make user enter a string of integers and output a different string - c++

Question

hi i am having trouble starting this program as i am new and have no idea how to use loops to construct this thanks
here are the directions:
For this assignment, write a program named assignment2 (source is the same name with .cpp extension) to
prompt the user for an integer value (ignore negative values) and then output this value using the following rules:
Each digit within the integer value is to be displayed the same number of times as the value of the digit
itself, with one exception...the digit 0 will be displayed once, like the digit 1.
Separate each string of digits using a single dash character.
For example:
If the input value is 120473, the display should look like:
1-22-0-4444-7777777-333
If the input value is 5938061, the display should look like:
55555-999999999-333-88888888-0-666666-1
In addition, ask the user if they would like to retry using another integer value. If so, repeat the above. End the
program when the user chooses to quit (does not want to retry).
This assignment is an exercise in using the following:
Unary Operators:
! ++ --
Binary Operators:
+ - * / % && ||
Data types:
bool
char
int
enum
Flow control:
if-else
switch
do-while loop
while loop
for loop
In addition, you are allowed to use any necessary functions provided by the Math library. To include the Math
library, add the following line to your list of include statements:
#include <cmath>

Answer 1

For most digit manipulation assignments, I recommend treating the number as a string of characters rather than as a number.
The Foundation
Let's start with the foundation:
#include <iostream>
#include <string>
#include <cstdlib>
using std::cout;
using std::cin;
using std::getline;
int main(void)
{
cout << "Paused. Press Enter to continue.\n";
cin.ignore(100000, '\n');
return EXIT_SUCCESS;
}
The above program will hopefully keep the console (terminal) window open until the Enter key is pressed.
Getting The Input
We'll ask the User for a number, this is also known as prompting:
// The prompt text doesn't change so it's declared as const.
// It's declared as static because there is only one instance.
static const char prompt[] = "Enter a number: ";
cout.write(prompt, sizeof(prompt) - 1U); // Subtract 1 so the terminating nul is not output.
// Input the number as text
string number_as_text;
getline(cin, number_as_text);
Printing The Digits
Really, before this step, you should verify that the text only contains numbers. Repeat the prompting until the User inputs nothing or valid data.
A string can be accessed as an array. So we'll set up a loop:
const unsigned int length = number_as_text.length();
for (unsigned int index = 0U;
index < length;
++index)
{
// Extract the digit.
const char c = number_as_text[index];
// Verify it is a digit.
if (!isdigit(c))
{
continue;
}
unsigned int quantity = c - '0'; // Convert to a number.
if (quantity == 0) quantity = 1; // The requirements lie, for zero there is a quantity of 1.
// Use "quantity" to print copies of the character.
}
cout << "\n";
Stuff
I'm not going to write the entire program for you, as you haven't paid for my services. So you will have to figure out when to print the '-' and how to print many copies of the digit.
If this answer is not correct, please update your question with some clarifications or restrictions.