{ artist.name }}</h2>
{% else %}
<h2>{{ artist.name }}</h2>
{% endif %}
</dt>
<dd>
<ul>
{% for track in artist.tracks %}
<li>“{{ track.title }}”
<i>({{ track.album.title }})</i>
{% endfor %}
</ul>
</dd>
</dl>
{% endfor %}
Now here's pretty much the exact same code from a different project of mine that doesn't work anymore:
def index(request):
productList = PartModel.objects.filter(isBuild=True, isActive=True).order_by('name')
productCollection = []
for product in productList:
product.part_list = product.buildpart.all().order_by('family__type')[:5]
productCollection.append(product)
return render(request, 'index.html', { 'productCollection': productCollection, })
and its corresponding template:
{% for product in productCollection %}
<p>{{ product.name }}
<p>${{ product.price }}
<ul>
{% for part in product.part_list %}
<li>{{ part.family.type.name }} | {{ part.name }}
{% endfor %}
</ul>
{% endfor %}
This code used to work but now it doesn't. In the code that works I succeed in going through each artist and attaching that artist's tracks. In the code that fails I try to go through each PartModel instance that is a build and get that PartModel instance's corresponding parts. They are identical as far as I can tell. productCollection gets populated but the part_list data for some reason is blank. This leads me to believe the problem is with this line:
product.part_list = product.buildpart.all().order_by('family__type')[:5]
But I cannot discern the difference from this line:
artist.tracks = Track.objects.filter(artist=artist).order_by('order')
Thanks in advance for any help!

Could not parse the remainder django template

I have a condition within a loop in my template like this:
{% for message in message_trash %}
<td><a href="#">
{% if request.session.user_email == message.message_user_reciever.user_email %}
{{ message.message_user_reciever.user_firstName }} {{ message.message_user_reciever.user_lastName }}
{% elif request.session.user_email == message.message_user_sender.user_email %}
{{ message.message_user_sender.user_firstName }} {{ message.message_user_sender.user_lastName }}
{% endif %}
</a><small>Friends</small></td>
{% endfor %}
but i don't know why i get this error when applying the url?
TemplateSyntaxError: Could not parse the remainder: '==message.message_user_reciever.user_email' from 'request.session.user_email==message.message_user_reciever.user_email'
Update:
this is the view and variables that i render to the template:
def trashMessages(request, userId):
if isMessageOwner(request, userId):
user = Users.objects.get(user_id=userId)
message_trash = Messages.objects.filter(Q(message_user_reciever= user, message_sender_type='TRASH') | Q(message_user_sender=user, message_reciever_type='TRASH'))
return render(request, 'navigation_messages.html', {'user': user, 'message_trash': message_trash, 'type': 'trash'})
On testing your code out, I can only replicate your issue is by swapping:
{% if request.session.user_email == message.message_user_reciever.user_email %}
for
{% if request.session.user_email ==message.message_user_reciever.user_email %}
Note the missing space. Is the snippet in your question exactly as it is in your template?

Variable subtraction in django templates

It is able to write {{ myval.add:5 }}, {{ myval|add:value }} and even {{ myval|add:-5 }}.
However, I can't find out what I should type to add value * -1 like {{ myval|add:-value }}. This doesn't work, sadly.
You need to use double quotes:
{{ myval|add:"-5" }}
This subtracts five from myval.
The built-in Django template tags/filters aren't all-encompassing, but it's super easy to write your own custom template tags: https://docs.djangoproject.com/en/dev/howto/custom-template-tags/
You could make your own subtract template tag pretty easily:
#register.filter
def subtract(value, arg):
return value - arg
Use django-mathfilters from PyPI: https://pypi.python.org/pypi/django-mathfilters
To install :
$ pip install django-mathfilters
Then add mathfilters in your INSTALLED_APPS.
In template:
{% load mathfilters %}
<ul>
<li>8 + 3 = {{ 8|add:3 }}</li>
<li>13 - 17 = {{ 13|sub:17 }}</li>
{% with answer=42 %}
<li>42 * 0.5 = {{ answer|mul:0.5 }}</li>
{% endwith %}
{% with numerator=12 denominator=3 %}
<li>12 / 3 = {{ numerator|div:denominator }}</li>
{% endwith %}
<li>|-13| = {{ -13|abs }}</li>
</ul>
I recently started working with Django and stumbled upon this one as well: I needed a very simple template loop that stops printing after n times and shows a "more" link to toggle the rest of the items.
With great interest I read the struggle of people trying to understand why this is not being added to the Django default filters (since before 2013). I didn't feel like creating a custom template tag and I kind of found a way to subtract 2 variables using strings and add in combination with with and stringformat
Let's say I have a list of items where I want to print the first 2 and hide the rest, showing how many hidden items are there, eg.
John, Anna and 5 others like this (when given a list of 7 items)
As long as the number of visible items is harcoded in the template (eg. 2), it's possible to add the negative 2 |add:"-2", but I wanted the number of visible items to be a variable as well. The Math-filter library as suggested above doesn't seem up to date (I haven't tested it with Django 2.x).
The trick seems to be to use the add helper to concat the strings "-" with the integer as string, so it can be coerced back to a negative integer in a any consecutive calls to the add helper. This doesn't work however if the value is not a string, so that's where the stringformat helper comes in.
With string value
template posts.html (note how visible is explicitely passed as string - alternative below)
{% for post in posts %}
<h4>{{ post.title }}</h4>
...
{% include 'show_likes.html' with likes=post.likes visible="3" %}
{% endfor %}
template show_likes.html (note the add:0 to make the boolean operator work)
{% with show=visible|default:"2" %}
{% for like in likes %}
{% if forloop.counter <= show|add:0 %}
{% if not forloop.first %},{% endif %}
{{ like.username }}
{% endif %}
{% endfor %}
{% if likes|length > show|add:0 %}
{% with rest="-"|add:show %}
and {{ likes|length|add:rest }} more
{% endwith %}
{% endif %}
like this
{% endwith %}
Alternative with integer
You could just convert your integer to a string in the calling template using |stringformat:"d"
If however the number of visible items you want to show is an integer, you'll have to add a call to stringformat:"d" to have it converted to string
template posts.html
{% for post in posts %}
<h4>{{ post.title }}</h4>
...
{% include 'show_likes.html' with likes=post.likes visible=3 %}
{% endfor %}
template show_likes.html
{% with show=visible|default:2 %}
{% with show_str=show|stringformat:"d" %}
{% for like in likes %}
{% if forloop.counter <= show %}
{% if not forloop.first %},{% endif %}
{{ like.username }}
{% endif %}
{% endfor %}
{% if likes|length > show|add:0 %}
{% with rest="-"|add:show_str %}
and {{ likes|length|add:rest }} more
{% endwith %}
{% endif %}
{% endwith %}
{% endwith %}
Since I'm a very beginner with Django and Python, I'm pretty sure this approach is far worse than actually creating a custom helper! So I'm not suggesting anyone should be using this. This was just my attempt on trying to solve this with the available template helpers and without any custom stuff.
Hope this helps
Lo primero es multiplicar por -1 para convertirlo en una valor negativo y guardarlo en una variable y posterior a usar la suma
The first thing is to multiply by -1 to turn it into a negative value
and save it in a variable and then use the add
{% widthratio val2 1 -1 as result %}
{{result|add:val1}}
After search I found that I can make {% with var=value %} with filters to make the arithmetic operations "with other variables or not"
For example: I have x = 5 and y = 3 and need to add the y's value to x value, all what I need is these steps:
1- Create variable x : {% with x=5 %}
2- Create variable y : {% with y=3 %}
3- In my HTML tags, say <h1>, write that : <h1>{{ x|add:y }}</h1>
4- Close the y's with : {% endwith %}
5- Close the x's with : {% endwith %}
Hope it works with you, it worked with me.
{% with i=3 %}
{% with x=1 %}
<h1>{{i|add:x}}</h1> <!-- result is 4 -->
{% endwith %}
{% endwith %}

Numeric for loop in Django templates

How do I write a numeric for loop in a Django template? I mean something like
for i = 1 to n
I've used a simple technique that works nicely for small cases with no special tags and no additional context. Sometimes this comes in handy
{% for i in '0123456789'|make_list %}
{{ forloop.counter }}
{% endfor %}
{% with ''|center:n as range %}
{% for _ in range %}
{{ forloop.counter }}
{% endfor %}
{% endwith %}
Unfortunately, that's not supported in the Django template language. There are a couple of suggestions, but they seem a little complex. I would just put a variable in the context:
...
render_to_response('foo.html', {..., 'range': range(10), ...}, ...)
...
and in the template:
{% for i in range %}
...
{% endfor %}
My take on this issue, i think is the most pythonic. Create a my_filters.py in your apps templatetags directory.
#register.filter(name='times')
def times(number):
return range(number)
Usage in your template:
{% load my_filters %}
{% for i in 15|times %}
<li>Item</li>
{% endfor %}
You can pass a binding of
{'n' : range(n) }
to the template, then do
{% for i in n %}
...
{% endfor %}
Note that you'll get 0-based behavior (0, 1, ... n-1).
(Updated for Python3 compatibility)
Maybe like this?
{% for i in "x"|rjust:"100" %}
...
{% endfor %}
I'm just taking the popular answer a bit further and making it more robust. This lets you specify any start point, so 0 or 1 for example. It also uses python's range feature where the end is one less so it can be used directly with list lengths for example.
#register.filter(name='range')
def filter_range(start, end):
return range(start, end)
Then in your template just include the above template tag file and use the following:
{% load myapp_filters %}
{% for c in 1|range:6 %}
{{ c }}
{% endfor %}
Now you can do 1-6 instead of just 0-6 or hard coding it. Adding a step would require a template tag, this should cover more uses cases so it's a step forward.
You can pass :
{ 'n' : range(n) }
To use template :
{% for i in n %}
...
{% endfor %}
I tried very hard on this question, and I find the best answer here:
(from how to loop 7 times in the django templates)
You can even access the idx!
views.py:
context['loop_times'] = range(1, 8)
html:
{% for i in loop_times %}
<option value={{ i }}>{{ i }}</option>
{% endfor %}
You don't pass n itself, but rather range(n) [the list of integers from 0 to n-1 included], from your view to your template, and in the latter you do {% for i in therange %} (if you absolutely insist on 1-based rather than the normal 0-based index you can use forloop.counter in the loop's body;-).
Just incase anyone else comes across this question… I've created a template tag which lets you create a range(...): http://www.djangosnippets.org/snippets/1926/
Accepts the same arguments as the 'range' builtin and creates a list containing
the result of 'range'.
Syntax:
{% mkrange [start,] stop[, step] as context_name %}
For example:
{% mkrange 5 10 2 as some_range %}
{% for i in some_range %}
{{ i }}: Something I want to repeat\n
{% endfor %}
Produces:
5: Something I want to repeat
7: Something I want to repeat
9: Something I want to repeat
You should use "slice" in template, a example like this:
in views.py
contexts = {
'ALL_STORES': Store.objects.all(),
}
return render_to_response('store_list.html', contexts, RequestContext(request, processors=[custom_processor]))
in store_list.html:
<ul>
{% for store in ALL_STORES|slice:":10" %}
<li class="store_item">{{ store.name }}</li>
{% endfor %}
</ul>
This method supports all the functionality of the standard range([start,] stop[, step]) function
<app>/templatetags/range.py
from django import template
register = template.Library()
#register.filter(name='range')
def _range(_min, args=None):
_max, _step = None, None
if args:
if not isinstance(args, int):
_max, _step = map(int, args.split(','))
else:
_max = args
args = filter(None, (_min, _max, _step))
return range(*args)
Usage:
{% load range %}
<p>stop 5
{% for value in 5|range %}
{{ value }}
{% endfor %}
</p>
<p>start 5 stop 10
{% for value in 5|range:10 %}
{{ value }}
{% endfor %}
</p>
<p>start 5 stop 10 step 2
{% for value in 5|range:"10,2" %}
{{ value }}
{% endfor %}
</p>
Output
<p>stop 5
0 1 2 3 4
</p>
<p>start 5 stop 10
5 6 7 8 9
</p>
<p>start 5 stop 10 step 2
5 7 9
</p>
This essentially requires a range function. A Django feature ticket was raised (https://code.djangoproject.com/ticket/13088) for this but closed as "won't fix" with the following comment.
My impression of this idea is that it is trying to lead to programming in the template. If you have a list of options that need to be rendered, they should be computed in the view, not in the template. If that's as simple as a range of values, then so be it.
They have a good point - Templates are supposed to be very simple representations of the view. You should create the limited required data in the view and pass to the template in the context.
{% for _ in ''|center:13 %}
{{ forloop.counter }}
{% endfor %}
If the number is coming from a model, I found this to be a nice patch to the model:
def iterableQuantity(self):
return range(self.quantity)
You can use:
{% with ''|center: i as range %}
For those who are looking to simple answer, just needing to display an amount of values, let say 3 from 100 posts for example just add {% for post in posts|slice:"3" %} and loop it normally and only 3 posts will be added.
This shows 1 to 20 numbers:
{% for i in "x"|rjust:"20"|make_list %}
{{ forloop.counter }}
{% endfor %}
also this can help you:
(count_all_slider_objects come from views)
{% for i in "x"|rjust:count_all_slider_objects %}
{{ forloop.counter }}
{% endfor %}
or
{% with counter=count_all_slider_objects %}
{% if list_all_slider_objects %}
{% for slide in list_all_slider_objects %}
{{forloop.counter|add:"-1"}}
{% endfor%}
{% endif %}
{% endwith %}
You can pass range(n) instead of n in the context in views.py. This will give you an iterable list.
context['range']= range(n)
Then you can iterate in your template this way:
{% for i in range %}
<!-- your code -->
{% endfor %}
{% for i in range(10) %}
{{ i }}
{% endfor %}